# Into Math Grade 2 Module 12 Lesson 2 Answer Key Represent Regrouping for Subtraction

We included HMH Into Math Grade 2 Answer Key PDF Module 12 Lesson 2 Represent Regrouping for Subtraction to make students experts in learning maths.

## HMH Into Math Grade 2 Module 12 Lesson 2 Answer Key Represent Regrouping for Subtraction

I Can represent subtraction of two-digit numbers with and without regrouping.

How can you show the problem? How many baseball cards does Steve have now?

Steve has _________ baseball cards now.

Have children work in groups. Read the following problem: Steve has 15 baseball cards. He gives 7 baseball cards to Evan. How many baseball cards does Steve have now?
Given that,
The total number of baseball cards near Steve = 15
The total number of baseball cards that Steve gives to Evan is = 7.
Therefore 15 – 7 = 8
Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.
The minuend is 5 and subtrahend is 7.
We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

Build Understanding

Question 1.
Elena has 42 pennies in a jar. She gives 14 pennies to Mark. How many pennies does Elena have now?

A. How can you use tools to show 42 pennies? Draw to show your work.

Given that,
Elena has 42 pennies in a jar.
She gives 14 pennies to Mark.
Therefore 42 – 14 = 28.
Therefore Elena has 28 pennies now.
Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.
The minuend is 2 and subtrahend is 4.
We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

There are 4 tens and 2 ones.
There are not enough ones to subtract one.
Covert 1 tens into 10 ones. Then have 12 ones 12 – 4 = 8 ones.
3 tens – 1 ten = 2tens.
The difference is 28.

B. Are there enough ones to subtract 4 ones?
No there are not enough ones to subtract.
To subtract 4 make 1 ten into 10 ones and then subtract.

C. How can you regroup 1 ten as 10 ones? Change your drawing above to show the regrouping.
1 ten = 10 ones.
we can regroup when the minuend is smaller than the subtrahend.
We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

D. Subtract 4 ones from 12 ones. How many ones are left?
________ ones
12 ones – 4 ones = 8 ones.
Therefore 8 ones are left.

E. Subtract 1 ten from 3 tens. How many tens are left?
_________ tens
3 tens – 1 ten = 2 tens.
Therefore 2 tens are left.

F. How many pennies does Elena have now?
________ pennies
Given that,
Elena has 42 pennies in a jar.
She gives 14 pennies to Mark.
Therefore 42 – 14 = 28.
Therefore Elena has 28 pennies now.

Turn and Talk What do you do when there are not enough ones to subtract? Explain.
We can regroup by borrowing 1 ten from the tens place to one place to make ten ones and then we subtract.

Question 2.
Theo is working on a puzzle that has 75 pieces. He has used 29 pieces so far. How many pieces have not been used?

A. Subtract 9 ones from 15 ones to find the difference. Subtract the tens. Draw in the chart above to show your work.
15 – 9 = 6
Here we do have not enough ones to subtract.
Regroup 1 ten into 10 ones
Then it is 15 ones.
15 ones – 9 ones = 6 ones.

B. Write how many tens and ones.
_________ tens _____ ones
75 – 29 = 46
After regrouping there are 4 ones and 6 tens

C. Solve.
_________ puzzle pieces have not been used.
Given that,
Theo has 75 puzzle pieces.
He used 29 puzzle pieces.
The puzzle pieces have not been used = 75 – 29 = 46.
Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.
The minuend is 5 and subtrahend is 9.
We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

Check Understanding

Question 1.
Cindy has 31 bug stickers. Gabe has 17 bug stickers. How many more bug stickers does Cindy have than Gabe?

Use a concrete model or draw to solve. Regroup if you need to.
_________ more bug stickers
Given that,
Cindy has 31 bug stickers.
Gabe has 17 bug stickers
Therefore 31 – 17 = 14.
Therefore Cindy has 14 bug stickers more than Gabe.

Here we have 3 tens and 1 one.
There are not enough ones to subtract one.
Covert 1 tens into 10 ones. Then have 11 ones 11 -7 = 4 ones.
2 tens – 1 ten = 1ten.
The difference is 14.

Question 2.
Attend to Precision Hayden has 34 beads. She uses 22 beads to make a bracelet. How many beads does Hayden have now? Draw to show your work.

Given that,
The total number of beads near Hayden = 34.
She uses some beads to make a bracelet = 22
The remaining beads are 34 – 22 = 12.
Here there is no need of regrouping. Because the minuend is greater than the subtrahend.

There are 3 tens and 4 ones.
We subtracted 2 tens and 2 ones then the difference is 12

Question 3.
Use Structure Subtract 39 from 56. Draw to show the regrouping. Write the difference.

56 – 39 = 17
Here we use regrouping in subtraction. Because the minuend is smaller than the subtrahend.
The minuend is 6 and subtrahend is 9.
We can regroup by borrowing 1 ten from the tens place to one place to make ten ones.

There are 5 tens and 6 ones.
There are not enough ones to subtract so 1 ten is converted into 10 ones.
Then we subtracted 3 tens and 9 ones then the difference is 17

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