This handy Spectrum Math Grade 4 Answer Key Chapter 6 Lesson 6.5 Subtracting Fractions with Like Denominators provides detailed answers for the workbook questions.
Spectrum Math Grade 4 Chapter 6 Lesson 6.5 Subtracting Fractions with Like Denominators Answers Key
Subtract the numerators.
\(\frac{7}{12}\) – \(\frac{5}{12}\) = \(\frac{7-5}{12}\) = \(\frac{2}{12}\)
Write the difference over the common denominator.
Subtract.
Question 1.
a.
Answer:
\(\frac{8}{12}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{11}{12}\) – \(\frac{3}{12}\) = \(\frac{11-3}{12}\) = \(\frac{8}{12}\)
Write the difference over the common denominator as shown above.
b.
Answer:
\(\frac{4}{10}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{7}{10}\) – \(\frac{3}{10}\) = \(\frac{7-3}{10}\) = \(\frac{4}{10}\)
Write the difference over the common denominator as shown above.
c.
Answer:
\(\frac{2}{4}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{3}{4}\) – \(\frac{1}{4}\) = \(\frac{3-1}{4}\) = \(\frac{2}{4}\)
Write the difference over the common denominator as shown above.
d.
Answer:
\(\frac{1}{7}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{6}{7}\) – \(\frac{5}{7}\) = \(\frac{6-5}{7}\) = \(\frac{1}{7}\)
Write the difference over the common denominator as shown above.
e.
Answer:
\(\frac{1}{5}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{4}{5}\) – \(\frac{3}{5}\) = \(\frac{4-3}{5}\) = \(\frac{1}{5}\)
Write the difference over the common denominator as shown above.
Question 2.
a.
Answer:
\(\frac{2}{10}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{5}{10}\) – \(\frac{3}{10}\) = \(\frac{5-3}{10}\) = \(\frac{2}{10}\)
Write the difference over the common denominator as shown above.
b.
Answer:
\(\frac{1}{12}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{8}{12}\) – \(\frac{7}{12}\) = \(\frac{8-7}{12}\) = \(\frac{1}{12}\)
Write the difference over the common denominator as shown above.
c.
Answer:
\(\frac{2}{5}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{4}{5}\) – \(\frac{2}{5}\) = \(\frac{4-2}{5}\) = \(\frac{2}{5}\)
Write the difference over the common denominator as shown above.
d.
Answer:
\(\frac{3}{10}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{7}{10}\) – \(\frac{4}{10}\) = \(\frac{7-4}{10}\) = \(\frac{3}{10}\)
Write the difference over the common denominator as shown above.
e.
Answer:
\(\frac{4}{8}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{5}{8}\) – \(\frac{1}{8}\) = \(\frac{5-1}{8}\) = \(\frac{4}{8}\)
Write the difference over the common denominator as shown above.
Question 3.
a.
Answer:
\(\frac{6}{10}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{9}{10}\) – \(\frac{3}{10}\) = \(\frac{9-3}{10}\) = \(\frac{6}{10}\)
Write the difference over the common denominator as shown above.
b.
Answer:
\(\frac{2}{11}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{7}{11}\) – \(\frac{5}{11}\) = \(\frac{7-5}{11}\) = \(\frac{2}{11}\)
Write the difference over the common denominator as shown above.
c.
Answer:
\(\frac{7}{9}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{8}{9}\) – \(\frac{1}{9}\) = \(\frac{8-1}{9}\) = \(\frac{7}{9}\)
Write the difference over the common denominator as shown above.
d.
Answer:
\(\frac{2}{5}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{4}{5}\) – \(\frac{2}{5}\) = \(\frac{4-2}{5}\) = \(\frac{2}{5}\)
Write the difference over the common denominator as shown above.
e.
Answer:
\(\frac{2}{9}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{8}{9}\) – \(\frac{6}{9}\) = \(\frac{8-6}{9}\) = \(\frac{2}{9}\)
Write the difference over the common denominator as shown above.
Question 4.
a. \(\frac{5}{7}\) – \(\frac{3}{7}\) = _______________
Answer:
\(\frac{2}{7}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{5}{7}\) – \(\frac{3}{7}\) = \(\frac{5-3}{7}\) = \(\frac{2}{7}\)
Write the difference over the common denominator as shown above.
b. \(\frac{7}{12}\) – \(\frac{3}{12}\) = _______________
Answer:
\(\frac{4}{12}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{7}{12}\) – \(\frac{3}{12}\) = \(\frac{7-3}{12}\) = \(\frac{4}{12}\)
Write the difference over the common denominator as shown above.
c. \(\frac{8}{9}\) – \(\frac{8}{9}\) = _______________
Answer:
\(\frac{0}{9}\) = 0
Explanation:
When denominators are same, subtract the numerators.
\(\frac{8}{9}\) – \(\frac{8}{9}\) = \(\frac{8-8}{9}\) = \(\frac{0}{9}\) = 0
Write the difference over the common denominator as shown above.
d. \(\frac{12}{12}\) – \(\frac{8}{12}\) = _______________
Answer:
\(\frac{4}{12}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{12}{12}\) – \(\frac{8}{12}\) = \(\frac{12-8}{12}\) = \(\frac{4}{12}\)
Write the difference over the common denominator as shown above.
Question 5.
a. \(\frac{9}{12}\) – \(\frac{7}{12}\) = _______________
Answer:
\(\frac{2}{12}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{9}{12}\) – \(\frac{7}{12}\) = \(\frac{9-7}{12}\) = \(\frac{2}{12}\)
Write the difference over the common denominator as shown above.
b. \(\frac{4}{4}\) – \(\frac{3}{4}\) = _______________
Answer:
\(\frac{1}{4}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{4}{4}\) – \(\frac{3}{4}\) = \(\frac{4-3}{4}\) = \(\frac{1}{4}\)
Write the difference over the common denominator as shown above.
c. \(\frac{9}{10}\) – \(\frac{7}{10}\) = _______________
Answer:
\(\frac{2}{10}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{9}{10}\) – \(\frac{7}{10}\) = \(\frac{9-7}{10}\) = \(\frac{2}{10}\)
Write the difference over the common denominator as shown above.
d. \(\frac{3}{3}\) – \(\frac{1}{3}\) = _______________
Answer:
\(\frac{2}{3}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{3}{3}\) – \(\frac{1}{3}\) = \(\frac{3-1}{3}\) = \(\frac{2}{3}\)
Write the difference over the common denominator as shown above.
Question 6.
a. \(\frac{5}{8}\) – \(\frac{1}{8}\) = _______________
Answer:
\(\frac{4}{8}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{5}{8}\) – \(\frac{1}{8}\) = \(\frac{5-1}{8}\) = \(\frac{4}{8}\)
Write the difference over the common denominator as shown above.
b. \(\frac{6}{7}\) – \(\frac{5}{7}\) = _______________
Answer:
\(\frac{1}{7}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{6}{7}\) – \(\frac{5}{7}\) = \(\frac{6-5}{7}\) = \(\frac{1}{7}\)
Write the difference over the common denominator as shown above.
c. \(\frac{11}{12}\) – \(\frac{8}{12}\) = _______________
Answer:
\(\frac{3}{12}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{11}{12}\) – \(\frac{8}{12}\) = \(\frac{11-8}{12}\) = \(\frac{3}{12}\)
Write the difference over the common denominator as shown above.
d. \(\frac{7}{10}\) – \(\frac{0}{10}\) = _______________
Answer:
\(\frac{7}{10}\)
Explanation:
When denominators are same, subtract the numerators.
\(\frac{7}{10}\) – \(\frac{0}{10}\) = \(\frac{7-0}{10}\) = \(\frac{7}{10}\)
Write the difference over the common denominator as shown above.