This handy **Spectrum Math Grade 4 Answer Key Chapter 6 Lesson 6.14 Fractions as Multiples** provides detailed answers for the workbook questions.

## Spectrum Math Grade 4 Chapter 6 Lesson 6.14 Fractions as Multiples Answers Key

\(\frac{4}{5}\) = 4 × (\(\frac{1}{5}\))

\(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) = \(\frac{4}{5}\)

**Write the addition equation and multiplication equation for each fraction.**

Question 1.

\(\frac{6}{10}\) = _____________ × (__________)

OR

Answer:

6 x \(\frac{1}{10}\)

OR

\(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) \(\frac{1}{10}\) + \(\frac{1}{10}\)

Explanation:

Given,

\(\frac{6}{10}\)

As multiplication is a repeated addition, each repeated addition can be written in two ways:

\(\frac{6}{10}\) = 6 × (\(\frac{1}{10}\))

\(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) \(\frac{1}{10}\) + \(\frac{1}{10}\) = \(\frac{6}{10}\)

Question 2.

\(\frac{2}{8}\) = _____________ × (__________)

OR

Answer:

2 x \(\frac{1}{8}\)

OR

\(\frac{1}{8}\) + \(\frac{1}{8}\)

Explanation:

Given,

\(\frac{2}{8}\)

As multiplication is a repeated addition, each repeated addition can be written in two ways:

\(\frac{2}{8}\) = 2 × (\(\frac{1}{8}\))

\(\frac{1}{8}\) + \(\frac{1}{8}\) = \(\frac{2}{8}\)

Question 3.

\(\frac{2}{4}\) = _____________ × (__________)

OR

Answer:

2 x \(\frac{1}{4}\)

OR

\(\frac{1}{4}\) + \(\frac{1}{4}\)

Explanation:

Given,

\(\frac{2}{4}\)

As multiplication is a repeated addition, each repeated addition can be written in two ways:

\(\frac{2}{4}\) = 2 × (\(\frac{1}{4}\))

\(\frac{1}{4}\) + \(\frac{1}{4}\) = \(\frac{2}{4}\)

Question 4.

\(\frac{7}{3}\) = _____________ × (__________)

OR

Answer:

7 x \(\frac{1}{3}\)

OR

\(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\)

Explanation:

Given,

\(\frac{7}{3}\)

As multiplication is a repeated addition, each repeated addition can be written in two ways:

\(\frac{7}{3}\) = 7 × (\(\frac{1}{3}\))

\(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) = \(\frac{7}{3}\)

Question 5.

\(\frac{10}{6}\) = _____________ × (__________)

OR

Answer:

10 x \(\frac{1}{6}\)

OR

\(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) \(\frac{1}{6}\) + \(\frac{1}{6}\)

Explanation:

Given,

\(\frac{10}{6}\)

As multiplication is a repeated addition, each repeated addition can be written in two ways:

\(\frac{10}{6}\) = 10 × (\(\frac{1}{6}\))

\(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) \(\frac{1}{6}\) + \(\frac{1}{6}\) = \(\frac{10}{6}\)

Question 6.

\(\frac{5}{12}\) = _____________ × (__________)

OR

Answer:

5\(\frac{1}{12}\)

OR

\(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\)

Explanation:

Given,

\(\frac{5}{12}\)

As multiplication is a repeated addition, each repeated addition can be written in two ways:

\(\frac{5}{12}\) = 5 × (\(\frac{1}{12}\))

\(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) = \(\frac{5}{12}\)