Our Roman Numerals Worksheet will help you in practicing and making you efficient in this topic. So our questions are based on roman numerations and rules that are used in solving them. In this Roman Numerals Comparison Worksheet, you will solve problems related to the comparison of two roman numerals, find the largest and smallest roman numeral among the given roman numbers. Look no further and begin practicing using our Worksheet on Comparing Roman Numerals.
Also, Read: Worksheet on Roman Numeration
Rules for Converting Roman Numerals to Numbers
We have to follow certain rules while converting roman numbers into Hindi – Arabic numerals as mentioned below
- When a roman number is given we have initially split the given number into digit, double-digit, triple-digit, quadruple-digit symbols
- Find the largest Roman numeral by using the decimal value.
- Now if the largest numeral appears first then we have to count how many times it is repeated. Remember a number can’t be repeated more than three times.
- Now if the number is repeated, multiply its value by the number of times it is repeated.
- Now add the value of roman to the value of a decimal number.
- If in case largest numeral appears second then subtract the value of the number before its value.
Rules for Converting Numbers to Roman Numerals
We have certain rules to covert Hindu-Arabic numbers into roman numerical as mentioned below.
- Each symbol can only be repeated three times.
- We have to split the given number into units form.
- Always remember if a smaller number is placed before a larger number, the number has the effect of addition. Which means the smaller number must be added to the larger number.
- And if a smaller number is placed after a larger number then we have to perform subtraction, which means we have to subtract a smaller number from a larger number
1. Compare and find the largest Roman numeral.
(i). MDCCCLXXIX, MDXXVI
(ii)CDXI, MDCCXI
(iii)MCMLX, DCCXLIII
(iv)CLVII, XXIV
(v)XXXVIII, XXV
Solution:
To the largest numeral among given numerals, we have to initially convert those roman numerals into Hindu-Arabic numbers.
We have to repeat the above steps till we get our number.
Now let’s solve our problems.
(i) MDCCCLXXIX, MDXXVI
First let’s covert MDCCCLXXIX = M + D + 3(C) + L + 2(X) + IX
= 1000 + 500 + 3(100) + 50 + 2(10) + 9
= 1879
Now, MDXXVI = M + D + 2(X) + VI
= 1000 + 500 + 2(10) + 6
= 1526
Now that we know MDCCCLXXIX = 1879 & MDXXVI = 1526
Since 1879 is greater than 1526
Answer:Â MDCCCLXXIX is larger than MDXXVI
(ii) CDXI, MDCCXI
First let’s covert CDXI = CD + XI
= (1000-100) + 10 + 1
= 911
Now, MDCCXI = M + D + 2(C) + X + I
= 1000 + 500 + 2(100) + 10 + 1
= 1711
Now that we know CDXI = 911 & MDCCXI = 1711
Since 1711 is greater than 911
Answer:Â MDCCXI is larger than CDXI
(iii). MCMLX, DCCXLIII
First let’s covert MCMLX = M + CM + L + X
= 1000 + (1000- 100) + 50 + 10
= 1960
Now, DCCXLIII = D + 2(C) + XL + 3(I)
= 500 + 2(100) + (50-10) + 3(1)
= 743
Now that we know MCMLX = 1960 & DCCXLIII = 743
Since 1960 is greater than 743
Answer:Â MCMLX is larger than DCCXLIII
(iv). CLVII, XXIV
First let’s covert CLVII = C + L + V + I + I
= 100 + 50 + 5 + 1 +1
= 157
Now XXIV = X + X + IV
= 10 + 10 + 4
= 24.
Now that we know CLVII = 157 & XXIV = 24
Since 157 is greater than 24
Answer:Â CLVII is larger than XXIV
(v). XXXVIII, XXV
First let’s covert: CLVII = 3(X) + V +3( I)
= 30 + 5 + 3
= 38
XXV = 2(V)
= 10 + 10 + 5
= 25.
Now that we know CLVII = 38 & XXV = 25
Since 38 is greater than 22
Answer:Â CLVII is larger than XXV
2. Compare and find the smallest Roman numeral.
(i). CMLVI, DLXXII
(ii). LXXXVI, XI
(iii). CXXV, XXV
(iv). CC, VI
(v). CCL, XXVI
Solution:
Now let’s solve our problems.
To the smallest numeral among given numerals, we have to initially convert those roman numerals into Hindu-Arabic numbers.
(i). CMLVI, DLXXII
First let’s covert CMLVI = CM + L + V + I
= 900+ 50 + 5 + 1
= 956
Now, DLXXII = D+ L + 2(X) + 2(I)
= 500 + 50 +2(10) + 2(1)
= 572
Now that we know CMLVI = 956 & DLXXII = 572
Since 572is smaller than 956
Answer:Â DLXXII is smaller than CMLVI
(ii). LXXXVI, XI
First let’s covert LXXXVI = L + 3(X) + V + I
= 50 + 30 + 5 + 1
= 86
Now, XI = X + I
= 10 + 1
= 11
Now that we know LXXXVI = 86 & XI = 11
Since 11 is smaller than 86
Answer:Â XI is smaller than LXXXVI
(iii). CXXV, XXV.
First let’s covert CXXV = C + 2(X) + V
= 100+ 2(10) + 5
= 125
Now XXV = 2(X) + V
= 2(10) + 5
= 25
Now that we know CXXV = 125 & XXV = 25
Since 25 is smaller than 125
Answer:Â XXV is smaller than CXXV
(iv). CC, VI.
First let’s covert CC = 2(C)
= 2(100)
= 200
Now LLVI = 2(L) + V + I
= 2(50) + 5 + 1
= 106
Now that we know CC = 200 & LLVI = 106
Since 106 is smaller than 200
Answer:Â LLVI is smaller than CC
(v). CCL, XXVI
First let’s covert CCL = 2(C) + L
= 2(100) + 50
= 250
Now, XXVI = 2(X) + V + I
= 2(10) + 5 + 1
= 26
Now that we know CCL = 250 & XXVI = 26
Since 26 is smaller than 250
3.Compare and fill in the blank with correct sign (<, >, =)
(i). MMVI ____ MLIX
(ii) XXVIII ____ LV
(iii) 105 ___ CV
(iv) CLXV ___ 165
(v) CLXXXIX ___ MCXXIV
Solution:
To compare any two Roman numerical or any two Hindu-Arabic numbers first we need to find decimal value for those numbers.
(i) MMMVI____ MLIX
First let’s covert MMMVI = 3(M) + V + I
= 3(1000) + 5 + 1
= 3006
MLIX = M + L + IX
= 1000 + 50 + (10 – 1)
= 1059
Now that we know MMMVI = 3006 & MLIX = 1059
As we know 3006 is greater than 1059.
So MMMVI is greater than MLIX
Answer: MMXVI > MLIX
(ii) XXVIII____ LV
First let’s covert XXVIII = 2(X) + V + 3(I)
= 2(10) + 5 + 3(1)
= 28
LV = L + V
= 50 + 5
= 55
Now that we know XXVIII = 28 & LX = 55
As we know 28 is smaller than 55.
So XXVIII is smaller than LX
Answer: MMXVI < MLIX
(iii) 105___ CV
To compare any two digits they have to be in the same format, so let’s covert Hindu-Arabic number 105 into roman numerals.
So 105 = 100 + 5
= CV
Answer: 105 = CV
(iv). CLXV ___ 165
To compare any two digits they have to be in same format, so let’s convert roman numerical CLXV into -Arabic number.
As we already know steps to convert any given roman numerical to Hindu-Arabic digit let’s follow those steps and find out.
Let’s covert CLXV = C + L + V + X
= 100 + 50 + 10 + 5
= 165
Answer: CLXV = 165
(v). CLXXXIX____ MCXXIV
Following above mentioned steps and rules
First let’s covert CLXXXIX = C + L + 3(X) + IV
= 100 + 50 + 3(10) + (5-1)
= 189
MCXXIV = M + C + 2(X) + IV
= 1000 + 100 + 2 (10) + (5 – 1)
= 1124
Now that we know CLXXXIX = 189 & MCXXIV = 1124
As we know 189 is smaller than 1124.
So CLXXXIX is smaller than MCXXIV
Answer: CLXXXIX < MCXXIV