Math Worksheet on Divide by 2-Digit Divisors will give your child various problems on dividing 3 digits or more numbers. Ask them to practice questions from Division by 2-Digit Divisors Worksheet and learn how to identify quotient and remainder in the further modules. Know the procedure of Long Division involving 2-Digit Divisors and get an idea of the concept. Try to practice using the Division by Two Digit Numbers Worksheet and cross the Solutions provided.

Division by 2 Digit Divisors Worksheets with Answers is free to use and easily accessible. They can be a great way to strengthen student’s basic skills on Facts about Division and Mental Division. Take your Division Skills to Next Level by Solving from the Simple Worksheets on Division with 2 Digit Numbers.

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## Simple Division with 2-Digit Divisors Worksheet

**Example 1:
**Divide 64878 by 62

**Solution:**

Here 6 <62, Put 0 in the quotient and subtract 0 from 6 i.e. 6-0=6.

Place 4 after 6 it becomes 64. We know that 64 is not exactly divisible by 62. 62 Ã—1=62. We will go for it.

Subtract 62 from 64 i.e. 64-62=2.

Bring down the digit 8 and place it after 2. It becomes 28.

Place 0 as quotient and subtract 0 from 28 i.e. 28-0=28

Bring down the digit 7. It becomes 287. We know that 287 is not exactly divisible by 62. i.e. 62 Ã—4=248.

Subtract 248 from 287.i.e. 287-248=39. Bring down the digit 8 and place it after 39. It becomes 398.

Place 6 as quotient and subtract 372 from 398 6 i.e. 398-372=26.**
**Hence, by dividing 64878 with 62 we get 1046 as quotient and 26 as the remainder.

**Example 2:**

## Find the quotient and remainder of 16869 by 31

Solution:

Solution:

As 1<31,Place 0 in the quotient and subtract 0 from 1 i.e. 1-0=1.

Bring down the digit 6 and place it after 1. It becomes 16.

As 16<31, Place 0 in the quotient and subtract 0 from 16 i.e. 16-0=16.

Bring down the digit 8 and place it after 16. It becomes 168. 168 is not exactly divisible by 31. 31 Ã— 5=155.

Subtract 155 from 168 i.e. 168-155=13.

Bring down the digit 6 and place it after 13. It becomes 136. It is not exactly divisible by 31. 31 Ã— 4=124.

Subtract 124 from 136 i.e. 136-124=12. Bring down the digit 9 and place it after 12.

It is not exactly divisible by 31. 31 Ã— 4=124.

Subtract 124 from 129 i.e. 129-124=5.

Hence by dividing 16869 by 31, 544 is the quotient and 5 is the remainder.

**Example 3:
**Divide 64838 by 72

**Solution:**

As 6 <72, place 0 as quotient and subtract 0 from 6 i.e. 6-0=6.

Bring down the digit 4 and it becomes 64. As 64<72, place 0 as the quotient and subtract 0 from 64.i.e. 64-0=64.

Bring down the digit 8 and it becomes 648. we know that 648 is exactly divisible by 72. 72 Ã— 9=648. place 9 in the quotient and subtract 648 from 648 i.e. 648-648=0.

Bring down the digit 7. As 7<72, Place 0 as the quotient and subtract 0 from 7. i.e. 7-0=7.

Bring down the digit 2 and place it after 7. It becomes 72. 72 is exactly divisible by 72 i.e. 72 Ã—1=72.

Place 1 as quotient and subtract 72 from 72 i.e. 72-72=0.

Hence, on dividing 64872 with 72 we get 901 as quotient and 0 as the remainder.

**Example 4:
**Find the quotient and remainder of 42824 by 53

**Solution:**

As 4< 53, place 0 in the quotient and subtract 0 from 4 i.e. 4-0=4.

Bring down digit 2 and place it after 4. It becomes 42.

As 42< 53, Place 0 in the quotient and subtract 0 from 42 i.e. 42-0=42.

Bring down the digit 8 and place it after 42. It becomes 428.

428 is not exactly divisible by 53.Â 53 Ã— 8=424. Subtract 424 from 428. i.e. 428-424=4.

Bring down digit 2 and place it after 4. As 42 < 53, place 0 as quotient and subtract 0 from 42. i.e. 42-0=42.

Bring down digit 4 and place it after 42. It becomes 424. We know that 424 is exactly divisible by 53. i.e. 53 Ã—8=424.

Hence by dividing 42824 with 53 we get 808 as the quotient and 0 as the remainder.

**Example 5:
**Divide 98553 by 91

**Solution:**

As 9<91, place 0 in the quotient and subtract 9-0=9.

Bring down the digit 8 and place it after 9. It becomes 98. It is not exactly divisible by 91. 91Ã—1=91.

Place 1 in the quotient and subtract 91 from 98. i.e. 98-91=7.

Bring down the digit 5 and place it after 7. It becomes 75.

As 75<91, place 0 in the quotient and place 0 below 75. 75-0=75.

Bring down the digit 5 and place it after 75. We know that 755 is not exactly divisible by 91. 91Ã—8=728.

Subtract 728 from 755. we get 27.

Bring down the digit 3 and place it after 27. It becomes 273.

we know that 91Ã—3=273. Place 3 in the quotient and subtract 273 from 273. i.e. 273-273=0.

Hence by dividing 98553 by 91 we get 1083 as the quotient and 0 as the remainder.

**Example 6:
**Divide 15300 by 50

**Solution:**

As 1<50, place 0 as the quotient and subtract 0 from 1.i.e. 1-0=1.

Bring down the digit 5 and place it after 1. It becomes 15.

As 15<50,place 0 as the quotient and subtract 0 from 15.i.e. 15-0=15.

Bring down the digit 3 and place it after 15. We know that 50 Ã—3=150. Place 3 as the quotient and subtract 150 from 153 i.e. 153-150=3.

Place 0 after 3 it becomes 30. As 30 <50, place 0 as the quotient and subtract 0 from 30. i.e. 30-0=30.

Bring down the digit 0 and place it after 30. It becomes 300.

We know that 50 Ã— 6=300.

Hence by dividing 15300 by 50 we get 306 as quotient and 0 as the remainder.

**Example 7:
**Find the Quotient and remainder of 18968 by 48

**Solution:**

As 1<48, Place 0 as the quotient. subtract 0 from 1. i.e. 1-0=1.

Bring down the digit 8 and place it after 1. It becomes 18.

As 18<48, Place 0 as the quotient. Subtract 0 from 18. i.e. 18-0=18.

Bring down the digit 9 and place it after 18. It becomes 189.

We know that 189 is not exactly divisible by 48. 48 Ã— 3=144.

Place 3 as quotient and subtract 144 from 189. i.e. 189-144=45.

Bring down the digit 6 and place it after 45. It becomes 456.

We know that 48 Ã— 9=432. Place 9as quotient and subtract 432 from 456 i.e. 456-432=24.

Bring down the digit 8 and place it after 24. It becomes 248.

We know that 48 Ã— 5=240. Place 5 as quotient and subtract 240 from 248.i.e. 248-240=8.Â Â **
**Hence, by dividing 18968 by 48 we get 395 as quotient and 8 as the remainder.

**Example 8:**

## Find the division of 58298 by 54

Solution:

Solution:

Here 5<54, place 0 as quotient and subtract 0 from 5=5

Bring down the digit 8 and place it after 5. It becomes 58.

We know that 54 Ã—1=54. Place 1as quotient and Subtract 54 from 58. i.e. 58-54=4.

Bring down digit 2 and place it after 4. It becomes 42. As 42<54, Place 0 as the quotient and subtract 0 from 42 i.e. 42-0=42.

Bring down the digit 6 and place it after 42. It becomes 426.

426 is not exactly divisible by 54. We know that 54 Ã—7=378. Subtract 378 from 426.i.e. 426-378=48.

Bring down the digit 6 and place it after 48. It becomes 486.

We know that 54 Ã— 9=486. Subtract 486 from 486.

Hence by dividing 58266 with 54 we get 1079 as quotient and 0 as the remainder.