We included **HMH Into Math Grade 2 Answer Key PDF** **Module 12 Lesson 6 Subtract Two-Digit Numbers **to make students experts in learning maths.

## HMH Into Math Grade 2 Module 12 Lesson 6 Answer Key Subtract Two-Digit Numbers

I Can record the steps when subtracting two-digit numbers.

**Step It Out**

Question 1.

Wayne collects M2 pencils. Carmen collects 13 pencils. How many fewer pencils does Carmen collect than Wayne?

A. Are there enough ones to subtract 3? Circle Yes or No.

yes

no

Answer:

There are not enough ones to subtract. Because the minuend has smaller than the subtrahend.

The minuend is 2 and subtrahend is 3.

B. If there are not enough ones, regroup 1 ten as 10 ones. Then write the new number of tens and ones.

Answer:

After regrouping there are 3 tens and 12 ones.

C. Subtract the ones. Write the number in the ones place.

_______ – 3 = ________

Answer:

After regrouping. The number of ones is 12.

In the ones place 12 – 3 = 9.

D. Subtract the tens. Write the number in the tens place.

________ – 1 = ________

Answer:

The new number in the tens place is 3.

In the tens place 3 – 1 = 2.

E. Solve the problem

_________ fewer pencils

Answer:

Given that,

The total number of pencils that Wayne collects is = 42.

The total number of pencils that Carmen collects = 13.

Therefore 42 – 13 = 29.

Carmen collect 29 pencils fewer than Wayne.

Question 2.

Subtract 39 from 97

A. Are there enough ones to subtract from? Explain.

Answer:

97 – 39 = 58

There are not enough ones to subtract.

B. Regroup if you need to. Subtract the ones.

Answer:

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 7 and subtrahend is 9.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

C. Subtract the tens.

Answer:

After regrouping there are 8 tens in the tens place.

8 – 3 = 5.

D. Write the difference.

97 – 39 = ________

Answer:

The difference of 97 – 39 = 58.

Subtracting 97 from 39 then we get 58.

58 is the difference.

**Turn and Talk** How is regrouping for subtraction different from regrouping for addition? Explain.

Answer:

In the addition, the regrouping is done when the addition of one place is 2 digit number.

In subtraction, the regrouping is done when the minuend is smaller than the subtrahend.

**Check Understanding**

**Subtract. Regroup if you need to.**

Question 1.

Answer:

Here there is no need for regrouping. Because the minuend is greater than the subtrahend.

The minuend is 9 and the subtrahend is 3

Question 2.

Answer:

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 4 and subtrahend is 6.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

**On Your Own**

Question 3.

Use Structure There are 92 cans of peas in a carton. Theresa puts 75 of the cans on a shelf. How many cans of peas are in the carton now?

________ cans of peas

Answer:

Given that,

The total number of cans of peas in a carton = 92.

The total number of cans that Theresa put on the shelf = 75.

The remaining can of peas in a carton = 92 – 75 = 17

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

**Attend to Precision Subtract. Regroup if you need to.**

Question 4.

Answer:

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 7 and subtrahend is 9.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

Question 5.

Answer:

Here regrouping in subtraction is not needed. Because the minuend and subtrahend are equal.

The minuend is 6 and subtrahend is 6.

Question 6.

Answer:

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 2 and subtrahend is 8.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

Question 7.

**Open-Ended** Write a two-digit number to complete the problem. Solve the problem.

Joel has 62 buttons.

He gives ________ buttons to his friends.

How many buttons does Joel have now?

_________ buttons

Answer:

Given that,

Joel has 62 buttons.

He gives 31 buttons to his friends.

The total number of buttons near the Joel = 62 – 31 = 31.

Therefore Joel has 31 buttons now.

**On Your Own**

Question 8.

**Reason** Mr. Cannon has 42 books in his library. He has 14 books about computers. How many books are not about computers?

_________ books

Answer:

Given that,

The total number of books in Mr. Cannon’s library = 42.

The total number of computer books = 14

The total number books that not about computer = 42 – 14 = 28

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 2 and subtrahend is 4.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

Question 9.

**Use Repeated Reasoning** Explain the subtraction that you did to solve Problem 8. Be sure to tell about the values of the digits in the numbers.

Answer:

42 – 14 = 28

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 2 and subtrahend is 7.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

After regrouping there are 12ones and 3 tens

In the ones place = 12 – 4 = 8.

In the tens place = 3 – 1 = 2.

**Attend to Precision Subtract. Regroup if you need to.**

Question 10.

Answer:

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 5 and subtrahend is 6.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

Question 11.

Answer:

Here regrouping in subtraction is not needed. Because the minuend Is greater than the subtrahend.

The minuend is 9 and subtrahend is 2.

Question 12.

Answer:

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 2 and subtrahend is 4.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

Question 13.

Answer:

Here regrouping in subtraction is not needed. Because the minuend Is greater than the subtrahend.

The minuend is 4 and subtrahend is 1.

Question 14.

Answer:

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 8 and subtrahend is 9.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

Question 15.

Answer:

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 1 and subtrahend is 5.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

Question 16.

Answer:

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 4 and subtrahend is 7.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

Question 17.

Answer:

Here regrouping in subtraction is not needed. Because the minuend Is greater than the subtrahend.

The minuend is 5 and subtrahend is 4.

Question 18.

Answer:

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 8 and subtrahend is 9.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.