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Bridges in Mathematics Grade 5 Home Connections Answer Key Unit 2 Module 2
Bridges in Mathematics Grade 5 Home Connections Unit 2 Module 2 Session 1 Answer Key
Cafeteria Problems
Question 1.
The cafeteria at King Elementary asked the students to vote on their favorite main dishes. The circle graphs below show the results. Use the information to answer the questions below.
a. What fraction of the fourth graders did not vote for super salad? Show your work.
Answer:
\(\frac{1}{2}\) + \(\frac{1}{4}\) + \(\frac{1}{8}\)
\(\frac{3}{4}\) + \(\frac{1}{8}\)
LCD of 4, 8 is 8
\(\frac{6}{8}\) + \(\frac{1}{8}\) = \(\frac{7}{8}\)
So, \(\frac{7}{8}\) fraction of the fourth graders did not vote for super salad.
b. What fraction of the fifth grade voted for turkey burgers or chicken nuggets? Show your work.
Answer:
\(\frac{1}{3}\) + \(\frac{1}{6}\) = \(\frac{1}{2}\)
\(\frac{1}{2}\) fraction of the fifth grade voted for turkey burgers or chicken nuggets.
c. 192 fourth graders voted. How many of them voted for turkey burgers? Show your work.
Answer:
Given,
192 fourth graders voted.
Fraction fourth graders voted for turkey burgers is \(\frac{1}{4}\)
192 × \(\frac{1}{4}\) = 48
So, 48 fourth graders voted for turkey burgers.
d. 174 fifth graders voted. How many of them voted for chicken nuggets?
Answer:
Given,
174 fifth graders voted.
Fraction fifth graders voted for chicken nuggets is \(\frac{1}{6}\)
174 × \(\frac{1}{6}\) = 29
So, 29 fifth graders voted for chicken nuggets.
Question 2.
What is:
a. \(\frac{1}{2}\) of 60?
b. \(\frac{1}{3}\) × 60?
c. \(\frac{1}{2}\) of 100?
d. \(\frac{1}{5}\) × 100?
Answer:
a. \(\frac{1}{2}\) of 60
\(\frac{1}{2}\) × 60 = 30
b. \(\frac{1}{3}\) × 60
\(\frac{1}{3}\) × 60 = 20
c. \(\frac{1}{2}\) of 100
\(\frac{1}{2}\) × 100 = 50
d. \(\frac{1}{5}\) × 100
\(\frac{1}{5}\) × 100 = 20
Question 3.
While waiting for his grandma to arrive, Patrick spent \(\frac{1}{2}\) of an hour on the phone with a friend and \(\frac{1}{4}\) of an hour listening to the radio. How long did Patrick spend waiting for his grandma? Write your answer both in minutes and as a fraction of an hour.
Answer:
Given,
While waiting for his grandma to arrive, Patrick spent \(\frac{1}{2}\) of an hour on the phone with a friend and \(\frac{1}{4}\) of an hour listening to the radio.
\(\frac{1}{2}\) + \(\frac{1}{4}\)
LCD of 2, 4 is 4.
\(\frac{2}{4}\) + \(\frac{1}{4}\) = \(\frac{3}{4}\) fraction of an hour
Question 4.
Beth walked \(\frac{1}{3}\) of a mile from her house to her friend’s house, \(\frac{1}{4}\) of a mile to the post office, and then another \(\frac{1}{2}\) of a mile from the post office back home. How far did Beth walk?
Answer:
Given,
Beth walked \(\frac{1}{3}\) of a mile from her house to her friend’s house, \(\frac{1}{4}\) of a mile to the post office, and then another \(\frac{1}{2}\) of a mile from the post office back home.
\(\frac{1}{2}\) + \(\frac{1}{3}\) + \(\frac{1}{4}\)
\(\frac{3}{4}\) + \(\frac{1}{3}\)
LCD of 3, 4 is 12
\(\frac{9}{12}\) + \(\frac{4}{12}\) = \(\frac{13}{12}\) = 1\(\frac{1}{12}\)
Question 5.
CHALLENGE Rodney and Josiah each bought a package of the same kind of cookies at the store. Rodney ate \(\frac{1}{2}\) package of cookies on Monday and \(\frac{1}{3}\) of the same package on Tuesday. Josiah ate \(\frac{5}{12}\) of his package on Monday and \(\frac{1}{2}\) of the package on Tuesday. Who ate more? How much more?
Answer:
Given,
Rodney and Josiah each bought a package of the same kind of cookies at the store.
Rodney ate \(\frac{1}{2}\) package of cookies on Monday and \(\frac{1}{3}\) of the same package on Tuesday.
Josiah ate \(\frac{5}{12}\) of his package on Monday and \(\frac{1}{2}\) of the package on Tuesday.
\(\frac{5}{12}\) – \(\frac{4}{12}\) = \(\frac{1}{12}\)
Josiah ate \(\frac{1}{12}\) more of the package of cookies.
Bridges in Mathematics Grade 5 Home Connections Unit 2 Module 2 Session 3 Answer Key
Adding & Subtracting Fractions
Question 1.
Solve the problems on this page. If your answer is an improper fraction, find its equivalent mixed number.
\(\frac{3}{4}\) + \(\frac{1}{2}\) = \(\frac{3}{4}\) + \(\frac{2}{4}\) = \(\frac{5}{4}\) = 1\(\frac{1}{4}\)
\(\frac{5}{4}\) is an improperfraction because 5 is greater than 4. \(\frac{4}{4}\) is equal to 1, so \(\frac{5}{4}\) is equal to 1\(\frac{1}{4}\).
a.
1\(\frac{5}{10}\) – \(\frac{4}{10}\) =
Answer:
1\(\frac{5}{10}\) – \(\frac{4}{10}\)
1 + \(\frac{5}{10}\) – \(\frac{4}{10}\)
\(\frac{5}{10}\) – \(\frac{4}{10}\) = \(\frac{1}{10}\)
1 + \(\frac{1}{10}\) = 1 \(\frac{1}{10}\)
b.
\(\frac{7}{4}\) – \(\frac{3}{4}\) =
Answer:
\(\frac{7}{4}\) – \(\frac{3}{4}\) = \(\frac{7-3}{4}\) = \(\frac{4}{4}\) = 1
c.
\(\frac{4}{12}\) + 1\(\frac{2}{3}\) =
Answer:
\(\frac{4}{12}\) + 1\(\frac{2}{3}\)
\(\frac{4}{12}\) + 1 + \(\frac{2}{3}\)
\(\frac{4}{12}\) + \(\frac{2}{3}\)
LCD is 12
\(\frac{4}{12}\) + \(\frac{8}{12}\) = \(\frac{12}{12}\) = 1
1 + 1 = 2
d.
1\(\frac{2}{3}\) + \(\frac{1}{6}\) =
Answer:
1\(\frac{2}{3}\) + \(\frac{1}{6}\)
1 + \(\frac{2}{3}\) + \(\frac{1}{6}\)
\(\frac{2}{3}\) + \(\frac{1}{6}\)
LCD is 6.
\(\frac{4}{6}\) + \(\frac{1}{6}\) = \(\frac{5}{6}\)
1 + \(\frac{5}{6}\) = 1\(\frac{5}{6}\)
e.
\(\frac{5}{10}\) – \(\frac{1}{4}\) =
Answer:
\(\frac{5}{10}\) – \(\frac{1}{4}\)
LCD is 20
\(\frac{10}{20}\) – \(\frac{5}{20}\) = \(\frac{5}{20}\) = \(\frac{1}{4}\)
f.
4\(\frac{30}{60}\) + 1\(\frac{1}{4}\) =
Answer:
4\(\frac{30}{60}\) + 1\(\frac{1}{4}\)
4 + \(\frac{30}{60}\) + 1 + \(\frac{1}{4}\)
4 + 1 = 5
\(\frac{30}{60}\) + \(\frac{1}{4}\) = \(\frac{3}{4}\)
5 + \(\frac{3}{4}\) = 5\(\frac{3}{4}\)
Question 2.
Find two different ways to show that \(\frac{1}{3}\) + \(\frac{1}{4}\) is not equal to \(\frac{2}{7}\). You can use numbers, words, and labeled sketches.
Answer:
\(\frac{1}{3}\) + \(\frac{1}{4}\)
LCD of 3, 4 is 12
\(\frac{4}{12}\) + \(\frac{3}{12}\) = \(\frac{7}{12}\)
+ 
= \(\frac{7}{12}\)
Question 3.
Dan must do homework for \(\frac{1}{2}\) an hour and clean his room for \(\frac{1}{3}\) of an hour before he can play. What fraction of an hour must Dan do homework and clean before he can play?
Answer:
Given,
Dan must do homework for \(\frac{1}{2}\) an hour and clean his room for \(\frac{1}{3}\) of an hour before he can play.
\(\frac{1}{2}\) + \(\frac{1}{3}\)
LCD of 2, 3 is 6.
\(\frac{3}{6}\) + \(\frac{2}{6}\) = \(\frac{5}{6}\)
Question 4.
Danielle found a nickel on the playground at school. She also found $0.20 on the sidewalk.
a. How much money did she find?
Answer:
Given,
Danielle found a nickel on the playground at school. She also found $0.20 on the sidewalk.
$0.20 + $0.05 = $0.25
b. What fraction of a dollar did Danielle find?
Answer: 0.25 can be written in the fraction form as 1/4.
She found 1/4 of a dollar.
Question 5.
CHALLENGE Mariah has an after-school babysitting job. This is a record of the number of hours she worked last week.
Mariah gets paid $6 per hour. How much money did she earn babysitting last week? Show your work.
Answer:
(2 \(\frac{1}{2}\) + 3\(\frac{1}{2}\) + 2\(\frac{1}{4}\) + 3\(\frac{2}{3}\)) × 6
(\(\frac{5}{2}\) + \(\frac{7}{2}\) + \(\frac{9}{4}\) + \(\frac{11}{3}\)) × 6
(\(\frac{12}{2}\) + \(\frac{9}{4}\) + \(\frac{11}{3}\)) × 6
(\(\frac{12}{2}\) + \(\frac{71}{12}\)) × 6
(\(\frac{72}{12}\) + \(\frac{71}{12}\)) × 6
= \(\frac{143}{12}\) × 6
= \(\frac{143}{2}\)
= 71.5
Bridges in Mathematics Grade 5 Home Connections Unit 2 Module 2 Session 5 Answer Key
Fraction Action
Question 1.
Color some of the circles in each set to show the fractions below.
a.
\(\frac{1}{2}\)
Answer:
b.
\(\frac{1}{4}\)
Answer:
c.
\(\frac{3}{4}\)
Answer:
d.
\(\frac{1}{6}\)
Answer:
\(\frac{1}{6}\) = \(\frac{2}{12}\)
e.
\(\frac{2}{6}\)
Answer:
\(\frac{2}{6}\) = \(\frac{1}{3}\)
f.
\(\frac{5}{6}\)
Answer:
g.
\(\frac{1}{3}\)
Answer:
h.
\(\frac{3}{3}\)
Answer:
\(\frac{3}{3}\) = 1
i.
\(\frac{0}{3}\)
Answer:
Question 2.
Add the following fractions. If the sum is greater than 1, write the answer as both an improper fraction and a mixed number.
ex \(\frac{1}{2}\) + \(\frac{3}{4}\) = \(\frac{5}{4}\) = 1\(\frac{1}{4}\)
a.
\(\frac{0}{3}\) + \(\frac{2}{8}\)
Answer:
\(\frac{0}{3}\) + \(\frac{2}{8}\) = 0 + \(\frac{2}{8}\) = \(\frac{2}{8}\) = \(\frac{1}{4}\)
b.
\(\frac{1}{4}\) + \(\frac{5}{6}\)
Answer:
Given,
\(\frac{1}{4}\) + \(\frac{5}{6}\)
LCD is 24.
\(\frac{6}{24}\) + \(\frac{20}{24}\) = \(\frac{26}{24}\) = \(\frac{13}{12}\) = 1\(\frac{1}{12}\)
c.
\(\frac{1}{6}\) + \(\frac{1}{3}\)
Answer:
Given,
\(\frac{1}{6}\) + \(\frac{1}{3}\)
LCD is 6.
\(\frac{1}{6}\) + \(\frac{2}{6}\) = \(\frac{3}{6}\) = \(\frac{1}{2}\)
d.
\(\frac{3}{3}\) + \(\frac{3}{4}\)
Answer:
\(\frac{3}{3}\) + \(\frac{3}{4}\)
1 + \(\frac{3}{4}\) = 1\(\frac{3}{4}\)
Question 3.
Marsha walked 1\(\frac{1}{2}\) miles to school yesterday morning. After school, she walked \(\frac{3}{4}\) of a mile to her aunt’s house. How many miles did she walk in all yesterday?
a. Estimate the answer. _______
Answer: 2 miles
b. Find the exact answer. Show all your work.
Answer:
Given,
Marsha walked 1\(\frac{1}{2}\) miles to school yesterday morning.
After school, she walked \(\frac{3}{4}\) of a mile to her aunt’s house.
1\(\frac{1}{2}\) + \(\frac{3}{4}\)
1 + \(\frac{1}{2}\) + \(\frac{3}{4}\)
1 + 1\(\frac{1}{4}\) = 2\(\frac{1}{4}\)
Question 4.
Francisco and his mom got some fruit at the fruit stand yesterday. They bought 2\(\frac{1}{2}\) pounds of peaches, \(\frac{7}{8}\) of a pound of raspberries, and 1\(\frac{1}{4}\) pounds of apricots. How many pounds of fruit did they buy in all?
a. Estimate the answer. _______
Answer: 7
b. Find the exact answer. Show all your work.
Answer:
Given,
Francisco and his mom got some fruit at the fruit stand yesterday.
They bought 2\(\frac{1}{2}\) pounds of peaches, \(\frac{7}{8}\) of a pound of raspberries, and 1\(\frac{1}{4}\) pounds of apricots.
2\(\frac{1}{2}\) + \(\frac{7}{8}\) + 1\(\frac{1}{4}\)
2 + \(\frac{1}{2}\) + \(\frac{7}{8}\) + 1 + \(\frac{1}{4}\)
2 + 1 = 3
\(\frac{1}{2}\) + \(\frac{7}{8}\) + \(\frac{1}{4}\)
LCD is 8.
\(\frac{4}{8}\) + \(\frac{7}{8}\) + \(\frac{2}{8}\) = \(\frac{13}{8}\)
3 + 1 \(\frac{5}{8}\) = 4 \(\frac{5}{8}\) = \(\frac{37}{8}\)
Question 5.
CHALLENGE Camila had a large collection of basketball cards. She gave half of them to her friend Erin and a sixth of them to her brother. She still has 150 cards left. How many cards did she start with? Show all your work.
Answer:
Given,
Camila had a large collection of basketball cards. She gave half of them to her friend Erin and a sixth of them to her brother.
Let the total number of cards be x.
Her friend = x/2
Her brother = x/6
She still has 150 cards left.
x/2 + x/6 = 150
3x + x + 150(6) = 6x
4x + 900 = 6x
6x – 4x = 900
2x = 900
x = 900/2
x = 450
She has 450 cards.