Practice with the help of Spectrum Math Grade 5 Answer Key Chapter 5 Lesson 5.3 Subtracting Fractions with Unlike Denominators regularly and improve your accuracy in solving questions.
Spectrum Math Grade 5 Chapter 5 Lesson 5.3 Subtracting Fractions with Unlike Denominators Answers Key
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
Then, subtract fractions, and write the difference in simplest form.
Subtract. Write answers in simplest form.
Question 1.
a.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{3}{4}\) – \(\frac{1}{2}\)
LCD is 4.
\(\frac{3}{4}\) – \(\frac{2}{4}\) = \(\frac{1}{4}\)
b.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{5}{6}\) – \(\frac{1}{3}\)
LCD is 6
\(\frac{5}{6}\) – \(\frac{2}{6}\) = \(\frac{3}{6}\) = \(\frac{1}{2}\)
c.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{9}{10}\) – \(\frac{2}{5}\)
LCD is 10
\(\frac{9}{10}\) – \(\frac{4}{10}\) = \(\frac{5}{10}\) = \(\frac{1}{2}\)
d.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{4}{7}\) – \(\frac{1}{8}\)
LCD is 56
\(\frac{32}{56}\) – \(\frac{7}{56}\) = \(\frac{25}{56}\)
e.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{5}{9}\) – \(\frac{1}{3}\)
LCD is 9
\(\frac{5}{9}\) – \(\frac{1}{3}\) = \(\frac{2}{9}\)
Question 2.
a.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{2}{5}\) – \(\frac{1}{9}\)
LCD is 45.
\(\frac{18}{45}\) – \(\frac{5}{45}\) = \(\frac{13}{45}\)
b.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{3}{5}\) – \(\frac{2}{7}\)
LCD is 35.
\(\frac{21}{35}\) – \(\frac{10}{35}\) = \(\frac{11}{35}\)
c.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{2}{3}\) – \(\frac{3}{8}\)
LCD is 24
\(\frac{16}{24}\) – \(\frac{9}{24}\) = \(\frac{7}{24}\)
d.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{5}{6}\) – \(\frac{1}{3}\)
LCD is 6
\(\frac{5}{6}\) – \(\frac{2}{6}\) = \(\frac{3}{6}\) = \(\frac{1}{2}\)
e.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{3}{4}\) – \(\frac{2}{9}\)
LCD is 36
\(\frac{27}{36}\) – \(\frac{8}{36}\) = \(\frac{19}{36}\)
Question 3.
a.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{7}{10}\) – \(\frac{3}{6}\)
LCD is 30
\(\frac{21}{30}\) – \(\frac{15}{30}\) = \(\frac{6}{30}\) = \(\frac{1}{5}\)
b.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{8}{9}\) – \(\frac{1}{4}\)
LCD is 36
\(\frac{32}{36}\) – \(\frac{9}{36}\) = \(\frac{23}{36}\)
c.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{7}{8}\) – \(\frac{5}{12}\)
LCD is 24
\(\frac{21}{24}\) – \(\frac{10}{24}\) = \(\frac{11}{24}\)
d.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{7}{10}\) – \(\frac{1}{4}\)
LCD is 20
\(\frac{14}{20}\) – \(\frac{5}{20}\) = \(\frac{9}{20}\)
e.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{4}{5}\) – \(\frac{3}{7}\)
LCD is 35
\(\frac{28}{35}\) – \(\frac{15}{35}\) = \(\frac{13}{35}\)
Subtract. Write answers in simplest form.
Question 1.
a.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{5}{9}\) – \(\frac{5}{18}\)
LCD is 18
\(\frac{10}{18}\) – \(\frac{5}{18}\) = \(\frac{5}{18}\)
b.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{5}{8}\) – \(\frac{3}{12}\)
LCD is 24
\(\frac{15}{24}\) – \(\frac{6}{24}\) = \(\frac{9}{24}\) = \(\frac{3}{8}\)
c.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{7}{18}\) – \(\frac{3}{9}\)
LCD is 18
\(\frac{7}{18}\) – \(\frac{6}{18}\) = \(\frac{1}{18}\)
d.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{4}{8}\) – \(\frac{7}{16}\)
LCD is 16
\(\frac{8}{16}\) – \(\frac{7}{16}\) = \(\frac{1}{16}\)
Question 2.
a.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{5}{10}\) – \(\frac{1}{15}\)
LCD is 30
\(\frac{15}{30}\) – \(\frac{2}{30}\) = \(\frac{13}{30}\)
b.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{9}{18}\) – \(\frac{2}{15}\)
LCD is 90
\(\frac{45}{90}\) – \(\frac{12}{90}\) = \(\frac{33}{90}\) = \(\frac{11}{30}\)
c.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{9}{10}\) – \(\frac{9}{14}\)
LCD is 70
\(\frac{63}{70}\) – \(\frac{45}{70}\) = \(\frac{18}{70}\) = \(\frac{18}{70}\) = \(\frac{9}{35}\)
d.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{6}{16}\) – \(\frac{1}{8}\)
LCD is 16
\(\frac{6}{16}\) – \(\frac{2}{16}\) = \(\frac{4}{16}\) = \(\frac{1}{4}\)
Question 3.
a.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{5}{8}\) – \(\frac{1}{9}\)
LCD is 72
\(\frac{45}{72}\) – \(\frac{8}{72}\) = \(\frac{37}{72}\)
b.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{7}{10}\) – \(\frac{7}{15}\)
LCD is 30
\(\frac{21}{30}\) – \(\frac{14}{30}\) = \(\frac{7}{30}\)
c.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{8}{36}\) – \(\frac{3}{14}\)
LCD is 252
\(\frac{56}{252}\) – \(\frac{54}{252}\) = \(\frac{2}{252}\) = \(\frac{1}{126}\)
d.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{13}{36}\) – \(\frac{9}{35}\)
LCD is 1260
\(\frac{455}{1260}\) – \(\frac{324}{1260}\) = \(\frac{131}{1260}\)
Question 4.
a.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{10}{25}\) – \(\frac{2}{9}\)
LCD is 225
\(\frac{90}{225}\) – \(\frac{50}{225}\) = \(\frac{40}{225}\) = \(\frac{8}{45}\)
b.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{5}{24}\) – \(\frac{3}{15}\)
LCD is 120
\(\frac{25}{120}\) – \(\frac{24}{120}\) = \(\frac{1}{120}\)
c.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{1}{8}\) – \(\frac{3}{26}\)
LCD is 104
\(\frac{13}{104}\) – \(\frac{12}{104}\) = \(\frac{1}{104}\)
d.
Answer:
When subtracting fractions that have different denominators, rename fractions to have a common denominator.
\(\frac{9}{14}\) – \(\frac{1}{8}\)
LCD is 56
\(\frac{36}{104}\) – \(\frac{7}{56}\) = \(\frac{29}{56}\)
