McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients

All the solutions provided in McGraw Hill My Math Grade 5 Answer Key PDF Chapter 6 Lesson 9 Estimate Quotients will give you a clear idea of the concepts.

McGraw-Hill My Math Grade 5 Answer Key Chapter 6 Lesson 9 Estimate Quotients

Math in My World

Example 1

Ms. Glover buys 2 kites for a total of $15.18. If each kite costs the same, about how much did each kite cost? Explain why your answer is reasonable.
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 1
Estimate the quotient of 15.18 and 2.
1. Use compatible numbers.
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 2
Helpful Hint
Compatible numbers are numbers that are easy to compute mentally.
So, $15.18 ÷ 2 = ____________
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 3
Answer:
$8
Explanation:
Ms. Glover buys 2 kites for a total of $15.18.
If each kite costs the same,
Cost of each kite ,

Compatible numbers are numbers that are easy to compute mentally.
So, 2 x 8 = 16, which is close to 15.18 the answer is reasonable.

Example 2

Three friends went out to dinner. The total cost of their meals was $32.57. If the friends split the bill evenly, about how much will each person pay? Explain why your answer is reasonable.
Estimate $32.57 ÷ 3 by rounding.

1. Round $32.57 to the nearest whole dollar because 33 and 3 are compatible numbers.
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 4

2. Divide.
___________ ÷ ___________ = __________
Each friend will pay about ____________.
Since 3 × __________ = ___________ and _____________ 32.57, the answer is reasonable.
Answer:
$11

Explanation:
The total cost of 3 meals was $32.57.
If the friends split the bill evenly,
Estimate $32.57 ÷ 3 by rounding.
$32.57 ÷ 3 = $11
Since 3 × 11 = 33
33 is approximately equal to 32.57, the answer is reasonable.

Guided Practice

Estimate each quotient.

Question 1.
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 5
Answer:

Explanation:
Compatible numbers are numbers that are easy to compute mentally.
19.50 is estimated to 20
20 ÷ 5 = 4
So, 5 x 4 = 20, which is close to 19.50 the answer is reasonable.

Question 2.
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 6
Answer:

Explanation:
Compatible numbers are numbers that are easy to compute mentally.
47.25 is rounded to nearest tenth 50
50 ÷ 25 = 2
So, 25 x 2 = 50, which is close to 47.25 the answer is reasonable.

Question 3.
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 7
Answer:

Explanation:
Compatible numbers are numbers that are easy to compute mentally.
16.8 is rounded to nearest tenth 20
20 ÷ 4 = 5
So, 5 x 4 = 20, which is close to 16.8 the answer is reasonable.

Talk Math

Describe another way you could estimate in Example 2. Are both estimates reasonable? Explain.
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 8
Answer:
$11

Explanation:
Compatible numbers are numbers that are easy to compute mentally.
$32.57 ÷ 3 = $11
Since 3 × 11 = 33
33 is approximately equal to 32.57, the answer is reasonable.

Independent Practice

Estimate each quotient.

Question 4.
87.3 ÷ 11
Answer:
8
Explanation:
Round 87.3 to the nearest whole number,
88 and 11 are compatible numbers.

Since 8 × 11 = 88 and approximately equal 87.3, the answer is reasonable.

Question 5.
44.7 ÷ 5
Answer:
9
Explanation:
Round 44.7 to the nearest whole number,
45 and 5 are compatible numbers.

Since 9 × 5 = 45 and approximately equal 44.7, the answer is reasonable.

Question 6.
195.8 ÷ 12
Answer:
20
Explanation:
Round 195.8 to the nearest whole number,
200 and 10 are compatible numbers.

Since 10 × 20 = 200 and approximately equal 195.8, the answer is reasonable.

Question 7.
$28.20 ÷ 6
Answer:
$5
Explanation:
Round $28.20 to the nearest whole dollar number,
30 and 6 are compatible numbers.

Since 5 × 6 = 30 and approximately equal $28.20, the answer is reasonable.

Question 8.
$7.92 ÷ 6
Answer:
1
Explanation:
Round $7.92 to the nearest whole dollar number,
6 and 6 are compatible numbers.

Since 6 × 1 = 6 and approximately equal $7.92, the answer is reasonable.

Question 9.
88.3 ÷ 9
Answer:
10
Explanation:
Round 88.3 to the nearest whole number,
90 and 9 are compatible numbers.

Since 9 × 10 = 90 and approximately equal 88.3, the answer is reasonable.

Question 10.
128.9 ÷ 12
Answer:
10
Explanation:
Round 128.9 to the nearest whole number,
100 and 10 are compatible numbers.

Since 10 × 10 = 100 and approximately equal 128.9, the answer is reasonable.

Question 11.
576.4 ÷ 62
Answer:
10
Explanation:
Round 576.4 to the nearest whole number,
600 and 60 are compatible numbers.

Since 10 × 60 = 600 and approximately equal 576.4, the answer is reasonable.

Question 12.
$15.47 ÷ 7
Answer:
2
Explanation:
Round $15.47 to the nearest whole dollar number,
14 and 7 are compatible numbers.

Since 2 × 7 = 88 and approximately equal $15.47, the answer is reasonable.

Question 13.
56.3 ÷ 18
Answer:
3
Explanation:
Round 56.3 to the nearest whole number,
60 and 20 are compatible numbers.

Since 3 × 20 = 60 and approximately equal 56.3, the answer is reasonable.

Problem Solving

Question 14.
It costs $158.75 to purchase 15 tickets to the state fair. About how much does one ticket cost?
Answer:
$10
Explanation:
It costs $158.75 to purchase 15 tickets to the state fair.
Cost of each ticket = $158.75 ÷15
Round $158.75 to the nearest whole number,
$150 and 15 are compatible numbers.

Since 10 × 15 = 150 and approximately equal $158.75, the answer is reasonable.

Question 15.
Jake bought 3 drawing pens for $8.07. Each pen costs the same amount. About how much did he spend for one pen?
Answer:
$3
Explanation:
Jake bought 3 drawing pens for $8.07.
Cost of each pen,
Round $8.07 to the nearest whole number,
$9 and 3 are compatible numbers.

Since $3 × 3 = $9 and approximately equal $8.07, the answer is reasonable.

Question 16.
A canoe rental company offers two trips along the river. Neil and Gabriela choose the longer trip. If they split the cost of the rental, about how much will each person pay?
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 9
Answer:
$8
Explanation:
Neil and Gabriela choose the longer trip which costs $16.32.
If they split the cost of the rental, each person has to pay,
$16.32 ÷ 2 = $8
Round $16.32 to the nearest whole number,
$16 and 2 are compatible numbers.
Since $8 × 2 = $16 and approximately equal $16.32, the answer is reasonable.

Question 17.
Mathematical PRACTICE Make Sense of Problems It costs $88.50 for 6 adults to see an exhibit on Egyptian mummies. About how much does it cost one adult to see the exhibit?
Answer:
$15
Explanation:
It costs $88.50 for 6 adults to see an exhibit on Egyptian mummies.
Cost for one adult to see the exhibit,
$88.50 ÷ 6 = $8
Round $16.32 to the nearest whole number,
$90 and 6 are compatible numbers.
Since $15 × 6 = $90 and approximately equal $88.50, the answer is reasonable.

Question 18.
Mathematical PRACTICE Model Math Write a real-world estimation problem involving dividing a decimal by a whole number. Then estimate the quotient.
Answer:
James bought 5 pens for $8.07. Each pen costs the same amount. About how much did he spend for one pen?
Explanation:
James bought 5 pens for $8.07.
Cost of each pen,
Round $8.07 to the nearest whole number,
$10 and 5 are compatible numbers.
Since $2 × 5 = $10 and approximately equal $8.07, the answer is reasonable.

Question 19.
Building on the Essential Question How can I use compatible numbers to estimate the quotient of a decimal and whole number?
Answer:
Compatible numbers are close in value to the actual numbers that make estimating the answer and computing problems easier.
Explanation:
Compatible numbers are the numbers that are easy to add, subtract, multiply, or divide mentally.
When using estimation to approximate a calculation,
replace actual numbers with compatible numbers.

McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 My Homework Answer Key

Practice

Estimate each quotient.

Question 1.
32.17 ÷ 7
Answer:
5
Explanation:
Round 32.17 to the nearest whole number,
35 and 7 are compatible numbers.

Since 5 × 7 = 35 is approximately equal 32.17, the answer is reasonable.

Question 2.
$175.32 ÷ 3
Answer:
60
Explanation:
Round $175.32 to the nearest whole number,
180 and 3 are compatible numbers.

Since $60 × 3 = $180 is approximately equal $175.32, the answer is reasonable.

Question 3.
21.9 ÷ 3
Answer:
7
Explanation:
Round 21.9 to the nearest whole number,
21 and 3 are compatible numbers.

Since 7 × 3 = 21 is approximately equal 21.9, the answer is reasonable.

Question 4.
36.3 ÷ 6
Answer:
6
Explanation:
Round 36.3 to the nearest whole number,
36 and 6 are compatible numbers.

Since 6 × 6 = 36 is approximately equal 36.3, the answer is reasonable.

Question 5.
17.5 ÷ 5
Answer:
4
Explanation:
Round 17.5 to the nearest whole number,
20 and 5 are compatible numbers.

Since 4 × 5 = 20 is approximately equal 17.5, the answer is reasonable.

Question 6.
120.6 ÷ 2
Answer:
60
Explanation:
Round 120.6 to the nearest whole number,
120 and 2 are compatible numbers.

Since 60 × 2 = 120 is approximately equal 120.6, the answer is reasonable.

Problem Solving

Use the table to answer Exercises 7-9.
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 10
The information in the table can be used to determine the density of each object. Density describes how tightly the particles in an object are packed together. You can find density by dividing an object’s mass by its volume.

Question 7.
Estimate the density of aluminum.
Answer:
3 kg/m³
Explanation:
Round 13.5 to the nearest whole number,
15 and 5 are compatible numbers.

Since 3 × 5 = 15 is approximately equal 13.5, the answer is reasonable.

Question 8.
Is the density of gold greater than the density of mercury? Explain.
Answer:
Yes, the density of gold greater than the density of mercury.
Explanation:
Density = Mass ÷  Volume
Mass of gold = 56.7 grams.
Volume of gold = 3 cm³
Density of gold = 56.7 ÷ 3
Estimate 56.7 to the nearest whole number 60
D = 60 ÷ 3 = 20 kg/m³
Mass of mercury = 121.5 grams.
Volume of mercury = 9 cm³
Density of mercury = 121.5 ÷ 9 = 13.5 20 kg/m³
Compare both the densities gold is more than the mercury.

Question 9.
The density of gold is about how many times greater than the density of aluminum?
Answer:
6.5 kg/m³
Explanation:
Density of gold = 56.7 ÷ 3
Estimate 56.7 to the nearest whole number 60
D = 60 ÷ 3 = 20 kg/m³
Density of mercury = 121.5 ÷ 9 = 13.5 20 kg/m³
Compare both 60 – 13.5 = 6.5 kg/m³

Question 10.
Harry’s mother makes cakes for a local restaurant. She buys flour and sugar in large amounts. She has 157.86 pounds of flour and 82.69 pounds of sugar. If she uses 15 pounds of flour and 8 pounds of sugar each day, for about how many days will the flour last?
McGraw Hill My Math Grade 5 Chapter 6 Lesson 9 Answer Key Estimate Quotients 11
Answer:
10 days.
Explanation:
Harry’s mother has 157.86 pounds of flour and 82.69 pounds of sugar.
157.86 + 82.69 = 240.55 pounds.
If she uses 15 pounds of flour and 8 pounds of sugar each day,
Each day she uses 15 + 8 = 23 pounds.
For about how many days will the flour last,
240.55 ÷ 23 = 10.43
Estimate to the nearest whole numbers to 10 days.

Question 11.
Mathematical PRACTICE Model Math Write a division problem involving the division of a decimal by a whole number with an estimated quotient of 7.
Answer:
Jake bought 3 drawing pens for $21.3. Each pen costs the same amount. About how much did he spend for one pen?
Explanation:
Jake bought 3 drawing pens for $21.3.
Cost of each pen,
Round $21.3 to the nearest whole number,
$21 and 3 are compatible numbers.
21 ÷ 3 = 7
Since $7 × 3 = $21 and approximately equal $21.3, the answer is reasonable.

Test Practice

Question 12.
Kendall measured the rainfall in her area for a year. Her readings totaled 34.56 inches. Which is the best estimate of the average rainfall per month?
(A) about 1 inch per month
(B) about 2 inches per month
(C) about 3 inches per month
(D) about 4 inches per month
Answer:
Option(C)
Explanation:
1year = 12 months.
Average reading per month = 34.56 inches.
Best estimate of the average rainfall per month,
34.56 ÷ 12 = 2.88 or 3 inches.

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