180 Days of Math for Sixth Grade Day 163 Answers Key

By accessing our 180 Days of Math for Sixth Grade Answers Key Day 163 regularly, students can get better problem-solving skills.

180 Days of Math for Sixth Grade Answers Key Day 163

Directions: Solve each problem.

Question 1.
180 Days of Math for Sixth Grade Day 163 Answers Key 1
Answer:
180-Days-of-Math-for-Sixth-Grade-Day-163-Answers-Key-1
Explanation:
Perform subtraction operation on above two given numbers. Subtract 168 from 234 the difference is 66.

Question 2.
100 • 43 = __________
Answer:
100 • 43 = 4,300
Explanation:
Perform multiplication operation on above two given numbers. Multiply 100 with 43 the product is 4,300.

Question 3.
What is the quotient of 1,496 and 10?
Answer:
1,496/10 = 149.6
The quotient of 1,496 and 10 is 149.6.
Explanation:
Perform division operation on above two given numbers. Divide 1,496 by 10 the quotient is 149.6.

Question 4.
Round 26,937 to the nearest thousand.
Answer:
Rounded 26,937 to the nearest thousand as 27,000.
Explanation:
Given number is 26,937.
If we are rounding to the nearest thousand then we have to take the hundreds place value.
The number at the hundreds place is 9.
The number which is equal to 5 or above we have to round up the value.
The number which is below 5 we have to round down the value.
The number at the hundreds place is 9, which is above 5. So, round up the value.
Rounded 26,937 to the nearest thousand as 27,000.

Question 5.
Simplify \(\frac{4}{10}\).
Answer:
The given fraction is \(\frac{4}{10}\).
4/10 = 2/5
The simplified form of the fraction \(\frac{4}{10}\) is equal to \(\frac{2}{5}\).

Question 6.
(-3) + (-2) × (-5) = _________
Answer:
(-3) + (-2) × (-5)
= (-3) + 10
= -3 + 10
= 7
Explanation:
Multiply -2 with -5 the product is 10. Now the expression is (-3) + 10.
Next perform addition operation. Add -3 with 10 the sum is 7.

Question 7.
2.3 + 2.7 – 180 Days of Math for Sixth Grade Day 163 Answers Key 2 = 1.8
Answer:
2.3 + 2.7 – 180-Days-of-Math-for-Sixth-Grade-Day-163-Answers-Key-2 = 1.8
Explanation:
To get the result 1.8 we need to perform addition and subtraction operation on the given equation. Add 2.3 with 2.7 the sum is 5. Subtract 3.2 from 5 the difference is 1.8. The missing number is 3.2.

Question 8.
Solve for r when \(\frac{r}{3}\) = 16.
r = __________
Answer:
\(\frac{r}{3}\) = 16
r = 16 x 3
r = 48
Explanation:
To calculate r value we need to perform multiplication operation on above numbers. Multiply 16 with 3 the product is 48. The value of r is 48.

Question 9.
Calculate the perimeter of a square with 3.5-cm sides.
Answer:
Given side = 3.5 cm
Perimeter of a square = 4 x side
Perimeter of a square = 4 x 3.5 cm = 14 cm
The perimeter of a square with 3.5 cm sides is 14 cm.

Question 10.
Name the solid shape.
180 Days of Math for Sixth Grade Day 163 Answers Key 3
Answer:
The above solid shape is Triangular prism.

Question 11.
180 Days of Math for Sixth Grade Day 163 Answers Key 4
One-third of the vehicles that crossed the bridge on Thursday were trucks. How many trucks crossed the bridge on Thursday?
Answer:

Question 12.
Complete the multiplication table.
180 Days of Math for Sixth Grade Day 163 Answers Key 5
Answer:
180-Days-of-Math-for-Sixth-Grade-Day-163-Answers-Key-5
Explanation:
The given multiplication table is completed by multiplying the values in first rows with values in first columns as we can observe in the above image.

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