180 Days of Math for Sixth Grade Day 79 Answers Key

By accessing our 180 Days of Math for Sixth Grade Answers Key Day 79 regularly, students can get better problem-solving skills.

180 Days of Math for Sixth Grade Answers Key Day 79

Directions: Solve each problem.

Question 1.
Calculate 25 less than 81.
Answer:

Question 2.
392 • 15 = ___________
Answer:
392 × 15 = 5880

Question 3.
527 ÷ 6 = __________
Answer: 87.83

Question 4.
Is 394 evenly divisible by 4?
Answer: 394 ÷ 4 = 98.5

Question 5.
\(\frac{2}{3}\) × \(\frac{4}{5}\) = ____________
Answer:
Given,
\(\frac{2}{3}\) × \(\frac{4}{5}\) = \(\frac{2×4}{3×5}\) = \(\frac{8}{15}\)

Question 6.
5² – 6² = __________
Answer:
5² – 6² =
5² = 25
6² = 36
25 – 36 = -11

Question 7.
86 – = 32
Answer:
Let the unknown value be x
86 – x = 32
86 – 32 = x
x = 86 – 32
x = 54

Question 8.
Solve for p.
\(\frac{1}{5}\)p = 10
p = __________
Answer:
Given,
\(\frac{1}{5}\)p = 10
p = 10 × 5
p = 50

Question 9.
How many millimeters are in 7 centimeters?
Answer:
We have to convert from centimeters to millimeters.
1 centimeter = 10 millimeters
7 centimeters = 7 × 10 = 70 millimeters

Question 10.
At what angle do perpendicular lines meet?
Answer: The perpendicular lines meet at 90 degrees

Question 11.
In a game, the probability of the spinner landing on a 2 is \(\frac{1}{3}\). How many times would you expect to land on a 2 if you spin the spinner 12 times?
Answer:
Given, the probability of the spinner landing on a 2 is \(\frac{1}{3}\).
12 × \(\frac{1}{3}\) = 4

Question 12.
Paul bought a pet and supplies at a pet store. He spent $14.95 to buy his hamster. He also bought a cage for $25.95. The food for the hamster costs $2.00 for a week’s supply. If he bought a four-week supply of food, what was his total bill at the pet store?
Answer:
Given,
Paul bought a pet and supplies at a pet store. He spent $14.95 to buy his hamster.
He also bought a cage for $25.95.
The food for the hamster costs $2.00 for a week’s supply.
2 × 4 = $8
$14.95 + $25.95 + $8 = $48.90