This handy Spectrum Math Grade 4 Answer Key Chapter 6 Lesson 6.14 Fractions as Multiples provides detailed answers for the workbook questions.
Spectrum Math Grade 4 Chapter 6 Lesson 6.14 Fractions as Multiples Answers Key
\(\frac{4}{5}\) = 4 × (\(\frac{1}{5}\))
\(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) = \(\frac{4}{5}\)
Write the addition equation and multiplication equation for each fraction.
Question 1.
\(\frac{6}{10}\) = _____________ × (__________)
OR
Answer:
6 x \(\frac{1}{10}\)
OR
\(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) \(\frac{1}{10}\) + \(\frac{1}{10}\)
Explanation:
Given,
\(\frac{6}{10}\)
As multiplication is a repeated addition, each repeated addition can be written in two ways:
\(\frac{6}{10}\) = 6 × (\(\frac{1}{10}\))
\(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) \(\frac{1}{10}\) + \(\frac{1}{10}\) = \(\frac{6}{10}\)
Question 2.
\(\frac{2}{8}\) = _____________ × (__________)
OR
Answer:
2 x \(\frac{1}{8}\)
OR
\(\frac{1}{8}\) + \(\frac{1}{8}\)
Explanation:
Given,
\(\frac{2}{8}\)
As multiplication is a repeated addition, each repeated addition can be written in two ways:
\(\frac{2}{8}\) = 2 × (\(\frac{1}{8}\))
\(\frac{1}{8}\) + \(\frac{1}{8}\) = \(\frac{2}{8}\)
Question 3.
\(\frac{2}{4}\) = _____________ × (__________)
OR
Answer:
2 x \(\frac{1}{4}\)
OR
\(\frac{1}{4}\) + \(\frac{1}{4}\)
Explanation:
Given,
\(\frac{2}{4}\)
As multiplication is a repeated addition, each repeated addition can be written in two ways:
\(\frac{2}{4}\) = 2 × (\(\frac{1}{4}\))
\(\frac{1}{4}\) + \(\frac{1}{4}\) = \(\frac{2}{4}\)
Question 4.
\(\frac{7}{3}\) = _____________ × (__________)
OR
Answer:
7 x \(\frac{1}{3}\)
OR
\(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\)
Explanation:
Given,
\(\frac{7}{3}\)
As multiplication is a repeated addition, each repeated addition can be written in two ways:
\(\frac{7}{3}\) = 7 × (\(\frac{1}{3}\))
\(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) = \(\frac{7}{3}\)
Question 5.
\(\frac{10}{6}\) = _____________ × (__________)
OR
Answer:
10 x \(\frac{1}{6}\)
OR
\(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) \(\frac{1}{6}\) + \(\frac{1}{6}\)
Explanation:
Given,
\(\frac{10}{6}\)
As multiplication is a repeated addition, each repeated addition can be written in two ways:
\(\frac{10}{6}\) = 10 × (\(\frac{1}{6}\))
\(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) \(\frac{1}{6}\) + \(\frac{1}{6}\) = \(\frac{10}{6}\)
Question 6.
\(\frac{5}{12}\) = _____________ × (__________)
OR
Answer:
5\(\frac{1}{12}\)
OR
\(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\)
Explanation:
Given,
\(\frac{5}{12}\)
As multiplication is a repeated addition, each repeated addition can be written in two ways:
\(\frac{5}{12}\) = 5 × (\(\frac{1}{12}\))
\(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) = \(\frac{5}{12}\)