All the solutions provided inÂ **McGraw Hill My Math Grade 4 Answer Key PDF Chapter 9 Lesson 8 Model Fractions and Multiplication **will give you a clear idea of the concepts.

## McGraw-Hill My Math Grade 4 Answer Key Chapter 9 Lesson 8 Model Fractions and Multiplication

You have learned to write a fraction as a sum of unit fractions. For example, \(\frac{4}{5}\) = \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\).

You can also write a fraction as a multiple of a unit fraction.

**Build It
**Use an equation to write \(\frac{4}{5}\) as a multiple of a unit fraction.

One Way:

Use fraction tiles.

Model \(\frac{4}{5}\) using fraction tiles. Draw your result below.

How many \(\frac{1}{5}\)-tiles did you use?

Another Way:

Use repeated addition.

You know that \(\frac{4}{5}\) = \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\)

How many times is added to equal \(\frac{4}{5}\)?

So, \(\frac{4}{5}\) = ________________ Ă— \(\frac{1}{5}\).

Answer:

\(\frac{4}{5}\) = 4 Ă— \(\frac{1}{5}\).

Explanation:

\(\frac{4}{5}\) as a multiple of a unit fraction = ??

1. Use fraction tiles:

2. Use repeated addition:

You know that \(\frac{4}{5}\) = \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\)

=> 4 timesÂ \(\frac{1}{5}\) is added to equal \(\frac{4}{5}\).

You know that 6 is a multiple of 2. Any multiples of 6, such as 12, 18, and 24, are also multiples of 2. The same is true for fractions. A multiple of a fraction can also be written as a multiple of a unit fraction.

**Try It
**Use an equation to write 2 Ă— \(\frac{4}{5}\) as a multiple of a unit fraction.

Use repeated addition to write 2 Ă— \(\frac{4}{5}\) as \(\frac{4}{5}\) + \(\frac{4}{5}\).

\(\frac{4}{5}\) + \(\frac{4}{5}\) = \(\frac{8}{5}\) Add like fractions.

Model \(\frac{8}{5}\) using fraction tiles. Draw your result below.

How many \(\frac{1}{5}\)-tiles did you use? ______________

So, \(\frac{8}{5}\) is a multiple of \(\frac{4}{5}\). It is also a multiple of \(\frac{1}{5}\).

\(\frac{8}{5}\) = ________________ Ă— \(\frac{1}{5}\)

Write an equation showing that \(\frac{8}{5}\) is a multiple of the unit fraction \(\frac{1}{5}\).

\(\frac{8}{5}\) = ________________ Ă— \(\frac{1}{5}\)

So, 2 Ă— \(\frac{4}{5}\) = ________________ Ă— \(\frac{1}{5}\).

Answer:

Equation showing that \(\frac{8}{5}\) is a multiple of the unit fraction \(\frac{1}{5}\) is

2 Ă— \(\frac{4}{5}\) = 8 Ă— \(\frac{1}{5}\).

Explanation:

2 Ă— \(\frac{4}{5}\) as a multiple of a unit fraction = ??

1. Use fraction tiles:

2 Ă— \(\frac{4}{5}\) = \(\frac{4}{5}\) + \(\frac{4}{5}\) = \(\frac{8}{5}\)

2. Use repeated addition:

2 Ă— \(\frac{4}{5}\) = \(\frac{4}{5}\) + \(\frac{4}{5}\).

=> \(\frac{4}{5}\) + \(\frac{4}{5}\) = \(\frac{8}{5}\)

So, \(\frac{8}{5}\) is a multiple of \(\frac{4}{5}\). It is also a multiple of \(\frac{1}{5}\).

\(\frac{8}{5}\) = 8 Ă— \(\frac{1}{5}\)

**Talk About It
**Question 1.

**Mathematical PRACTICE**Identify Structure Write an equation showing how \(\frac{3}{8}\) is a multiple of \(\frac{1}{8}\).

Answer:

Equation showing \(\frac{3}{8}\) is a multiple of \(\frac{1}{8}\) is \(\frac{1}{8}\) + \(\frac{1}{8}\) + \(\frac{1}{8}\)

Explanation:

\(\frac{3}{8}\) is a multiple of \(\frac{1}{8}\):

=> \(\frac{1}{8}\) + \(\frac{1}{8}\) + \(\frac{1}{8}\)

=> (1 + 1 + 1) Ă· 8

=> \(\frac{3}{8}\)

Question 2.

Write equations showing how \(\frac{6}{8}\) is a multiple of both \(\frac{3}{8}\) and \(\frac{1}{8}\).

Answer:

Equations showing \(\frac{6}{8}\) is a multiple of both \(\frac{3}{8}\) and \(\frac{1}{8}\) is 2 Ă— \(\frac{3}{8}\) = 6 Ă— \(\frac{1}{8}\)

Explanation:

\(\frac{6}{8}\) is a multiple of both \(\frac{3}{8}\) and \(\frac{1}{8}\):

1. \(\frac{6}{8}\) is a multiple of both \(\frac{3}{8}\)

=> \(\frac{3}{8}\) + \(\frac{3}{8}\)

=> (3 + 3) Ă· 8

=> \(\frac{6}{8}\)

2. \(\frac{6}{8}\) is a multiple ofÂ \(\frac{1}{8}\):

=> \(\frac{1}{8}\) + \(\frac{1}{8}\) + \(\frac{1}{8}\)+ \(\frac{1}{8}\)+\(\frac{1}{8}\) + \(\frac{1}{8}\)

=> (1 + 1 + 1 + 1 + 1 + 1) Ă· 8

=> \(\frac{6}{8}\)

**Practice It
**

**Algebra Use an equation to write each fraction or product as a multiple of a unit fraction.**

Question 3.

\(\frac{3}{4}\) ________________

Answer:

Equation showing \(\frac{3}{4}\) as a multiple of a \(\frac{1}{4}\) unit fraction is

\(\frac{1}{4}\) + Â \(\frac{1}{4}\) + Â \(\frac{1}{4}\)

Explanation:

\(\frac{3}{4}\) as a multiple of a unit fraction:

=> \(\frac{1}{4}\) + \(\frac{1}{4}\)+ \(\frac{1}{4}\)

=> (1 + 1 +1) Ă· 4

=> \(\frac{3}{4}\)

Question 4.

\(\frac{7}{8}\) ________________

Answer:

Equation showing \(\frac{7}{8}\) as a multiple of a \(\frac{1}{8}\) unit fraction is 7 Ă— \(\frac{1}{8}\)

Explanation:

\(\frac{7}{8}\) as a multiple of a unit fraction:

=> \(\frac{1}{8}\) + \(\frac{1}{8}\) + \(\frac{1}{8}\)+ \(\frac{1}{8}\)+ \(\frac{1}{8}\)+ \(\frac{1}{8}\)+ \(\frac{1}{8}\)

=> (1 + 1 + 1 + 1 + 1 + 1 + 1) Ă· 8

=> \(\frac{7}{8}\)

Question 5.

\(\frac{5}{12}\) ________________

Answer:

Equation showing \(\frac{5}{12}\) as a multiple of a \(\frac{1}{12}\) unit fraction is 5 Ă— \(\frac{1}{12}\)

Explanation:

\(\frac{5}{12}\) as a multiple of a unit fraction:

=> \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\)+ \(\frac{1}{12}\)+ \(\frac{1}{12}\)

=> (1 + 1 + 1 + 1 + 1) Ă· 12

=> \(\frac{5}{12}\)

Question 6.

\(\frac{5}{6}\) ________________

Answer:

Equation showing \(\frac{5}{6}\) as a multiple of a \(\frac{1}{6}\) unit fraction is 5 Ă— \(\frac{1}{6}\)

Explanation:

Equation showing \(\frac{5}{6}\) as a multiple of a unit fraction:

=> \(\frac{1}{6}\) + \(\frac{1}{6}\)+ \(\frac{1}{6}\)+ \(\frac{1}{6}\)+\(\frac{1}{6}\)

=> (1 + 1 + 1 + 1 + 1) Ă· 6

=>Â \(\frac{5}{6}\)

Question 7.

2 Ă— \(\frac{2}{3}\) ________________

Answer:

Equation showing 2 Ă— \(\frac{2}{3}\) as a multiple of a \(\frac{1}{3}\) and \(\frac{2}{3}\) unit fraction is 4 Ă— \(\frac{1}{3}\) = 2 Ă— \(\frac{2}{3}\)

Explanation:

2 Ă— \(\frac{2}{3}\) as a multiple of a unit fraction:

=>Â \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\)

=> 4 Ă— \(\frac{1}{3}\) or 2 Ă— \(\frac{2}{3}\)

Question 8.

2 Ă— \(\frac{5}{6}\) ________________

Answer:

Equation showing 2 Ă— \(\frac{5}{6}\) as a multiple of a \(\frac{5}{6}\) and \(\frac{1}{6}\) is \(\frac{5}{6}\) + \(\frac{5}{6}\) = 10 Ă— \(\frac{1}{6}\)

Explanation:

2 Ă— \(\frac{5}{6}\) as a multiple of a unit fraction:

=> \(\frac{5}{6}\)+ \(\frac{5}{6}\)

=> \(\frac{10}{6}\)

= \(\frac{1}{6}\) + \(\frac{1}{6}\)+\(\frac{1}{6}\)+ \(\frac{1}{6}\)+ \(\frac{1}{6}\)+ \(\frac{1}{6}\)+ \(\frac{1}{6}\)+ \(\frac{1}{6}\)+ \(\frac{1}{6}\) + \(\frac{1}{6}\)

=> 10 Ă— \(\frac{1}{6}\)

=> 10\(\frac{1}{6}\)

Question 9.

4 Ă— \(\frac{3}{4}\) ________________

Answer:

Equation showing 4 Ă— \(\frac{3}{4}\) as a multiple of a \(\frac{3}{4}\) unit fraction is \(\frac{3}{4}\) + \(\frac{3}{4}\)+ \(\frac{3}{4}\)+\(\frac{3}{4}\)

Explanation:

4 Ă— \(\frac{3}{4}\) as a multiple of a unit fraction:

=>\(\frac{3}{4}\) + \(\frac{3}{4}\)+ \(\frac{3}{4}\)+\(\frac{3}{4}\)

=> (3 + 3 + 3 + 3) Ă· 4

=> 12 Ă· 4 or \(\frac{12}{4}\)

Question 10.

3 Ă— \(\frac{7}{8}\) ________________

Answer:

Equation showing 3 Ă— \(\frac{7}{8}\) as a multiple of a \(\frac{7}{8}\) unit fraction is \(\frac{7}{8}\) + \(\frac{7}{8}\) + \(\frac{7}{8}\)

Explanation:

3 Ă— \(\frac{7}{8}\) as a multiple of a unit fraction:

=> \(\frac{7}{8}\) + \(\frac{7}{8}\) + \(\frac{7}{8}\)

=> (7 + 7 + 7) Ă· 8

=> 21 Ă· 8 or \(\frac{21}{8}\)

Question 11.

5 Ă— \(\frac{3}{5}\) ________________

Answer:

Equation showing 5 Ă— \(\frac{3}{5}\) as a multiple of a \(\frac{3}{5}\) unit fraction is \(\frac{3}{5}\) + \(\frac{3}{5}\) + \(\frac{3}{5}\)+ \(\frac{3}{5}\)+ \(\frac{3}{5}\)

Explanation:

5 Ă— \(\frac{3}{5}\) as a multiple of a unit fraction:

=> \(\frac{3}{5}\) + \(\frac{3}{5}\) + \(\frac{3}{5}\)+ \(\frac{3}{5}\)+ \(\frac{3}{5}\)

=> (3 + 3 + 3 + 3 + 3) Ă· 5

=\(\frac{15}{5}\)

Question 12.

6 Ă— \(\frac{7}{12}\) ________________

Answer:

Equation showing 6 Ă— \(\frac{7}{12}\) as a multiple of a \(\frac{7}{12}\) unit fraction is \(\frac{7}{12}\) + \(\frac{7}{12}\) + \(\frac{7}{12}\) + \(\frac{7}{12}\) +\(\frac{7}{12}\) + \(\frac{7}{12}\)

Explanation:

6 Ă— \(\frac{7}{12}\) as a multiple of a unit fraction:

=> \(\frac{7}{12}\) + \(\frac{7}{12}\) + \(\frac{7}{12}\) + \(\frac{7}{12}\) +\(\frac{7}{12}\) + \(\frac{7}{12}\)

=> (7 + 7 + 7 + 7 + 7 + 7) Ă· 12

=> \(\frac{42}{12}\)

**Apply It
**Question 13.

**Mathematical PRACTICE**Model Math Use fraction tiles and repeated addition to write 3 Ă— \(\frac{3}{4}\) as a multiple of a unit fraction. Draw your result below.

Answer:

Equation showing 3 Ă— \(\frac{3}{4}\) as a multiple of a \(\frac{1}{4}\) unit fraction is 9 Ă— \(\frac{1}{4}\)

Explanation:

3 Ă— \(\frac{3}{4}\) as a multiple of a unit fraction.

=> \(\frac{1}{4}\) + \(\frac{1}{4}\)+ \(\frac{1}{4}\)+ \(\frac{1}{4}\)+ \(\frac{1}{4}\)+ \(\frac{1}{4}\)+ \(\frac{1}{4}\)+\(\frac{1}{4}\) + \(\frac{1}{4}\)

=> (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1)Â Ă· 4

=> \(\frac{9}{4}\)

Question 14.

Gracie and Jackson each bought \(\frac{2}{3}\) pound of blackberries. Circle the correct equation that represents 2 Ă— \(\frac{2}{3}\) as a multiple of a unit fraction.

2 Ă— \(\frac{2}{3}\) = 4 Ă— \(\frac{1}{3}\)

2 Ă— \(\frac{2}{3}\) = 2 Ă— \(\frac{1}{3}\)

Answer:

2 Ă— \(\frac{2}{3}\) as a multiple of a \(\frac{1}{3}\) unit fraction is 4 Ă— \(\frac{1}{3}\).

Explanation:

Number of pound of blackberries Gracie and Jackson each bought = \(\frac{2}{3}\) .

2 Ă— \(\frac{2}{3}\) as a multiple of a unit fraction = ??

=> \(\frac{2}{3}\) + \(\frac{2}{3}\)

=> (2 + 2) Ă· 3

=> \(\frac{4}{3}\)

=> \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\)Â +\(\frac{1}{3}\)

=> 4 Ă— \(\frac{1}{3}\)

Question 15.

**Mathematical PRACTICE** Use Algebra Find the unknown in the equation

m Ă— \(\frac{1}{6}\) = \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\).

Answer:

Unknown in the equation m Ă— \(\frac{1}{6}\) = \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) is 5.

Explanation:

Equation given:

m Ă— \(\frac{1}{6}\) = \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\).

=> m = ??

=> m Ă— \(\frac{1}{6}\) = \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\)

=> m Ă— \(\frac{1}{6}\) = (1 + 1 + 1 + 1 + 1) Ă· 6

=> m Ă— \(\frac{1}{6}\) = 5 Ă— \(\frac{1}{6}\)

=> m = {5 Ă— \(\frac{1}{6}\)} Ă· 5 Ă— \(\frac{1}{6}\)

=> m = 5.

**Write About It
**Question 16.

How can any fraction \(\frac{a}{b}\) be written as a multiple of a unit fraction?

Answer:

Any fraction \(\frac{a}{b}\) be written as a multiple of a unit fraction by using the number of times the unit fraction holds to express the given fraction.

### McGraw Hill My Math Grade 4 Chapter 9 Lesson 8 My Homework Answer Key

**Practice
**

**Algebra Use an equation to write each fraction as a multiple of a unit fraction.**

Question 1.

Answer:

Equation showing \(\frac{5}{6}\) as a multiple of a \(\frac{1}{6}\) unit fraction is 5 Ă— \(\frac{1}{6}\)

Explanation:

Equation showing to the above fraction tiles:

\(\frac{1}{6}\) + \(\frac{1}{6}\)+ \(\frac{1}{6}\)+ \(\frac{1}{6}\)+ \(\frac{1}{6}\)

=> (1 + 1 + 1 + 1 + 1) Ă· 6

=> 5 Ă— \(\frac{1}{6}\)

Question 2.

Answer:

Equation showing \(\frac{8}{10}\) as a multiple of a \(\frac{1}{10}\) unit fraction is 8 Ă— \(\frac{1}{10}\)

Explanation:

Equation showing to the above fraction tiles:

\(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\)

=> (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 ) Ă· 10

=> 8 Ă— \(\frac{1}{10}\)

**Algebra Use an equation to write each fraction or product as a multiple of a unit fraction.
**Question 3.

\(\frac{3}{8}\) ___________________

Answer:

Equation showing \(\frac{3}{8}\) as a multiple of a \(\frac{1}{8}\) unit fraction is 3 Ă— \(\frac{1}{8}\)

Explanation:

\(\frac{3}{8}\) = \(\frac{1}{8}\) + \(\frac{1}{8}\) + \(\frac{1}{8}\)

= 3 Ă— \(\frac{1}{8}\)

Question 4.

\(\frac{7}{12}\) ___________________

Answer:

Equation showing \(\frac{7}{12}\) as a multiple of a \(\frac{1}{12}\) unit fraction is 7 Ă— \(\frac{1}{12}\)

Explanation:

\(\frac{7}{12}\) = \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\) + \(\frac{1}{12}\)

= (1 + 1 + 1 + 1 + 1 + 1 + 1) Ă· 12

= 7 Ă— \(\frac{1}{12}\)

Question 5.

\(\frac{6}{10}\) ___________________

Answer:

Equation showing \(\frac{6}{10}\) as a multiple of a \(\frac{1}{10}\) unit fraction is 6 Ă— \(\frac{1}{10}\)

Explanation:

\(\frac{6}{10}\) = \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\) + \(\frac{1}{10}\)

= (1 + 1 + 1 + 1 + 1 + 1) Ă· 10

= 6 Ă— \(\frac{1}{10}\)

Question 6.

\(\frac{4}{5}\) ___________________

Answer:

Equation showing \(\frac{4}{5}\) as a multiple of a \(\frac{1}{5}\) unit fraction is 4 Ă— \(\frac{1}{5}\)

Explanation:

\(\frac{4}{5}\) = \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\)

= (1 + 1 + 1 + 1) Ă· 5

= 4 Ă— \(\frac{1}{5}\)

Question 7.

3 Ă— \(\frac{4}{5}\) ___________________

Answer:

Equation showing 3 Ă— \(\frac{4}{5}\) as a multiple of a \(\frac{1}{5}\) unit fraction is 12 Ă— \(\frac{1}{5}\)

Explanation:

3 Ă— \(\frac{4}{5}\) = \(\frac{12}{5}\) = \(\frac{1}{5}\)Â + \(\frac{1}{5}\) + \(\frac{1}{5}\)Â + \(\frac{1}{5}\)Â + \(\frac{1}{5}\)Â + \(\frac{1}{5}\) + \(\frac{1}{5}\)Â + \(\frac{1}{5}\) + \(\frac{1}{5}\)Â + \(\frac{1}{5}\) + \(\frac{1}{5}\)Â + \(\frac{1}{5}\)

= 12 Ă— \(\frac{1}{5}\)

Question 8.

5 Ă— \(\frac{2}{5}\) ___________________

Answer:

Equation showing 5 Ă— \(\frac{2}{5}\) as a multiple of a \(\frac{1}{5}\) unit fraction is 10 Ă— \(\frac{1}{5}\)

Explanation:

5 Ă— \(\frac{2}{5}\) = \(\frac{10}{5}\) = \(\frac{1}{5}\)Â + \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\) + \(\frac{1}{5}\)Â + \(\frac{1}{5}\) + \(\frac{1}{5}\)Â + \(\frac{1}{5}\) + \(\frac{1}{5}\)Â + \(\frac{1}{5}\)

= 10 Ă— \(\frac{1}{5}\)

Question 9.

8 Ă— \(\frac{6}{10}\) ___________________

Answer:

Equation showing 8 Ă— \(\frac{6}{10}\) as a multiple of a \(\frac{8}{10}\) unit fraction is 6 Ă— \(\frac{8}{10}\)

Explanation:

8 Ă— \(\frac{6}{10}\) = \(\frac{48}{10}\) = \(\frac{8}{10}\) + \(\frac{8}{10}\) + \(\frac{8}{10}\)+ \(\frac{8}{10}\) + \(\frac{8}{10}\)+ \(\frac{8}{10}\)

= 6 Ă— \(\frac{8}{10}\)

Question 10.

7 Ă— \(\frac{8}{12}\) ___________________

Answer:

Equation showing 7 Ă— \(\frac{8}{12}\) as a multiple of a \(\frac{7}{12}\) unit fraction is 8 Ă— \(\frac{7}{12}\)

Explanation:

7 Ă— \(\frac{8}{12}\) = \(\frac{56}{12}\) = \(\frac{7}{12}\) + \(\frac{7}{12}\)Â + \(\frac{7}{12}\) + \(\frac{7}{12}\) + \(\frac{7}{12}\) + \(\frac{7}{12}\)Â + \(\frac{7}{12}\) + \(\frac{7}{12}\)

= 8 Ă— \(\frac{7}{12}\)

**Problem Solving
**Question 11.

**Mathematical PRACTICE**Model Math Marcia has one cup of tea each day for 7 days. She puts \(\frac{2}{3}\) tablespoons of honey in each cup of tea. Write an equation that represents 7 Ă— \(\frac{2}{3}\) as a multiple of a unit fraction.

Answer:

Equation that represents 7 Ă— \(\frac{2}{3}\) as a multiple of a \(\frac{1}{3}\) unit fraction is 14 Ă— \(\frac{1}{3}\)

Explanation:

Number of days Marcia has one cup of tea = 7.

Number of cups of tea he has each day = 1.

Number of tablespoons of honey in each cup of tea she puts = \(\frac{2}{3}\).

Total number of tea with tablespoons of honey he has = Number of days Marcia has one cup of tea Ă— Number of cups of tea he has each day Ă— Number of tablespoons of honey in each cup of tea she puts

= 7 Ă— 1 Ă— \(\frac{2}{3}\)

= \(\frac{14}{3}\)

= \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\) + \(\frac{1}{3}\)+ \(\frac{1}{3}\)+ \(\frac{1}{3}\)+ \(\frac{1}{3}\)+ \(\frac{1}{3}\)+\(\frac{1}{3}\)+ \(\frac{1}{3}\)+\(\frac{1}{3}\)+\(\frac{1}{3}\) + \(\frac{1}{3}\)

= 14 Ă— \(\frac{1}{3}\)

Question 12.

Sam buys 4 tropical fish. Each fish is \(\frac{5}{8}\) of an inch long. Write an equation that represents 4 Ă— \(\frac{5}{8}\) as a multiple of a unit fraction.

Answer:

Equation that represents 4 Ă— \(\frac{5}{8}\) as a multiple of a \(\frac{5}{8}\) unit fraction is \(\frac{5}{8}\) + \(\frac{5}{8}\)+ \(\frac{5}{8}\)+ \(\frac{5}{8}\)

Explanation:

Number of tropical fish Sam buys = 4.

Number of inches each fish = \(\frac{5}{8}\)

Total number of inches all fishes = Number of tropical fish Sam buys Ă— Number of inches each fish

= 4 Ă— \(\frac{5}{8}\)

=> \(\frac{20}{8}\)