Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter

Students can use the Spectrum Math Grade 3 Answer Key Chapter 7 Lesson 7.9 Measuring Perimeter as a quick guide to resolve any of their doubts.

Spectrum Math Grade 3 Chapter 7 Lesson 7.9 Measuring Perimeter Answers Key

Perimeter is the distance around a shape.
Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter 1
Answer:
Perimeter = 54 in,

Explanation:
To calculate perimeter add together the lengths of all the sides,
Perimeter = 17 in. + 10 in. + 17 in. + 10 in.,
Perimeter = 54 in.

Find the perimeter of each shape.

Question 1.
a.
Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter 2
____________ yd.
Answer:
14 yards,

Explanation:
Given from the figure adding together all lengths is 3 yards + 4 yards + 3 yards + 4 yards = 14 yards, therefore perimeter is 14 yd.

b.
Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter 3
____________ ft.
Answer:
30 feet,

Explanation:
Given from the figure adding together all lengths is 10 feet + 5 feet + 10 feet + 5 feet = 30 feet, therefore perimeter is 30 feet.

c.
Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter 4
_____________ in.
Answer:
28 in.,

Explanation:
Given from the figure adding together all lengths is 13 in. + 13 in. + 2 in. = 28 in., therefore perimeter is 28 inches.

Question 2.
a.
Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter 5
_____________ yd.
Answer:
225 yards,

Explanation:
Given from the figure adding together all lengths is 100 yards +75 yards + 50 yards = 225 yards, therefore perimeter is 225 yards.

b.
Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter 6
_____________ yd.
Answer:
120 yards,

Explanation:
Given from the figure adding together all lengths is 50 yards + 10 yards + 50 yards + 10 yards = 120 yards therefore perimeter is 120 yards.

c.
Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter 7
_____________ ft.
Answer:
55 feet,

Explanation:
Given from the figure adding together all lengths is 17 feet +13 feet + 25 feet = 55 feet therefore perimeter is 55 feet.

Find the unknown side.

Question 3.
a.
Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter 8
P = __________ ft.
x = __________ ft.
Answer:
P = 42 feet,
x = 5 feet,

Explanation:
Given from the figure firstly we see the measurements of the sides which are given as 15 feet, 15 feet, 7 feet. So to find unknown side we see the opposite side, So opposite is not equal we assume unknown side as 5 ft. Now perimeter is 15 feet + 7 feet + 15 feet + 5 feet = 42 feet therefore, P = 42 feet and x = 5feet.

b.
Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter 9
P = ___________ in.
w = ___________ in.
Answer:
P = 34 in.,
W = 8 in.

Explanation:
Given from the figure firstly we see the measurements of the sides which are given as 10 in., 6in.,10in,, So to find the unknown side we see the opposite side it is opposite side, w is greater we assume as 8 in., Now perimeter is 6 in.  + 10 in. + 8 in. + 10 in. = 34 in., therefore P = 34 in., W=8 in..

c.
Spectrum Math Grade 3 Chapter 7 Lesson 9 Answer Key Measuring Perimeter 10
P = ____________ in.
z = ____________ in.
Answer:
P = 160 in.,
z = 30 in.,

Explanation:
Given from the figure the given measurements are 60 in., 40 in.,30 in., z, So to find unknown side let’s assume that z = 30 in. by measuring the other sides so the perimeter is 60 in. + 40 in. + 30 in. + 30 in. = 160 in. therefore p = 160 in., z = 30 in..

Solve.

Question 1.
The town of Yarmouth is planning a skateboard park and needs to know the perimeter of the park. The property measures 7 yards by 3 yards by 10 yards by 5 yards. What is the perimeter?
The park’s perimeter is ______________ yards.
Answer:
25 yards,

Explanation:
Given the measurements of the park is 7 yards, 3 yards, 10 yards, 5 yards. So the perimeter is 7 yards + 3 yards + 10 yards + 5 yards = 25 yards, therefore, the park’s perimeter is 25 yards.

Question 2.
John cleared a vacant lot to plant o garden. The lot measured 35 by 15 feet. What is the perimeter of the garden lot?
The perimeter of the lot is ______________ feet.
Answer:
100 feet,

Explanation:
Given the measurements of the lot are length is 35 feet and breadth is 15 feet, So perimeter of the garden lot is 35 feet +15 feet + 35 feet + 15 feet = 100 feet, therefore the perimeter of the garden lot is 100 feet.

Question 3.
Gabriel built a case for his tropical birds. The cage measures 14 feet by 12 feet. What is the perimeter of the cage?
The perimeter of the cage is ___________ feet.
Answer:
52 feet,

Explanation:
Given the measurements of the cage are 14 feet by 12 feet that is 14 feet, 12 feet, 14 feet, 12 feet. So the perimeter is 14 feet + 12 feet + 14 feet + 12 feet = 52 feet, therefore the perimeter of the cage is 52 feet.

Question 4.
The length of the walking track is 103 feet and the width is 50 feet. What is the perimeter of the track?
The perimeter is ____________ feet.
Answer:
306 feet,

Explanation:
Given the measurements of walking track are length is 103 feet and width is 50 feet. So, the perimeter is 103 feet + 50 feet + 103 feet + 50 feet = 306 feet . Therefore the perimeter of track  is 306 feet.

Question 5.
Anna is buying trim to go around her rug. Her rug measures 54 inches by 142 inches. How many inches of trim will Anna need to buy?
Anna will need to buy _____________ inches of trim.
Answer:
392 inches,

Explanation:
Given the rug measures 54 inches by 142 inches that is 54 inches +142 inches + 54 inches + 142 inches = 392 inches, therefore Anna will need to buy 392 inches of trim.

Question 6.
Natalie is putting a fence around her pool. Her pool is 10 feet by 8 feet. How many feet of fencing will Natalie need?
Natalie will need ______________ feet of fencing.
Answer:
Natalie will need 36 feet of fencing,

Explanation:
Given measurements of pool are 10 feet by 8 feet that is 10 feet, 8 feet, 10 feet, 8 feet. Therefore 10 feet + 8 feet + 10 feet + 8 feet = 36 feet, Natalie will need 36 feet of fencing.

Question 7.
The rectangular third-grade classroom has a perimeter of 130 feet. If it is 25 feet wide, how many feet long is the classroom?
The classroom is ______________ feet long.
Answer:
40 feet long,

Explanation:
Given perimeter of rectangular third-grade is 130 feet, width is 25 feet, So as we know that perimeter of rectangle is 2(l + b) = 130, 2(l + 25 feet )=130 feet, 2l + 50 feet = 130 feet, 2l = 130 feet – 50 feet, 2l = 80 feet, l = 80 feet/2 = 40 feet, therefore the classroom is 40 feet long.

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