Worksheets on Temperature Conversion available here will assist you in learning conversion of temperature from one scale of the unit to another easily. Practice the Temperature Conversion Problems covering questions on covering from Fahrenheit to Celsius and Celsius to Fahrenheit, Kelvin to Celsius, and Vice Versa. Step by Step Solutions provided for all the Temperature Conversion Word Problems Worksheet makes it easy for kids to use them as references if in case they needed any of them.

Do Check: Converting the Temperature from Celsius to Fahrenheit

## Temperature Conversion Practice Problems

**Example 1.**

Convert the temperature given below in the Celsius scale to Fahrenheit scale:

(i)35^{0}c

(ii)49^{0}c

(iii)68^{0}c

(iv)17^{0}c

(v)25^{0}c

(vi)98^{0}c

**Solution:**

To convert from Celsius to Fahrenheit we need to follow three steps

1. Multiply the Celsius by 9

2. Divide by 5

3. Add 32

(i) 35^{0}c

By Multiplying 35 with 9 we get 315.

Divide 315 by 5 we get 63.

Add 32 to 63 we get 95^{0}F.

Hence, 35^{0}c is 95^{0}F.

(ii) 49^{0}c

By Multiplying 49 with 9 we get 441.

Divide 441 by 5 we get 88.2.

Add 32 to 88.2 we get 120^{0}F.

Hence, 49^{0}c is 120^{0}F.

(iii)68^{0}c

By Multiplying 68 with 9 we get 612.

Divide 612 by 5 we get 122.4.

Add 32 to 122.4 we get 154.4^{0}F.

Hence, 68^{0}c is 154.4^{0}F.

(iv)17^{0}c

By Multiplying 17 with 9 we get 153.

Divide 153 by 5 we get 30.6.

Add 32 to 30.6 we get 62.6^{0}F.

Hence, 17^{0}c is 62.6^{0}F.

(v)25^{0}c

By Multiplying 25 with 9 we get 225.

Divide 225 by 5 we get 45.

Add 32 to 45 we get 77^{0}F.

Hence, 25^{0}c is 77^{0}F.

(vi)98^{0}c

By Multiplying 98 with 9 we get 882.

Divide 882 by 5 we get 176.4.

Add 32 to 176.4 we get 208.4^{0}F.

Hence, 25^{0}c is 208.4^{0}F.

**Example 2. **

Convert the temperatures below from the Fahrenheit scale to the Celsius scale.

(i)85^{0}F

(ii)48^{0}F

(iii)268^{0}F

(iv)97^{0}F

(v)35^{0}F

(vi)198^{0}F

**Solution:**

For converting the temperature from Fahrenheit to Celsius we need to follow the below steps.

1.Subtract 32 from the Fahrenheit

2.Multiply by 5.

3.Divide by 9.

(i)85^{0}F

By Subtracting 32 from 85 we get 53.

By Multiplying 53 with 5 we get 265.

By dividing 265 with 9 we get 29.44 C.

Therefore, 85^{0}F is converted to 29.44^{0}c.

(ii)48^{0}F

By Subtracting 32 from 48 we get 16.

By Multiplying 16 with 5 we get 80.

By dividing 80 with 9 we get 8.88 C.

Hence, 48 F is converted to 8.88^{0}c.

.(iii)268^{0}F

By Subtracting 32 from 268 we get 236.

By Multiplying 236 with 5 we get 1,180.

By dividing 1,180 with 9 we get 131.11 C.

Therefore, 268^{0}F is converted to 131.11^{0}c.

(iv)97^{0}F

By Subtracting 32 from 97 we get 65.

By Multiplying 65 with 5 we get 325.

By dividing 325 with 9 we get 36.11 C.

Hence, 97^{0}F is converted to 36.11^{0} c.

(v)35^{0}F

By Subtracting 32 from 35 we get 3.

By Multiplying 3 with 5 we get 15.

By dividing 15 with 9 we get 1.66 C.

Therefore, 35^{0}F is converted to 1.66^{0} c.

(vi)198^{0}F

By Subtracting 32 from 198 we get 166.

By Multiplying 166 with 5 we get 830.

By dividing 830 with 9 we get 92.22^{0} C.

Hence, 198^{0}F is converted to 92.22 c.

**Example 3.**

On Saturday the minimum temperature in Hyderabad was 78^{0}F. Find the temperature on the Celsius scale?

**Solution:**

The minimum temperature in Hyderabad = 78^{0}F

The temperature on the Celsius scale=5/9(78-32)

=5/9(46)

=25.55^{0} c.

Hence, the temperature in Hyderabad is 25.55^{0} c.

**Example 4.**

In July month the maximum temperature in Vijayawada was 39^{0}c. Find out the temperature in degree celsius of Vijayawada on that day?

**Solution:**

The maximum temperature in Vijayawada=39^{0}c

The temperature in degree celsius of Vijayawada=9/5(39+32)

=9/5(71)

=639/5

=127.8^{0}F.

**Example 5.
**The temperature in the Afternoon was 32c. It was dropped 3c in the evening. Find the temperature in the evening?

**Solution:**

The temperature in the Afternoon=32c

The temperature dropped in the evenig=3c

The temperature in the evening=32-3=29c.

Hence, the temperature in the evening is 29c.

**Example 6.
**The temperature was 32c on Thursday and 36c on Friday. How much did the temperature rise on Friday?

**Solution:**

The temperature on Thursday=32c

The temperature on Friday=36c

The temperature rise on Friday=36c-32c

=4c

Hence, the temperature rise on Friday was 4c.

**Example 7.
**Calcutta’s highest temperature was recorded as 48c and the lowest temperature is recorded as 32c. Find the difference in temperature?

**Solution:**

The highest temperature in Calcutta was recorded = 48c

The lowest temperature is recorded = 32c

The difference in temperature=48-32=16c

Therefore, the difference in temperature is 16c.

**Example 8.
**A liquid is heated at a rate of 7 degrees Celsius per minute. If the temperature now is at 43 degrees Celsius, how long will the temperature by 92 degrees Celsius?

**Solution:**

The given rate is 7c.

Initial temperature t1=43c

Final temperature t2=92c

Time taken t=t2-t1/rate

=92-43/7

=49/7=7minutes.

Therefore, it will take 7 minutes for the temperature to be 92 degrees celsius.