# To find Area of a Rectangle when Length and Breadth are of Different Units | How to Calculate Rectangle Area?

Finding the Area of a Rectangle can be tricky when it comes to different units. In such a case, you need to convert them to the same units and then solve them using the basic formula. Try to solve the problems in the rectangle area on a frequent basis and understand how to approach similar problems. Students of 5th Grade Math can learn how to calculate the area of a rectangle when both length and breadth are of different units of length. Know the formula to find the area of a rectangle, steps explained clearly.

Do Check:

Example 1.
Find the area of a rectangle whose length is 20 cm and breadth is 40 mm?

Solution:

Given,
The Length of a rectangle=20 cm
We know that 10 mm=1 cm
Therefore 40 mm=40/10 cm=4 cm
The Breadth of a rectangle=4 cm
=20 cm Ã— 4 cm
=80 sq cm
Hence, the area of the rectangle is 80 sq cm.

Example 2.
Find the area of the rectangle whose length is 24 m and breadth is 300 cm?

Solution:

Given,
Length of a rectangle=24 m
The breadth of a rectangle=34 cm
we know that 100 cm=1 m
Therefore, 34 cm=300/100 m=3 m
Area of the rectangle=length Ã— breadth
=24 m Ã— 3 m= 72 sq m

Example 3.
Find the area of the rectangle whose length is 15 cm and breadth is 62 mm?

Solution:

Given,
The area of the rectangle=15 cm
The breadth of the rectangle=62 mm
We know that 10 mm=1 cm
Therefore, 62 mm=62/10 cm=6.2 cm
We know that Area of the rectangle=length Ã—Â  breadth
=15 cm Ã— 6.2 cm
=93 sq cm

Example 4.
A rectangular room has a length of 13 m and a breadth of 40 cm. How much carpet is required to cover the entire room?

Solution:

The area of the room is equal to the area of the carpet.
Length of the rectangular room=13 m
The breadth of the rectangular room=40 cm
We know that 100 cm=1m
Therefore, 40 cm=40/100 m=2/5 =0.4 m
Area of the rectangle=length Ã— breadth
=13 m Ã— 0.4 m
=5.2 sq m
So the area of the carpet is 5.2 sq m.
Hence, a 5.2 sq m carpet is required.

Example 5.
One side of the rectangle is 7 inches and another side is 9 m. Find the area of the rectangle in inches?

Solution:

Given,
One side of the rectangle=7 inches
Another side of the rectangle=9 m
We know that 1 m=39.37 inch
9 m=9 Ã— 39.37 inches
=354.33 inches
Area of rectangle is=length Ã— breadth
=7 inches Ã— 354.33 inches
=2,480.31 inches
Hence, the area of a rectangle is 2,480.31 inches.

Example 6.
The length of the rectangle is 5 cm and the breadth of the rectangle is 205 cm. If the length is greater by 2 m, what should be the width in cm so that the new rectangle has the same area as that of the first one?

Solution:

Given,
The length of the first rectangle=5 cm
The breadth of the first rectangle=205 cm
The length of the new rectangle=5 cm+2m
we know that 1m=100 cm
2 m=2 Ã— 100=200 cm
The length of the new rectangle is=5 cm +200 cm=205 cm
The area of the first rectangle=205 cmÃ—5 cm=1025sq cm
The breadth of the new rectangle=w Ã— 205 cm=1025 sq cm
w=1025/205=5
Hence, the width of the new rectangle is 5 cm.

Example 7.
How many square tiles with the side of 3 cm cover the surface of a rectangular room with a length of 16 cm and a width of 9 m?

Solution:

Given,
Side of the square=3 cm
Length of the rectangular room=16 cm
Width of the rectangular room=9 m
We know that 1m=100 cm
9 m=9 Ã— 100 cm=900 cm
Area of the rectangular room=16 cm Ã— 900 cm
=14400 sq cm
Area of the square=32=9 sq cm
No. of square tiles required to cover the surface of rectangular room=14400/9=1600 square tiles
Hence, 1600 square tiles are required to cover the surface of the rectangular room.

Example 8.
A square and a rectangle which has a length of 2 m with a width of 2 cm have the same area. Find the area of the rectangle in cm and side of a square?

Solution:

Given,
The length of the rectangle=2 m
=2 Ã— 100 cm=200 cm
The width of the rectangle=2 cm
Area of the rectangle=200 cm Ã— 2 cm=400 sq cm
Hence, the area of the rectangle is 400 sq cm.
Also given, the area of rectangle and square has the same area.
So the area of the square=400 sq cm
We know that Area of the square=side Ã— side
Side of the square=$$\sqrt{ 400 }$$
=20
Hence, the side of the square is 20

Example 9.
The length of the rectangle is 500 cm and the breadth of the rectangle is 6 cm. If the length is smaller by 2 m, what should be the width in cm so that the new rectangle has the same area in sq cm as that of the first one?

Solution:

Given,
the length of the first rectangle=500 cm
The breadth of the rectangle=6 cm
The area of the first rectangle=500Ã—6=3000 sq cm
The length of the new rectangle=5cm-2m
we know that 1m=100 cm
2m=200 cm
500 cm-200 cm=300 cm
The breadth of the new rectangle=w Ã— 300=3000
w=3000/300=30
Hence, the width of the new rectangle is 30 cm.

Example 10.
How many boxes whose length and breadth are 3 cm and 5 m respectively are needed to cover a rectangular region whose length and breadth are 220 cm and 700 cm?

Solution:

Given,Â  Length of the box is 3 cm
The breadth of the box is 5 m
We have to convert 5 m into cm because all the units are in cm
We know that 1m=100 cm
5m=500 cm
Region length is 220 cm
we know the formula,
The area of a rectangle=length Ã— breadth
Therefore, Area of region = l x b
Area of region = 220 cm x 700 cm= 154000 cmÂ²
Again use theÂ  area of a rectangle formula,
Area of one box is = 3 cm x 500 cm
= 1500 cmÂ²
Number of boxes = Area of region /Area of one box = 154000/1500 =102
Thus, 102 boxes are required.

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