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Bridges in Mathematics Grade 5 Home Connections Answer Key Unit 7 Module 2
Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 2 Session 2 Answer Key
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Question 1.
Jade’s mom made 8 cups of chicken soup. She wants to freeze the soup in \(\frac{1}{2}\)-cup containers. How many containers will she need to hold all of the soup?
a. Write an expression that represents the problem.
Answer:
x = 8 ÷ \(\frac{1}{2}\),
Explanation:
Given Jade’s mom made 8 cups of chicken soup. She wants to freeze the soup in \(\frac{1}{2}\)-cup containers, Let x be the many containers will she need to hold all of the soup an expression that represents the problem is x = 8 ÷ \(\frac{1}{2}\).
b. Solve the problem. Show your thinking with equations, a ratio table, or a rectangular array.
Answer:
16 containers,
Explanation:
As Jade’s mom made 8 cups of chicken soup. She wants to freeze the soup in \(\frac{1}{2}\)-cup containers, Let x be the many containers will she need to hold all of the soup an equation that represents the problem is x = 8 ÷ \(\frac{1}{2}\) solving we get 8 X 2 = 16 containers.
Question 2.
Jade s braces cost her parents $2,848. Her parents will pay $89 each month. How many months will it take them to pay for her braces?
a. Write an expression that represents the problem.
Answer:
x = $2,848 ÷ $89,
Explanation:
Given Jade’s braces cost her parents $2,848. Her parents will pay $89 each month. So let x be many months will it take them to pay for her braces an expression that represents the problem is x = $2,848 ÷ $89.
b. Solve the problem. Show your thinking with equations, a ratio table, or a rectangular array.
Answer:
32 months,
Explanation:
As Jade’s braces cost her parents $2,848. Her parents will pay $89 each month. So let x be many months will it take them to pay for her braces an equation that represents the problem is x = $2,848 ÷ $89
89)2848(32
267
178
178
0 the result is 32 months.
Question 3.
Jade s brother, Marcus, has 3 licorice ropes to share with his friends. He cut each rope into fourths. How many pieces did he have when he was finished?
a. Write an expression that represents the problem.
Answer:
x = 3 X \(\frac{1}{4}\),
Explanation:
Given Jade’s brother Marcus has 3 licorice ropes to share with his friends. He cut each rope into fourths. So many pieces did he have when he was finished let it be x an expression that represents the problem is x = 3 X \(\frac{1}{4}\),
b. Solve the problem. Show your work.
Answer:
x = \(\frac{3}{4}\),
Explanation:
Given Jade’s brother Marcus has 3 licorice ropes to share with his friends. He cut each rope into fourths. So many pieces did he have when he was finished let it be x an expression that represents the problem is x = 3 X \(\frac{1}{4}\) = \(\frac{3}{4}\).
Question 4.
Evaluate each expression.
a. 2 × (4 + (120 ÷ 6)) = ________________
Answer:
48,
Explanation:
Given to solve the expression 2 X (4 + (120 ÷ 6)) = 2 X (4 + (20)) = 2 X (24) = 48.
b. \(\frac{16}{4}\) + (13 × 9) = _______________
Answer:
121,
Explanation:
Given to solve the expression \(\frac{16}{4}\) + (13 X 9) = 4 + (117) = 121.
c. (2 ÷ 3 × 2) – (9 ÷ 3) = ________________
Answer:
-1.666 or –\(\frac{5}{3}\),
Explanation:
Given to solve the expression (2 ÷ 3 X 2) – (9 ÷ 3) = 2 X \(\frac{1}{3}\) X 2 – 3 =
\(\frac{4}{3}\) – 3 = 1.333 – 3 = -1.666 or \(\frac{4}{3}\) – 3 = \(\frac{4 – 9}{3}\) = –\(\frac{5}{3}\).
d. (\(\frac{2}{3}\) × 12) + (14 – (2 × 2)) = ________________
Answer:
18,
Explanation:
Given to solve the expression (\(\frac{2}{3}\) X 12) + (14 – (2 X 2)) = 2 X 4 + (14 – 4) = 8 + 10 = 18.
Question 5.
Find the product.
a. 180 × \(\frac{2}{3}\) = _______________
Answer:
120,
Explanation:
Asked to find the product of 180 X \(\frac{2}{3}\) = \(\frac{180 X 2}{3}\) = 120.
b. \(\frac{4}{5}\) × 22 = _______________
Answer:
\(\frac{88}{5}\) or 17\(\frac{3}{5}\),
Explanation:
Asked to find the product of \(\frac{4}{5}\) X 22 = \(\frac{4 X 22}{5}\) = \(\frac{88}{5}\) as numerator is greater than denominator we write in mixed fraction as \(\frac{17 X 5 + 3}{5}\) = 17\(\frac{3}{5}\).
c. \(\frac{2}{3}\) × \(\frac{3}{4}\) = ______________
Answer:
\(\frac{1}{2}\),
Explanation:
Asked to find the product of \(\frac{2}{3}\) X \(\frac{3}{4}\) we get \(\frac{2 X 3}{3 X 4}\) = \(\frac{1}{2}\).
Question 6.
Write a story problem for the problem 21 × \(\frac{3}{7}\). Then solve the problem and show your work.
Answer:
Story Problem: There are 21 students in a class who went to picnic, the ticket in the picnic is
$\(\frac{3}{7}\), How much did the total students spent to purchase the tickets.
Result : $9,
Explanation:
Asked to write a story problem for the problem 21 X \(\frac{3}{7}\) so it is story problem: There are 21 students in a class who went to picnic, the ticket in the picnic is
$\(\frac{3}{7}\), How much did the total students spent to purchase the tickets. Now solving 21 X \(\frac{3}{7}\) = \(\frac{21 X 3}{7}\) = $9 is the amount spent to purchase the tickets.
Question 7.
CHALLENGE Jasmin had a large collection of seashells from her trip to the beach. She gave \(\frac{1}{2}\) of the shells to her 5 siblings to share evenly, and \(\frac{1}{4}\) of the shells to her two friends to share evenly. Did a single friend or a sibling get more of the collection? How do you know?
Answer:
Single friend got more collection, By calculating,
Explanation:
Given Jasmin had a large collection of seashells from her trip to the beach. She gave \(\frac{1}{2}\) of the shells to her 5 siblings to share evenly, and \(\frac{1}{4}\) of the shells to her two friends to share evenly. As each sibling received \(\frac{1}{2}\) ÷ 5 = \(\frac{1}{2}\) X \(\frac{1}{5}\) = \(\frac{1}{10}\),
and each friend received \(\frac{1}{4}\) ÷ 2 = \(\frac{1}{4}\) X \(\frac{1}{2}\) = \(\frac{1}{8}\) as \(\frac{1}{10}\) < \(\frac{1}{8}\) so a single friend got more of the collection by checking I came to know.
Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 2 Session 4 Answer Key
Related Division Problems
Question 1.
Eva has 680 cookies and several plates. She puts 68 cookies on each plate. How many plates does Eva use?
a. Write an equation for the problem.
Answer:
Equation: x = 680 ÷ 68,
Explanation:
Given Eva has 680 cookies and several plates. She puts 68 cookies on each plate. So many plates does Eva use the equation is x = 680 ÷ 68.
b. Solve the problem. Show your work.
Answer:
10 plates,
Explanation:
Asked to solve as Eva has 680 cookies and several plates. She puts 68 cookies on each plate. So many plates does Eva use the equation is x = 680 ÷ 68,
68)680(10
680
0 therefore 10 plates.
Question 2.
Max has 612 cookies and several plates. He puts 68 cookies on each plate. How many plates does Max use?
a. Write an equation for the problem.
Answer:
Equation: x = 612 ÷ 68,
Explanation:
Given Max has 612 cookies and several plates. He puts 68 cookies on each plate. So many plates does Max use the equation is x = 612 ÷ 68.
b. Solve the problem. Show your work.
Answer:
9 plates,
Explanation:
As Max has 612 cookies and several plates. He puts 68 cookies on each plate. so many plates does Max use are solving 612 ÷ 68
68)612(9
612
0 therefore 9 plates.
Question 3.
Erika has 748 cookies and several plates. She puts 68 cookies on each plate. How many plates does Erika use?
a. Write an equation for the problem.
Answer:
Equation: x = 748 ÷ 68,
Explanation:
Given Erika has 748 cookies and several plates. She puts 68 cookies on each plate. So many plates does Erika use the equation is x = 748 ÷ 68.
b. Solve the problem. Show your work.
Answer:
11,
Explanation:
As Erika has 748 cookies and several plates. She puts 68 cookies on each plate. So many plates does Erika use solving 748 ÷ 68 we get
68)748(11
68
68
68
0 therefore it is 11 plates.
Question 4.
Solve. Hint: Use the results of the first problem to help with the rest.
a. 840 ÷ 84 = ________________
Answer:
10,
Explanation:
Asked to solve 840 ÷ 84 =
84)840(10
840
0 so it is 10.
b. 924 ÷ 84 = ________________
Answer:
11,
Explanation:
Asked to solve 924 ÷ 84 =
84)924(11
84
84
84
0 so it is 11.
c. 756 ÷ 84 = ________________
Answer:
9,
Explanation:
Asked to solve 756 ÷ 84 =
84)756(9
756
0 so it is 9.
d. 672 ÷ 84 = ________________
Answer:
8,
Explanation:
Asked to solve 672 ÷ 84 =
84)672(8
672
0 so it is 8.
e. 1,008 ÷ 84 = ________________
Answer:
12,
Explanation:
Asked to solve 1,008 ÷ 84 =
84)1,008(12
84
168
168
0 so it is 12.
Review
Question 5.
What is the volume of a box that has a length of 8 cm, a width of 14 cm, and a height of 12 cm? Show your work.
Answer:
1,344 cubic centimeters,
Explanation;
Asked to find the volume of a box that has a length of 8 cm, a width of 14 cm and a height of 12 cm as we know volume of a cube is length X width X height so it is 8 cm X 14 cm X 12 cm = 1,344 cubic centimeters.
Question 6.
What is the volume of a box that has a base of area 38 cm2 and a height of 22 cm? Show your work.
Answer:
836 cubic centimeters,
Explanation:
Asked to find the volume of a box that has a base of area 38 cm2 and a height of 22 cm as we know volume of a cube is area X height so it is 38 cm2 X 22 cm = 836 cubic centimeters.
Question 7.
Fill in the blanks to make each equation true.
a. 8.21 + 3.89 = ______________ + 4.00
Answer:
8.10,
Explanation:
Asked to make the given equation true 8.21 + 3.89 = ______________ + 4.00 true as left side it is
8.21 + 3.89 = 12.1 so the blank be x means x = 12.1 – 4.00 = 8.10. So the equation is
8.21 + 3.89 = 8.10 + 4.00.
b. 0.997 – ______________ = 1.000 – 0.457
Answer:
0.454,
Explanation:
Asked to make the given equation true 0.997 – ______________ = 1.000 – 0.457 true as right side it is 1.000 – 0.457 = 0.543 let the blank be x so x = 0.997 – 0.543 = 0.454, therefore the equation is 0.997 – 0.543 = 1.000 – 0.457.
c. 28 × 24 = (28 × 25) – (28 × ______________)
Answer:
1,
Explanation:
Asked to make the given equation true 28 × 24 = (28 × 25) – (28 × ______________) left side it is 672, let the blank be x right side it is (28 X 25) – (28 X x) = 700 – 28x, Now 28x = 700 – 672 = 28 therefore x = 28/28 = 1 the equation is 28 X 24 = (28 X 25) – (28 X 1).
d. 28 × 24 = (56 × ______________)
Answer:
12,
Explanation:
Asked to make the given equation true 28 X 24 = (56 X ______________) left side is 28 X 24 = 672 and let the blank value be x so 56 X x = 672 x = 672/56 = 12 therefore the equation is 28 X 24 = 56 X 12.
e. 89 × 17 = (___________ × 17) – (1 × 17)
Answer:
90,
Explanation:
Asked to make the given equation true 89 X 17 = (______________ X 17) – (1 X 17) left side it is 1,513, let the blank be x right side it is (x X 17) – (1 X 17) = 17x – 17, Now 17x = 1,513 + 17 = 1,530 therefore x = 1,530/17 = 90 the equation is 89 X 17 = (90 X 17) – (1 X 17).
Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 2 Session 6 Answer Key
More Division Practice
Question 1.
Mr. Arnold’s students are going on a field trip to the Art Museum. The 28 students’ tickets cost $161. How much did each ticket cost?
a. Solve the problem. Show your work.
Answer:
Each ticket costs $5.75,
Explanation:
Given Mr. Arnold’s students are going on a field trip to the Art Museum. The 28 students’ tickets cost $161. So each ticket cost is $161 ÷ 28,
28)161(5.75
140
21.0
19.6
1.4
1.4
0, Therefore it is $5.75.
b. Between which two whole numbers does your answer lie?
______________ and _______________
Answer:
5 and 6,
Explanation:
As the each ticket cost is $5.75 it lies between two whole numbers are whole number before 5.75 is 5 and whole number next to 5.75 is 6 so the answer is between 5 nd 6.
c. Write an equation to represent the problem and the answer.
Answer:
Equation: $161 ÷ 28,
Each ticket costs $5.75,
Explanation:
Given Mr. Arnold’s students are going on a field trip to the Art Museum. The 28 students’ tickets cost $161. So the equation for each ticket cost is $161 ÷ 28 solving
28)161(5.75
140
21.0
19.6
1.4
1.4
0, Therefore it is $5.75.
d. Explain what you did with the remainder, if any, and why.
Answer:
Remainder is 21 less than numerator 28 we took decimal point divisions till we get zero as remainder,
Explanation:
As remainder is 21 less than numerator 28 we took decimal point division we further divided 21 by 28 we got decimal quotient 0.75 till and we got zero as remainder.
Question 2.
Solve. Show your work.
1065 ÷ 39 = ________________
1953 ÷ 36 = ________________
837 ÷ 45 = _________________
Answer:
1065 ÷ 39 = 27\(\frac{12}{39}\),
1953 ÷ 36 = 54\(\frac{9}{36}\),
837 ÷ 45 = 18\(\frac{27}{45}\),
Explanation:
Asked to solve 1065 ÷ 39 we get
39)1065(27
78
285
273
12 so it is 27\(\frac{12}{39}\),
Now we solve 1953 ÷ 36 we get
36)1953(54
180
153
144
9 so it is 54\(\frac{9}{36}\),
Now solving 837 ÷ 45 we get
45)837(18
45
387
360
27 so it is 18\(\frac{27}{45}\).
Question 3.
Solve each problem. Show your work.
a. 270 ÷ 27 = ________________
Answer:
10,
Explanation:
Asked to solve 270 ÷ 27 we get
27)270(10
270
0 so the result is 10.
b. 540 ÷ 27 = ________________
Answer:
20,
Explanation:
Asked to solve 540 ÷ 27 we get
27)540(20
540
0 so the result is 20.
c. 810 ÷ 27 = ______________
Answer:
30,
Explanation:
Asked to solve 810 ÷ 27 we get
27)810(30
810
0 so the result is 30.
d. What strategy or strategies did you use for these problems?
Answer:
Short division method,
Explanation:
Strategies we can use equal groups, partition, repeated subtraction, long division, short division I used short division method first by writing the problem dividing the first number of the dividend by the divisor and go on writing the quotient till we get remainder which cannot be further divided or zero then we stop dividing and the result will be the quotient along with the remainder left if the remainder is zero the result will be the only quotient.
Question 4.
Solve each problem. Show your work.
a. 430 ÷ 43 = _______________
Answer:
10,
Explanation:
Asked to solve 430 ÷ 43 we get
43)430(10
430
0 so the result is 10.
b. 473 ÷ 43 = _______________
Answer:
11,
Explanation:
Asked to solve 473 ÷ 43 we get
43)473(11
430
43
43
0 so the result is 11.
c. 387 ÷ 43 = _______________
Answer:
9,
Explanation:
Asked to solve 387 ÷ 43 we get
43)387(9
387
0 so the result is 9.
d. What strategy or strategies did you use for these problems?
Answer:
Short division method,
Explanation:
Strategies we can use equal groups, partition, repeated subtraction, long division, short division I used short division method first by writing the problem dividing the first number of the dividend by the divisor and go on writing the quotient till we get remainder which cannot be further divided or zero then we stop dividing and the result will be the quotient along with the remainder left if the remainder is zero the result will be the only quotient.
Question 5.
Convert each fraction to a decimal.
a. \(\frac{6}{8}\) = 0. _____________
Answer:
0.75
Explanation:
Asked to convert fraction \(\frac{6}{8}\) into decimal so it is
8)60(0.75
56
40
40
0 so it is 0.75.
b. 1\(\frac{3}{4}\) = 1. _____________
Answer:
1.75,
Explanation:
Asked to convert fraction 1\(\frac{3}{4}\) into decimal first we convert mixed fraction into fraction 1\(\frac{3}{4}\) = 1\(\frac{1 X 4 + 3}{4}\) = \(\frac{7}{4}\) now we convert to decimal fraction
4)7(1.75
4
30
28
20
20
0 so the result is 1.75.
Question 6.
Convert each decimal to a fraction.
a. 0.6 = ______________
Answer:
\(\frac{6}{10}\),
Explanation:
Asked to convert 0.6 decimal to fraction first we write the given decimal in the form of a ratio (p/q) where the denominator is equal to 1. Now we multiply the numerator and denominator by multiples of 10, for every decimal point such that the decimal in the numerator becomes a whole number. (If there are two numbers after the decimal point then multiply by 100/100 and so on) so 0.6 X \(\frac{10}{10}\) = \(\frac{6}{10}\).
b 1.25 = ______________
Answer:
\(\frac{125}{100}\),
Explanation:
Asked to convert 1.25 decimal to fraction first we write the given decimal in the form of a ratio (p/q) where the denominator is equal to 1. Now we multiply the numerator and denominator by multiples of 10, for every decimal point such that the decimal in the numerator becomes a whole number. (If there are two numbers after the decimal point then multiply by 100/100) as we have two numbers after the decimal point we multiply by 100/100 we get 1.25 X \(\frac{100}{100}\) = \(\frac{125}{100}\).
Question 7.
Round each number to the nearest tenth, whole number, ten, and hundred.
Answer:
Explanation:
Rounded each number to the nearest tenth, whole number, ten and hundred as shown above.