The percentage of the whole number is calculated by dividing the value by the total value and then multiply by 100. The percentage is nothing but “per 100”. The students of 5th grade can learn the relationship between fractions and percentages with the help of this article. By learning the concept of percent the students can solve different types of problems. We have shown percentage problems with answers in the below sections so that you can verify if you are stuck at some point in percentage problem-solving.

**Percentage = (Value/Total Value) × 100**

**Do Refer:**

### Real World Problems Involving Percentage

Learn the concept of percentage in-depth by referring to some of the percentage word problems with solutions.

**Example 1.**

In an exam, Preethi secured 278 marks. If she secured 81% Find the maximum marks?

**Solution:**

Given,

Total number of marks = 278

Preethi secured marks = 81%

Percentage formula = P% × X = Y

Where P = 81%

Y = 278

Then 81% × X = 278

81/100 × X = 278

X = 278 × 100/81

X = 27800/81 = 343.2

Thus Preethi got 278 marks out of 343.2 marks.

**Example 2. **

A container contains 40% of milk. what quantity of container is required to get 160 l of milk?

**Solution:**

Given,

Let the container contains a milk = 40%

Quality of container is required to get = 160 l

Percentage formula = P% × X = Y

Where P = 40%

Y = 160

Then 40% × X = 160

40/100 × X = 160

X = 160 × 100/40

X = 16000/40 = 400

**Example 3. **

There are 200 students in a class. If 20% are absent on a Saturday. Find the number of students present in the class?

**Solution:**

Given,

Number of students absent on Saturday = 200

Then

20/100 × 200 = 40

Therefore the number of students present = 200 – 40 = 160 students.

**Example 4. **

A box contains of oranges .6% of them are spoiled and 48 are good. find the total number of oranges in the box.

**Solution:**

Given,

Let the total number of boxes = m

6% of oranges are spoiled and 48 are good

Therefore 6% of m = 48

Percentage formula = P% × X = Y

6/100 × m = 66

Then P = 6/100

X = m

Y = 66

m = 66 × 100/6

m = 6600/6 = 1100

**Example 5.**

Find the decimal 0.6 into a percentage?

**Solution:**

Given,

First, we convert the decimal number into a fraction

0.6 = 6/100 = 6%

Thus the percentage of the decimal 0.6 is 6%

**Example 6. **

Find the fraction 3/25 into a percentage?

**Solution:**

In order to convert the fraction into a percentage, we have to multiply the given fraction by 100.

3/25 × 100 = 12%

**Example 7. **

Navya scores 68 marks out of 90 in her maths exam. Convert her Marks into percentages?

**Solution:**

Given,

Navya scores 68 marks out of 90 in her exam

68 × 100/90 = 75%

Thus Navya scored 75% on her maths exam.

**Example 8. **

A donkey gives 2l of milk each day. If the milkman sells 50% of the milk, how many litres of milk is left with him

**Solution:**

Given,

A donkey gives milk = 2l

Milk man sells = 50%

Percentage formula = P% × X = Y

Where P = 50%

Y = 2l

50/100 × X = 2

X = 2 × 100/50

X = 200/50 = 4

**Example 9. **

Arjun was able to cover 10% of the 20 km walk in the morning. what is the percentage of the journey is still left to be covered?

**Solution:**

Given,

Arjun was able to cover 10% of 20 km

Percentage formula = P% × X = Y

Where P = 10%

Y = 20

10/100 × X = 20

X = 20 × 100/10

X = 200/10 = 200

**Example 10. **

In a class 10% of the students are boys. If the total number of students in a class is 80. What is the number of girls?

**Solution:**

Given,

Total number of boys in a class = 10%

Total number of students in a class = 80

Percentage formula = P% × X = Y

Where P = 10%

Y = 80

10/100 × X = 80

X = 80 × 100/10

X = 800/10 = 80