We included **HMH Into Math Grade 2 Answer Key PDF** **Module 12 Lesson 2 Represent Regrouping for Subtraction **to make students experts in learning maths.

## HMH Into Math Grade 2 Module 12 Lesson 2 Answer Key Represent Regrouping for Subtraction

I Can represent subtraction of two-digit numbers with and without regrouping.

**Spark Your Learning**

How can you show the problem? How many baseball cards does Steve have now?

Steve has _________ baseball cards now.

Have children work in groups. Read the following problem: Steve has 15 baseball cards. He gives 7 baseball cards to Evan. How many baseball cards does Steve have now?

Answer:

Given that,

The total number of baseball cards near Steve = 15

The total number of baseball cards that Steve gives to Evan is = 7.

Therefore 15 – 7 = 8

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 5 and subtrahend is 7.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

**Build Understanding**

Question 1.

Elena has 42 pennies in a jar. She gives 14 pennies to Mark. How many pennies does Elena have now?

A. How can you use tools to show 42 pennies? Draw to show your work.

Answer:

Given that,

Elena has 42 pennies in a jar.

She gives 14 pennies to Mark.

Therefore 42 – 14 = 28.

Therefore Elena has 28 pennies now.

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 2 and subtrahend is 4.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

There are 4 tens and 2 ones.

There are not enough ones to subtract one.

Covert 1 tens into 10 ones. Then have 12 ones 12 – 4 = 8 ones.

3 tens – 1 ten = 2tens.

The difference is 28.

B. Are there enough ones to subtract 4 ones?

Answer:

No there are not enough ones to subtract.

To subtract 4 make 1 ten into 10 ones and then subtract.

C. How can you regroup 1 ten as 10 ones? Change your drawing above to show the regrouping.

Answer:

1 ten = 10 ones.

we can regroup when the minuend is smaller than the subtrahend.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

D. Subtract 4 ones from 12 ones. How many ones are left?

________ ones

Answer:

12 ones – 4 ones = 8 ones.

Therefore 8 ones are left.

E. Subtract 1 ten from 3 tens. How many tens are left?

_________ tens

Answer:

3 tens – 1 ten = 2 tens.

Therefore 2 tens are left.

F. How many pennies does Elena have now?

________ pennies

Answer:

Given that,

Elena has 42 pennies in a jar.

She gives 14 pennies to Mark.

Therefore 42 – 14 = 28.

Therefore Elena has 28 pennies now.

**Turn and Talk** What do you do when there are not enough ones to subtract? Explain.

Answer:

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones and then we subtract.

Question 2.

Theo is working on a puzzle that has 75 pieces. He has used 29 pieces so far. How many pieces have not been used?

A. Subtract 9 ones from 15 ones to find the difference. Subtract the tens. Draw in the chart above to show your work.

Answer:

15 – 9 = 6

Here we do have not enough ones to subtract.

Regroup 1 ten into 10 ones

Then it is 15 ones.

15 ones – 9 ones = 6 ones.

B. Write how many tens and ones.

_________ tens _____ ones

Answer:

75 – 29 = 46

After regrouping there are 4 ones and 6 tens

C. Solve.

_________ puzzle pieces have not been used.

Answer:

Given that,

Theo has 75 puzzle pieces.

He used 29 puzzle pieces.

The puzzle pieces have not been used = 75 – 29 = 46.

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 5 and subtrahend is 9.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

**Check Understanding**

Question 1.

Cindy has 31 bug stickers. Gabe has 17 bug stickers. How many more bug stickers does Cindy have than Gabe?

Use a concrete model or draw to solve. Regroup if you need to.

_________ more bug stickers

Answer:

Given that,

Cindy has 31 bug stickers.

Gabe has 17 bug stickers

Therefore 31 – 17 = 14.

Therefore Cindy has 14 bug stickers more than Gabe.

Here we have 3 tens and 1 one.

There are not enough ones to subtract one.

Covert 1 tens into 10 ones. Then have 11 ones 11 -7 = 4 ones.

2 tens – 1 ten = 1ten.

The difference is 14.

**On Your Own**

Question 2.

Attend to Precision Hayden has 34 beads. She uses 22 beads to make a bracelet. How many beads does Hayden have now? Draw to show your work.

_________ beads

Answer:

Given that,

The total number of beads near Hayden = 34.

She uses some beads to make a bracelet = 22

The remaining beads are 34 – 22 = 12.

Here there is no need of regrouping. Because the minuend is greater than the subtrahend.

There are 3 tens and 4 ones.

We subtracted 2 tens and 2 ones then the difference is 12

Question 3.

Use Structure Subtract 39 from 56. Draw to show the regrouping. Write the difference.

Answer:

56 – 39 = 17

Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.

The minuend is 6 and subtrahend is 9.

We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

There are 5 tens and 6 ones.

There are not enough ones to subtract so 1 ten is converted into 10 ones.

Then we subtracted 3 tens and 9 ones then the difference is 17

**I’m in a Learning Mindset!**

What do I do when I don’t know what to do?

Answer:

Take it easy or Learn something about yourself.