Are you stuck up at some point while calculating the rectangle area? Then, this article will shed some light on you regarding how to calculate the length, breadth of a rectangle using its area. You will get an idea of the formula in finding the Length L, width B using Area A, Procedure for finding so, etc. explained clearly. Answer the Questions on finding Length, Width given the Area of a Rectangle and enhance your problem-solving ability on the concept. Students of 5th Grade can get benefitted a lot in terms of knowledge on the topic as well as to have strong fundamentals for higher classes.
Also, Check:
- To find Area of a Rectangle when Length and Breadth are of Different Units
- Worksheet on Area and Perimeter of Rectangles
- Perimeter and Area of Rectangle
How to find the Length and Width of a Rectangle when given the Area?
Example 1.
Find the breadth of the rectangle whose length is 8 cm and the area is 72 sq cm?
Solution:
Given,
The length of the rectangle=8 cm
The area of the rectangle=72 sq cm
The breadth of the rectangle=?
We know that Area= length × breadth
Therefore,breadth=Area/length
breadth=72/8=9 cm
Therefore, the breadth of the rectangle is 9 cm.
Example 2.
Find the length of the rectangle whose breadth is 500 cm and the area is 20 sq m?
Solution:
Given,
The breadth of the rectangle=500 cm
we know that 100 cm=1 m
500cm=500/100=5 m
The area of the rectangle=20 sq m
The length of the rectangle=?
We know that Area= length × breadth
Therefore,length=Area/breadth
=20/5=4 m
Hence, the length of the rectangle is 4 m.
Example 3.
A rectangle with a length of 13 units longer than its width and an area of 30 sq units. Find the length of the rectangle’s shortest side?
Solution:
A rectangle has a length of 13 units longer than its width i.e. l=w+13 —> eq 1
Area of the rectangle=30
l × w=30 —>eq 2
Substitute l=w+13 in eq 2
(w+13) × w=30
w2+13 w=30
w2+13 w-30=0
Factor the polynomial
(w-2)(w+15)=0
w=2,or w=-15
-15 is not valid as the width for the rectangle.
2 is the width of the rectangle which is shorter side since the length is 13 units longer(l=w+13).
Example 4.
If the area of the rectangle is 55 sq cm and the length of the rectangle is 11 cm. Find the breadth of the rectangle?
Solution:
Given,
The area of the rectangle=55 sq cm
The Length of the rectangle=11 cm
The breadth of the rectangle=?
We know that length × breadth=Area
breadth=Area/length
breadth=55/11=5 cm
Hence, the Breadth of the rectangle is 5 cm.
Example 5.
If the area of the rectangle is 605 sq cm and its length is five times the width. Find the length and width of the rectangle?
Solution:
Given,
The area of the rectangle=605 sq cm
Length is five times the width.
Let the width of the rectangle be x.
The length of the rectangle is 5x.
We know that area of the rectangle=length × breadth
605=5x.x
5x2=605
x2=605/5=121
x=11
The length of the rectangle is 5x=5(11)=55 cm
The breadth of the rectangle is x=11 cm
Therefore, the length and breadth of the rectangle are 55 cm,11 cm.
Example 6.
The area of the rectangular screen is 280 sq m. Its length is 14 m. Find its width?
Solution:
Given,
The area of the rectangular screen is =280 sq m
The Length of the rectangular screen=14 m
The width of the rectangular screen is=?
By the formula, Area=length × breadth
280 sq m=14 × breadth
breadth=280/14
=20
Hence, the breadth of the rectangle is 20 m.
Example 7.
The area of the rectangular house is 2000 sq m. The width of the rectangular house is 200 meters. Find the length of the rectangular house?
Solution:
Given,
The area of the rectangular house is =2000 sq m
The width of the rectangular house is =200 meters
The length of the rectangular house=?
As we know that area=length × breadth
length= Area/breadth
=2000/200=10 m
Hence, the length of the rectangular house=10 m.
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