Word Problems on Area of a Rectangle | Area of a Rectangle Word Problems

Word Problems on Area of Rectangle provided develops mathematical interest among kids by relating the concept to real-life situations. You will find a variety of problems in finding the area of rectangular shapes in this article. Try solving the Area of a Rectangle Problems provided on a regular basis and get a good hold of the concept. Learn how to solve the problems by finding the rectangle area using the formula and try to apply the knowledge to solve related problems.

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Example 1.
Find the area of the rectangle of length 45 cm and width 20 cm?

Solution:
The length of the rectangle=45 cm
The width of the rectangle=20 cm
The area of the rectangle=45×20=900
Hence, the area of the rectangle is 900 cm2.

Example 2.
Find the area of the rectangular room of length 11 mm and width 18 mm?

Solution:
The length of the rectangular room=11 mm
The width of the rectangular room=18 mm
The area of the rectangular room=11×18=198.
Therefore, the area of the rectangular room=198 sq mm.

Example 3.
Find the area of the rectangle of length 73 cm and width 28 cm?

Solution:
The length of the rectangle=73 cm
The width of the rectangle=28 cm
The area of the rectangle=73 × 28=2044.
Therefore, the area of the rectangle=2044 sq cm.

Example 4.
The area of the rectangle is 96 cm2. The length of the rectangle is 8 cm. Find the breadth of the rectangle?

Solution:
The area of the rectangle=96 cm2
The length of the rectangle=8 cm
The breadth of the rectangle=area of the rectangle/length of the rectangle
=96/8=12
Therefore, the breadth of the rectangle is 12 cm.

Example 5.
The length of the rectangular cardboard is 6 cm, and the rectangular cardboard’s breadth is 9 cm. Find the area of the rectangular cardboard?

Solution:
The length of the rectangular cardboard =6 cm
The breadth of the rectangular cardboard=9 cm
The area of the rectangular cardboard=6 ×9=54 sq cm
Hence, the area of the rectangular cardboard is 54 sq cm.

Example 6.
The length of the rectangle is 5 cm and the breadth of the rectangle is 7 cm. If the length is greater by 2 cm, what should be the width so that the new rectangle has the same area as that of the first one?
Solution:
The area of the first rectangle=5×7=35sq cm
The length of the new rectangle=5+2=7cm
The breadth of the new rectangle=w × 7=35
w=35/7=5
Hence, the width of the new rectangle is 5 cm.

Example 7.
How many squares with the side of 4 cm cover the surface of a rectangle with a length of 16 cm and a width of 9 cm?

Solution:
The side of a square=4
The area of a square=42=16
The length of the rectangle=16sq cm
The width of a rectangle=9 cm
The area of the rectangle=16 × 9=144 sq cm
The no. of squares is 144/16 =9
Therefore, 9 squares are required to cover the surface of the rectangle.

Example 8.
A square with a side of 8 cm and a rectangle with a width of 2 cm has the same area. What’s the length of the rectangle?
Solution:
The area of the square is 82=64 sq cm
The width of the rectangle=6
l × 2=64
l=64/2=32
Hence, the length of the rectangle is 32 cm.

Example 9.
The length of the rectangle is 5 cm and the breadth of the rectangle is 6 cm. If the length is smaller by 2 cm, what should be the width so that the new rectangle has the same area as that of the first one?
Solution:
The area of the first rectangle=5×6=30 sq cm
The length of the new rectangle=5-2=3cm
The breadth of the new rectangle=w × 3=30
w=30/3=10
Hence, the width of the new rectangle is 10 cm.

Example 10.
How many paper squares with the side of 4 cm cover the surface of the rectangular cardboard with a length of 6 cm and width of 8 cm?

Solution:
The side of a square=4
The area of a square=42=16
The length of the rectangle=6sq cm
The width of a rectangle=8 cm
The area of the rectangle=6 × 8=48 sq cm
The no. of squares is 48/16 =3
Therefore, 3 squares are required to cover the surface of the rectangle.

Example 11.
Srinu decided to build the house in a square shape whose side is 8 m in his rectangular field which is of the length 45 m and width 65 m. Find the area of the field?
Solution:
The length of the rectangular field=45 m
The width of the rectangular field=65 m
The area of the rectangular field=45 × 65=2,925 sq m
The field covered by the house is a square with a side of 8 m.
The area=82=64
The area of the rectangular field=2,925-64
=2,861 sq m.
Hence, the area of the rectangular field=2,861 sq m.

Example 12.
A rectangle has a length of 14 cm and its width is 4 cm smaller than length. Find the area of the rectangle?
Solution:
Length of the rectangle=14 cm
width of the rectangle=14-4=10 cm
Area of the rectangle=14 ×10=140 sq cm
Hence, the area of the rectangle=140 sq cm.

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