By accessing our 180 Days of Math for Sixth Grade Answers Key Day 78 regularly, students can get better problem-solving skills.
180 Days of Math for Sixth Grade Answers Key Day 78
Directions: Solve each problem.
Question 1.
Calculate 52 and 29 more.
Answer:
Question 2.
372 × 10 = ___________
Answer: 372 × 10 = 3720
Question 3.
Divide 437 by 9.
Answer:
437 divided by 9 is 48.5
Question 4.
Circle the prime number(s).
63
71
81
91
Answer:
is the prime number
So, the correct answer is option B.
Question 5.
Is \(\frac{10}{12}\) less than, greater than, or equal to \(\frac{5}{6}\)?
Answer:
The simplified form of \(\frac{10}{12}\) is \(\frac{5}{6}\)
So, the fraction \(\frac{10}{12}\) is equal to \(\frac{5}{6}\)
Question 6.
2 × 5 – 4 × 3 = ____________
Answer:
(2 × 5) – (4 × 3)
10 – 12
-2
Question 7.
Answer:
We have to convert the given mixed fraction into the improper fraction.
2 \(\frac{2}{3}\) = \(\frac{8}{3}\)
So,
Question 8.
Find f.
34f = 204
f = _________
Answer:
Given,
34f = 204
f = 204/34
f = 6
Question 9.
Calculate the area of a square with 12 cm sides.
Answer:
Given,
s = 12 cm
We know that,
Area of a square = s × s
A = 12cm × 12 cm
A = 144 sq.cm
Thus the area of a square is 144 sq. cm.
Question 10.
How many lines of symmetry does a rectangle have?
Answer: A rectangle has 2 lines of symmetry.
Question 11.
Inside a bag of candy there are 16 lollipops, 12 pieces of chocolate, and 7 pieces of licorice, If you reach into the bag and grab a piece of candy, what is the probability that it will not be a lollipop?
Answer:
Given data,
Inside a bag of candy there are 16 lollipops, 12 pieces of chocolate, and 7 pieces of licorice.
Total = 16 + 12 + 7 = 35
The probability that it will not be a lollipop = (16 + 12)/35
= 28/35
Question 12.
A burger restaurant serves twice as many cheeseburgers as hamburgers. It also sells \(\frac{1}{3}\) as many double hamburgers as regular hamburgers. If the restaurant sells 120 cheeseburgers, how many double hamburgers does it sell?
Answer:
Given,
A burger restaurant serves twice as many cheeseburgers as hamburgers.
It also sells \(\frac{1}{3}\) as many double hamburgers as regular hamburgers
120 × \(\frac{1}{3}\) = 40 double hamburgers