McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter

All the solutions provided in McGraw Hill My Math Grade 3 Answer Key PDF Chapter 13 Lesson 9 Area and Perimeter will give you a clear idea of the concepts.

McGraw-Hill My Math Grade 3 Answer Key Chapter 13 Lesson 9 Area and Perimeter

Two rectangles can have the same area but different perimeters.

Math in My World

Example 1

Elizabeth will build two fences, one surrounding each garden shown below. How much area does each garden cover? How much fencing will she need for each garden?
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 1
1. Find the area of each garden.
Garden 1
A = l × w
= 6 × 2
= ____________
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 2
Garden 2
A = l × w
= 4 × 3
= ____________
Answer:
Garden 1
A = l × w
= 6 × 2
= 12 sq. ft
Garden 2
A = l × w
= 4 × 3
= 12 sq. ft
The gardens have same area.

2. Find the perimeter of each garden.
Garden 1
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 3
Garden 1 needs ____________ feet of fencing.
Garden 2 needs ____________ feet of fencing.
Answer:
Garden 1
The perimeter is 6 + 2 + 6 + 2 = 16 ft
Garden 1 needs 16 feet of fencing.
Garden 2
The perimeter is 3 + 4 + 3 + 4 = 14 ft
Garden 2 needs 14 feet of fencing.

Example 2

Draw and label a rectangle that has the same perimeter as the rectangle shown, but a different area.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 4
1. Find the perimeter and area of the rectangle shown.
The perimeter is 6 + 4 + 6 + 4, or ____________ inches.
The area is 6 × 4, or ____________ square inches. ← Multiply the length by the width.

2. Draw and label a rectangle that has a perimeter of 20 inches, but a different area.
What is the length of the rectangle you drew? ____________
What is the width of the rectangle you drew? ____________
What is the area of the rectangle you drew? ____________
Answer:
The perimeter is 6 + 4 + 6 + 4, or 2(6 + 4) = 20 inches.
The area is 6 × 4, or 24 square inches. ← Multiply the length by the width.
The length of the rectangle is 6 in.
The width of the rectangle is 4 in.
The area of the rectangle is 24 sq. inches

Talk Math

Refer to Example 2. Describe the length and width of a different rectangle you could have drawn.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 5
Answer:
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 7
length = 5cm
width = 6 cm
Area = 5 × 6 = 30 sq. cm
Perimeter = 2(5 + 6) = 2 × 11 = 22 cm

Guided Practice

Question 1.
Describe the length and width of a rectangle that has the same area as the one below, but a different perimeter.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 6
Answer:
length = 8yd
width = 3 yd
Area = 8 × 3 = 24 sq. yd
perimeter = 2(8 + 3) = 2 × 11 = 22 cm

Independent Practice

Draw and label a rectangle that has the same area, but a different perimeter, than each rectangle shown.

Question 2.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 7
Answer:
length = 5cm
width = 6 cm
Area = 5 × 6 = 30 sq. cm
Perimeter = 2(5 + 6) = 2 × 11 = 22 cm

Question 3.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 8
Answer:
s = 4 yd
Area = 4 × 4 = 16 sq. yd
Perimeter = 4 × 4 = 16 yd

Draw and label a rectangle that has the same perimeter, but a different area, than each rectangle shown.

Question 4.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 9
Answer:
l = 10ft
w = 3ft
A = 10 × 3 = 30sq. ft
P = 2(10 + 3) = 2 × 13 = 26 ft

Question 5.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 10
Answer:
l = 4 m
w = 9m
A = 4 × 9 = 36 sq. m
P = 2(4 + 9) = 2 × 13 = 26 m

Question 6.
Circle the rectangles that have the same perimeter, but different areas.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 11
Answer:
P = 2(8 + 4) = 2 × 12 = 24
P = 4 × 6 = 24
P = 2(9 + 5) = 2 × 14 = 28
McGraw-Hill-My-Math-Grade-3-Chapter-13-Lesson-9-Answer-Key-Area-and-Perimeter-11

Problem Solving

William’s Windows makes the rectangular windows given in the table. Use this information to solve Exercises 7 and 8.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 12

Question 7.
Mathematical PRACTICE Make Sense of Problems Which windows will use the same number of square feet of glass?
Answer:
Window A:
A = 6 × 3 = 18 sq. ft
Window B:
A = 5 × 4 = 20 sq. ft
Window C:
A = 9 × 2 = 18 sq. ft
Window A and C will use the same number of square feet of glass.

Question 8.
Each window will have a wood border surrounding it. Which windows will use the same amount of wood border?
Answer: Window A and C will use the same amount of wood border.

HOT Problems

Question 9.
Mathematical PRACTICE Which One Doesn’t Belong? Circle the rectangle that does not belong with the other two. Explain.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 13
Answer:
McGraw-Hill-My-Math-Grade-3-Chapter-13-Lesson-9-Answer-Key-Area-and-Perimeter-13

Question 10.
Mathematical PRACTICE Reason What is true about the sum of the length and the width for any rectangles with the same perimeter, but different areas?
Answer:
All rectangles are also parallelograms, but not all parallelograms are rectangles. The perimeter P of a rectangle is given by the formula, P=2l+2w, where l is the length and w is the width of the rectangle. The area A of a rectangle is given by the formula, A=lw, where l is the length and w is the width.

Question 11.
Building on the Essential Question How can two rectangles with the same area have different perimeters?
Answer: Recognise that shapes with the same areas can have different perimeters and vice versa. It is not always the case that shapes with the same area have the same perimeter. Likewise, it is not always true that shapes with the same perimeter have equal area.

McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 My Homework Answer Key

Practice

Question 1.
In the space at the right, draw and label a different rectangle that also has a perimeter of 16 meters, but a different area than shown above.
Answer:
McGraw-Hill-My-Math-Grade-3-Chapter-13-Lesson-9-Answer-Key-Area-and-Perimeter-2
P = 2(6 + 2)
P = 2 × 8 = 16 ft
A = 6 × 2 = 12 sq. ft

Draw and label a rectangle that has the same area, but a different perimeter, than each rectangle shown.

Question 2.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 14
Answer:
A = 8 × 3
A = 24 sq. cm
P = 2(8 + 3) = 2 × 11 = 22 cm

Question 3.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 15
Answer:
A = 9 × 1 = 9 sq. yd
P = 2(9 + 1)
= 2 × 10 = 20 yd

Problem Solving

David’s Dog Pens makes the rectangular dog pens shown in the table. Use this information to solve Exercises 4 and 5.
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 16
Question 4.
Which dog pens will take up the same area?
Answer:
Dog pens 1:
8 × 6 = 48 sq. ft
Dog pens 2:
10 × 4 = 40 sq. ft
Dog pens 3:
8 × 5 = 40 sq. ft
Dog pens 2 and 3 will take up the same area.

Question 5.
Which dog pens have the same perimeter?
Answer:
Dog pens 1:
2(8 + 6) = 2 × 14 = 28 ft
Dog pens 2:
2(10 + 4) = 2 × 14 = 28 ft
Dog pens 3:
2(8 + 5) = 2 × 13 = 26 ft
Thus, dog pens 1 and 2 have the same perimeter

Question 6.
Mathematical PRACTICE If Keep Trying Alexa drew a rectangle with an area of 36 square centimeters. The rectangle she drew has the smallest perimeter possible for this area. What is the length and width of the rectangle she drew?
Answer:
Alexa drew a rectangle with an area of 36 square centimeters.
P = 2(9 + 4)
= 2 × 13
= 26 cm
Length = 9
Width = 4 cm

Test Practice

Question 7.
Which rectangle has the same area as Rectangle E, but a different perimeter?
McGraw Hill My Math Grade 3 Chapter 13 Lesson 9 Answer Key Area and Perimeter 17
(A) Rectangle A
(B) Rectangle B
(C) Rectangle C
(D) Rectangle D
Answer:
Rectangle A:
A = 6 × 6 = 36 sq. units
P = 2(6 + 6) = 2 × 12 = 24 units
Rectangle B:
A = 7 × 6 = 42 sq. units
P = 2(7 + 6) = 2 × 13 = 26 units
Rectangle C:
A = 10 × 3 = 30 sq. units
P = 2(10 + 3) = 26 units
Rectangle D:
A = 8 × 5 = 40 sq. units
P = 2(8 + 5) = 2 × 13 = 26 units
Rectangle E:
A = 9 × 4 = 36 sq. units
P = 2(9 + 4) = 2 × 13 = 26 units
Rectangle A and E has same area but different perimeter.

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