Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms

We included HMH Into Math Grade 7 Answer Key PDF Module 11 Lesson 2 Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms to make students experts in learning maths.

HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms

I Can derive and apply the formulas for surface area of any right prism.

Spark Your Learning

Sara is wrapping a gift box with dimensions 10 inches by 14 inches by 5 inches with wrapping paper. What is the least amount of wrapping paper she will need to cover the gift box without any overlap?
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 1
Answer:
520 in2
Explanation:
Dimensions: l = 10 inches, w = 14 inches, h = 5 inches
Surface area: A
A = 2(x w + w x h x h x l)
A = 2(10×14 + 14×5 + 5×10)
A = 2(140 + 70 + 50)
A = 2(260)
A = 520 in2

Turn and Talk What is the difference between area and surface area?
Answer:
180 inches
Explanation:
Surface area: A
A = 2(x w + w x h x h x l)
A = 2(10×14 + 14×5 + 5×10)
A = 2(140 + 70 + 50)
A = 2(260)
A = 520 in2
Volume: V = (l).(w).(h)
V = 10 x 14 x 5 = 700 in3

Build Understanding

Question 1.
A wooden toy box is represented by the net shown with it.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 2
A. How many faces make up the toy box? What does the net show about these faces?
Answer:
6 faces

B. Are any of the faces congruent? If so, which ones?
Answer:
Base and base are congruent
Front and Back are congruent

C. What is the shape of the two bases? What is their combined area?
Answer:
Rectangle


Combined area
A = Length x width
A = (18+18) x 35
A = 36 x 35
A = 1236 in2

D. What is the combined area of the front and back faces?
Answer:
1050 in2
Explanation:
Area A = length x width
A = 2(15 x 35 )
A = 2(525) = 1050 in2

E. What is the combined area of the left and right faces?
Answer:
540 in2
Explanation:
Area A = length x width
A = 2(15 x 18 )
A = 2(270) = 540 in2

F. How can you find the total surface area of the toy box? What is this value?
Answer:
2850 in2
Explanation:
Dimensions: l = 35 inches, w = 15 inches, h = 18 inches
Surface area: A
A = 2(x w + w x h x h x l)
A = 2(35 × 15 + 15 x 18 + 18 x 35)
A = 2(525 + 270 + 630)
A = 2(1425)
A = 2850 in2

G. Use the net to derive a formula for surface area of a box with length l, width w, and height h:
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 3
Surface area = 2lw + HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4 + HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4
Since lw is the area of a _________, replace lw with B: 2B + 2lh + 2wh.
Both parts of the expression 2lh + 2wh contain an h, so factor it out: 28 + h(HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4 + HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4).
Since 2l + 2w represents the ____________ of the base, replace 2l + 2w with P:
Surface Area = 2B + HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4 h
Answer:
Surface area = 2lw + 2wh + 2hl
Since lw is the area of a Base, replace lw with B: 2B + 2lh + 2wh.
Both parts of the expression 2lh + 2wh contain an h, so factor it out: 2B + h(2l + 2w).
Since 2l + 2w represents the P of the base, replace 2l + 2w with P:
Surface Area = 2B + Ph

Turn and Talk How could you change the surface area formula for a cube to make it simpler?
Answer:
6s2
Explanation:
s is the side of a cube.
Surface area cube of same length, width and height= 2sxs + 2sxs + 2sxs = 6s2
Surface area = 2lw + 2wh + 2hl
l = s, w = s, h = s
Since s x s is the area of a Base, replace s x s with B: 2B + 2s.s + 2s.s.
Both parts of the expression 2s.s + 2s.s contain an h, so factor it out: 2B + s(2s + 2s).
Since 2s+ 2s represents the P of the base, replace 2s + 2s with P:
Surface Area = 2s.s + Ps
Step It Out

The surface area of a right prism is S = 2B + Ph, where B is the base area, P is the base perimeter, and h is the height of the prism.

Question 2.
A foundation has the water bottles shown as giveaways for its annual fundraiser. What is the approximate surface area of the water bottle, treating the top surface as flat and ignoring the spout?
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 6
A. From the picture, the area of the base is approximately HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 7 square inches and the height is HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 7inches.
The perimeter of the base is HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 7 × HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 7 = HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 7 inches.
Answer:
A. From the picture, the area of the base is approximately 6.9 square inches and the height is 8 inches.
The perimeter of the base is 2 × 5 = 10 inches.
Explanation:
The surface area of a right prism is S = 2B + Ph, where B is the base area, P is the base perimeter, and h is the height of the prism
B= 6.9 sq in
The perimeter of the base is 2 × 5 = 10 inches.

B. Find the approximate surface area.
S = 2B + Ph
S = 2 HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4 + HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4 (HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4)
S = HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4 + HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4
S = HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4
The surface area of the water bottle is approximately HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 4 square inches.
Answer:
S = 2B + Ph
S = 2 (6.9) + 10 (8)
S = 13.8 + 80
S = 93.8 square inches.
The surface area of the water bottle is approximately 94 square inches.
Explanation:
Given, base = 6.9; perimeter = 10; height = 8
S = 2B + Ph
S = 2 (6.9) + 10 (8)
S = 13.8 + 80
S = 93.8 square inches.

Check Understanding

Question 1.
A couch cushion needs to be covered with fabric. The dimensions of the cushion are 1.5 feet long by 1.5 feet wide by 0.5 foot high. What is the least amount of fabric that will be needed to cover the couch cushion?
Answer:
7.5 in2
Explanation:
length 1.5 feet, width 1.5 feet and height = 0.5 feet
Surface area: A
A = 2(x w + w x h x h x l)
A = 2(1.5×1.5 + 1.5 x 0.5 + 0.5×1.5)
A = 2(2.25 + 0.75 + 0.75)
A = 2(3.75)
A = 7.5 in2

Question 2.
Bobby is sanding a five-sided storage chest with the dimensions shown. The base is a regular pentagon. If he sands only the outside of the chest, approximately how much area must he sand?
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 8
Answer:
236 square feet.
Explanation:
The surface area of a right prism is S = 2B + Ph,
where B is the base area, P is the base perimeter, and h is the height of the prism.
P = perimeter of base = 5×5 = 25
B area of base = 43sq ft
S = 2B + Ph
S = 2 (43) + 25 (6)
S = 86 + 150
S = 236 square feet.

Question 3.
A photographer’s darkroom needs a new coat of black paint on all surfaces of the room, including the ceiling and the floor. The room is a cube with edge length 11 feet. How much surface area must be painted?
Answer:
726 sq ft
Explanation:
6 s x s = 6 (11 x 11) = 6 x 121 = 726 sq ft
or
B= 121 sq ft
P = 44 ft
S = 2B + Ph
S = 2 (121) + 44 (11) = 242 + 484 = 726 sq feet

On Your Own

Question 4.
Lily is using wrapping paper to cover a box with dimensions 7 centimeters by 10 centimeters by 5 centimeters. What is the least amount of paper Lily will need to cover the box?
Answer:
310 square cm.
Explanation:
The surface area of a rectangular prism is S = 2B + Ph,
where B is the base area, P is the base perimeter, and h is the height of the prism.
length l = 7cm, width w = 10 cm and height h = 5 cm
P = perimeter of base = 2(7+10) = 34 cm
B area of base = 7 x 10 = 70 sq cm
S = 2B + Ph
S = 2 (70) + 34 (5)
S = 140 + 170
S = 310 square cm.

Question 5.
Use Structure Gavin is making a scale replica of a tent for his social studies project. The replica is in the shape of a triangular prism. It has an isosceles triangle base with side lengths 6 inches, 5 inches, and 5 inches. The height of the triangle is 4 inches, and the depth of the tent is 7 inches. How much fabric will Gavin need to make the outside of the replica, including the “floor”?
Answer:
88 square in.
Explanation:
The surface area of a triangular prism is S = 2B + Ph,
where B is the base area, P is the base perimeter, and h is the height of the prism
h= 4in; P = perimeter of base = 6 + 5 + 5 = 16 in
B area of base = 1/2(4 x 6) = 12 sq in
S = 2B + Ph
S = 2 (12) + 16 (4)
S = 24 + 64
S = 88 square in.

Question 6.
Blake made a storage bin out of poles in the shape of a regular hexagonal prism, as shown. He wants to cover the surface area of the prism, including the floor, with a tarp to protect his things from the weather. What is the approximate surface area that the tarp will cover? Explain.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 9
Answer:
547.2 square feet.
Explanation:
The surface area of a regular hexagonal prism is S = 2B + Ph,
where B is the base area, P is the base perimeter, and h is the height of the prism
P = perimeter of base = 6 x 6 = 36sq feet
B area of base = 93.6sq ft
S = 2B + Ph
S = 2 (93.6) + 36 (10)
S = 187.2 + 360
S = 547.2 square feet.

Find the surface area of each prism.

Question 7.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 10
Answer:
352 square cm.
Explanation:
The formula for the surface area of triangular prism is:
Surface area = (Perimeter of the base × Length of the prism) + (2 × Base Area)
SA = (S1 +S2 + S3)L + bh
P = perimeter of base = 12+10+10 = 32 cm
B area of base = (8×6) = 48 sq cm
S = 2B + Ph
S = 2 (48) + 32 (8)
S = 96 + 256
S = 352 square cm.

Question 8.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 11
Answer:
924 square cm.
Explanation:
The surface area of a rectangular prism is S = 2B + Ph,
where B is the base area, P is the base perimeter, and h is the height of the prism
length l = 22cm, width w = 5.5 cm and height h = 7.5 cm
P = perimeter of base = 2(22+5.5) = 242 cm
B area of base = 22×10 = 220 sq cm
S = 2B + Ph
S = 2 (220) + 242 (7.5)
S = 440 + 484
S = 924 square cm.

Question 9.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 12
Answer:
2194 sq in
Explanation:
B= 509 sq in
P = 6 x 14 =84 in
S = 2B + Ph
S = 2 (509) + 84 (14)
= 1018 + 1176 = 2194 sq in

Question 10.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 13
Answer:
253.5 sq cm
Explanation:
B= 6.5 x 6.5 = 42.25 sq cm
P = 4 x 6.5 = 26 cm
S = 2B + Ph
S = 2 (42.25) + 26 (6.5) = 84.5 + 169 = 253.5 sq cm
or
6 x side x side = 6 x 6.5 x 6.5 = 253.5 sq cm

I’m in a Learning Mindset!

How does using the formulas for surface area of right prisms help me find surface area more efficiently?
Answer:
Surface area = Bl + Ph
B base area and L is length
P is the perimeter of the base
h is the height of the triangle
the formulas for surface area of right prisms help me find surface area more efficiently and easy

Lesson 11.2 More Practice/Homework

Question 1.
Use Structure Melissa baked a cake. The box for the cake is ¡n the shape of a cube with edges 9 centimeters in length. Draw a supporting picture and find how many square centimeters of cardboard are needed to make the box.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 14
Answer:
486 sq cm
Explanation:
B= 9 x 9 = 81 sq cm
P = 4 x 9 = 36 cm
S = 2B + Ph
S = 2 (81) + 36 (9) = 162 + 324 = 486 sq cm
or
6 x side x side = 6 x 9 x 9 = 486 sq cm

Question 2.
Sue is upholstering a rectangular ottoman that measures 21 centimeters by 18 centimeters by 15 centimeters. What will be the total square centimeters of fabric that Sue must use to cover all faces of the ottoman?
Answer:
1926 square cm.
Explanation:
The surface area of a rectangular prism is S = 2B + Ph,
where B is the base area, P is the base perimeter, and h is the height of the prism
length l = 21cm, width w = 18 cm and height h = 15 cm
P = perimeter of base = 2(21 + 18) = 2 x 39 = 78 cm
B area of base = 21 x 18 = 378 sq cm
S = 2B + Ph
S = 2 (378) + 78 (15)
S = 756 + 1170
S = 1926 square cm.

Question 3.
A drawing of the attic in a house is shown. It needs insulation on all sides. How many square feet of insulation are needed?
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 15
Answer:
1761 ft2
Explanation:
Surface area = (Perimeter of the base × Length of the prism) + (2 × Base Area)
SA = (S1 +S2 + S3)L + bh
P = perimeter of base = 21.2 + 15 + 15 = 51.2 ft
B area of base = (15 x 15) = 225 ft2
SA = (S1 +S2 + S3)L + bh
SA = 51.2 x 30 + 225
S = 1536 +225 = 1761 ft2

For Problems 4-7, find the surface area of each prism. Round to the nearest tenth if necessary.

Question 4.
Math on the Spot
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 16
Answer:
164 square cm.
Explanation:
The surface area of a rectangular prism is S = 2B + Ph,
where B is the base area, P is the base perimeter, and h is the height of the prism
length l = 10 cm, width w = 4 cm and height h = 3 cm
P = perimeter of base = 2(10 + 4) = 2 x 14 = 28 cm
B area of base = 10 x 4 = 40 sq cm
S = 2B + Ph
S = 2 (40) + 28 (3)
S = 80 + 84
S = 164 square cm.

Question 5.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 17
Answer:
84 sq cm
Explanation:
The formula for the surface area of triangular prism is:
Surface area = (Perimeter of the base × Length of the prism) + (2 × Base Area)
SA = (S1 +S2 + S3)L + bh
P = perimeter of base = 5 + 5 + 6 = 16 cm
B area of base = (4×3) = 12 sq cm
S = 2B + Ph
S = 2 x12 + 16 x 4
S = 24 + 64
S = 84 sq cm
Question 6.
Regular pentagon base 7.
B ≈ 61.94 cm2
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 18
Answer:
273.88 cm2
Explanation:
B = 61.94 cm2
P = 6 x 5 = 30 cm
S = 2B + Ph
S = 2 (61.94) + 30 (5)
= 123.88 + 150 = 273.88 cm2

Question 7.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 19
Answer:
672 cm2
Explanation:
Surface area = (Perimeter of the base × Length of the prism) + (2 × Base Area)
SA = (S1 +S2 + S3)L + bh
P = perimeter of base = 16 + 12 + 20 = 48 cm
B area of base = (16 x 12) = 192 cm2
SA = (S1 +S2 + S3)L + bh
SA = 48 x 10 + 192
S = 480 +192 = 672 cm2
Test Prep

Question 8.
Find the surface area of the figure.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 20
(A) 41 ft2
(B) 69 ft2
(C) 75 ft2
(D) 96 ft2
Answer:
Option(D)
Explanation:
Base = 4; height = 3; length = 7
Surface Area = 2(4×3)/2 + (4×7) + (3×7)+ 7×5
= 12 + 28 + 21 + 35 = 96 ft2

Question 9.
Mark bought a jewelry box in the shape of a cube. The jewelry box has edge lengths of 6 inches. What is the total surface area of the jewelry box?
(A) 36 in2
(B) 108 in2
(C) 216 in2
(D) 1,296 in2
Answer:
Option (C)
Explanation:
Surface area of cube = 6 x side x side
= 6 x 6 x 6 = 216 in2

Question 10.
Find the surface area of a rectangular prism with length of 4.7 inches, width of 6.4 inches, and height of 8.2 inches. Round to the nearest tenth.
Answer:
242.2 in2
Explanation:
length 4.7 inches, width of 6.4 inches, and height of 8.2 inches
Surface area: A
A = 2(x w + w x h x h x l)
A = 2(4.7 x 6.4 + 6.4 x 8.2 + 8.2 x 4.7)
A = 2(30.08 +52.48 + 38.54)
A = 2(121.1)
A = 242.2 in2

Question 11.
Find the surface area of a regular hexagonal prism with side length 4.2 millimeters, height 3.9 millimeters, and base area of approximately 45.8 square millimeters. Round to the nearest tenth.
Answer:
189.88 square millimeters.
The surface area of a regular hexagonal prism is S = 2B + Ph, where B is the base area,
P is the base perimeter, and h is the height of the prism
P = perimeter of base = 6 x 4.2 = 25.2 square millimeters
B area of base = 45.8 square millimeters
height = 3.9 millimeters
S = 2B + Ph
S = 2 (45.8) + 25.2 (3.9)
S = 91.26 + 98.28
S = 189.88 square millimeters.

Spiral Review

Question 12.
Identify the two-dimensional figure that results from slicing a cylinder parallel to its base.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 21
Answer:
Rectangle

Explanation:
When the two-dimensional figure slice a cylinder parallel to its base the result is recctangle.

Question 13.
Find the area of the composite figure.
HMH Into Math Grade 7 Module 11 Lesson 2 Answer Key Derive and Apply Formulas for Surface Areas of Cubes and Right Prisms 22
Answer:
21 sq ft
Explanation:

5 x 3 = 15 sq ft
2 x 3 = 6 sq ft
total surface area = 15 + 6 = 21 sq ft

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