180 Days of Math for Sixth Grade Day 108 Answers Key

By accessing our 180 Days of Math for Sixth Grade Answers Key Day 108 regularly, students can get better problem-solving skills.

180 Days of Math for Sixth Grade Answers Key Day 108

Directions: Solve each problem.

Question 1.
180 Days of Math for Sixth Grade Day 108 Answers Key 1
Answer:
180-Days-of-Math-for-Sixth-Grade-Day-108-Answers-Key-1

Question 2.
Multiply 63 and 10.
Answer: 63 × 10 = 630

Question 3.
180 Days of Math for Sixth Grade Day 108 Answers Key 2
Answer: 280 ÷ 4 = 70

Question 4.
List the prime numbers between 2 and 10.
Answer: 2, 3, 5, 7

Question 5.
4 × 2.5 = __________
Answer: 2.5 × 4 = 10.0

Question 6.
3 × 6 – 3 × 5 = __________
Answer:
3 × 6 – 3 × 5
(3 × 6) – (3 × 5)
18 – 15 = 3

Question 7.
180 Days of Math for Sixth Grade Day 108 Answers Key 3 × 48 = 96
Answer:
Let the unknown value be a
a × 48 = 96
a = 96/48
a = 2
2 × 48 = 96

Question 8.
Find m.
20m = 100
m = __________
Answer:
20m = 100
m = 100/20
m = 5

Question 9.
Calculate the distance a car can travel in 3 hours at 55 mph.
Answer:
distance = speed × time
distance= 55 × 3 = 165 mph

Question 10.
Name the polygon with 8 sides.
Answer: The polygon with 8 sides is an octagon.

Question 11.
180 Days of Math for Sixth Grade Day 108 Answers Key 4
If you randomly choose a letter from one of these columns, from which column would you have a better probability of choosing a letter made up of only straight lines?
Answer:

Question 12.
Round each item in the bill to the nearest nickel. Then calculate the total and find the change from $20.00.
180 Days of Math for Sixth Grade Day 108 Answers Key 5
Answer:

Leave a Comment

Scroll to Top
Scroll to Top