Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 3 Answer Key

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Bridges in Mathematics Grade 5 Home Connections Answer Key Unit 7 Module 3

Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 3 Session 2 Answer Key

Division Review

Solve each problem. Be sure to show your work.

Question 1.
Kyra made 184 brownies for a potluck dinner.
a. If she arranges them on 12 plates, how many brownies will be on each plate?
Answer:
15\(\frac{4}{12}\),

Explanation:
Given Kyra made 184 brownies for a potluck dinner if she arranges them on 12 plates many brownies will be on each plate will be
12)184(15
     12
        64
60
4  as remainder is 4 it is 15\(\frac{4}{12}\).

b. If she arranges them on 15 plates, how many brownies will be on each plate?
Answer:
12\(\frac{4}{15}\) will be on the plate,

Explanation:
Given Kyra made 184 brownies for a potluck dinner if she arranges them on 15 plates many brownies will be on each plate will be
15)184(12
     15
        34
30
4 so 12\(\frac{4}{15}\).

c. If she arranges them on 23 plates, how many brownies will be on each plate?
Answer:
8 will be on the each plate,

Explanation:
If she arranges them on 23 plates many brownies will be on each plate are
23)184(8
184
0 therefore 8.
d. Should Kyra arrange the brownies on 12, 15, or 23 plates? Why?
Answer:
on 23 plates, No brownies will be left,

Explanation:
Kyra should arrange the brownies on 23 plates because if we distribute 184 by 12 plates their is remainder of 4 brownies if we arrange using 15 plates also we are getting remainder of 4 brownies and only for 23 plates if we divide 184 brownies we are getting 0 remainder therefore Kyra should arrange on 23 plates.

Question 2.
Solve:
a. \(\frac{1}{4}\) ÷ 9 = ______________
Answer:
\(\frac{1}{36}\),

Explanation:
Asked to solve \(\frac{1}{4}\) ÷ 9 = \(\frac{1}{4}\) X \(\frac{1}{9}\)  = \(\frac{1 X 1}{4 X 9}\) = \(\frac{1}{36}\).

b. 7 ÷ \(\frac{1}{6}\) = ______________
Answer:
42,

Explanation:
Asked to solve 7 ÷ \(\frac{1}{6}\) so 7 X 6 = 42.

c. \(\frac{1}{5}\) ÷ 8 = ______________
Answer:
\(\frac{1}{40}\),

Explanation:
Asked to solve \(\frac{1}{5}\) ÷ 8 = \(\frac{1}{5}\) X \(\frac{1}{8}\)  = \(\frac{1 X 1}{5 X 8}\) = \(\frac{1}{40}\).

Question 3.
Solve each problem. Show your work.
a. 380 ÷ 38 = _______________
Answer:
10,

Explanation:
Asked to solve 380 ÷ 38 = 380 X \(\frac{1}{38}\)  = \(\frac{380 X 1}{38}\) both numerator and denominator goes by 38 we get \(\frac{38 X 10}{38}\) = 10.

b. 190 ÷ 38 = _______________
Answer:
5,

Explanation:
Asked to solve 190 ÷ 38 = 190 X \(\frac{1}{38}\)  = \(\frac{190 X 1}{38}\) both numerator and denominator goes by 38 we get \(\frac{38 X 5}{38}\) = 5.

c. 570 ÷ 38 = _______________
Answer:
15,

Explanation:
Asked to solve 570 ÷ 38 = 570 X \(\frac{1}{38}\)  = \(\frac{570 X 1}{38}\) both numerator and denominator goes by 38 we get \(\frac{38 X 15}{38}\) = 15.

d. What strategy or strategies did you use for these problems?
Answer:
Short division method,

Explanation:
Strategies we can use equal groups, partition, repeated subtraction, long division, short division I used short division method first by writing the problem dividing the first number of the dividend by the divisor and go on writing the quotient till we get remainder which cannot be further divided or zero then we stop dividing and the result will be the quotient along with the remainder left if the remainder is zero the result will be the only quotient.

Question 4.
Solve each problem. Show your work.
a. 670 ÷ 67 = ______________
Answer:
10,

Explanation:
Asked to solve 670 ÷ 67 = 670 X \(\frac{1}{67}\)  = \(\frac{670 X 1}{67}\) both numerator and denominator goes by 67 we get \(\frac{67 X 10}{67}\) = 10.

b. 603 ÷ 67 = ______________
Answer:
9,

Explanation:
Asked to solve 603 ÷ 67 = 603 X \(\frac{1}{67}\)  = \(\frac{603 X 1}{67}\) both numerator and denominator goes by 67 we get \(\frac{67 X 9}{67}\) = 9.

c. 737 ÷ 67 = _______________
Answer:
11,

Explanation:
Asked to solve 737 ÷ 67 = 737 X \(\frac{1}{67}\)  = \(\frac{737 X 1}{67}\) both numerator and denominator goes by 67 we get \(\frac{67 X 11}{67}\) = 11.

d. What strategy or strategies did you use for these problems?
Answer:
Division by equal groups,

Explanation:
Used division strategy as division is an operation by which we separate into equal groups or find the number of equal groups. Division is the inverse of multiplication, where equal groups are put together to find the result.

Question 5.
CHALLENGE Lily has 1,062 books to give away. She gave 279 books to her younger sister. She gave \(\frac{1}{3}\) of her remaining books to her brother. She divided the remaining books into 15 boxes to give to a homeless shelter. If she put the same number of books into each of the 15 boxes, how many books are in each box?
Answer:
17 books in each box and 6 books remaining,

Explanation:
Given Lily has 1,062 books to give away. She gave 279 books to her younger sister. She gave \(\frac{1}{3}\) of her remaining books to her brother. She divided the remaining books into 15 boxes to give to a homeless shelter. If she put the same number of books into each of the 15 boxes, so many books are in each box would be after giving to her younger sister Lily has 1,062 books – 279 books = 783 books now from783 books she gave \(\frac{1}{3}\) to her brother she is left with 783 books X \(\frac{1}{3}\) = 261 books these books she puts in 15 boxes so it is 261 X \(\frac{1}{15}\) we get
15)261(17
     15 
111
105
      6
17 books each box and 6 books remaining.

Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 3 Session 4 Answer Key

Reviewing Numbers Small & Large

Question 1.
Write two fractions that are equal to each decimal number.
0.2 = ____________ and ______________
0.02 = ____________ and ______________
0.002 = ____________ and ______________
0.06 = ____________ and ______________
Answer:
0.2 = \(\frac{2}{10}\) and \(\frac{20}{100}\),
0.02 =  \(\frac{2}{100}\) and \(\frac{20}{1,000}\),
0.002 = \(\frac{2}{1,000}\) and \(\frac{20}{10,000}\),
0.06 = \(\frac{6}{100}\) and \(\frac{60}{1,000}\),

Explanation:
Asked to write two fractions that are equal to each decimal number so it is
0.2 = \(\frac{2}{10}\) and \(\frac{20}{100}\),
0.02 =  \(\frac{2}{100}\) and \(\frac{20}{1,000}\),
0.002 = \(\frac{2}{1,000}\) and \(\frac{20}{10,000}\),
0.06 = \(\frac{6}{100}\) and \(\frac{60}{1,000}\).

Question 2.
Complete the chart below.
Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 3 Answer Key 1
Answer:
Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 3 Answer Key-1

Explanation:
Completed the given chart above.

Question 3.
Round each number to the place shown to complete the chart below.
Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 3 Answer Key 2
Answer:
Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 3 Answer Key-2

Explanation:
Rounded each number to the place shown to complete the chart above.

Question 4.
A microgram is a unit of mass that is one millionth of a gram (0.000001 g) or one thousandth of a milligram (0.001 mg). What is the mass, in micrograms, of 100 milligrams?
Answer:
Mass in 1 microgram of 100 milligrams = 0.1 grams,

Explanation:
Given a microgram is a unit of mass that is one millionth of a gram (0.000001 g) or one thousandth of a milligram (0.001 mg). The mass in micrograms of 100 milligrams is as 1 microgram = 0.001 milligrams so 100 milligrams = 0.001 X 100 grams = 0.1 grams.

Question 5.
The football team for the University of Hawaii, the Rainbow Warriors, plays its home games in the Aloha Stadium in Honolulu, Hawaii. The stadium holds about 50,000 people.
a. How many stadiums of this size would it take to hold 500,000 people (a bit less than the number of people living in Fresno, California)?
Answer:
10 stadiums,

Explanation:
Given the football team for the University of Hawaii, the Rainbow Warriors, plays its home games in the Aloha Stadium in Honolulu, Hawaii. The stadium holds about 50,000 people.
So many stadiums of this size would it take to hold 500,000 people (a bit less than the number of people living in Fresno, California is 500,000/50,000 = 10.

b. According to estimates, there are over 100 million people living in the Philippines. How many Aloha Stadiums would it take to hold 100 million people?
Answer:
2,000 stadiums,

Explanation:
As Aloha Stadium holds about 50,000 people for would it take to hold 100 million people is
100,000,000/50,000 = 2,000 stadiums.

Question 6.
The table below shows the estimated population of different countries as of 2014. Round each number to complete the table.
Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 3 Answer Key 3
Answer:
Bridges in Mathematics Grade 5 Home Connections Unit 7 Module 3 Answer Key-3

Explanation:
The table above shows the estimated population of different countries as of 2014. Rounded each number to complete the table as shown above.

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