Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks

Practicing the Bridges in Mathematics Grade 2 Student Book Answer Key Unit 2 Place Value & Measurement with Jack’s Beanstalks will help students analyze their knowledge of concepts.

Bridges in Mathematics Grade 2 Student Book Answer Key Unit 2 Place Value & Measurement with Jack’s Beanstalks

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 1 Session 3 Answer Key

Cups & Beans

Question 1.
Scoop about 50 beans out of one of the containers. Then count them by 10s and 1s to find out exactly how many beans you scooped.

a. Record your results:
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 42
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-Cups & Beans-1a

Explanation:
Number of beans are in one container = 50.
Number of beans scooped by 10s = Number of beans are in one container ÷ 10
= 50 ÷ 10
= 5.
Number of beans scooped by 10s = Number of beans are in one container ÷ 1
= 50 ÷ 1
= 5.

b. How many beans in all? ____________
Answer:
Total number of beans scooped in all = 2,750.

Explanation:
Number of beans are in one container = 50.
Number of beans scooped by 10s = 5.
Number of beans scooped by 1s = 50.
Total number of times beans scooped = Number of beans scooped by 10s + Number of beans scooped by 1s
= 5 + 50
= 55.
Total number of beans scooped in all = Number of beans are in one container × Total number of times beans scooped
= 55 × 50
= 2,750.

c. Circle the sentence that is true.
I have more than 50 beans. I have fewer than 50 beans.
Answer:
Sentence that is true:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-Cups & Beans-1c

Explanation:
Total number of beans scooped in all = 2,750.
I have more than 50 beans. I have fewer than 50 beans.
=> Number of beans more than 50.

d. How many more? (How many beans must you take away to get 50?)
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 43
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-Cups & Beans-1d

Explanation:
Number of beans scooped = 50.
Number of beans to show = 50.
Difference:
50 – ??? = 50.
=> 50 – 50 = ???
=> 0 = ????.

e. How many fewer ?(How many beans must you add to get 50?)
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 44
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-Cups & Beans-1e

Explanation:
Number of beans scooped = 50.
Number of beans to show = 50.
Addition:
50 + ??? = 50.
=> 50 – 50 = ???
=> 0 = ????.

Question 2.
Combine your cups and leftover beans with your partner’s. If you have 10 or more left over, make a new cup of 10.

a. Record your results:
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 45
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-Cups & Beans-2a

Explanation:
Number of beans scooped = 50.
Number of beans more added = 10.
Total number of beans in all = Number of beans scooped + Number of beans more added
= 50 + 10
= 60.
Number of beans scooped in 10s = Total number of beans in all ÷ 10
= 60 ÷ 10
= 6.

b. How many beans in all? ____________
Answer:
Total number of beans in all = 60.

Explanation:
Number of beans scooped = 50.
Number of beans more added = 10.
Total number of beans in all = Number of beans scooped + Number of beans more added
= 50 + 10
= 60.

c. Circle the sentence that is true.
We have more than 100 beans. we have fewer than 100 beans.
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-Cups & Beans-2c

Explanation:
Total number of beans in all = 60.
=> Total number of beans in all are lesser than 100.

d. How many more? (How many beans must you take away to get 100?)
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 46
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-Cups & Beans-2d

Explanation:
Total number of beans in all = 60.
Number of beans to show = 100.
Subtraction:
Total number of beans in all – ??? = 100.
=> 60 – ??? = 100.
=> 60 + 100 = ???
=> 160 = ???.

e. How many fewer? (How many beans must you add to get 100?)
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 47
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-Cups & Beans-2e

Explanation:
Total number of beans in all = 60.
Number of beans to show = 100.
Addition:
Total number of beans in all + ??? = 100.
=> 60 + ??? = 100.
=> ??? = 100 – 60
=> ??? = 40.

How Many Tennis Balls?

There are 10 tennis balls in each bucket. Count by 10s and 1s to find out how many tennis balls there are in each row. Then tell how many more or how many fewer it would take to make the number at the end of the row. You can use the grids at the bottom of each page to help.

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 48

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 49
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls

Explanation:
Number of tennis balls in each bucket = 10.
1. Total number of balls = 3(10) + 4 extra balls = 30 + 4 = 34.
50 – ?? = 34.
=> 50 – 34 = ??
=> 6 = ??
2. Total number of balls = 2(10) + 3 extra balls = 20 + 3 = 23.
23 – ?? = 20.
=> 23 – 20 = ??
=> 3 = ??
3. Total number of balls = 4(10) + 8 extra balls = 40 + 8 = 48.
50- ?? = 48.
=> 50 – 48 = ??
=> 2 = ??
4. Total number of balls = 5(10) + 2 extra balls = 50 + 2 = 52.
52 – ?? = 50.
=> 52 – 50 = ??
=> 2 = ??
5. Total number of balls = ?? + 11 extra balls = 10.
= ?? = 10 + 11
=> ?? = 21.

How many Tennis Balls

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 50

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 51
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-How many Tennis Balls

Explanation:
Number of tennis balls in each bucket = 10.
6. Total number of balls = 8(10) + 6 extra balls = 80 + 6 = 86.
86 – ?? = 80
=> 86 – 80 = ??
=> 6 = ??
7. Total number of balls = 4(10) + 15 extra balls = 40 + 15 = 55.
55 + ?? = 60.
=> ?? = 60 – 55
=> ?? = 5.
8. Total number of balls = 9(10) + 13 extra balls = 90 + 13 = 103.
103 – ?? = 100.
=> 103 – 100 = ??
=> 3 = ??
9. Total number of balls = 12(10) + 0 extra balls = 120 + 0 = 120.
120 – ?? = 125.
=> ?? = 125 – 120
=> ?? = 5.

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 1 Session 4 Answer Key

Show Me Base Ten

Show each number in three different ways. Circle groups of ten and ones. Then fill in the blanks to tell how many tens and ones you used.

ex
forty-two (42)
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 52

Question 1.
thirty-three (33)
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 53
Answer:
Number: thirty-three (33).
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Show Me Base Ten-1

Explanation:
Number given = 33.
1. Tens – 3
Ones – 3.
2. Tens – 1
Ones – 23.
3. Tens – 2
Ones – 13.

Question 2.
fifty-one (51)
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 54
Answer:
Number: fifty-one (51)
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Show Me Base Ten-2

Explanation:
Number given = 51.
1. Tens – 5
Ones – 1.
2. Tens – 4
Ones – 11.
3. Tens – 3
Ones – 21.

Question 3.
seventy-five (75)
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 55
Answer:
Number: seventy-five (75)
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Show Me Base Ten-3

Explanation:
Number given = 75.
1. Tens – 7
Ones – 5.
2. Tens – 5
Ones – 25.
3. Tens – 4
Ones – 35.

Question 4.
eighty-seven (87)
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 56
Answer:
Number: eighty-seven (87).
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Show Me Base Ten-4

Explanation:
Number given = 87.
1. Tens – 8
Ones – 7.
2. Tens – 5.
Ones – 37.
3. Tens – 6.
Ones – 27.

Question 5.
What number is this?
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 57
Tens ____________
Ones ____________
Total ____________
Answer:
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 57
Tens – 6.
Ones – 11.
Total – 71.

Explanation:
Number given = ??.
1. Tens – 6
Ones – 11.
=> Number = 6(10) + 11(1)
= 60 + 11
= 71.

Question 6.
What number is this?
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 58
Tens ____________
Ones ____________
Total ____________
Answer:
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 58
Tens – 1.
Ones – 26.
Total – 36.

Explanation:
Number given = ??.
1. Tens – 1
Ones – 26.
=> Number = 1(10) + 26(1)
= 10 + 26
= 36.

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 1 Session 5 Answer Key

Base Ten Riddles

Solve these problems.

Question 1.
I have 2 tens and 5 ones. Who am I? ____________
Answer:
I am Twenty five (25).

Explanation:
Number = ??
I have 2 tens and 5 ones.
=> Tens: 2.
Ones: 5.
=> Number: 2(10) + 5(1)
= 20 + 5
= 25.

Question 2.
I have 30 ones and 1 hundred. Who am I? ____________
Answer:
I have 30 ones and 1 hundred. 130 I am.

Explanation:
I have 30 ones and 1 hundred. Who am I?
=> Number = 1(100) + 0(10) + 30(1)
= 100 + 0 + 30
= 130.

Question 3.
If you gave me 2 more tens, I would be 80. Who am I? ____________
Answer:
If you gave me 2 more tens, I would be 80. I am 60.

Explanation:
If you gave me 2 more tens, I would be 80.
=> 80 =  ?? + 2(10)
=> 80 = ?? + 20
=> 80 – 20 = ??
=> 60 = ??

Question 4.
I am 341. How many hundreds do I have? ____________
Answer:
I am 341. 3 hundreds I have.

Explanation:
Number = 341.
Hundred = 3.
Tens = 4.
ones = 1.

Question 5.
I have 2 tens and 10 ones. Who am I? ____________
Answer:
I am Thirty(30).

Explanation:
Number = ??
I have 2 tens and 10 ones.
=> Tens: 2.
Ones: 10.
=> Number: 2(10) + 10(1)
= 20 + 10
= 30.

Question 6.
I am 45. I have 25 ones. How many tens do I have? ____________
Answer:
I am 45. I have 25 ones. 2 tens I have.

Explanation:
Number = 45.
I have 25 ones.
=> Tens: ??.
Ones: 5.
=> Number =  ??(10) + 25(1)
=> 45 = ??(10) + 25
=> 45 – 25 = ??(10)
=> 20 = ??
=> 20 ÷ 10 = ??
=> 2 = ??.

Question 7.
I have 12 tens and 3 ones. Who am I? ____________
Answer:
I have 12 tens and 3 ones. I am 123 number.

Explanation:
Number = ??
I have 12 tens and 3 ones.
=> Tens: 12.
Ones: 3.
=> Number: 12(10) + 3(1)
= 120 + 3
= 123.

Question 8.
I am 125. I have 12 tens. How many ones do I have? ____
Answer:
I am 125. I have 12 tens. 5 ones I have in my number.

Explanation:
Number = 125.
I have 12 tens.
=> Tens: 12.
Ones: 5.
=> Number = Tens + Ones.
=> 125 = 12(10) + 1(??)
=> 125 = 120 + 1(??)
=> 125 – 120 = 1(??)
=> 5 = 1(??)

Challenge Problems

Question 9.
I have 13 tens, 2 hundreds, and 21 ones. Who am I? ____________
Answer:
I have 13 tens, 2 hundreds, and 21 ones. 351 I am.

Explanation:
Number = ???.
I have 13 tens, 2 hundreds, and 21 ones.
=> Number = 2(100) + 13(10) + 21(1)
= 200 + 130 + 21
= 330 + 21
= 351.

Question 10.
If you took away 2 tens and 2 ones, I would be 29. Who am I? _____
Answer:
If you took away 2 tens and 2 ones, I would be 29. 51 I am.

Explanation:
Number = ???
If you took away 2 tens and 2 ones, I would be 29. Who am I?
=> Number = ??
=> 29 = Number – (2tens + 2ones)
=> 29 = ?? – [2(10) + 2(1)]
=> 29 = ?? – [(20+ 2)]
=> 29 = ?? -22
=> 29 + 22 = ??
=> 51 = ??.

Question 11.
I have 9 hundreds, 9 tens, and 10 ones. Who am I? ____________
Answer:
I have 9 hundreds, 9 tens, and 10 ones. 1,000 I am.

Explanation:
Number = ???
I have 9 hundreds, 9 tens, and 10 ones.
=> Number = 9(100) + 9(10) + 10(1)
= 900 + 90 + 10
= 990 + 10
= 1,000.

Question 12.
If you gave me 3 more tens, I would be 115. Who am I? ____________
Answer:
If you gave me 3 more tens, I would be 115. 112 I am.

Explanation:
Number = ???
If you gave me 3 more tens, I would be 115.
=> 115 = Number + 3(1)
=> 115 = ??? + 3
=> 115 – 3 = ???
=> 112 = ???.

Question 13.
I have 7 hundreds, 10 tens, and 10 ones. Who am I? ____________
Answer:
I have 7 hundreds, 10 tens, and 10 ones. 810 I am.

Explanation:
Number = ???
I have 7 hundreds, 10 tens, and 10 ones.
=> Number = 7(100) + 10(10) + 10(1)
=> 700 + 100 + 10
=> 800 + 10
=> 810.

Question 14.
If you took away 3 tens, I would be 70. Who am I? ____________
Answer:
If you took away 3 tens, I would be 70. 100 I am.

Explanation:
Number = ???
If you took away 3 tens, I would be 70.
=> 70 = Number(???)  – 3(10)
=> 70 = ??? – 30
=> 70 + 30 = ???
=> 100 = ???

Question 15.
I have 12 ones, and I am between 20 and 30. Who am I? _____ How many tens do I have? ______
Answer:
I have 12 ones, and I am between 20 and 30. 22  I am. 1 tens I have.

Explanation:
Tens in the number = ??
I have 12 ones, and I am between 20 and 30.
=> ??(10) + 12(1) = between 20 and 30.
=> 2((10) + 12(1) = 20 + 12 = 32. NO.
=> 1((10) + 12(1) = 10 + 12 = 22. YES.

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 1 Session 6 Answer Key

Counting Rows

Fill in each table below to show how many dots are in each collection.

Question 1.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 59
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Counting Rows-1

Explanation:
Number of rows = 5.
Number of columns = 10.
Number = Number of rows × Number of columns
= 5 × 10
= 50.

Question 2.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 60
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Counting Rows-2

Explanation:
Number of tens = 5(10) = 50.
Number of ones = 7(1) = 7.
Number = Number of tens + Number of ones
= 5(10) + 7(1)
= 50 + 7
= 57.

Question 3.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 61
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Counting Rows-3

Explanation:
Number of tens = 8(10) = 80.
Number of ones = 3(1) = 3.
Number = Number of tens + Number of ones
= 8(10) + 3(1)
= 80 + 3
= 83.

Question 4.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 62
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Counting Rows-4

Explanation:
Number of tens = 1(10) = 10.
Number of ones = 2(1) = 2.
Number = Number of tens + Number of ones
= 10 + 2
= 12.

Question 5.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 63
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Counting Rows-5

Explanation:
Hundreds = (10 × 10) = 1(100).
Number = Hundreds + Tens + Ones
= 100 + 1(10) + 2
= 100 + 10 + 2
= 110 + 2
= 112.

Question 6.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 64
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Counting Rows-6

Explanation:
Hundreds = (10 × 10) = 1(100).
Number = Hundreds + Tens + Ones
= 100 + 2(10) + 3
= 100 + 20 + 3
= 120 + 3
= 123.

Question 7.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 65
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Counting Rows-7

Explanation:
Hundreds = (10 × 10) = 100.
Number = Hundreds + Tens + Ones
= 100 + 6(10) + 7
= 100 + 60 + 7
= 160 + 7
= 167.

Question 8.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 66
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Counting Rows-8

Explanation:
Hundreds = 10(10) = 100.
Number =  Hundreds + Tens + Ones
= 100 + 9(10) + 9
= 100 + 90 + 9
= 190 + 9
= 199.

Question 9.
If you added 1 more dot to the group of dots in problem 8, how many dots would there be? ______
Answer:
If one dot is added to the group of dots in problem 8, 200 dots will be there.

Explanation:
Hundreds = 10(10) = 100.
Number =  Hundreds + Tens + Ones
= 100 + 9(10) + 9
= 100 + 90 + 9
= 190 + 9
= 199.
If you added 1 more dot to the group of dots in problem 8,
=> 199 + 1
=> 200.

Lots of Dots Challenge

Put a circle around:
the 190th dot
the 212th dot
the 480th dot
the 657th dot
the 804th dot
the 999th dot
the 500th dot

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 67
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Lots of Dots Challenge-

Explanation:
Put a circle around:
the 190th dot = 100 + 90 = 190th dot.
the 212th dot = 100 + 100 + 12 = 200 + 12 = 212th dot.
the 480th dot = 4(100) + 80 = 400 + 80 = 480th dot.
the 657th dot = 6(100) + 57 = 600 + 57 = 657th dot.
the 804th dot = 8(100) + 04 = 800 + 04 = 804th dot.
the 999th dot = 9(100) + 99 = 900 + 99 = 999th dot.
the 500th dot = 5(100) = 500th dot.

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 2 Session 2 Answer Key

Measuring Jack’s Beans

Question 1 – 7.
Use Unifix cubes to measure each of the strips Jack cut to match the lengths of the beans on the giant bean stalk. Write the length of each bean below.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 69
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 68
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Measuring Jack's Beans-1-7

Explanation:
Length of green bean = 2 cubes.
Length of yellow bean = 3 cubes.
Length of white bean = 4 cubes.
Length of blue bean = 5 cubes.
Length of brown bean = 6 cubes.
Length of red bean = 7 cubes.

Question 8.
When you are finished measuring all the paper strips, color each bean on this sheet to match the color name below the drawing.
Answer:
Each bean colored o match the color name below the drawing:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-How Many Tennis Balls-Measuring Jack's Beans-1-7

Explanation:
Length of green bean = 2 cubes.
Length of yellow bean = 3 cubes.
Length of white bean = 4 cubes.
Length of blue bean = 5 cubes.
Length of brown bean = 6 cubes.
Length of red bean = 7 cubes.

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 2 Session 3 Answer Key

Measuring Jack’s Garden Beds

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 69

Use Unifix cubes to help Jack find out how many bricks it will take to go all the way around each of the garden beds.

Question 1.
Garden Bed 1 ____ cubes
Answer:
Garden Bed 1 are 9 cubes.

Explanation:
Number of cubes Garden Bed 1 = 9.

Question 2.
Garden Bed 2 ____ cubes
Answer:
Garden Bed 2 are 5 cubes.

Explanation:
Number of cubes Garden Bed 2 = 5.

Question 3.
Garden Bed 3 ____ cubes
Answer:
Garden Bed 3 are 9 cubes.

Explanation:
Number of cubes Garden Bed 3 = 9.

Question 4.
Garden Bed 4 ____ cubes
Answer:
Garden Bed 4 are 5 cubes.

Explanation:
Number of cubes Garden Bed 4 = 5.

Question 5.
Garden Bed 5 ____ cubes
Answer:
Garden Bed 5 are 9 cubes.

Explanation:
Number of cubes Garden Bed 5 = 9.

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 3 Session 2 Answer Key

Measuring with Ten-Strips

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 70
Answer:
Bridges-in-Mathematics-Grade-2-Student-Book-Answer-Key-Unit-2-Place-Value-&-Measurement-with-Jack’s-Beanstalks-Measuring with Ten-Strips

Explanation:
Length of ruler = 0.6 strips.
Length of pencil = 14 strips = 10 + 4 = 14 strips.
Length of book = 8 strips.
Length of Laptop = 10 + 6 = 16 strips.
Length of Dinning table = 36 = 3(10 ) + 6 = 30 + 6 = 36 strips.
Length of Box = 0.5 strips.

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 3 Session 4 Answer Key

Measuring Beans

Help Jack measure his beans! How long are the beans together?

Question 1.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 71
Black bean: 10 cubes long
White bean: 9 cubes long How long together? _______
Answer:
Length of the beans together = 19 cubes.

Explanation:
Black bean: 10 cubes long.
White bean: 9 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 10 + 9
=> 19 cubes.

Question 2.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 72
Black bean: 10 cubes long
White bean: 13 cubes long How long together? _______
Answer:
Length of the beans together = 23 cubes.

Explanation:
Black bean: 10 cubes long.
White bean: 13 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 10 + 13
=> 23 cubes.

Question 3.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 73
Black bean: 10 cubes long
White bean: 21 cubes long How long together? ______
Answer:
Length of the beans together = 31 cubes.

Explanation:
Black bean: 10 cubes long.
White bean: 21 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 10 + 21
=> 31 cubes.

Question 4.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 74
Black bean: 10 cubes long
White bean: 27 cubes long How long together? ____________
Answer:
Length of the beans together = 37 cubes.

Explanation:
Black bean: 10 cubes long.
White bean: 27 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 10 + 27
=> 37 cubes.

Question 5.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 75
Black bean: 10 cubes long
White bean: 6 cubes long How long together? ___________
Answer:
Length of the beans together = 16 cubes.

Explanation:
Black bean: 10 cubes long.
White bean: 6 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 10 + 6
=> 16 cubes.

Question 6.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 76
Black bean: 10 cubes long
White bean: 25 cubes long How long together? ___________
Answer:
Length of the beans together = 35 cubes.

Explanation:
Black bean: 10 cubes long.
White bean: 25 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 10 + 25
=> 35 cubes.

Question 7.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 77
Black bean: 10 cubes long
White bean: 17 cubes long How long together? ________
Answer:
Length of the beans together = 27 cubes.

Explanation:
Black bean: 10 cubes long.
White bean: 17 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 10 + 17
=> 27 cubes.

Question 8.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 78
Black bean: 10 cubes long
White bean: 27 cubes long How long together? ___________
Answer:
Length of the beans together = 37 cubes.

Explanation:
Black bean: 10 cubes long.
White bean: 27 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 10 + 27
=> 37 cubes.

Question 9.
How long are the beans together?

  • 2 black beans (Remember that all of Jack’s black beans are 10 cubes long.)
  • 1 white bean, 13 cubes long

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 79
Answer:
Length of the beans together = 33 cubes.

Explanation:
Black bean: 2(10) = 20 cubes long.
White bean: 1(13) = 13 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 20 + 13
=> 33 cubes.

Question 10.
How long are the beans together?

  • 2 black beans
  • 1 white bean, 46 cubes long

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 80
Answer:
Length of the beans together = 66 cubes.

Explanation:
Black bean: 2(10) = 20 cubes long.
White bean: 1(46) = 46 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 20 + 46
=> 66 cubes.

Question 11.
How long are the beans together?

  • 3 black beans
  • 1 white bean, 22 cubes long

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 81
Answer:
Length of the beans together = 52 cubes.

Explanation:
Black bean: 3(10) = 30 cubes long.
White bean: 1(22) = 22 cubes long.
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 30 + 22
=> 52 cubes.

Question 12.
How long are the beans together?

  • 5 black beans
  • 1 white bean, 53 cubes long

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 82
Answer:
Length of the beans together = 103 cubes.

Explanation:
Black bean: 5(10) = 50 cubes long.
White bean: 1(53) = 53 cubes long
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 50 + 53
=> 103 cubes.

Question 13.
How long are the beans together?

  • 6 black beans
  • 1 white bean, 44 cubes long

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 83
Answer:
Length of the beans together = 104 cubes.

Explanation:
Black bean: 6(10) = 60 cubes long.
White bean: 1(44) = 44 cubes long
Length of the beans together = ?? cubes.
=> Black bean + White bean
=> 60 + 44
=> 104 cubes.

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 3 Session 5 Answer Key

Buckets of Beans

Jack charges for his beans by length, H per cube. Here are the lengths of his beans.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 84
Customers buy different numbers of beans. How much do they have to pay?

Practice

2 green beans. How much money? _______

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 85
Answer:
Cost of 2 green beans = 20H.

Explanation:
Length of green beans = 10 cubes.
Length of 2 green beans = 2 × 10 = 20 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 2 green beans = 20 × H
= 20H.

Practice

1 green bean, 1 black bean. How much money?

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 86

Answer:
Cost of 1 green, 1 black beans = 55H.

Explanation:
Length of 1 green beans = 10 cubes.
Length of 1 black beans = 45 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 1 green, 1 black beans = (10 + 45) × H
=> 55 × H
=> 55H.

Question 1.
1 green bean, 1 purple bean. How much money? _______
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 87
Answer:
Cost of 1 green, 1 purple beans = 25H.

Explanation:
Length of 1 green bean = 10 cubes.
Length of 1 purple bean = 15 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 1 green, 1 purple beans = (10 + 15) × H
=> 25 × H
=> 25H.

Question 2.
1 purple bean, 1 red bean. How much money?
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 88
Answer:
Cost of 1 red, 1 purple beans = 27H.

Explanation:
Length of 1 red bean = 12 cubes.
Length of 1 purple bean = 15 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 1 red, 1 purple beans = (12 + 15) × H
=> 27 × H
=> 27H.

Question 3.
1 black bean, 1 white bean. How much money? _______
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 90
Answer:
Cost of 1 red, 1 purple beans = 75H.

Explanation:
Length of 1 black bean = 45 cubes.
Length of 1 white bean = 30 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 1 black, 1 white beans = (45 + 30) × H
=> 75 × H
=> 75H.

Question 4.
1 green bean, 1 rainbow bean. How much money? _______
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 91
Answer:
Cost of 1 green , 1 rainbow beans = 70H.

Explanation:
Length of 1 green bean = 10 cubes.
Length of 1 rainbow bean = 60 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 1 green , 1 rainbow beans = (10 + 60) × H
=> 70 × H
=> 70H.

Question 5.
2 green beans, 1 black bean. How much money? ________
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 92
Answer:
Cost of 2 green , 1 black beans = 65H.

Explanation:
Length of 2 green bean = 2(10) = 20 cubes.
Length of 1 black bean = 45 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 2 green , 1 black beans = (20 + 45) × H
=> 65 × H
=> 65H.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 84

Question 6.
2 purple beans. How much money? _______
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 92
Answer:
Cost of 2 purple beans = 30H.

Explanation:
Length of 2 purple bean = 2(15) = 30 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 2 purple beans = 30 × H
=> 30H.

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 93

Question 7.
1 rainbow bean, 1 white bean. How much money? ________
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 92
Answer:
Cost of 1 Rainbow, 1 white beans = 90H.

Explanation:
Length of 1 Rainbow bean = 60 cubes.
Length of 1 white bean = 30 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 1 Rainbow, 1 white beans = (60 + 30) × H
=> 90 × H
=> 90H.

Question 8.
2 black beans, 1 green bean. How much money? ________
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 92
Answer:
Cost of 2 black, 1 green beans = 100H.

Explanation:
Length of 2 black bean = 2(45) = 90 cubes.
Length of 1 green bean = 10 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 2 black, 1 green beans = (90 + 10) × H
=> 100 × H
=> 100H.

Challenge Problems

Question 9.
2 rainbow beans, 2 white beans. How much money? ________
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 92
Answer:
Cost of 2 rainbow, 2 white beans = 180H.

Explanation:
Length of 2 rainbow beans = 2(60) = 120 cubes.
Length of 2 white beans = 2(30) = 60 cubes.
Jack charges for his beans by length, H per cube.
=> Cost of 2 rainbow, 2 white beans = (120 + 60) × H
=> 180 × H
=> 180H.
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 93

Question 10.
How much for 1 of every kind of bean? _______
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 92
Answer:
Length of 1 green bean = 10 cubes.
Length of 1 white bean = 30 cubes.
Length of 1 red bean = 12 cubes.
Length of 1 purple beans = 15 cubes.
Length of 1 rainbow beans = 60 cubes.
Length of 1 black beans = 45 cubes.

Explanation:
For every 1 bean:
Length of 1 green bean = 10 cubes.
Length of 1 white bean = 30 cubes.
Length of 1 red bean = 12 cubes.
Length of 1 purple beans = 15 cubes.
Length of 1 rainbow beans = 60 cubes.
Length of 1 black beans = 45 cubes.

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 94

Challenge Problems

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 95

Question 11.
A customer bought 3 beans and the total price was 135. What beans did she buy?
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 96
bean 1 _____ bean 2 _____ bean 3 ______
Answer:
bean 1- rain bow.
bean 2-  black.
bean 3-  white.

Explanation:
Number of beans customer bought = 3.
Total price = 554.
Length of 1 green bean = 10 cubes.
Length of 1 white bean = 30 cubes.
Length of 1 red bean = 12 cubes.
Length of 1 purple beans = 15 cubes.
Length of 1 rainbow beans = 60 cubes.
Length of 1 black beans = 45 cubes.
=> 60 cubes + 45 cubes  + 30 cubes
=> 105 cubes + 30 cubes
=> 135 cubes.

Question 12.
A customer bought 2 white beans and 1 purple bean. She gave Jack $1. How much change did Jack give her?
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 97
Jack gave her ____ in change.
Answer:
Jack gave her 25 in change.

Explanation:
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 95
2 white beans and 1 purple bean. She gave Jack $1.
Length of 2 white beans = 2(30) = 60 cubes.
Length of 1 purple bean = 15 cubes.
Amount of money Jack gave = $1.
Cost of 2 white beans and 1 purple bean = (60 + 15) × H
= 75H.
Conversion:
1 Dollar = 100 H.
=> 100 – 75
=> 25 H.

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 3 Session 6 Answer Key

Adding Vines

Help Jack add the lengths of his bean vines. Use the number lines to show and solve each problem.

Question 1.
Green vine: 10 feet. Yellow vine: 20 feet. How long together? ________
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 98
Answer:
Total length of Green , yellow wine together = 30 feet.

Explanation:
Length of Green vine = 10 feet.
Length of Yellow vine = 20 feet.
Total length of Green , yellow wine together = Length of Green vine + Length of Yellow vine
= 10 + 20
= 30 feet.

Question 2.
Green vine: 9 feet. Yellow vine: 31 feet. How long together? _____
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 98
Answer:
Total length of Green , yellow wine together = 40 feet.

Explanation:
Length of Green vine = 9 feet.
Length of Yellow vine = 31 feet.
Total length of Green , yellow wine together = Length of Green vine + Length of Yellow vine
= 9 + 31
= 40 feet.

Question 3.
Green vine: 33 feet. Yellow vine: 47 feet. How long together? _____
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 98
Answer:
Total length of Green , yellow wine together = 80 feet.

Explanation:
Length of Green vine = 33 feet.
Length of Yellow vine = 47 feet.
Total length of Green , yellow wine together = Length of Green vine + Length of Yellow vine
= 33 + 47
= 80 feet.

Question 4.
Green vine: 49 feet. Yellow vine: 51 feet. How long together? _______
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 98
Answer:
Total length of Green , yellow wine together = 100 feet.

Explanation:
Length of Green vine = 49 feet.
Length of Yellow vine = 51 feet.
Total length of Green , yellow wine together = Length of Green vine + Length of Yellow vine
= 49 + 51
= 100 feet.

Question 5.
Green vine: 67 feet. Yellow vine: 33 feet. How long together? ______
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 98
Answer:
Total length of Green , yellow wine together = 100 feet.

Explanation:
Length of Green vine = 67 feet.
Length of Yellow vine = 33 feet.
Total length of Green , yellow wine together = Length of Green vine + Length of Yellow vine
= 67 + 33
= 100 feet.

Question 6.
Green vine: 99 feet. Yellow vine: 21 feet. How long together? ________
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 98
Answer:
Total length of Green , yellow wine together = 120 feet.

Explanation:
Length of Green vine = 99 feet.
Length of Yellow vine = 21 feet.
Total length of Green , yellow wine together = Length of Green vine + Length of Yellow vine
= 99 + 21
= 120 feet.

Question 7.
Green vine: 98 feet. Yellow vine: 22 feet. How long together? _______
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 98
Answer:
Total length of Green , yellow wine together = 120 feet.

Explanation:
Length of Green vine = 98 feet.
Length of Yellow vine = 22 feet.
Total length of Green , yellow wine together = Length of Green vine + Length of Yellow vine
= 98 + 22
= 120 feet.

Question 8.
Green vine: 110 feet. Yellow vine: 45 feet. Purple vine: 5 feet.
How long together? ________
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 98
Answer:
Total length of Green , yellow wine together = 160 feet.

Explanation:
Length of Green vine = 110 feet.
Length of Yellow vine = 45 feet.
Length of purple vine = 5 feet.
Total length of Green , yellow wine together = Length of Green vine + Length of Yellow vine + Length of purple vine
= 110 + 45 + 5
= 155 + 5
= 160 feet.

Question 9.
CHALLENGE Jack has two vines. The green vine is 60 feet long. The yellow vine is 40 feet long. How much longer is the green vine? _________
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 98
Answer:
20 feet longer is the green vine.

Explanation:
Length of Green vine = 60 feet.
Length of Yellow vine = 40 feet.
Total length of Green , yellow wine together = Length of Green vine + Length of Yellow vine
= 60 + 40
= 100 feet.
Difference:
Length of Green vine – Length of Yellow vine
= 60 – 40
= 20 feet.

Question 10.
CHALLENGE Jack has two vines. The green vine is 95 feet long. The yellow vine is 60 feet long. How much longer is the green vine? _________
Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 98
Answer:
35 feet longer is the green vine.

Explanation:
Length of Green vine = 95 feet.
Length of Yellow vine = 60 feet.
Total length of Green , yellow wine together = Length of Green vine + Length of Yellow vine
= 95 + 60
= 155 feet.
Difference:
Length of Green vine – Length of Yellow vine
= 95 – 60
= 35 feet.

Bridges in Mathematics Grade 2 Student Book Unit 2 Module 4 Session 3 Answer Key

Circle and then color in all the counting-by-2s numbers on this grid.

Bridges in Mathematics Grade 2 Student Book Unit 2 Answer Key Place Value & Measurement with Jack’s Beanstalks 99

Answer:

Explanation:
Number of 2’s:
2, 4, 6, 8, 10.
12,14,16,18,20.
22, 24, 26, 28, 30.
32, 34, 36, 38, 40.
42, 44, 46, 48, 50.
52, 54, 56, 58, 60.
62, 64, 66, 68, 70.
72, 74, 76, 78, 80.
82, 84, 86, 88, 90.
92, 94, 96, 98, 100.

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