Word Problems on Area of Rectangle provided develops mathematical interest among kids by relating the concept to real-life situations. You will find a variety of problems in finding the area of rectangular shapes in this article. Try solving the Area of a Rectangle Problems provided on a regular basis and get a good hold of the concept. Learn how to solve the problems by finding the rectangle area using the formula and try to apply the knowledge to solve related problems.

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**Example 1.**

Find the area of the rectangle of length 45 cm and width 20 cm?

**Solution:
**The length of the rectangle=45 cm

The width of the rectangle=20 cm

The area of the rectangle=45Ã—20=900

Hence, the area of the rectangle is 900 cm

^{2}.

**Example 2.
**Find the area of the rectangular room of length 11 mm and width 18 mm?

**Solution:**

The length of the rectangular room=11 mm

The width of the rectangular room=18 mm

The area of the rectangular room=11Ã—18=198.

Therefore, the area of the rectangular room=198 sq mm.

**Example 3.
**Find the area of the rectangle of length 73 cm and width 28 cm?

**Solution:**

The length of the rectangle=73 cm

The width of the rectangle=28 cm

The area of the rectangle=73 Ã— 28=2044.

Therefore, the area of the rectangle=2044 sq cm.

**Example 4.**

The area of the rectangle is 96 cm^{2}. The length of the rectangle is 8 cm. Find the breadth of the rectangle?

**Solution:
**The area of the rectangle=96 cm

^{2}

The length of the rectangle=8 cm

The breadth of the rectangle=area of the rectangle/length of the rectangle

=96/8=12

Therefore, the breadth of the rectangle is 12 cm.

**Example 5.
**The length of the rectangular cardboard is 6 cm, and the rectangular cardboard’s breadth is 9 cm. Find the area of the rectangular cardboard?

**Solution:**

The length of the rectangular cardboard =6 cm

The breadth of the rectangular cardboard=9 cm

The area of the rectangular cardboard=6 Ã—9=54 sq cm

Hence, the area of the rectangular cardboard is 54 sq cm.

**Example 6.
**The length of the rectangle is 5 cm and the breadth of the rectangle is 7 cm. If the length is greater by 2 cm, what should be the width so that the new rectangle has the same area as that of the first one?

**Solution:**

The area of the first rectangle=5Ã—7=35sq cm

The length of the new rectangle=5+2=7cm

The breadth of the new rectangle=w Ã— 7=35

w=35/7=5

Hence, the width of the new rectangle is 5 cm.

**Example 7.
**How many squares with the side of 4 cm cover the surface of a rectangle with a length of 16 cm and a width of 9 cm?

**Solution:**

The side of a square=4

The area of a square=4

^{2}=16

The length of the rectangle=16sq cm

The width of a rectangle=9 cm

The area of the rectangle=16 Ã— 9=144 sq cm

The no. of squares is 144/16 =9

Therefore, 9 squares are required to cover the surface of the rectangle.

**Example 8.
**A square with a side of 8 cm and a rectangle with a width of 2 cm has the same area. What’s the length of the rectangle?

**Solution:**

The area of the square is 8

^{2}=64 sq cm

The width of the rectangle=6

l Ã— 2=64

l=64/2=32

Hence, the length of the rectangle is 32 cm.

**Example 9.
**The length of the rectangle is 5 cm and the breadth of the rectangle is 6 cm. If the length is smaller by 2 cm, what should be the width so that the new rectangle has the same area as that of the first one?

**The area of the first rectangle=5Ã—6=30 sq cm**

Solution:

Solution:

The length of the new rectangle=5-2=3cm

The breadth of the new rectangle=w Ã— 3=30

w=30/3=10

Hence, the width of the new rectangle is 10 cm.

**Example 10.
**How many paper squares with the side of 4 cm cover the surface of the rectangular cardboard with a length of 6 cm and width of 8 cm?

**Solution:**

The side of a square=4

The area of a square=4

^{2}=16

The length of the rectangle=6sq cm

The width of a rectangle=8 cm

The area of the rectangle=6 Ã— 8=48 sq cm

The no. of squares is 48/16 =3

Therefore, 3 squares are required to cover the surface of the rectangle.

**Example 11.
**Srinu decided to build the house in a square shape whose side is 8 m in his rectangular field which is of the length 45 m and width 65 m. Find the area of the field?

**Solution:**

The length of the rectangular field=45 m

The width of the rectangular field=65 m

The area of the rectangular field=45 Ã— 65=2,925 sq m

The field covered by the house is a square with a side of 8 m.

The area=8

^{2}=64

The area of the rectangular field=2,925-64

=2,861 sq m.

Hence, the area of the rectangular field=2,861 sq m.

**Example 12.
**A rectangle has a length of 14 cm and its width is 4 cm smaller than length. Find the area of the rectangle?

**Solution:**

Length of the rectangle=14 cm

width of the rectangle=14-4=10 cm

Area of the rectangle=14 Ã—10=140 sq cm

Hence, the area of the rectangle=140 sq cm.