 In this Adding Units of Measurement worksheet, you will find various questions on the addition of metric measures. The addition of metric measures is similar to the addition of ordinary numbers. In metric addition, we will arrange them in columns according to their units and we will add them.

Alongside you need to know about converting the metric measures from one unit to another unit. You can use and download this Worksheet on Addition of Metric Measures for free, and take a printout of the page for the sake of practicing purposes. Free Interactive Exercises in the Metric Measurements Addition Worksheet will improve subject knowledge on the concept.

### Addition of Metric Measures Worksheet PDF

Problem 1:
Find the value of the  132 g 24 mg + 64 g 50 mg =?

Solution:

As given in the question, the value is 132 g 24 mg + 64 g 50 mg
Now, we can perform the addition operation in between the given values to get the final value. The addition means adding given two numbers and get the resultant sum.
So, the given values are 132 g 24 mg + 64 g 50 mg,
After performing the addition the value is,
132 g 24 mg + 64 g 50 mg = 196 g 74 mg
Therefore, the value of the 132 g 24 mg + 64 g 50 mg = 196g 74mg.

Problem 2:
Find the value of the following:
8 kg 6 hg 3 dag 1 g + 5 kg 4 hg 7 dag 6 g

Solution:

As given in the question, the number is 8 kg 6 hg 3dag 1 g + 5 kg 4 hg 7dag 6 g
Now, we will find the value of the given number. In between the given number ‘+’ (plus sign) is there. So, we perform the addition operation to get the sum value.
The addition means adding of given numbers and the resultant value is a sum.
So, the value is 8 kg 6 hg 3dag 1 g + 5 kg 4 hg 7dag 6 g, first arrange the given numbers in the column vertically and add them from right to left as shown below Therefore, the final value of the given numbers is 14kg 1hg 0dag 7g.

Problem 3:
Find the value of 6kl 4 hl 5 dal 2 l + 4kl 7 hl 3 dal 6 l + 2kl 9 hl 1 dal 0 l

Solution:

As given in the question, the number is 6kl 4 hl 5 dal 2 l + 4kl 7 hl 3 dal 6 l + 2kl 9 hl 1 dal 0 l
Now, we will find the value of the given number. In between the given number ‘+’ (plus sign) is there. So, we perform the addition operation to get the sum value.
The addition means adding of given numbers and the resultant value is the sum.
So, the value is 6kl 4 hl 5 dal 2 l + 4kl 7 hl 3 dal 6 l + 2kl 9 hl 1 dal 0 l first arrange the given numbers in the column vertically and add them from right to left as shown below, Now, we can perform the addition perform as shown below, Therefore, the sum of 6kl 4 hl 5 dal 2 l + 4kl 7 hl 3 dal 6 l + 2kl 9 hl 1 dal 0 l is 14kl 0 hl 9 dal 8l.

Problem 4:
Find the sum of the below-given value,
242 km 200 m + 186 km 136 m + 112 km 326 m

Solution:

In the given question, the value is 242 km 200 m + 186 km 136 m + 112 km 326 m
Now, we can find the sum of the given value.
In the given value, ‘+’ (plus sign) is present. So, we can perform the addition operation of the given value. In addition, we will add given two numbers and the resultant value is the sum.
So, the given value is 242 km 200 m + 186 km 136 m + 112 km 326 m.
After performing the addition operation, the resultant sum value is,
242 km 200 m + 186 km 136 m + 112 km 326 m = 540 km 662 m.
Therefore, the sum of the given value is 540 km 662 m.

Problem 5:
Raji has 8 kg 250 g of rice in a bag and she added more than 6 hg 450 g to it. How much amount of rice is in the bag?

Solution:

As given in the question,
Weight of rice in bag = 8 kg 250 g
Weight of rice she added = 6 hg 450 g
Now, we find the total weight of the rice bag using the addition law.
So, the total weight of the rice in bag = weight of rice in bag + weight of rice she added. Therefore, the total amount of rice in the bag is 8kg 6 hg 700 g.

Problem 6:
Add 48m 43 cm and 32m 8cm. Express the sum in meters.

Solution:

As given in the question, the value is 48m 43cm and 32m 8cm.
Now, we need to find the value in meters. Using addition, we add the given two numbers and obtain the resultant value i.e. sum.
Convert the cm value into meter value at first and then we can add the given values easily.
100 cm = 1 meter
So, the given numbers in meters are,
48 m 43 cm = 48.43 m
32 m 8 cm = 32.08 m
48.43 m + 32.08 m = 80.51 m.
Hence, the sum of given values in meters is 80.51 m.

Problem 7:
John walked 5.326 km on Monday, 9.052 km on Tuesday, and some distance 18.9 km walked on Wednesday. How much did he walk on those three days?

Solution:

As given in the question,
He walked 5. 326 km on Monday.
He walked 9.052 km on Tuesday.
He walked 18.9 km on Wednesday.
Now, we will find the total km he walked on those three days.
So, the given values are,
5.326 km + 9.052 km + 18. 009 km
We have to perform the addition operation, you will get the total value.
5.326 km + 9.052 km + 18. 009 km = 32.387 km
Therefore, the total distance he walked on those three days is 32. 387 km.

Problem 8:
Akhila bought 2 pieces of cloth. one of them was 34 cm long, the second one was 53 cm long. How much cloth did she buy altogether?

Solution:

As given in the question, Akhila bought 2 pieces of cloth.
One of them was 34 cm long.
The second one was 53 cm long.
Now, let us find the total cm of cloth did she bought altogether.
So, the total of cloth is 34 cm + 53 cm,
34 cm + 53 cm = 87 cm.
Therefore, the total cloth she bought is 87 cm.

Problem 9:
Find the value of the below figure, Solution:

As given in the question, the figure consists of some value.
Now, we can find the value of the given values using the addition law.
So, the sum of the given values is as shown in the below figure, Hence, the resultant sum of the given metric values is 118.602 dal.

Problem 10 :
The length of a rectangular garden is 12.75 m and its breadth is 8.25 m. How much fencing will be required for the 4 sides of this rectangular garden?

Solution:

In the given question, rectangular length and breadth are given.
Now, we will find how much fencing is required.
The rectangular garden length is 12.75 m.
The rectangular garden breadth is 8.25 m.
The rectangular has 4 sides, so the length and breadth of both sides’ values are the same.
So, the fencing required is,
12.75 m + 8.25 m+ 12. 75m + 8.25 m = 42.00 m
Therefore, the fencing required for the 4 sides of the garden is 42 m.

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