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## Word Problems on Division by 2 Digit Number

Here we will solve some of the word problems on division by 2-digit numbers. Apply the same method for solving the word problems on division by 2-digit numbers.

### 2-Digit Division Problems with Answers

**Example 1:**

32 chocolates are distributed among 16 children. How many chocolates did each child get?

**Solution:**

No of chocolates distributed=32

No of Children=16

Total no of chocolates each child get=32÷16=2.

Therefore each child got 2 Chocolates.

**Example 2:**

The price of the three apples is 99. Find the cost of 2 apples?

**Solution:**

The price of 3 apples=99

The cost of one apple=99÷3=33

Therefore, the cost of two apples=33*2=66.

**Example 3:**

One packet has 24 sweets. How many packets will contain 216 sweets? How many sweets are there in 3 packets?

**Solution:**

No. of sweets in each packet=24.

No. of packets required for 216 sweets = 216÷24=9.

No of sweets in 3 packets =24*3=72.

**Example 4:**

A class of 90 students was taken on a tour. They were taken by buses, each bus would contain 30 students. Find the no of buses required?

**Solution:**

No of students taken to a tour=90

No. of students in each bus=30

No. of buses required for 90 students=90÷30=3.

Therefore, 3 buses required for 90 students.

**Example 5:**

In a godown, Rajesh has 93 rice bags. If he decides to give 5 rice bags to each of his friends. How many friends will get the rice bags? How many will be left?

**Solution:**

No of rice bags Rajesh has=93

No of rice bags Rajesh gave to each of his friends=5

No of Rajesh friends will get the rice bags=93÷5=18

No of rice bags given to his friends=18*5=90

Therefore, No of bags left=93-90=3.

**Example 6:**

The cost of 8 chocolates is 96. Find the cost of 3 chocolates?

**Solution:**

The cost of 8 chocolates=96

The cost of 1 chocolates=96÷8=12

The cost of 3 chocolates=3*12=36.

Therefore, the cost of 3 chocolates=36.

**Example 7:**

There are 98 marbles. If there are 14 boxes, how many marbles can be kept in each box? Also, find the no of marbles that can be kept in 2 boxes?

**Solution:**

No of marbles=98

No of boxes=14

No of marbles in each box=98÷14=7

No of marbles in 2 boxes=2*7=14.

**Example 8:**

There are 96 artificial flowers. If 12 flowers are to be arranged in one wase. Find the total no of vases required to arrange 96 flowers?

**Solution:**

No of flowers=96

No of flowers required for one vase=12

No of vases required for arranging 96 flowers=96÷12=8

Therefore, we can arrange 96 flowers in 8 vases.

**Example 9:**

There are 98 students in the class. If 16 members can be seated in a row. Find the total no of rows required to arrange 98 students?

**Solution:**

No of students in the class=98

No of students in a row=16

No of rows required=98÷16=6

Therefore 6 rows required for arranging 98 students.

**Example 10:**

Gita bought 90 pens and put 10 pens in one packet. How many packets required for 10 pens?

**Solution:**

No of pens Gita has=90

No of pens in one packet=10

No of packets required for 90 pens=90÷10=9

Therefore 9 packets required for arranging 90 pens.

**Example 11:**

The price of 12 Biscuit packets is 84rs. Sita has only 60 rs. How many Biscuit packets Sita can buy? How much money did she have after buying Biscuits?

**Solution:**

Price of 12 Biscuit packets=84

price of each Biscuit packets=84÷12=7

No of Biscuit packets Sita can buy=60÷7=8

Therefore Sita can buy 8 biscuit packets for 56rs.

Sita has left money=60-56=4rs.