Practice with the help of Spectrum Math Grade 5 Answer Key Chapter 5 Lesson 5.6 Problem Solving regularly and improve your accuracy in solving questions.
Spectrum Math Grade 5 Chapter 5 Lesson 5.6 Problem Solving Answers Key
Solve each problem. Write answers in simplest form. Show your work.
Question 1.
Caroline needs 3\(\frac{1}{7}\) cups of sugar for her first batch of brownies and 2\(\frac{8}{9}\) cups of sugar for a second batch. How much sugar does she need in all?
Caroline needs ___________ cups of sugar.
Answer:
Given,
Caroline needs 3\(\frac{1}{7}\) cups of sugar for her first batch of brownies and 2\(\frac{8}{9}\) cups of sugar for a second batch.
3\(\frac{1}{7}\) + 2\(\frac{8}{9}\)
3 + 2 + \(\frac{1}{7}\) + \(\frac{8}{9}\)
5 + \(\frac{1}{7}\) + \(\frac{8}{9}\)
5 + 1 \(\frac{2}{63}\) = 6 \(\frac{2}{63}\) cups of sugar
Question 2.
Robert’s gas tank has 5\(\frac{3}{5}\) gallons of gas in it. If he adds 7\(\frac{2}{3}\) gallons, how much gas will be in the tank?
There will be ____________ gallons of gas in the tank.
Answer:
Given,
Robert’s gas tank has 5\(\frac{3}{5}\) gallons of gas in it.
he adds 7\(\frac{2}{3}\) gallons
5\(\frac{3}{5}\) + 7\(\frac{2}{3}\)
5 + 7 + \(\frac{3}{5}\) + \(\frac{2}{3}\)
12 + \(\frac{3}{5}\) + \(\frac{2}{3}\) = 13 \(\frac{4}{15}\)
There will be 13 \(\frac{4}{15}\) gallons of gas in the tank.
Question 3.
A hamburger weighs \(\frac{1}{3}\) pound, and an order of french fries weighs \(\frac{1}{4}\) pound. How many pounds total will a meal of hamburger and french fries weigh?
The meal will weigh _______________ pounds.
Answer:
Given,
A hamburger weighs \(\frac{1}{3}\) pound, and an order of french fries weighs \(\frac{1}{4}\) pound.
\(\frac{1}{3}\) + \(\frac{1}{4}\)
LCM = 12
\(\frac{4}{12}\) + \(\frac{3}{12}\) = \(\frac{7}{12}\)
The meal will weigh \(\frac{7}{12}\) pounds.
Question 4.
Jonn is 5\(\frac{6}{10}\) feet tall ana Jamar is \(\frac{5}{8}\) feet taller than John. How tall ¡s Jamar?
Jamar is _____________ feet tall.
Answer:
Given,
Jonn is 5\(\frac{6}{10}\) feet tall ana Jamar is \(\frac{5}{8}\) feet taller than John.
5\(\frac{6}{10}\) + \(\frac{5}{8}\)
5 + \(\frac{6}{10}\) + \(\frac{5}{8}\) = 6 \(\frac{9}{40}\)
Jamar is 6 \(\frac{9}{40}\) feet tall.
Question 5.
Mrs. Stevenson has used 4\(\frac{2}{3}\) inches of string. She needs 1\(\frac{6}{7}\) inches more. How much string will Mrs. Stevenson have used when she is done?
Mrs. Stevenson will have used ______________ inches of string.
Answer:
Given,
Mrs. Stevenson has used 4\(\frac{2}{3}\) inches of string.
She needs 1\(\frac{6}{7}\) inches more.
4\(\frac{2}{3}\) + 1\(\frac{6}{7}\)
4 + \(\frac{2}{3}\) + 1 + \(\frac{6}{7}\)
4 + 1 + \(\frac{2}{3}\) + \(\frac{6}{7}\)
5 + \(\frac{2}{3}\) + \(\frac{6}{7}\) = 6 \(\frac{11}{21}\)
Mrs. Stevenson will have used 6 \(\frac{11}{21}\) inches of string.
Question 6.
It takes Lacy 8\(\frac{1}{3}\) seconds to climb up the slide and 2\(\frac{1}{4}\) seconds to go down the slide. How many seconds is Lacy’s trip up and down the slide?
Lacy’s trip is _____________ seconds long.
Answer:
Given,
It takes Lacy 8\(\frac{1}{3}\) seconds to climb up the slide and 2\(\frac{1}{4}\) seconds to go down the slide.
8\(\frac{1}{3}\) + 2\(\frac{1}{4}\)
8 + \(\frac{1}{3}\) + 2 + \(\frac{1}{4}\)
10 + \(\frac{7}{12}\) = 10\(\frac{7}{12}\)
Lacy’s trip is 10\(\frac{7}{12}\) seconds long.
Solve each problem. Write answers in simplest form. Show your work.
Question 1.
Eric needs \(\frac{1}{2}\) deck of playing cards for a magic trick. He only has \(\frac{2}{7}\) of a deck. What fraction of a deck does Eric still need?
Eric still needs _______________ of a deck.
Answer:
Given,
Eric needs \(\frac{1}{2}\) deck of playing cards for a magic trick.
He only has \(\frac{2}{7}\) of a deck
\(\frac{1}{2}\) – \(\frac{2}{7}\) = \(\frac{3}{14}\)
Eric still needs \(\frac{3}{14}\) of a deck.
Question 2.
Randy ran 1\(\frac{3}{4}\) miles. Natasha ran \(\frac{9}{10}\) miles. How many more miles did Randy run than Natasha?
Randy ran ______________ miles more than Natasha.
Answer:
Given,
Randy ran 1\(\frac{3}{4}\) miles. Natasha ran \(\frac{9}{10}\) miles.
1\(\frac{3}{4}\) – \(\frac{9}{10}\) = \(\frac{17}{20}\)
Randy ran \(\frac{17}{20}\) miles more than Natasha.
Question 3.
A soccer ball weighs 6 ounces when fully inflated. Raymundo has inflated the ball to 4\(\frac{2}{3}\) ounces. How many more ounces must be added before the ball is fully inflated?
The ball needs _____________ more ounces to be fully inflated.
Answer:
Given,
A soccer ball weighs 6 ounces when fully inflated.
Raymundo has inflated the ball to 4\(\frac{2}{3}\) ounces.
6 – 4\(\frac{2}{3}\)
5 \(\frac{3}{3}\)– 4\(\frac{2}{3}\) = 1\(\frac{1}{3}\)
The ball needs 1\(\frac{1}{3}\) more ounces to be fully inflated.
Question 4.
In January, employees at Home Real Estate Company worked 6\(\frac{3}{4}\) hours a day. In February, employees worked 7\(\frac{1}{8}\) hours a day. How many more hours did employees work daily during February than during January?
Employees worked _____________ hours more during February.
Answer:
Given,
In January, employees at Home Real Estate Company worked 6\(\frac{3}{4}\) hours a day. In February, employees worked 7\(\frac{1}{8}\) hours a day.
7\(\frac{1}{8}\) – 6\(\frac{3}{4}\) = \(\frac{3}{8}\)
Employees worked \(\frac{3}{8}\) hours more during February.
Question 5.
Peter’s hat size is 7\(\frac{3}{8}\) units. Cal’s hat size is 6\(\frac{7}{12}\) units. How many units larger is Peter’s hat size than Cals?
Peter’s hat size is ____________ units larger than Cal’s.
Answer:
Given,
Peter’s hat size is 7\(\frac{3}{8}\) units.
Cal’s hat size is 6\(\frac{7}{12}\) units.
7\(\frac{3}{8}\) – 6\(\frac{7}{12}\) = \(\frac{19}{24}\)
Peter’s hat size is \(\frac{19}{24}\) units larger than Cal’s.
Question 6.
Mrs. Anderson uses 3\(\frac{1}{5}\) cups of apples for her pies. Mrs. Woods uses 4\(\frac{2}{3}\) cups of apples for her pies. How many more cups of apples does Mrs. Woods use than Mrs. Anderson?
Mrs. Woods uses _______________ more cups of apples.
Answer:
Given,
Mrs. Anderson uses 3\(\frac{1}{5}\) cups of apples for her pies.
Mrs. Woods uses 4\(\frac{2}{3}\) cups of apples for her pies.
4\(\frac{2}{3}\) – 3\(\frac{1}{5}\) = 1 \(\frac{7}{15}\)
Mrs. Woods uses 1 \(\frac{7}{15}\) more cups of apples.