This handy Spectrum Math Grade 4 Answer Key Chapters 1-5 Mid-Test provides detailed answers for the workbook questions.
Spectrum Math Grade 4 Chapters 1-5 Mid-Test Answers Key
Add or Subtract.
Question 1.
a.
Answer:
Step 1: The sum of ones digit place will be, 3+2=5.
Step 2: Thus, the ones digit place will be 5, 23+2=25
b.
Answer:
Step 1: The sum of ones digit place will be, 3+6=9.
Step 2: Thus, the ones digit place will be 9, 33+6=39
c.
Answer:
Step 1: The sum of ones digit place will be, 7+2=9.
Step 2: Thus, the ones digit place will be 9, 17+2=19
d.
Answer:
Step 1: The sum of ones digit place will be, 2+7=9.
Step 2: Thus, the ones digit place will be 9, 32+7=39
e.
Answer:
Step 1: The sum of ones digit place will be, 1+5=6.
Step 2: Thus, the ones digit place will be 9, 61+5=66
Question 2.
a.
Answer:
Step 1: The sum of ones digit place will be, 4+5=9.
Step 2: Thus, the ones digit place will be 9, 14+5=19
b.
Answer:
Step 1: The sum of ones digit place will be, 3+1=4.
Step 2: Thus, the ones digit place will be 9, 73+1=74
c.
Answer:
Step 1: The sum of ones digit place will be, 0+9=9.
Step 2: Thus, the ones digit place will be 9, 80+9=89
d.
Answer:
Step 1: The sum of ones digit place will be, 2+7=9.
Step 2: Thus, the ones digit place will be 9, 52+7=59
e.
Answer:
Step 1: The sum of ones digit place will be, 1+8=9.
Step 2: Thus, the ones digit place will be 9, 71+8=79
Question 3.
a.
Answer:
Step 1: The sum of ones digit place will be, 3+7=10, where 1 is carry forward and needs to be added with tens digit place.
Step 2: Thus, the tens digit place will be 2+1=3, 23+7=30
b.
Answer:
Step 1: The sum of ones digit place will be, 2+9=11, where 1 is carry forward and needs to be added with tens digit place.
Step 2: Thus, the tens digit place will be 8+1=9, 82+9=91
c.
Answer:
Step 1: The sum of ones digit place will be, 4+7=11, where 1 is carry forward and needs to be added with tens digit place.
Step 2: Thus, the tens digit place will be 7+1=8, 74+7=81
d.
Answer:
Step 1: The sum of ones digit place will be, 1+9=10, where 1 is carry forward and needs to be added with tens digit place.
Step 2: Thus, the tens digit place will be 3+1=4, 31+9=40
e.
Answer:
Step 1: The sum of ones digit place will be, 3+8=11, where 1 is carry forward and needs to be added with tens digit place.
Step 2: Thus, the tens digit place will be 3+1=4, 33+8=41
Question 4.
a.
Answer:
Step 1: The sum of ones digit place will be, 8+5=14, where 1 is carry forward and needs to be added with tens digit place.
Step 2: Thus, the tens digit place will be 3+1=4, 38+5=44
b.
Answer:
Step 1: The sum of ones digit place will be, 7+8=15, where 1 is carry forward and needs to be added with tens digit place.
Step 2: Thus, the tens digit place will be 5+1=6, 57+8=65
c.
Answer:
Step 1: The sum of ones digit place will be, 6+8=14, where 1 is carry forward and needs to be added with tens digit place.
Step 2: Thus, the tens digit place will be 8+1=9, 86+8=94
d.
Answer:
Step 1: The sum of ones digit place will be, 2+9=11, where 1 is carry forward and needs to be added with tens digit place.
Step 2: Thus, the tens digit place will be 7+1=8, 72+9=81
e.
Answer:
Step 1: The sum of ones digit place, 4+9=13, where 1 is carry forward and needs to be added with tens digit place.
Step 2: Thus, the tens digit place will be 2+1=3, 24+9=33
Question 5.
a.
Answer:
Step 1: Subtract the ones digit place, 2-1=1
Step 2: Thus, the ones digit place will be 1, 32-1=31
b.
Answer:
Step 1: Subtract the ones digit place, 6-4=2
Step 2: Subtract the tens digit place, 8-1=7
Thus, 86-14=72
c.
Answer:
Step 1: Subtract the ones digit place, 5-5=0
Step 2: Subtract the tens digit place, 2-1=1
Thus, 25-15=10
d.
Answer:
Step 1: Subtract the ones digit place, 7-4=3
Step 2: Subtract the tens digit place, 8-3=5
Thus, 87-34=53
e.
Answer:
Step 1: Subtract the ones digit place, 7-5=2
Step 2: Subtract the tens digit place, 9-6=3
Thus, 97-65=32
Question 6.
a.
Answer:
Step 1: In Ones place digit, 4 is less than 8, so borrow 1 from the tens digit.
Step 2: Now the tens digit will be 6. Subtract the ones digit place, 14-8=6
Thus, 74-8=66
b.
Answer:
Step 1: In Ones place digit, 3 is less than 9, so borrow 1 from the tens digit.
Step 2: Now the tens digit will be 8. Subtract the ones digit place, 13-9=4
Thus, 93-9=84
c.
Answer:
Step 1: In Ones place digit, 7 is less than 8, so borrow 1 from the tens digit.
Step 2: Now the tens digit will be 0. Subtract the ones digit place, 17-8=9
Thus, 17-8=9
d.
Answer:
Step 1: In Ones place digit, 3 is less than 8, so borrow 1 from the tens digit.
Step 2: Now the tens digit will be 5. Subtract the ones digit place, 13-8=5
Thus, 63-8=55
e.
Answer:
Step 1: In Ones place digit, 8 is less than 9, so borrow 1 from the tens digit. Subtract the ones place digit, 18-9=9
Step 2: Now, the tens place digit will be 2. Subtract the tens digit place, 2-1=1
Thus, 38-19=19
Question 7.
a.
Answer:
Step 1: The sum of ones digit place is, 2+7=9
Step 2: The sum of tens digit place is, 5+1=6
Step 3: 52+17 = 69
b.
Answer:
Step 1: The sum of ones digit place is, 2+7+0=9
Step 2: The sum of tens digit place is, 3+1+1=5
Step 3: 32+17+10 = 59
c.
Answer:
Step 1: The sum of ones digit place is, 7+5=12, where 1 is carry forward and needs to be added with tens digit place.
Step 2: The sum of tens digit place is, 3+2+1=6
Step 3: 37+25 = 62
d.
Answer:
Step 1: The sum of ones digit place is, 3+1+8=12, where 1 is carry forward and needs to be added with tens digit place.
Step 2: The sum of tens digit place is, 4+2+1+1=8
Step 3: 43+21+18 = 82
e.
Answer:
Step 1: The sum of ones digit place is, 3+6=9
Step 2: The sum of tens digit place is, 7+2=9
Step 3: 73+26 = 99
Question 8.
a.
Answer:
Step 1: The sum of ones digit place is, 6+3=9
Step 2: The sum of tens digit place is, 3+1=4
Step 3: 36+13 = 49
b.
Answer:
Step 1: The sum of ones digit place is, 5+8=14, where 1 is carry forward and needs to be added with tens digit place.
Step 2: The sum of tens digit place is, 7+1=8
Step 3: 75+18 = 94
c.
Answer:
Step 1: The sum of ones digit place is, 1+9=10, where 1 is carry forward and needs to be added with tens digit place.
Step 2: The sum of tens digit place is, 4+3=7
Step 3: 41+39 = 80
d.
Answer:
Step 1: The sum of ones digit place is, 7+8=15, where 1 is carry forward and needs to be added with tens digit place.
Step 2: The sum of tens digit place is, 5+1+1=7
Step 3: 57+18 = 75
e.
Answer:
Step 1: The sum of ones digit place is, 7+8=15, where 1 is carry forward and needs to be added with tens digit place.
Step 2: The sum of tens digit place is, 3+2+1=6
Step 3: 37+28 = 65
Question 9.
a.
Answer:
Step 1: In Ones place digit, 0 is less than 8, so borrow 1 from the tens digit. Subtract the ones digit place, 10-8=2
Step 2: Now the tens digit will be 1. Subtract the tens digit place will be, 1-1=0
The hundreds place digit will be 3
Thus, 320-18=302
b.
Answer:
Step 1: Subtract the ones digit place, 5-3=2
Step 2: In tens place digit, 1 is less than 2, so borrow 1 from the tens digit. Subtract the tens digit place, 11-3=8
The hundreds place digit will be 6
Thus, 715-23=692
c.
Answer:
Step 1: In Ones place digit, 7 is less than 8, so borrow 1 from the tens digit. Subtract the ones digit place, 17-8=9
Step 2: Now the tens digit will be 7. Subtract the tens digit place, 7-7=0
The hundreds place digit is 2
Thus, 287-78=209
d.
Answer:
Step 1: In Ones place digit, 5 is less than 8, so borrow 1 from the tens digit. Subtract the ones digit place, 15-8=7
Step 2: Now the tens digit will be 4 which is less than 9, so borrow 1 from the hundreds digit. Subtract the hundreds digit place, 14-9=5
The hundreds place digit will be 4
Thus, 555-98=457
e.
Answer:
Step 1: In Ones place digit, 8 is less than 9, so borrow 1 from the hundreds digit as tens digit is 0. Now the tens digit will be 10.
Borrow 1 from tens place digit. Subtract the ones digit place, 18-9=9
Step 2: Subtract the tens digit place , 9-1=8
The hundreds place digit will be 3
Thus, 408-19=389
Question 10.
a.
Answer:
Step 1: In Ones place digit, 3 is less than 4 and in tens digit place 7 is less than 8. So borrow from the hundreds place digit.
Now the hundreds place digit will be 8, tens place digit will be 17.
Borrow 1 from tens place digit. Subtract the ones digit place, 13-4=9
Step 2: Now the tens place digit will be 16. Subtract the tens digit place , 16-8=8
Thus, 973-84=889
b.
Answer:
Step 1: In Ones place digit, 8 is less than 9 and in tens digit place 7 is less than 9. So borrow from the hundreds place digit.
Now the hundreds place digit will be 4, tens place digit will be 17.
Borrow 1 from tens place digit. Subtract the ones digit place, 18-9=9
Step 2: Now the tens place digit will be 16. Subtract the tens digit place , 16-9=7
Thus, 578-99=479
c.
Answer:
Step 1: In Ones place digit, 0 is less than 7 and in tens digit place 0 is less than 1. So borrow from the hundreds place digit.
Now the hundreds place digit will be 2, tens place digit will be 10.
Borrow 1 from tens place digit. Subtract the ones digit place, 10-7=3
Step 2: Now the tens place digit will be 9. Subtract the tens digit place , 9-1=8
Thus, 300-17=283
d.
Answer:
Step 1: Subtract the ones digit place, 2-0=2
Step 2: In tens place digit, 4 is less than 8. So borrow from the hundreds place digit.
Now the hundreds place digit will be 4. Subtract the tens digit place , 14-8=6
Thus, 542-80=462
e.
Answer:
Step 1: In Ones place digit, 3 is less than 4 and in tens digit place 6 is less than 7. So borrow from the hundreds place digit.
Now the hundreds place digit will be 5, tens place digit will be 16.
Borrow 1 from tens place digit. Subtract the ones digit place, 13-4=9
Step 2: Now the tens place digit will be 15. Subtract the tens digit place , 15-7=8
Thus, 663-74=589
Write each number in expanded form.
Question 11.
a. 732
Answer:
Step 1: Identify the place value of the given number using the place value chart.
Step 2: Multiply the given digit by its place value, 7×hundreds + 3×tens + 2×ones
Step 3: 7×100 + 3×10 + 2×1 = 700+30+2
b. 32,132
Answer:
Step 1: Identify the place value of the given number using the place value chart.
Step 2: Multiply the given digit by its place value, 3×Ten thousand + 2×thousand + 1×hundreds + 3×tens + 2×ones
Step 3: 3×10,000 + 2×1000 + 7×100 + 3×10 + 2×1 = 30,000+2,000+100+30+2
c. 4,790
Answer:
Step 1: Identify the place value of the given number using the place value chart.
Step 2: Multiply the given digit by its place value, 4×thousand + 7×hundreds + 9×tens + 0×ones
Step 3: 4×1000 + 7×100 + 9×10 + 0×1 = 4,000+700+90+0
Question 12.
a. 1,003
Answer:
Step 1: Identify the place value of the given number using the place value chart.
Step 2: Multiply the given digit by its place value, 1×thousand + 0×hundreds + 0×tens + 3×ones
Step 3: 1×1000 + 0×100 + 0×10 + 3×1 = 1,000+0+0+3
b. 2,314,732
Answer:
c. 3,001
Answer:
Step 1: Identify the place value of the given number using the place value chart.
Step 2: Multiply the given digit by its place value, 3×thousand + 0×hundreds + 0×tens + 1×ones
Step 3: 3×1000 + 0×100 + 0×10 + 1×1 = 3,000+0+0+1
Round each number to the place named.
Question 13.
a. 13,573
hundreds
Answer:
Given number is 5 digit number, the place values of digits are defined as shown below.
Thus, the hundred place digit is 5 or 5×100=500
b. 75,319
ten thousands
Answer:
Given number is 5 digit number, the place values of digits are defined as shown below.
Thus, the ten thousands place digit will be 7 or 7×10,000=70,000
c. 1,932,710
millions
Answer:
Given number is 7 digit number, the place values of digits are defined as shown below.
Thus, the millions place digit will be 1 or 1×1,000,000=1,000,000
Question 14.
a. 4,935
tens
Answer:
Given number is 4 digit number, the place values of digits are defined as shown below.
Thus, the tens place digit will be 3 or 3×10=30
b. 357,013
hundred thousand
Answer:
Given number is 6 digit number, the place values of digits are defined as shown below.
Thus, the hundred thousand place digit will be 3 or 3×100,000=300,000
c. 4,015
tens
Answer:
Given number is 4 digit number, the place values of digits are defined as shown below.
Thus, the hundred thousand place digit will be 1 or 1×10=10
Compare each pair of numbers. Write >, <, or =.
Question 15.
a. 13,702 _________ 13,207
Answer:
Here the given two numericals are of same digit numbers.
Start comparing with the left most digit or the hundreds place digit.
Comparing the hundreds place digit, 7 is greater than 2.
Therefore, 13,702 > 13,207
b. 3,976 _____________ 9,362
Answer:
Here the given two numericals are of same digit numbers.
Start comparing with the left most digit or the thousands place digit.
Comparing the hundreds place digit, 9 is greater than 3.
Therefore, 3,976 < 9,362
c. 932 _____________ 901
Answer:
Here the given two numericals are of same digit numbers.
Start comparing with the left most digit or the hundreds place digit.
Comparing the hundreds place digit, 3 is greater than 0.
Therefore, 932 > 901
Question 16.
a. 26,314 _____________ 260,314
Answer:
Here, the first number has 5 digits and second number has 6 digits.
Thus, the number with more digits is greater than the number with fewer digits.
Therefore, 26,314 < 260,314
b. 978 _____________ 978
Answer:
Here the given two numericals are of same digit numbers.
Start comparing with the left most digit. The given two numbers are same.
Therefore, 978 = 978
c. 3,721,460 ___________ 3,710,460
Answer:
Here the given two numericals are of same digit numbers.
Start comparing with the left most digit or the ten thousands place digit.
Therefore, 3,721,460 > 3,710,460
Add.
Question 17.
a.
Answer:
Add the digits in each place value.
Add the ones place numbers, 3+2=5. Now the ones place digit will be 5.
Add the tens place numbers, 0+7=7.Now the tens place digit will be 7.
Add the hundreds place numbers, 7+1=8. Now the hundreds place digit will be 8.
b.
Answer:
Add the digits in each place value.
Add the ones place numbers, 5+8=13. Now the ones place digit will be 3 and 1 will be carry forwaded to tens place.
Add the tens place numbers, 6+1+1=8. Now the tens place digit will be 8.
Add the hundreds place numbers, 6+1=7. Now the hundreds place digit will be 7.
c.
Answer:
Add the digits in each place value.
Add the ones place numbers, 3+5=8. Now the ones place digit will be 8.
Add the tens place numbers, 1+7=8. Now the tens place digit will be 8.
Add the hundreds place numbers, 7+3=10. Now the hundreds place digit will be 10.
d.
Answer:
Add the digits in each place value.
Add the ones place numbers, 1+0=1. Now the ones place digit will be 1.
Add the tens place numbers, 1+3=4. Now the tens place digit will be 4.
Add the hundreds place numbers, 5+4=9. Now the hundreds place digit will be 9.
e.
Answer:
Add the digits in each place value.
Add the ones place numbers, 0+9=9. Now the ones place digit will be 9.
Add the tens place numbers, 0+7=7. Now the tens place digit will be 7.
Add the hundreds place numbers, 3+4=7. Now the hundreds place digit will be 7.
Question 18.
a.
Answer:
Add the digits in each place value.
Add the ones place numbers, 4+8=12. Now the ones place digit will be 2 and 1 will be carry forwaded to tens place.
Add the tens place numbers, 1+1+1=3. Now the tens place digit will be 3.
Add the hundreds place numbers, 3+7=10. Now the hundreds place digit will be 0 and 1 will be carry forwaded to thousands place.
Thousands place digit will be 2+1=3
b.
Answer:
Add the ones place numbers, 5+5=10. Now the ones place digit will be 0 and 1 will be carry forwaded to tens place.
Add the tens place numbers, 2+2+1=5. Now the tens place digit will be 5.
Add the hundreds place numbers, 7+6=13. Now the hundreds place digit will be 3 and 1 will be carry forwaded to thousands place.
Thousands place digit will be 1+1=2
c.
Answer:
Add the ones place numbers, 1+5=6. Now the ones place digit will be 6.
Add the tens place numbers, 0+0=0. Now the tens place digit will be 0.
Add the hundreds place numbers, 2+4=6. Now the hundreds place digit will be 6.
Add the thousands place numbers, 3+1=4
d.
Answer:
Add the ones place numbers, 8+7=15. Now the ones place digit will be 5 and 1 will be carry forwaded to tens place.
Add the tens place numbers, 5+5+1=11. Now the tens place digit will be 1.
Add the hundreds place numbers, 3+7+1=11. Now the hundreds place digit will be 1 and 1 will be carry forwaded to thousands place.
Thousands place digit will be 7+1+1=9
e.
Answer:
Add the ones place numbers, 1+9=10. Now the ones place digit will be 0.
Add the tens place numbers, 0+0=0. Now the tens place digit will be 0.
Add the hundreds place numbers, 1+7=8. Now the hundreds place digit will be 8
Thousands place digit will be 8+1=9
Subtract.
Question 19.
a.
Answer:
Subtract the ones place number, 6-2=4.
Subtract the tens place number, 4-3=1.
Subtract the hundreds place number, 1-1=0.
Subtract the thousands place number, as 2 is less than 3, borrow from left most digit 3. After borrowing the thousands place will be 12, 12-3=9
Tens thousand place digit will be 2.
b.
Answer:
Subtract the ones place number, 5-5=0.
Subtract the tens place number, 1-0=1.
Subtract the hundreds place number, 3-3=0.
Subtract the thousands place number, 7-4=3
Subtract the tens thousands place number, 6-1=5
c.
Answer:
Subtract the ones place number, as 5 is less than 6, borrow from tens digit. After borrowing the ones place will be 15, 15-6=9
Now the tens place digit will be 8, subtract the tens place number, 8-8=0.
Subtract the hundreds place number, 1-1=0.
Subtract the thousands place number, as 0 is less than 9, borrow from tens thousand digit. After borrowing from the tens thousand place, the thousands place digit will be 10, 10-9=1
Now the ten thousands place will be 3.
d.
Answer:
Subtract the ones place number, 2-0=2
Subtract the tens place number, 3-3=0
Subtract the hundreds place number, 5-5=0
Subtract the thousands place number, 5-1=4
Subtract the tens thousands place number, 7-2=5
e.
Answer:
Subtract the ones place number, 9-2=7
Subtract the tens place number, 8-4=4
Subtract the hundreds place number, 7-6=1
Subtract the thousands place number, as 5 is less than 6, borrow from tens thousand digit. After borrowing from the tens thousand place, the thousands place digit will be 15, 15-6=9
Now the ten thousands place will be 1.
Question 20.
a.
Answer:
Subtract the ones place number, 5-4=1
Subtract the tens place number, 1-0=1
Subtract the hundreds place number, as 3 is less than 9, borrow from thousands digit. After borrowing from the thousands place, the thousands place digit will be 13, 13-9=4
Subtract the thousands place number, as 6 is less than 8, borrow from tens thousand digit. After borrowing from the tens thousand place, the thousands place digit will be 16, 16-8=8
Now the ten thousands place will be 0.
b.
Answer:
Subtract the ones place number, 9-9=0
Subtract the tens place number, 8-7=1
Subtract the hundreds place number, as 7 is less than 9, borrow from thousands digit. After borrowing from the left digit, the thousands place digit will be 17, 17-9=8
Now thousands place digit will be 7. Subtract the thousands place digit, 7-3=4.
Subtract the tens thousands place number, 9-7=2
c.
Answer:
As 4 is less than 9, borrow from hundreds digit. After borrowing from the hundreds place, the tens place digit will be 10. Borrow from tens digit now. Subtract the ones place number, 14-9=5
Subtract the tens place number, 9-0=9
Subtract the hundreds place number, 7-7=0
As 2 is less than 8, borrow from the left digit. Now the thousands place digit is 12. Subtract the thousands place digit, 12-8=4.
Now the tens place digit is 3. Subtract the tens thousands place number, 3-3=0
d.
Answer:
As 7 is less than 8, borrow from tens thousands digit. After borrowing, the tens thousands place digit will be 7.
The thousands place digit will be 16.
The hundreds place digit will be 17.
The tens place digit will be 18.
The ones place digit will be 17.
Subtract the ones place number, 17-8=9
Subtract the tens place number, 18-9=9
Subtract the hundreds place number, 17-8=9
Subtract the thousands place digit, 16-8=8
Subtract the tens thousands place number, 7-5=2
e.
Answer:
As 2 is less than 3, borrow from tens digit. After borrowing, the ones place digit will be 12. Subtract the ones place number, 12-3=9. Now the tens place digit will be 2.
As 2 is less than 8, borrow from hundreds digit. After borrowing, the tens place digit will be 13. Subtract the tens place number, 12-8=4. Now the hundreds place digit will be 8.
As 8 is less than 9, borrow from thousands digit. After borrowing, the hundreds place digit will be 18. Subtract the hundreds place number, 18-9=9. Now the thousands place digit will be 3.
As 3 is less than 7, borrow from tens thousands digit. After borrowing, the thousands place digit will be 13. Subtract the thousands place number, 13-7=6. Now the ten thousands place digit will be 2.
Subtract the hundreds place number, 2-1=1
Question 21.
a.
Answer:
As 4 is less than 8, borrow from tens digit. After borrowing, the ones place digit will be 14. Subtract the ones place number, 14-8=6. Now the tens place digit will be 5.
As 5 is less than 9, borrow from hundreds digit. After borrowing, the tens place digit will be 15. Subtract the tens place number, 15-9=6. Now the hundreds place digit will be 4.
Subtract the hundreds place number, 4-1=3
Subtract the thousands place digit, 2-2=0
b.
Answer:
Subtract the ones place number, 7-0=7
Subtract the tens place number, 9-1=8
As 3 is less than 8, borrow from thousands digit. After borrowing from the thousands place, the hundreds place digit will be 13, 13-8=5. Now the thousand place number will be 3.
Subtract the thousand place number, 3-2=1
c.
Answer:
As 2 is less than 5, borrow from hundreds digit. Now the hundreds place digit will be 6 and tens place digit will be 10. After borrowing, the ones place digit will be 12. Subtract the ones place number, 12-5=7. Now the tens place digit will be 9.
Subtract the tens place digit number, 9-1=8
Subtract the hundred place digit number, 6-6=0
d.
Answer:
Subtract the ones place digit, 4-3=1
As 8 is less than 9, borrow from thousands place. Now the hundreds place digit will be 10. Borrow from hundreds place and tens place digit will be 18, subtract tens place digit, 18-9=9.
Now the tens place digit will be 9, 9-0=9
The thousands place digit will be 1. Borrow from ten thousands place. Subtract the thousands place digit, 11-8=3
Subtract the ten thousands place, 2-1=1
e.
Answer:
Subtract the ones place digit, 7-2=5
Borrow from the thousands place, now the thousands place digit will be 8, hundreds place digit will be 13.
Borrow from the hundreds place, now the tens place digit will be 12, subtract the tens digit number, 12-5=7
Subtract the hundreds place digit, 12-4=8
The thousands place digit will be 8.
Add.
Question 22.
a.
Answer:
Add the ones place numbers, 2+4+4=10. Now the ones place digit will be 0 and 1 will be carry forwaded to tens digit.
Add the tens place numbers, 1+3+1+0=5. Now the tens place digit will be 5.
Add the hundreds place numbers, 1+7+3=11. Now the hundreds place digit will be 1 and 1 will be carry forwaded to tens digit.
Thousands place digit will be 4+1=5
b.
Answer:
Add the ones place numbers, 5+2=7
Add the tens place numbers, 1+3=4
Add the hundreds place numbers, 0+9=9
Add the thousands place numbers, 2+7=9
c.
Answer:
Add the ones place numbers, 5+0+5=10. Now the ones place digit will be 0 and 1 will be carry forwaded to tens digit.
Add the tens place numbers, 1+3+4+1=9
Add the hundreds place numbers, 2+7+0=9
Add the thousands place numbers, 8+1+1=10
d.
Answer:
Add the ones place numbers, 3+6=9
Add the tens place numbers, 1+4=5
Add the hundreds place numbers, 7+8=15. Now the hundreds place digit will be 5 and 1 will be carry forwaded to thousands digit.
Add the thousands place numbers, 5+3+1=9
Add the ten thousands place numbers, 2+1=3
e.
Answer:
Add the ones place numbers, 4+6+0=10. Now the ones place digit will be 0 and 1 will be carry forwaded to tens digit.
Add the tens place numbers, 1+4+1+1=7
Add the hundreds place numbers, 0+2+7=9
Add the thousands place numbers, 3+1=4
Question 23.
a.
Answer:
Add the ones place numbers, 8+2=10. Now the ones place digit will be 0 and 1 will be carry forwaded to tens digit.
Add the tens place numbers, 4+6+1=11. Now the tens place digit will be 0 and 1 will be carry forwaded to hundreds digit.
Add the hundreds place numbers, 5+1+1=7
Add the thousands place numbers, 3+8=11. Now the thousands place digit will be 1 and 1 will be carry forwaded to ten thousands digit.
Add the ten thousands place number, 8+1=9
b.
Answer:
Add the ones place numbers, 5+5+0+4=14. Now the ones place digit will be 4 and 1 will be carry forwaded to tens digit.
Add the tens place numbers, 1+1+2+1+1=6
Add the hundreds place numbers, 3+2+7+2=14. Now the hundreds place digit will be 4 and 1 will be carry forwaded to tens digit.
Add the thousands place numbers, 2+1+1=4
c.
Answer:
Add the ones place numbers, 5+5=10. Now the ones place digit will be 0 and 1 will be carry forwaded to tens digit.
Add the tens place numbers, 0+2+1=3
Add the hundreds place numbers, 8+1=9
Add the thousands place numbers, 7+2=9
Add the ten thousands place numbers, 3+1=4
d.
Answer:
Add the ones place numbers, 0+5+3+0=8
Add the tens place numbers, 0+1+4+2=7
Add the hundreds place numbers, 3+7+2+1=13. Now the hundreds place digit will be 3 and 1 will be carry forwaded to thousands digit.
Add the thousands place numbers, 7+1=8
e.
Answer:
Add the ones place numbers, 2+5=7
Add the tens place numbers, 4+2=6
Add the hundreds place numbers, 0+9=9
Add the thousands place numbers, 1+8=9
Question 24.
a.
Answer:
Add the ones place numbers, 4+3=7
Add the tens place numbers, 1+9=10. Now the tens place digit will be 3 and 1 will be carry forwaded to hundreds digit.
Add the hundreds place numbers, 6+2+1=9
Add the thousands place numbers, 5+3=8
b.
Answer:
Add the ones place numbers, 7+5=12. Now the ones place digit will be 2 and 1 will be carry forwaded to tens digit.
Add the tens place numbers, 1+1+1=3.
Add the hundreds place numbers, 4+8=12. Now the hundreds place digit will be 2 and 1 will be carry forwaded to thousands digit.
Add the thousands place numbers, 6+2+1=9
c.
Answer:
Add the ones place numbers, 2+2=4.
Add the tens place numbers, 3+1=4.
Add the hundreds place numbers, 9+5=14. Now the hundreds place digit will be 4 and 1 will be carry forwaded to thousands digit.
Add the thousands place numbers, 4+1=5
d.
Answer:
Add the ones place numbers, 5+6=11. Now the ones place digit will be 1 and 1 will be carry forwaded to tens digit.
Add the tens place numbers, 6+4+1=11. Now the tens place digit will be 1 and 1 will be carry forwaded to hundreds digit.
Add the hundreds place numbers, 7+0+1=8.
Add the thousands place numbers, 8+2=10
Add the ten thousands place numbers, 0+1=1
e.
Answer:
Add the ones place numbers, 9+2=11. Now the ones place digit will be 1 and 1 will be carry forwaded to tens digit.
Add the tens place numbers, 5+1+1=7.
Add the hundreds place numbers, 0+7=7.
Add the thousands place numbers, 5+8=13. Now the thousands place digit will be 1 and 1 will be carry forwaded to ten thousands digit.
Add the ten thousands place numbers, 4+3+1=8
Multiply.
Question 25.
a.
Answer:
Here, 7 is multiplied by 8.
7 times 8 equals to 56.
b.
Answer:
Here, 9 is multiplied by 4.
9 times 4 equals to 36.
c.
Answer:
Here, 7 is multiplied by 4.
7 times 4 equals to 28.
d.
Answer:
Here, 8 is multiplied by 6.
8 times 6 equals to 48.
e.
Answer:
Multiply 4 with ones place digit, 4×1=4. Thus, ones place digit will be 4.
Multiply 4 with tens place digit, 4×2=8. Thus, tens place digit will be 8.
Therefore, 21 multiplied by 4 will be 84.
Question 26.
a.
Answer:
Multiply 3 with ones place digit, 3×2=6. Thus, ones place digit will be 6.
Multiply 3 with tens place digit, 3×3=9. Thus, tens place digit will be 9.
Therefore, 32 multiplied by 3 will be 96.
b.
Answer:
Multiply 2 with ones place digit, 2×4=8. Thus, ones place digit will be 8.
Multiply 2 with tens place digit, 2×1=2. Thus, tens place digit will be 2.
Therefore, 14 multiplied by 2 will be 28.
c.
Answer:
Multiply 4 with ones place digit, 4×2=8. Thus, ones place digit will be 8.
Multiply 4 with tens place digit, 4×2=8. Thus, tens place digit will be 8.
Therefore, 44 multiplied by 2 will be 88.
d.
Answer:
Multiply 4 with ones place digit, 4×2=8. Thus, ones place digit will be 8.
Multiply 4 with tens place digit, 4×1=4. Thus, tens place digit will be 4.
Therefore, 12 multiplied by 4 will be 48.
e.
Answer:
Multiply 4 with ones place digit, 4×0=0. Thus, ones place digit will be 0.
Multiply 4 with tens place digit, 4×2=8. Thus, tens place digit will be 8.
Therefore, 20 multiplied by 4 will be 80.
Question 27.
a.
Answer:
Multiply 7 with ones place digit, 7×2=14. Thus, ones place digit will be 4 and 1 will be carry forwaded to tens place.
Multiply 7 with tens place digit, 7×3=21. Tens place digit will be 21+1=22.
Therefore, 32 multiplied by 7 will be 224.
b.
Answer:
Multiply 3 with ones place digit, 3×7=21. Thus, ones place digit will be 1 and 2 will be carry forwaded to tens place.
Multiply 3 with tens place digit, 3×4=12. Tens place digit will be 12+2=14.
Therefore, 47 multiplied by 3 will be 141.
c.
Answer:
Multiply 8 with ones place digit, 8×1=8. Thus, ones place digit will be 8.
Multiply 8 with tens place digit, 8×2=16. Tens place digit will be 16.
Therefore, 21 multiplied by 8 will be 168.
d.
Answer:
Multiply 9 with ones place digit, 9×0=0. Thus, ones place digit will be 0.
Multiply 8 with tens place digit, 9×4=36. Tens place digit will be 36.
Therefore, 40 multiplied by 9 will be 360.
e.
Answer:
Multiply 9 with ones place digit, 9×7=63. Thus, ones place digit will be 3 and 6 will be carry forwaded to tens place.
Multiply 9 with tens place digit, 9×1=9. Tens place digit will be 9+6=15.
Therefore, 17 multiplied by 9 will be 153.
Question 28.
a.
Answer:
Multiply 7 with ones place digit, 7×8=56. Thus, ones place digit will be 6 and 5 will be carry forwaded to tens place.
Multiply 7 with tens place digit, 7×4=28. Tens place digit will be 28+5=33.
Therefore, 48 multiplied by 7 will be 336.
b.
Answer:
Multiply 8 with ones place digit, 8×2=16. Thus, ones place digit will be 6 and 1 will be carry forwaded to tens place.
Multiply 8 with tens place digit, 8×7=56. Tens place digit will be 56+1=57.
Therefore, 72 multiplied by 8 will be 576.
c.
Answer:
Multiply 4 with ones place digit, 4×4=16. Thus, ones place digit will be 6 and 1 will be carry forwaded to tens place.
Multiply 4 with tens place digit, 4×8=32. Tens place digit will be 32+1=33.
Therefore, 84 multiplied by 4 will be 336.
d.
Answer:
Multiply 7 with ones place digit, 7×5=35. Thus, ones place digit will be 5 and 3 will be carry forwaded to tens place.
Multiply 7 with tens place digit, 7×2=14. Tens place digit will be 14+3=17.
Therefore, 25 multiplied by 7 will be 175.
e.
Answer:
Multiply 9 with ones place digit, 9×9=81. Thus, ones place digit will be 1 and 8 will be carry forwaded to tens place.
Multiply 9 with tens place digit, 9×4=36. Tens place digit will be 36+8=44.
Therefore, 49 multiplied by 9 will be 441.
Question 29.
a.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 0 × 11 = 00.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 11. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 00 + 110 = 110.
b.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 1 × 22 = 22.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 22. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 22 + 220 = 242.
c.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 2 × 31 = 62.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 93. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 62 + 930 = 992.
d.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 0 × 43 = 00.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 86. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 00 + 860 = 860.
e.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 0 × 50 = 00.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 50. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 00 + 500 = 500.
f.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 0 × 31 = 00.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 63. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 00 + 630 = 630.
Question 30.
a.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 5 × 75 = 375.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 150. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 375 + 1500 = 1875.
b.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 8 × 32 = 256.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 32. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 256 + 320 = 576.
c.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 1 × 132 = 132.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 528. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 132 + 5280 = 5412.
d.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 7 × 81 = 567.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 2430. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 567 + 2430 = 2997.
e.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 7 × 103 = 721.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 103. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 721 + 1030 = 1751.
f.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 8 × 282 = 2256.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 3×282=846. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 2256+ 8460= 10716.
Question 31.
a.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 5 × 418= 2090.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 4×418=1672. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 2090+ 16720= 18810.
b.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 2 × 500 = 1000.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 3×500=1500. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 1000+ 15000= 16000.
c.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 7 × 199 = 1393.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 4 × 199 = 796. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 1393 + 7960 = 9353.
d.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 3 × 578 = 1734.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 2×578 =1156. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 1734+ 11560 = 13294.
e.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 2 × 887 = 1774.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 5 × 887 = 4435. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 1774+ 44350 = 46124.
f.
Answer:
Step 1: Arrange the numbers vertically according to the place value.
Step 2: Multiply the ones digit of the multiplier with the multiplicand. Here, it is 3 × 399 = 3591.
Step 3: Place a zero below the ones digit of the partial product.
Step 4: Multiply the tens digit of the multiplier with the multiplicand. This will be 1×399=399. Place this next to the 0 below the partial product.
Step 5: Add the two products to get the final product. Here, 3591+ 3990 = 7581.
Divide.
Question 32.
a.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: 81 is divisible by 9, as we know that 9 × 9 = 81 so, we go for it.
Step 3: Write 9 in the quotient.
Check:
Do the inverse operation to check your answer.
If 81 ÷ 9 = 9, then 9 × 9 = 81 must be true.
b.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: 56 is divisible by 7, as we know that 7 × 8 = 56 so, we go for it.
Step 3: Write 8 in the quotient.
Check:
Do the inverse operation to check your answer.
If 56 ÷ 7 = 8, then 7 × 8 = 56 must be true.
c.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: 48 is divisible by 8, as we know that 8 × 6 = 48 so, we go for it.
Step 3: Write 6 in the quotient.
Check:
Do the inverse operation to check your answer.
If 48 ÷ 8 = 6, then 8 × 6 = 48 must be true.
d.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: 64 is divisible by 8, as we know that 8 × 8 = 64 so, we go for it.
Step 3: Write 8 in the quotient.
Check:
Do the inverse operation to check your answer.
If 64 ÷ 8 = 6, then 8 × 8 = 64 must be true.
e.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: 42 is divisible by 7, as we know that 7 × 6 = 42 so, we go for it.
Step 3: Write 6 in the quotient.
Check:
Do the inverse operation to check your answer.
If 42 ÷ 7 = 6, then 7 × 6 = 42 must be true.
Question 33.
a.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: 24 is divisible by 8, as we know that 8 × 3 = 24 so, we go for it.
Step 3: Write 3 in the quotient.
Check:
Do the inverse operation to check your answer.
If 24 ÷ 8 = 3, then 8 × 3 = 24 must be true.
b.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: 35 is divisible by 5, as we know that 5 × 7 = 35 so, we go for it.
Step 3: Write 7 in the quotient.
Check:
Do the inverse operation to check your answer.
If 35 ÷ 5 = 7, then 5 × 7 = 35 must be true.
c.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: 28 is divisible by 7, as we know that 7 × 4 = 28 so, we go for it.
Step 3: Write 4 in the quotient.
Check:
Do the inverse operation to check your answer.
If 28 ÷ 7 = 4, then 7 × 4 = 28 must be true.
d.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: 54 is divisible by 6, as we know that 6 × 9 = 54 so, we go for it.
Step 3: Write 9 in the quotient.
Check:
Do the inverse operation to check your answer.
If 54 ÷ 6 = 9, then 6 × 9 = 54 must be true.
e.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: 90 is divisible by 9, as we know that 9 × 10 = 90 so, we go for it.
Step 3: Write 9 in the quotient.
Check:
Do the inverse operation to check your answer.
If 90 ÷ 9 = 9, then 9 × 10 = 90 must be true.
Question 34.
a.
Answer:
Step 1: Divide the first figit of dividend by divisor, 3 is divisble by 3. We know that 3×1=3.
Step 2: Write 1 in the quotient. Next dividend is 0, we know that 3×0=0.
Step 3: Write 0’s in the quotient.
Step 4: Thus, the quotient will be 100 and remainder will be 0.
b.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 2 × 3 = 6 so, we go for it. Write 3 in the quotient.
Step 2: Now, the dividend will be 4, it is divisible by 2, as we know that 2 × 2 = 4 so, we go for it.
Step 3: Write 2 in the quotient. Next dividend will be 2, we know that 2 × 1 = 2 so, we go for it.
Step 4: Thus, 0 is the remainder and 321 is the quotient.
c.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 7 × 1 = 7 so, we go for it. Write 1 in the quotient.
Step 2: Now, the dividend will be 2, which is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 3: So, we have 21 as the new dividend. Write 0 in the quotient. We know that 7 × 3 = 21. so, we go for it.
Step 4: Write 3 in the quotient. Now the quotient will be 103. Thus, 0 will be the remainder.
d.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 4 × 1 = 4 so, we go for it. Write 1 in the quotient.
Step 2: Now, the dividend will be 8, it is divisible by 4, as we know that 4 × 2 = 8 so, we go for it.
Step 3: Write 2 in the quotient. Next dividend will be 4, we know that 4 × 1 = 4 so, we go for it.
Step 4: Thus, 0 is the remainder and 121 is the quotient.
e.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 8 × 1 = 8 so, we go for it. Write 1 in the quotient.
Step 2: Now, the dividend will be 6, which is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 3: So, we have 64 as the new dividend. Write 0 in the quotient. We know that 8 × 8 = 64. so, we go for it.
Step 4: Write 8 in the quotient. Now the quotient will be 108. Thus, 0 will be the remainder.
Question 35.
a.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: Now, the dividend will be 72, we know that 8×9=72. Write 9 in the quotient.
Step 3: So, we have 4 as the new dividend, which is less than the divisor.
Step 4: So, write 0 in the quotient. Now the quotient will be 90. Thus, 4 will be the remainder.
b.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: Now, the dividend will be 63, we know that 7×9=63. Write 9 in the quotient.
Step 3: So, we have 9 as the new dividend, we now that 7×1=7, subtract 9-7=2.
Step 4: So, write 1 in the quotient. Now the quotient will be 91. Thus, 2 will be the remainder.
c.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 5 × 1 = 5 so, we go for it. Write 1 in the quotient.
Step 2: Now, the dividend will be 2, which is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 3: So, we have 25 as the new dividend. Write 0 in the quotient. We know that 5 × 5 = 25. so, we go for it.
Step 4: Write 5 in the quotient. Now the quotient will be 105. Thus, 0 will be the remainder.
d.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: Now, the dividend will be 24, it is divisible by 6, as we know that 6 × 4 = 24 so, we go for it.
Step 3: Write 4 in the quotient. So, we have 7 as the new dividend. We know that 6 × 1 = 6. so, we go for it.
Step 4: Write 1 in the quotient. Now the quotient will be 41. Subtract 7-6=1. Thus, 1 will be the remainder.
e.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 2 × 4 = 8 so, we go for it. Write 4 in the quotient.
Step 2: Now, the dividend will be 7, as we know that 2 × 3 = 6 so, we go for it.
Step 3: Write 3 in the quotient. Subtract 7-6=1. Bring down the next digit. So, we have 16 as the new dividend. We know that 2 × 8 = 16. so, we go for it.
Step 4: Write 8 in the quotient. Now the quotient will be 438. Subtract 16-16=0. Thus, 0 will be the remainder.
Question 36.
a.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: Now, the dividend will be 45, it is divisible by 9, as we know that 9 × 5 = 45 so, we go for it.
Step 3: Write 5 in the quotient. So, we have 8 as the new dividend. 8 is less than 9. So write 8 in the remainder.
Step 4: Write 0 in the quotient. Now the quotient will be 90.
b.
Answer:
Step 1:The first digit of the dividend is divisible by the divisor, as we know that 7 × 1 = 7 so, we go for it. Write 1 in the quotient.
Step 2: Now, the dividend will be 12, write 1 in the quotient. as we know that 7 × 1 = 7 so, we go for it. Write 1 in the quotient. Subtract 12-7=5.
Step 3: Now, the dividend will be 50. As we know that 7 × 7 = 49 so, we go for it. Write 7 in the quotient. Subtract 50-49=1.
Step 3: So, we have 17 as the new dividend. We know that 7 × 2 = 14. so, we go for it. Subtract 17-14=3.
Step 4: Write 2 in the quotient. Now the quotient will be 1172. Thus, 3 will be the remainder.
c.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 6 × 1 = 6 so, we go for it. Write 1 in the quotient.
Step 2: Now, the dividend will be 8, as we know that 6 × 1 = 6 so, we go for it.
Step 3: Write 1 in the quotient. Subtract 8-6=2. So, we have 24 as the new dividend. We know that 6 × 4 = 24. so, we go for it.
Step 4: Write 4 in the quotient. Now the quotient will be 114. Thus, 0 will be the remainder.
d.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 3 × 3 = 9 so, we go for it. Write 3 in the quotient.
Step 2: Now, the dividend will be 4, as we know that 3 × 1 = 3 so, we go for it.
Step 3: Write 1 in the quotient. Subtract 4-3=1. Bring down the next digit. So, we have 19 as the new dividend. We know that 3 × 6 = 18. so, we go for it. Subtract 19-18=1.
Step 4: Write 6 in the quotient. Now the quotient will be 316. Thus, 1 will be the remainder.
e.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 4 × 1 = 4 so, we go for it. Write 1 in the quotient. Subtract 7-4=3.
Step 2: Now, the dividend will be 31. We know that 4 × 7 = 28. so, we go for it. Subtract 31-28=3.
Step 3: Write 7 in the quotient. We know that 4 × 8 = 32. so, we go for it. Subtract 33-32=1.
Step 4: Write 8 in the quotient. Now the quotient will be 178. Thus, 1 will be the remainder.
Question 37.
a.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 9 × 1 = 9 so, we go for it. Write 1 in the quotient. Subtract 9-9=0.
Step 2: Now, the dividend will be 0, which is less than 9. So bring down the next digit.
Step 3: Now, the dividend will be 8, which is less than 9. Write 0 in the quotient.
Step 4: Now the quotient will be 100. Thus, 8 will be the remainder.
b.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 2 × 2 = 4 so, we go for it. Write 2 in the quotient. Subtract 5-4=1.
Step 2: Now, the dividend will be 1, which is less than 2. So bring down the next digit.
Step 3: Now, the dividend will be 11, as we know that 2 × 5 = 10 so, we go for it. Write 5 in the quotient. Subtract 11-10=1.
Step 4: Now the dividend will be 10, as we know that 2 × 5 = 10 so, we go for it. Write 5 in the quotient. Subtract 10-10=0.
Now the quotient will be 255. Thus 0 will be the remainder.
c.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 4 × 1 = 4 so, we go for it. Write 1 in the quotient. Subtract 6-4=2.
Step 2: Now, the dividend will be 2, which is less than 2. So bring down the next digit.
Step 3: Now, the dividend will be 24, as we know that 4 × 6 = 24 so, we go for it. Write 6 in the quotient. Subtract 24-24=0.
Step 4: Now the dividend will be 8, as we know that 4 × 2 = 8 so, we go for it. Write 2 in the quotient. Subtract 8-8=0.
Step 5: Now the dividend will be 1, which is less than 4. Thus 1 will be the remainder and 1620 will be the quotient.
d.
Answer:
Step 1: The first digit of the dividend is divisible by the divisor, as we know that 8 × 1 = 8 so, we go for it. Write 1 in the quotient. Subtract 8-8=0.
Step 2: Now, the dividend will be 0, as we know that 8 × 1 = 8 so, we go for it. Write 1 in the quotient. Subtract 8-8=0.
Step 3: Now, the dividend will be 0, as we know that 8 × 1 = 8 so, we go for it. Write 1 in the quotient. Subtract 8-8=0.
Step 4: Now the quotient will be 111. Thus 0 will be the remainder.
e.
Answer:
Step 1: Since the first digit of the dividend is less than the divisor, bring down the next digit of the dividend. Now consider the first 2 digits to proceed with the division.
Step 2: Now, the dividend will be 44, as we know that 6 × 7 = 42 so, we go for it.
Step 3: Write 7 in the quotient. Subtract 44-42=2. Bring down the next digit. So, we have 25 as the new dividend. We know that 6 × 4 = 24. so, we go for it.
Step 4: Subtract 25-24=1. Now the quotient will be 74 and remainder will be 1.
Solve each problem. Show your work.
Question 38.
A total of 68 hikers went on a trip to Blue Hill Mountain. If 32 of the hikers were boys, how many hikers were girls?
____________ hikers were girls.
Answer:
Given that: A total of 68 hikers went on a trip to Blue Hill Mountain. If 32 of the hikers were boys.
To get the count of girls hikers subtract 68-32=36
Thus, we can say 36 hikers were girls.
Question 39.
On a trip to Washington, DC, there were 33 Fifth-graders and 27 fourth-graders. How many students were on the trip?
There were _____________ students on the trip.
Answer:
Given that: On a trip to Washington, DC, there were 33 Fifth-graders and 27 fourth-graders.
To get the total number of students, add 33+27=60
There were 60 students on the trip.
Question 40.
At the picnic grove, bird watchers saw 42 robins looking for worms. If there were 5 times as many starlings as robins, how many starlings were there?
There were _____________ starlings.
Answer:
Given that: At the picnic grove, bird watchers saw 42 robins looking for worms. If there were 5 times as many starlings as robins.
To get the total number of starlings, multiply 42×5=210
There were 210 starlings.
Question 41.
A group of friends is getting ready for a hike at night. Each of their flashlights take 4 batteries. If they have 72 batteries, how many flashlights can they take?
They can take ______________ flashlights.
Answer:
Given that: A group of friends is getting ready for a hike at night. Each of their flashlights take 4 batteries and they have 72 batteries.
To get the number of flashlights, divide 72÷4=18
They can take 18 flashlights.
Question 42.
There are 21 members of the soccer team on the bus. If each player carries on 4 pieces of equipment, how many pieces of equipment are on the bus?
There are ______________ pieces of equipment on the bus.
Answer:
Given that: There are 21 members of the soccer team on the bus. If each player carries on 4 pieces of equipment.
To know the pieces of equipment on the bus, multiply 21×4=84
There are 84 pieces of equipment on the bus.
Question 43.
At the high school, all textbooks must be turned in at the end of the year. There are 150 science books, 125 math books, and 107 Spanish books. How many books will be turned in?
_____________ books will be turned in.
Answer:
Given that: At the high school, all textbooks must be turned in at the end of the year. There are 150 science books, 125 math books, and 107 Spanish books.
To get the books to be turned in, add 150+125+107=382
382 books will be turned in.
