All the solutions provided in McGraw Hill My Math Grade 4 Answer Key PDF Chapter 5 Check My Progress will give you a clear idea of the concepts.
McGraw-Hill My Math Grade 4 Chapter 5 Check My Progress Answer Key
Check My Progress Page No. 291-292
Vocabulary Check
Question 1.
The Commutative Property of Multiplication states that the order in which two numbers are multiplied does not change the product. Provide an example below.
Answer: The commutative property of multiplication example is,
The numbers are 4 x 3 and 3 x 4.
This property states that the order in which two numbers are multiplied does not change the product.
So, the values is , 4 x 3 = 3 x 4
12 = 12.
Hence, it is a Commutative Property.
Question 2.
The Associative Property of Multiplication states that the grouping of factors does not change the product. Provide an example below.
Answer: The Associative property of multiplication example is,
The numbers are 2 x (2 x 4) = (2 x 2) x 4
This property states that the grouping of factors does not change the product
So, the values is , 2 x (2 x 4) = (2 x 2) x 4
16 = 16.
Hence, it is an Associative Property.
Question 3.
An estimate is an answer that is close to the exact answer. Provide an example below.
Answer: A example of the estimate is 365 × 24. Round 365 to the nearest hundred, and 24 to the nearest ten. So 365 ≈ 400, and 24 ≈ 20. Then 365 × 24 ≈ 400 × 20 = 8000. The actual value is 8760 and the estimated value is 8000.
Concept Check
Multiply.
Question 4.
Answer: 1140
Explanation: Given the values are 38 and 30.
Now, we will find the multiplication value.
Below is the process,
After multiplication, the product value is 1140.
Question 5.
Answer: 1040
Explanation: Given the values are 52 and 20.
Now, we will find the multiplication value.
The multiplication process is below,
Hence, after multiplication, the product value is 1040.
Question 6.
Answer: 470
Explanation: Given the values 47 and 10.
Now, we will find the multiplication value.
The multiplication process is below,
Therefore, the product of the given values is 470.
Estimate.
Question 7.
Answer: The estimated product value is 600.
Explanation: Given the values are 15 and 28.
Now, we will find the estimated product value.
So, the given values are rounded off to the nearest tens.
The value 15 is rounded off to 20 and 28 is rounded off to 30.
Now, the estimated product is 20 x 30 is 600. The actual product value is 15 x 28 = 420.
Hence, the estimated product is 600.
Question 8.
Answer: The estimated product value is 3500.
Explanation: Given the values 71 and 51.
Now, we will find the estimated product value.
So, the given values are rounded off to the nearest tens.
The value 71 is rounded off to 70 and 51 is rounded off to 50.
Now, the estimated product is 70 x 50 is 3500. The actual product is 71 x 51 is 3621.
Hence, the estimated product is 3500.
Question 9.
Answer: The estimated product value is $300.
Explanation: Given the values of $12 and 32.
Now, we will find the estimated product value.
So, the given values are rounded off to the nearest tens.
The value 12 is rounded off to 10 and 32 is rounded off to 30.
Now, the estimated product is 10 x 30 is 300. The actual product is 12 x 32 384.
Hence, the estimated product is 300.
Problem Solving
Question 10.
John jogs 30 miles every week. There are 52 weeks in a year. How many miles does John jog in a year?
Answer: John jogs 1560 miles in a year.
Explanation: Given that,
John jogs 30 miles every week.
There are 52 weeks in a year.
Now, we will find out how many miles John jogs in a year.
So, the values are 30 and 52. Multiply the values to get the value of the miles.
The multiplication process is,
Hence, John jogs 1560 miles in a year.
Question 11.
Ms. Armstrong drives a total of 42 miles each day to and from work. About how many miles does Ms. Armstrong drive in 18 work days?
Answer: Ms. Armstrong drives 756 miles in 18 work days.
Explanation: Given that,
Ms. Armstrong drives a total of 42 miles each day to and from work.
Now, we will find out how many miles Ms. Armstrong drives in 18 work days.
So, the values are 42 and 18. Multiply the values to get the product value.
The multiplication process is below,
Therefore, Ms. Armstrong drives 756 miles in 18 work days.
Question 12.
What is the total length of 30 newborn alligators?
Answer: The total length of 30 newborn alligators is 300 inches.
Explanation: Given the data,
The length of one alligator is 10 inches.
Now, we will find the length of the 30 alligators.
So, the values are 10 and 30. Multiply the values, we get the product value.
The multiplication process is,
Hence, the length of 30 newborn alligators is 300 inches.
Question 13.
The average person sends about 25 E-mails a month. About how many E-mails is this each year?
Answer: Each year the person sends 300 E-mails.
Explanation: Given that,
The average person sends about 25 E-mails a month.
Now, we will find out how many E-mails is this each year.
So, the values are 25 and each year has 12 months.
The multiplication of 25 and 12 is below,
Thus, the person sends 300 E-mails in this each year.
Question 14.
Mae is finding the product of 70 × 40. How many zeros will be in the product? Explain.
Answer: 2 zeros will be in the product.
Explanation: Given the data,
Mae is finding the product of 70 × 40.
Now, we will find out how many zeros will be in the product.
The product is,
Therefore, the product of 70 and 40 is 2800. In this product, 2 zeros will be there.
Test Practice
Question 15.
A kangaroo can travel 30 feet per jump. How far could a kangaroo travel if it jumps 14 times?
A. 420 feet
B. 320 feet
C. 52 feet
D. 42 feet
Answer: Option A
Explanation: As given in the question,
A kangaroo can travel 30 feet per jump.
Now, we need to find out how far could a kangaroo travel if it jumps 14 times.
So, the values are 30 ft and 14 times. Multiply the values we get the product value.
The multiplication process is,
Hence, 420 ft kangaroo travel if it jumps 14 times.