Eureka Math Grade 2 Module 4 Lesson 14 Answer Key

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Engage NY Eureka Math 2nd Grade Module 4 Lesson 14 Answer Key

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Eureka Math Grade 2 Module 4 Lesson 14 Problem Set Answer Key

Question 1.
Solve by writing the problem vertically. Check your result by drawing chips on the place value chart. Change 1 ten for 10 ones, when needed.
a. 134 – 23= __111____

Answer:
134 – 23 = 111.

Explanation:
In the above-given question,
given that,
drawing chips on the place value chart.
change 1 ten for 10 ones when needed.
1 x 100 = 100.
3 x 10 = 30.
4 x 1 = 4.
2 x 10 = 20.
3 x 1 = 3.
100 + 30 + 4 = 134.
20 + 3 = 23.
134 – 23 = 111.

b. 140 – 12 = __128_____

Answer:
140 – 12 = 128.

Explanation:
In the above-given question,
given that,
drawing chips on the place value chart.
change 1 ten for 10 ones when needed.
1 x 100 = 100.
4 x 10 = 40.
1 x 10 = 10.
2 x 1 = 2.
100 + 40 = 140.
10 + 2 = 12.
140 – 12 = 128.

Answer:
140 – 12 = 128.

Explanation:
In the above-given question,
given that,
drawing chips on the place value chart.
change 1 ten for 10 ones when needed.
1 x 100 = 100.
4 x 10 = 40.
1 x 10 = 10.
2 x 1 = 2.
100 + 40 = 140.
10 + 2 = 12.
140 – 12 = 128.

d. 161 – 26 = ___135____

Answer:
161 – 26 = 135.

Explanation:
In the above-given question,
given that,
drawing chips on the place value chart.
change 1 ten for 10 ones when needed.
1 x 100 = 100.
6 x 10 = 60.
1 x 1 = 1.
2 x 10 = 20.
6 x 1 = 6.
100 + 60 + 1 = 161.
20 + 6 = 26.
161 – 26 = 135.

e. 187 – 49 = ___138____

Answer:
187 – 49 = 138.

Explanation:
In the above-given question,
given that,
drawing chips on the place value chart.
change 1 ten for 10 ones when needed.
1 x 100 = 100.
8 x 10 = 80.
7 x 1 = 7.
4 x 10 = 40.
9 x 1 = 9.
100 + 80 + 7 = 187.
40 + 9 = 49.
187 – 49 = 138.

Question 2.
Solve the following problems vertically without a place value chart.
a. 63 – 28 = __35____

Answer:
63 – 28 = 35.

Explanation:
In the above-given question,
given that,
solve the problem vertically without using a place value chart.
6 x 10 = 60.
3 x 1 = 3.
2 x 10 = 20.
8 x 1 = 8.
60 + 3 = 63.
20 + 8 = 28.
63 – 28 = 35.

b. 163 – 28 = ___135____

Answer:
163 – 28 = 135.

Explanation:
In the above-given question,
given that,
solve the problem vertically without using a place value chart.
1 x 100 = 100
6 x 10 = 60.
3 x 1 = 3.
2 x 10 = 20.
8 x 1 = 8.
100 + 60 + 3 = 163.
20 + 8 = 28.
163 – 28 = 135.

Eureka Math Grade 2 Module 4 Lesson 14 Exit Ticket Answer Key

Solve by writing the problem vertically. Check your result by drawing chips on the place value chart. Change 1 ten for 10 ones, when needed.

Question 1.
145 – 28 = ___127_____

Answer:
145 – 28 = 127.

Explanation:
In the above-given question,
given that,
drawing chips on the place value chart.
change 1 ten for 10 ones when needed.
1 x 100 = 100.
4 x 10 = 40.
5 x 1 = 5.
2 x 10 = 20.
8 x 1 = 8.
100 + 40 + 5 = 145.
20 + 8 = 28.
145 – 28 = 127.

Question 2.
151 – 39 = ____112______

Answer:
151 – 39 = 112.

Explanation:
In the above-given question,
given that,
drawing chips on the place value chart.
change 1 ten for 10 ones when needed.
1 x 100 = 100.
5 x 10 = 50.
1 x 1 = 1.
3 x 10 = 30.
9 x 1 = 9.
100 + 50 + 1 = 151.
30 + 9 = 39.
151 – 39 = 112.

Eureka Math Grade 2 Module 4 Lesson 14 Homework Answer Key

Question 1.
Solve by writing the problem vertically. Check your result by drawing chips on the place value chart. Change 1 ten for 10 ones, when needed.
a. 156 – 42 = ____114____

Answer:
156 – 42 = 114.

Explanation:
In the above-given question,
given that,
drawing chips on the place value chart.
change 1 ten for 10 ones when needed.
1 x 100 = 100.
5 x 10 = 50.
6 x 1 = 6.
4 x 10 = 40.
2 x 1 = 2.
100 + 50 + 6 = 156.
40 + 2 = 42.
156 – 42 = 114.

b. 150 – 36 = ___114_____

Answer:
150 – 36 = 114.

Explanation:
In the above-given question,
given that,
drawing chips on the place value chart.
change 1 ten for 10 ones when needed.
1 x 100 = 100.
5 x 10 = 50.
3 x 10 = 30.
6 x 1 = 6.
100 + 50 = 150.
30 + 6 = 36.
150 – 36 = 114.

c. 163 – 45 = ___118_____

Answer:
163 – 45 = 118.

Explanation:
In the above-given question,
given that,
drawing chips on the place value chart.
change 1 ten for 10 ones when needed.
1 x 100 = 100.
6 x 10 = 60.
3 x 1 = 3.
4 x 10 = 40.
5 x 1 = 5.
100 + 60 + 3 = 163.
40 + 5 = 45.
163 – 45 = 118.

Question 2.
Solve the following problems without a place value chart.
a.

Answer:
134 – 29 = 105.

Explanation:
In the above-given question,
given that,
solve the problem without using a place value chart.
1 x 100 = 100.
3 x 10 = 30.
4 x 1 = 4.
2 x 10 = 20.
9 x 1 = 9.
100 + 30 + 4  = 134.
20 + 9 = 29.
134 – 29 = 105.

b.

Answer:
154 – 37 = 117.

Explanation:
In the above-given question,
given that,
solve the problem without using a place value chart.
1 x 100 = 100.
5 x 10 = 50.
4 x 1 = 4.
3 x 10 = 30.
7 x 1 = 7.
100 + 50 + 4  = 154.
30 + 7 = 37.
154 – 37 = 117.

Question 3.
Solve and show your work. Draw a place value chart and chips, if needed.
a. Aniyah has 165 seashells. She has 28 more than Ralph. How many seashells does Ralph have?

Answer:
The number of seashells does Ralph have = 137.

Explanation:
In the above-given question,
given that,
Aniyah has 165 seashells.
she has 28 more than Ralph.
165 – 28 = 137.
so the number of seashells does Ralph has = 137.

b. Aniyah and Ralph each give 19 seashells to Harold. How many seashells does Aniyah have left?

Answer:
The number of seashells do Aniyah have left = 146.

Explanation:
In the above-given question,
given that,
Aniyah and Ralph each give 19 seashells to Harold.
165 – 19 = 146.
so the number of seashells do Aniyah have left = 146.

c. How many seashells does Ralph have left?

Answer:
The number of seashells does Ralph have left = 118.

Explanation:
In the above-given question,
given that,
Aniyah and Ralph each give 19 seashells to Harold.
137 – 19 = 118.
so the number of seashells do Ralph have left = 118.