Into Math Grade 2 Module 12 Review Answer Key

We included HMH Into Math Grade 2 Answer Key PDF Module 12 Review to make students experts in learning maths.

HMH Into Math Grade 2 Module 12 Review Answer Key

Vocabulary

Question 1.
Draw a picture to show what the word regroup means.
Answer:
Regrouping is a process of making groups of tens when carrying out operations like addition or subtracting with 2-digit numbers.
HMH Into Math Grade 2 Module 12 Review Answer Key_1

Concepts and Skills

Solve. Regroup if you need to.

Question 2.
There are 36 blue chairs and 49 red chairs in the cafeteria. How many chairs are there?
HMH Into Math Grade 2 Module 12 Review Answer Key 1
________ chairs
Answer:
Given,
There are 36 blue chairs and 49 red chairs in the cafeteria.
36 + 49 = 85
HMH-Into-Math-Grade-2-Module-12-Review-Answer-Key-1

Fill in the bubble next to the correct answer.

Question 3.
For which problem will you need to regroup 10 ones as 1 ten?
HMH Into Math Grade 2 Module 12 Review Answer Key 2
Answer:
HMH-Into-Math-Grade-2-Module-12-Review-Answer-Key-2
16 + 78 = 94 need to regroup 10 one as 1 ten.

Question 4.
For which problem will you need to regroup 1 ten as 10 ones?
HMH Into Math Grade 2 Module 12 Review Answer Key 3
Answer:
HMH-Into-Math-Grade-2-Module-12-Review-Answer-Key-3
54 – 38 = 16 need to regroup 1 ten as 10 ones.

Question 5.
Add 73 and 17. Regroup if you need to.
HMH Into Math Grade 2 Module 12 Review Answer Key 4
Answer:
HMH-Into-Math-Grade-2-Module-12-Review-Answer-Key-4
73 + 17 need to regroup 10 one as 1 ten.

Question 6.
Subtract 31 from 82. Regroup if you need to.
HMH Into Math Grade 2 Module 12 Review Answer Key 5
Answer:
Subtract 31 from 82 we get 51.
HMH-Into-Math-Grade-2-Module-12-Review-Answer-Key-5
There is no need to regroup 1 ten as 10 ones

Question 7.
Complete the sentences to explain the addition you did in Problem 5.
I regrouped 3 ones and 7 ones as ______ ten ________ ones.
Then I added the tens:
1 ten + 7 tens + 1 ten = ________tens
9 tens 0 ones = ________
Answer:
I regrouped 3 ones and 7 ones as 1 ten 0 ones.
Then I added the tens:
1 ten + 7 tens + 1 ten = 9 tens
9 tens 0 ones = 90

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