# McGraw Hill My Math Grade 2 Chapter 6 Lesson 4 Answer Key Regroup Ones to Add

All the solutions provided in McGraw Hill Math Grade 2 Answer Key PDF Chapter 6 Lesson 4 Regroup Ones to Add will give you a clear idea of the concepts.

## McGraw-Hill My Math Grade 2 Answer Key Chapter 6 Lesson 4 Regroup Ones to Add

Explore and Explain

Teacher Directions: Model using base-ten blocks. Our library has 146 books about dogs. It has 145 books about cats. How many books about cats and dogs does the library have? Write the number sentence.

The total number of books about cats and dogs does the library have is 291 books and the number sentence is 146+145 = 291.

Explanation:
Given that library has 146 books about dogs and it has 145 books about cats. So the total number of books about cats and dogs does the library have is 146+145 which is 291 books. So the number sentence will be 146+145 = 291.

See and Show

Find 135 + 328.
Step 1 Add the ones. If there are 10 or more ones, regroup 10 ones as 1 ten. Write the 1 in the tens column.

Step 2 Add the tens.

Step 3 Add the hundreds.

So, 135 + 328 = 463

Use Work Mat 7 and base-ten blocks. Add.

Question 1.

436 + 245 = 681.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 436 and 245 we will get 681.

Question 2.

127 + 648 = 775

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 127 and 648 we will get 775.

Talk Math How is three-digit addition like two-digit addition?

Remember to write I in the tens column if you regroup.

On My Own

Add. Use base-ten blocks if needed.

Question 3.

468 + 23 = 491.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 468 and 23 we will get 491.

Question 4.

561 + 26 = 587.

Explanation:
Here, we will add ones digit first and then we will add tens digit, and then we will add hundreds digit. By adding 561 and 26 we will get 587.

Question 5.

411 + 379 = 790.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 411 and 379 we will get 790.

Question 6.

236 + 518 = 754.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 236 and 518 we will get 754.

Question 7.

468 + 18 = 486.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 468 and 18 we will get 486.

Question 8.

427 + 144 = 571.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 427 and 144 we will get 571.

Question 9.

306 + 408 = 714.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 306 and 408 we will get 714.

Question 10.

28 + 515 = 543.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 28 and 515 we will get 543.

Question 11.

273 + 224 = 497.

Explanation:
Here, we will add ones digit first and then we will add tens digit and then we will add hundreds digit. By adding 273 and 224 we will get 497.

Question 12.

749 + 9 = 758.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 749 and 9 we will get 758.

Question 13.

146 + 253 = 399.

Explanation:
Here, we will add ones digit first and then we will add tens digit, and then we will add hundreds digit. By adding 146 and 253 we will get 399.

Question 14.

135 + 16 = 151.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 135 and 16 we will get 151.

Question 15.

305 + 306 = 611.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 305 and 305 we will get 611.

Question 16.

607 + 13 = 620.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 607 and 13 we will get 620.

Question 17.

782 + 103 = 885.

Explanation:
Here, we will add ones digit first and then we will add tens digit, and then we will add hundreds digit. By adding 782 and 103 we will get 885.

Problem Solving

Question 18.
There are 247 red cars. There are 438 black cars. How many red and black cars in all?
____ cars
The total number of cars in all is 685 cars.

Explanation:
Given that there are 247 red cars and there are 438 black cars. So the total number of cars in all is 247+438 which is 685 cars.

Question 19.
Mr. Archer picked 416 apples last month. He picked 336 apples this month. How many apples did he pick in all?
____ apples
The number of apples did he pick in all is 752 apples.

Explanation:
Given that Mr. Archer picked 416 apples last month and he picked 336 apples this month. So the number of apples did he pick in all is 416+336 which is 752 apples.

Question 20.
The park ranger counted 105 black bears last year. This year, he counts 128 black bears. How many black bears did he count in all?

____ black bears
The total number of black bears is 233 black bears.

Explanation:
Given that the park ranger counted 105 black bears last year and this year, he counts 128 black bears. So the total number of black bears will be 105+128 which is 233 black bears.

Write Math Explain how to regroup ones make a ten when adding three-digit numbers.

By regrouping ones we get ten to the tens digit number. As the number is three digit number, so after regrouping tens digit number we will regroup hundreds digit number.

### McGraw Hill My Math Grade 2 Chapter 6 Lesson 4 My Homework Answer Key

Practice

Question 1.

463 + 118 = 581.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 352 and 281 we will get 581.

Question 2.

182 + 109 = 291.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 352 and 281 we will get 291.

Question 3.

334 + 128 = 462.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 334 and 128 we will get 462.

Question 4.

744 + 138 = 882

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 744 and 138 we will get 882.

Question 5.

363 + 219 = 582.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 363 and 219 we will get 582.

Question 6.

827 + 155 = 982.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 827 and 155 we will get 982.

Question 7.

335 + 116 = 451.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 335 and 116 we will get 451.

Question 8.

135 + 219 = 354.

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 135 and 219 we will get 354.

Question 9.

425 + 148 =

Explanation:
Here, we will add ones digit first and we will do regrouping then we will add tens digit and regroup, and then we will add hundreds digit. By adding 425 and 148 we will get .

Question 10.
149 children are on a playground. 131 more children come to the playground. How many children are on the playground now?
____ children
The number of children on the playground now is 280 children.

Explanation:
Given that 149 children are on a playground and 131 more children come to the playground. So the number of children on the playground now is 149+131 which is 280 children.

Question 11.
There are 152 tadpoles and 138 frogs in a pond. How many frogs and tadpoles are there in all?

____ frogs and tadpoles
There are 290 frogs and tadpoles.

Explanation:
Given that there are 152 tadpoles and 138 frogs in a pond. So the number of frogs and tadpoles there in all is 152+138 which is 290.

Test Practice

Question 12.
Find the sum. 368 + 619 = _____
(A) 919
(B) 968
(C) 987
(D) 997
C.

Explanation:
The sum of 368 + 619 is 987.

Math at Home Have your child explain how to regroup to add 215 + 215.