Students can practice the Usage of Decimals Worksheet Questions and learn how decimals are used in calculating money, distance, mass, capacity, etc. Help your child get proficiency in math by asking them to solve the problems on decimal usage in the Worksheet on Use of Decimal. This handy Use of Decimal Worksheet is free to print and aids you in learning about how to use decimal in various units of measurements. Try to answer the problems in the Decimal Numbers Worksheet and improve on the areas you are lagging.

Do Read:

- Use of Decimal in Measuring the Length
- Use of Decimal in Measuring the Distance
- Use of Decimal in Measuring the Mass
- Use of Decimal in Measuring the Capacity

**Example 1.**

1. 15 Rupees 20 paisa

2. 25 rupees 30 paisa

3. 150 Rupees 50 paisa

**Solution:**

1.15 Rupees 20 paisa is written as 15.20 p.

2. 25 rupees 30 paise is written as 25.30 p

3. 150 Rupees 50 paisa is written as 150.50 p

**Example 2.**

1. 289 Rupees 40 paisa

2. 389 Rupees 25 paisa

**Solution:**

1.289 Rupees 40 paisa is written as 289.40 p.

2. 389 Rupees 25 paisa is written as 389.25 p.

**Write m and cm into m using decimals
Example 3.**

1. 20 m 50 cm

2. 130 m 20 cm

**Solution:**

1. We know that 1 cm=0.01 m

Substitute 1cm=0.01 in cm

=20 m +50 (0.01) m

=20m+0.5 m

=20.5 m

20 m 50 cm is written as 20.5 m.

2. Since, we know that 1 cm=0.01 m

Substitute 1cm=0.01 in cm

=130 m +20 (0.01) m

=130 m+0.2 m

=130.2 m

130 m 20 cm is written as 130.2 m.

**Example 4.
**Write m and cm into m using decimals

1. 60 m 10 cm

2. 100m 30 cm

**Solution:**

1. We know that 1 cm=0.01 m

Substitute 1cm=0.01 in cm

60 m +10(0.01) m

=60 m+0.1 m

=60.1 m

60 m 10 cm is written as 60.1 m

2.As we know that 1 cm=0.01 m

Substitute 1cm=0.01 in cm

=100 m +30 cm

=100 m+30(0.01) m

=100 m+0.3 m

=100.3 m

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**Write km and m into km using decimals
Example 5.**

1.68 km 70 m

2.120 km 50 m

3. 56 km 30 m

4. 190 km 25 m

**Solution:**

1. 68 km 70 m

we know that 1 m=0.001 km

Substitute 1m=0.001 km in m

=68 km +70(0.001)km

=68 km +0.07 km

=68.07 km

2. 120 km 50 m

we know that 1 m=0.001 km

Substitute 1m=0.001 km in m

=120 km + 50(0.001) m

=120 km+0.05 km

=120.05 km

3. 56 km 30 m

we know that 1 m=0.001 km

Substitute 1m=0.001 km in m

=56 km + 30 (0.001) km

=56 km+0.03 km

=56.03 km

4. 190 km 25 m

we know that 1 m=0.001 km

Substitute 1m=0.001 km in m

=190 km+25(0.001) km

=190 km+0.025 km

=190.025 km

**Convert kg and g into kg**

**Example 6.
**1. 90 kg 120 g

2. 50 kg 500 g

3. 25 kg 200 g

**Solution:**

1. 90 kg 120 g

we know that 1 gram=0.001 kg

Substitute 1m=0.001 km in m

=90 kg+120(0.001) kg

=90 kg+0.12 kg

=90.12 kg

2. 50 kg 500 g

we know that 1 gram=0.001 kg

Substitute 1m=0.001 km in m

=50 kg + 500(0.001) kg

=50 kg + o.5 kg

=50.5 kg

3. 25 kg 200 g

we know that 1 gram=0.001 kg

Substitute 1m=0.001 km in m

=25 kg + 200 (0.001) kg

=25 kg + 0.2 kg

=25.02 kg

**Convert l and ml to l**1. 5

Example 7.

*l*450

*ml*

2. 45

*l*630

*ml*

3. 22

*l*180

*ml*

**Solution:**

1. 5 *l* 450 *ml*

we know that 1 *ml*=0.001* l
substitute 1 ml=0.001l in ml
*=5

*l*+450(0.001)

*l*

=5

*l*+0.45

*l*

=5.45

*l*

2. 45

*l*630

*ml*

we know that 1

*ml*=0.001

*l*

substitute 1 ml=0.001l in ml

substitute 1 ml=0.001l in ml

=45

*l*+ 630(0.001)

*ml*

=45

*l*+ 0.63

*ml*

=45.63

*ml*

3. 22

*l*180

*ml*

we know that 1

*ml*=0.001

*l*

substitute 1 ml=0.001l in ml

substitute 1 ml=0.001l in ml

=22

*l*+ 180 (0.001)

*ml*

=22

*l*+ 0.18

*ml*

=22 .18

*ml*