McGraw Hill My Math Grade 2 Chapter 5 Lesson 4 Answer Key Problem-Solving Strategy: Use Logical Reasoning

All the solutions provided in McGraw Hill Math Grade 2 Answer Key PDF Chapter 5 Lesson 4 Problem-Solving Strategy: Use Logical Reasoning will give you a clear idea of the concepts.

McGraw-Hill My Math Grade 2 Answer Key Chapter 5 Lesson 4 Problem-Solving Strategy: Use Logical Reasoning

Eva’s house number has three digits. The sum of the digits is 7. Two of the digits are even. The middle digit is I. The first digit is less than the last digit. What is Eva’s house number?

  1. Understand Underline what you know. Circle what you need to find
  2. Plan How will I solve the problem?
  3. Solve Use logical reasoning. First digit plus last digit equals 6
    2 and 4 are even and equals 6
    2 less than 4
    Eva’s house number is 214
  4. Check Is my answer reasonable? Explain.

Practice the Strategy

The number of dogs at the shelter is a two-digit, odd number. It is more than 80. The tens digit is less than the ones digit. The sum of the digits is 17. How many dogs are at the shelter?
McGraw Hill My Math Grade 2 Chapter 5 Lesson 4 Answer Key Problem-Solving Strategy Use Logical Reasoning 1

  1. Understand
    Underline what you know. Circle what you need to find.
  2. Plan How will I solve the problem?
  3. Solve I will…
    _____ dogs
  4. Check Is my answer reasonable? Explain.

Answer:
The number of dogs in the shelter is 89 dogs.

Explanation:
1. Given that the number of dogs at the shelter is a two-digit, odd number. It is more than 80 and the tens digit is less than the one digit. The sum of the digits is 17. We need to the number of dogs in the shelter.
2. By the given clue we will solve the problem.
3. As it is a two-digit number and it is more than 80, so the number is between 81 to 99. And the tens digit is less than the one digit and the sum of the digits is 17. So the two-digit number will be 89 where 8+9 = 17.
4. The answer is reasonable, as the sum of the two-digit number 89 is 8+9 = 17.

Apply the Strategy

Question 1.
A number has three digits. The digit in the hundreds place is the difference of 4 and 2. The digit in the tens place is the sum of 2 and 3. The digit in the ones place is 2 more than the digit in the tens place. What is the number?
__________
Answer:
The three-digit number is 257.

Explanation:
1. Given that a number has three digits. The digit in the hundreds place is the difference of 4 and 2. The digit in the tens place is the sum of 2 and 3 and the digit in the ones place is 2 more than the digit in the tens place. So we need to find that number.
2. By the given clue we will find out the number.
3. As it is a three-digit number and the digit in the hundreds place is the difference of 4 and 2 which is 4-2 = 2. And the digit in the tens place is the sum of 2 and 3 which is 2+3 = 5. As the digit in the ones, the place is 2 more than the digit in the tens place which is 5+2 = 7. So the three-digit number is 257.
4. The answer is reasonable, by the given clue we have solved the question.

Question 2.
Sylvia writes this number: three ones, two tens, and seven hundreds. What number is it?
_____
Answer:
The number is 723.

Explanation:
1. Given that Sylvia writes the number: three ones, two tens, and seven hundred. So we need to write the number which is given in words.
2. We will write the numbers that are given in the words.
3. Three ones are 3, two tens are 2 and seven hundred is 7. So the number will be 723.
4. The answer is reasonable, as we have written the numbers that are given in words.

Question 3.
Ruby is trying to solve a number riddle. The digit in the tens place is less than 2. It is an odd number. The number in the hundreds place is greater than 8. The number in the ones place is the sum of 6 and 3. What is the number?
McGraw Hill My Math Grade 2 Chapter 5 Lesson 4 Answer Key Problem-Solving Strategy Use Logical Reasoning 2
Answer:
The number is 199.

Explanation:
1. Given that Ruby is trying to solve a number riddle. The digit in the tens place is less than 2. It is an odd number. The number in the hundreds place is greater than 8. The number in the ones place is the sum of 6 and 3. So we need to find that number.
2. We will solve the problem by the given clue.
3. As the digit in the tens place is less than 2 and it is an odd number. So the tens place digit is 1 and the number in the hundreds place is greater than 8. So the number in the hundreds place will be 9 and the number in the ones place is the sum of 6 and 3. So the number in the ones place will be 6+3 which is 9. So the number will be 199.

Review the Strategies

Choose a strategy

  • Make a model.
  • Write a number sentence.
  • Find a pattern.

Question 4.
Paco puts pennies into three groups. He counts 80 pennies in the first group, 3 pennies in the second group, and 500 pennies in the third group. How many pennies does he have?
McGraw Hill My Math Grade 2 Chapter 5 Lesson 4 Answer Key Problem-Solving Strategy Use Logical Reasoning 3
_____ pennies
Answer:
583 pennies.

Explanation:
Given that Paco puts pennies into three groups and he counts 80 pennies in the first group, 3 pennies in the second group, and 500 pennies in the third group which is
80+3+500 = 583 pennies.

Question 5.
Ella’s family is going to visit her cousins. They will drive for 3 days. Each day they will drive 60 miles. How many miles will they drive in all?
McGraw Hill My Math Grade 2 Chapter 5 Lesson 4 Answer Key Problem-Solving Strategy Use Logical Reasoning 4
____ miles
Answer:
The number of miles did they drive in total is 180 miles.

Explanation:
Given that Ella’s family is going to visit her cousins and they will drive for 3 days. Each day they will drive 60 miles. So the number of miles did they drive in total is 60+60+60 which is 180 miles.

Question 6.
Jamie ate 20 cherries on Monday. She ate 20 cherries on Tuesday. She ate 20 cherries on Wednesday. If she continues, how many cherries will Jamie have eaten by Thursday?
____ cherries
Answer:
Jamie eats 80 cherries for Thursday.

Explanation:
Given that Jamie ate 20 cherries on Monday. She ate 20 cherries on Tuesday. She ate 20 cherries on Wednesday. So for Thursday Jamie eats 20+20+20+20 which is 80 cherries.

McGraw Hill My Math Grade 2 Chapter 5 Lesson 4 My Homework Answer Key

Underline what you know. Circle what you need to find.

Question 1.
Lucy is thinking of a number. The number is greater than two hundred twenty-five. Her number is less than 2 hundreds, 2 tens, and 7 ones. What is Lucy’s number?
__________
Answer:
The number that Lucy thinks is 226.

Explanation:
1. Given that Lucy is thinking of a number and that number is greater than two hundred twenty-five. Her number is less than 2 hundreds, 2 tens, and 7 ones. So we need to find that number.
2. We will find the number by given a clue.
3. As Lucy is thinking of a number that number is greater than two hundred twenty-five which is 225 and her number is less than 2 hundreds, 2 tens, and 7 ones which is 227. So the number that Lucy thinks is 226.

Question 2.
The number of blocks has 9 in the ones place. The number in the hundreds place is one more than the number in the tens place. Those two numbers equal 11. How many blocks are there?
McGraw Hill My Math Grade 2 Chapter 5 Lesson 4 Answer Key Problem-Solving Strategy Use Logical Reasoning 5
Answer:
The number is 659.

Explanation:
1. Given that the number of blocks has 9 in the ones place and the number in the hundreds place is one more than the number in the tens place. Those two numbers equal 11. So we need to find that number.
2. We will solve the problem by the given clue.
3. As the number of blocks has 9 in ones place. And the number in the hundreds place is one more than the number in the tens place. So the tens place digit be X and the hundreds place digit be X+1. As the total of two numbers is 11, so
X+X+1 = 11,
2X+1 = 11,
2X = 11-1,
2X = 10,
X = 10/2,
X = 5.
So the tens place digit is 5 and the hundreds place digit is 6. So the number will be 659.

Question 3.
Ralph has 957 race car stickers. He gave 10 to Ken. He gave 100 to Matt. How many stickers does Ralph have left?
_____ stickers
Answer:
The number of stickers Ralph has left is 847 stickers.

Explanation:
1. Given that Ralph has 957 race car stickers, he gave 10 to Ken and he gave 100 to Matt. So we need to find the number of stickers Ralph has left.
2. We will subtract the stickers he gave to Ken and Matt.
3. As Ralph has 957 race car stickers and he gave 10 to ken and 100 to Matt. The total number of stickers he gave is 100+10 which is 110 stickers. So the number of stickers Ralph has left is 957-110 which is 847 stickers.

Question 4.
My class collected 389 milk jugs. We used 40 jugs. We gave 30 milk jugs to the first graders. How many milk jugs did we have left?
____ milk jugs.
Answer:
The remaining milk jugs are 319.

Explanation:
1. Given that the class collected 389 milk jugs and used 40 jugs. We have 30 milk jugs for the first graders. So we need to find the milk jugs that are left.
2. We will add used jugs and the milk jugs that are given to the first graders and then we will subtract from the collected milk jugs.
3. The number of milk jugs collected is 389 and the milk jugs used 40 jugs. The milk jugs given to the first graders are 30. So the total milk jugs used is 40+30 which is 70. And the number of milk jugs left is 389-70 which is 319. So the remaining milk jugs are 319.
4. The answer is reasonable, by adding 319 and 70 we will get 389.

Math at Home Ask your child to write the number 961 on a piece of paper. Tell him or her to write the number that is one less than that number on the paper in expanded form.
Answer:
960 = 900+60+0.

Explanation:
Given the number is 961 and the number that is one less will be 961-1 which is 960. So in the expanded form 960 will be
960 = 900+60+0.

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