Practice with the help of Spectrum Math Grade 5 Answer Key Chapter 8 Pretest regularly and improve your accuracy in solving questions.
Spectrum Math Grade 5 Chapter 8 Pretest Answers Key
Check What You Know
Complete the following.
Question 1.
a. 6 ft. = _____________ yd.
Answer:
2 yd.
Explanation:
We know that,
1 yd = 3 ft.
6 ft = \(\frac{6}{3}\) = 2 yd.
b. 3 mi. = _____________ ft.
Answer:
15,840 ft.
Explanation:
We know that,
1 mi = 5,280 ft.
3 mi = 3 x 5,280 = 15,840 ft.
Question 2.
a. 4 qt. = _____________ pt.
Answer:
8 pt.
Explanation:
We know that,
1 qt = 2 pt.
4 qt = 4 x 2 = 8 pt.
b. 2 mi. 3,400 ft. = _____________ ft.
Answer:
13,960 ft.
Explanation:
Given,
2 mi. 3,400 ft. = _____________ ft.
convert miles to feet and then add.
We know that,
1 mi = 5,280 ft.
2 mi = 2 x 5,280 = 10,560ft.
So, 10,560 + 3,400 = 133,960 ft.
Question 3.
a. 5 gal. = _____________ qt.
Answer:
20 qt.
Explanation:
We know that,
1 gal = 4 qt.
5 gal = 5 x 4 = 20 pt.
b. 3 lb. = _____________ oz.
Answer:
48 oz.
Explanation:
We know that,
1 lb = 16 oz.
3 lb = 3 x 16 = 48 oz.
Question 4.
a. 500 mm = _____________ cm
Answer:
50 cm.
Explanation:
We know that,
1 cm = 10 mm
500 mm = \(\frac{500}{10}\) = 50 cm.
b. 6 L = _____________ mL
Answer:
6,000mL.
Explanation:
We know that,
1 L = 1,000 mL
6 L = 6,000 mL.
Question 5.
a. 8 kg = _____________ g
Answer:
8,000 g.
Explanation:
We know that,
1 kg = 1,000 g
8 kg = 8 x 1,000 = 8,000 g.
b. 12,000 mL = _____________ L
Answer:
12 L.
Explanation:
We know that,
1 L = 1,000 mL
12,000 mL = \(\frac{12,000}{1,000}\) = 12 L.
Draw a line plot to organize the data. Then, solve the problem.
Question 6.
Joseph needs to run 3 miles during his workout for the soccer team. He begins practice by running \(\frac{1}{2}\) mile and he takes 3 breaks during practice to run if mile each time. How much more will he need to run at the end of practice to finish his 3 miles?
Answer:
1\(\frac{1}{2}\) miles.
Explanation:
Joseph needs to run 3 miles during his workout for the soccer team.
He begins practice by running \(\frac{1}{2}\) mile and he takes 3 breaks.
3 – (\(\frac{1}{2}\) + \(\frac{1}{2}\) +\(\frac{1}{2}\))
= 3 – \(\frac{1+1+1}{2}\)
= 3 – \(\frac{3}{2}\)
= \(\frac{6 – 3}{2}\)
= \(\frac{3}{2}\)
= 1\(\frac{1}{2}\) miles.
Find the perimeter and area of the shapes below.
Question 7.
a.
P = ____________
A = ____________
Answer:
P = 20 ft.
A = 24 sq ft.
Explanation:
We know that,
The perimeter is the sum of the sides of a figure.
To find the perimeter, add the length of the sides.
So, the perimeter of the given rectangle is 6 + 6 + 4 + 4 = 20 ft.
We know that,
Area is the number of square units needed to cover a surface.
To calculate the area of a square or rectangle,
multiply the measure of the length by the measure of the width.
length = 4 ft; width = 6ft.
A = 4 x 6 = 24 sq ft.
b.
P = ____________
A = ____________
Answer:
P = 28 ft.
A = 39 sq ft.
Explanation:
We know that,
The perimeter is the sum of the sides of a figure.
To find the perimeter, add the length of the sides.
So, the perimeter of the given figure is 7 + 7 + 5 + 5 + 2 + 2 = 28 ft.
To calculate the area of an irregular shape,
you must first divide the shape into smaller rectangles or squares.
Then, add the area of each rectangle and square together to find the total area of the irregular shape.
Area of square = 5 x 5 = 25 ft.
Area of rectangle = 7 x 2 = 14 ft
A = 25 + 14 = 39 ft
So, Area of irregular shape = 39 sq ft.
Find the volume of each rectangular solid.
Question 8.
a.
V = ____________
Answer:
V = 36 cu in.
Explanation:
The volume of a rectangular solid can be found by figuring out how many cubes of a particular unit size will fit inside the shape.
First, divide the figure into given length units.
Next, divide the figure into given height units.
Finally, divided the figure into given width units.
Length = 3 in, height = 6 in, width = 2 in.
So, 3 x 6 x 2 = 36 cubic in.
b.
V = ____________
Answer:
V = 64 cu in.
Explanation:
The volume of a rectangular solid can be found by figuring out how many cubes of a particular unit size will fit inside the shape.
First, divide the figure into given length units.
Next, divide the figure into given height units.
Finally, divided the figure into given width units.
Length = 4 ft, height = 4 ft, width = 4 ft.
So, 4 x 4 x 4 = 64 cubic feet.
Solve each problem.
Question 9.
Mr. Woodson built a rectangular fence around his yard. The fence is 60 feet long and 35 feet wide. What is the area of the yard?
The area of the yard is _____________ square feet.
Answer:
The area of the yard is 2,100 square feet.
Explanation:
Given that,
Mr. Woodson built a rectangular fence of 60 feet long and 35 feet wide.
Area of the yard = length x width
length = 60 ft; width = 35 ft.
A = 60 x 35
A = 2,100 sq ft.
Question 10.
Angelica is wrapping a present in a rectangular box. The box is 10 cm in height, 45 cm in length, and 20 cm in width. What is the volume of the box?
The volume of the box is ___________ cubic centimeters.
Answer:
The volume of the box is 9,000 cubic centimeters.
Explanation:
Given that,
Angelica is wrapping a present in a rectangular box of 10 cm in height, 45 cm in length, and 20 cm in width.
The volume of the box = Length x Width x Height.
length = 45 cm, width = 20 cm, height = 10 cm.
V = 45 x 20 x 10
V = 9,000 cu cm.
Question 11.
The school is standing students side-by-side to form a rectangle. If the rectangle is 20 meters long and 10 meters wide, what is its area?
The area is ___________ square meters.
Answer:
The area is 200 square meters.
Explanation:
Given that,
The school is standing students side-by-side to form a rectangle of 20 m long and 10 m wide.
Area of the rectangle = length x width
length = 20 ft; width = 10 ft.
A = 20 x 10
A = 200 sq ft.
Question 12.
Akira began work at 8:03 a.m. He finished at 4:35 p.m. How long did Akira work?
Akira worked for ___________ hours and ___________ minutes.
Answer:
Akira worked for 8 hours and 32 minutes.
Explanation:
Given that,
Akira began work at 8:03 a.m.
He finished at 4:35 p.m.
Number of hours worked by Akira,
First, count the number of whole hours between the starting time and finishing time.
8:03 a.m to 4:35 p.m= 8 hours.
Next count the remaining minutes.
4:03 p.m to 4:35 p.m = 32 minutes.
Finally, Add the hours and minutes.
8 hr + 32 min = 8:32