McGraw Hill My Math Grade 4 Chapter 4 Lesson 9 Answer Key Multiply by a Multi-Digit Number

All the solutions provided in McGraw Hill Math Grade 4 Answer Key PDF Chapter 4 Lesson 9 Multiply by a Multi-Digit Number will give you a clear idea of the concepts.

McGraw-Hill My Math Grade 4 Answer Key Chapter 4 Lesson 9 Multiply by a Multi-Digit Number

Math in My World

Example 1
Today is Laura’s birthday, and she is nine years old. Except for leap years, there are 365 days in one year. How many days old is Laura?

Find 365 × 9

So, Laura is ___ days old.

Check for Reasonableness
The product, ____, is close to the estimate, ____

Answer:
Given that,
Today is Laura’s birthday, and she is nine years old. Except for leap years.
There are 365 days in one year.

365 × 9 = 3,285.
So, Laura is 3,285 days old.
The product is 3,285 and it is close to the estimate 3,300.

Example 2
Find 3 × $1,175.

Answer:

Talk Math
Explain why it is a good idea to estimate answers to multiplication problems.

Answer:
Estimate is helpful to the reasonableness of the answer. To estimate first we round up the multiplier and the multiplicand to the nearest tens ones and hundreds and so on. then multiply the rounded numbers.

Guided Practice

Multiply. Check for reasonableness.

Question 1.

Answer:
First multiply 2 with 5 then you get 10.
Second multiply 2 with 30 then you get 60.
Third multiply 2 with 100 then 200.
Then add the total products that is 10 + 60 + 200 = 270.

Question 2.

Answer:
First multiply 6 with 2 then you get 12.
Second multiply 6 with 30 then you get 180.
Third multiply 6 with 500 then 3,000.
Then add the total products that is 12 + 180 + 3,000 = 3,192.

Independent Practice

Multiply. Check for reasonableness.

Question 3.

Answer:
First multiply 3 with 3 then you get 9.
Second multiply 3 with 10 then you get 30.
Third multiply 3 with 300 then 900.
Then add the total products that is 9 + 30 + 900 =939.

Question 4.

Answer:
First multiply 5 with 9 then you get 45.
Second multiply 5 with 10 then you get 50.
Third multiply 5 with 800 then 4,000.
Then add the total products that is 45 + 50 + 4,000 = 4,095.

Question 5.

Answer:
First multiply 5 with 1 then you get 5.
Second multiply 5 with 80 then you get 400.
Third multiply 5 with 700 then 3,500.
Then add the total products that is 5 + 400 +3,500 = 3,905.

Question 6.

Answer:
First multiply 4 with 8 then you get 32.
Second multiply 4 with 30 then you get 120.
Third multiply 4 with 200 then 800.
Then add the total products that is 32 + 120 + 800 = 952.

Question 7.
7 × $460 = ____
Estimate:
Answer:
First multiply 7 with 0 then you get 0.
Second multiply 7 with 60 then you get 420.
Third multiply 7 with 400 then 2800
Then add the total products that is 0 + 420 + 2,800 = 3,220.

Estimation of 3,220 is 3,200.

Question 8.
7 × 561 = ____
Answer:
First multiply 7 with 1 then you get 7.
Second multiply 7 with 60 then you get 420.
Third multiply 7 with 500 then 3,500
Then add the total products that is 7 + 420 + 3,500 = 3927.

Question 9.
8 × 6,328 = ____
Answer:
First multiply 8 with 8 then you get 64.
Second multiply 8 with 20 then you get 160.
Third multiply 8 with 300 then 2,400.
Fourth multiply 8 with 6000 then 48,000
Then add the total products that is 64 + 160 +2,400 + 48,000 = 50624.

Question 10.
9 × $5,679 = ____
Answer:
First multiply 9 with 9 then you get 81.
Second multiply 9 with 20 then you get 180.
Third multiply 9 with 300 then 27,00.
Fourth multiply 9 with 6000 then 54,000
Then add the total products that is 81 + 180 + 2,700 + 54,000 = 56,961.

Algebra Find each unknown number.

Question 11.
8 × 7,338 = x
x = ____
Answer:
Multiplication of 8 with 7,338 then you get 58,704.
8 × 7,338 = 58,704.
x = 58,704.
Therefore the unknown is 58,704.

Question 12.
7 × 8,469 = y
y = ____
Answer:
Multiplication of 7 with 8,469 then you get 59,283.
7 × 8,469 = 59,283.
y = 59,283.
Therefore the unknown is 59,283.

Question 13.
9 × $9,927 = t
t = ____
Answer:
Multiplication of 9 with $9,927 then you get $89,343.
9 × $9,927 = $89,343.
t = $89,343.
Therefore the unknown is $89,343.

Question 14.
9 × 8,586 = u
u = ____
Answer:
Multiplication of 9 with 8,586 then you get 77,274.
9 × 8,586 = 77274.
u = 77,274.
Therefore the unknown is 77,274.

Algebra Find each produd if n = 8.

Question 15.
n × 295 = ___
Answer:
Given that is
n x 295
n = 8.
Substitute n value in equation.
Multiplication of 8 with 295 then you get 2360.
8 x 295 = 2360.

Question 16.
737 × n = ___
Answer:
Given that is
737 x n
n = 8.
Substitute n value in equation.
Multiplication of 737 with 8 then you get 5896.
737 x 8 = 5896.

Question 17.
n × $2,735 = ____
Answer:
Given that is
n × $2,735
n = 8.
Substitute n value in equation.
Multiplication of 8 with $2,735 then you get $21880.
8 × $2,735 = $21880.

Compare. Use >, <, or =.

Question 18.
4 × 198 3 × 248
Answer:
4 × 198 = 792.
3 × 248 = 774.
4 × 198 > 3 × 248.
4 × 198 is greater than 3 × 248.

Question 19.
7 × 385 6 × 457
Answer:
7 × 385 = 2695.
6 × 457 = 2742.
7 × 385 less than 6 × 457.
7 × 385 < 6 × 457.

Problem Solving

Question 20.
Mr. Gibbons buys 8 cases of seeds at the school plant sale. If there are 144 packages of seeds in each case, how many packages of seeds has he bought?

Answer:
Given that,
Mr. Gibbons buys 8 cases of seeds at the school plant sale.
There are 144 packages of seeds in each case
The number of packages are 144 x 8 = 1,152.
Therefore there are 1,152 packages in 8 cases.

Question 21.
On average, 1,668 gallons of water are used daily by each person in the United States. How much water is used by one person in a week?
Answer:
Given that,
On average, 1,668 gallons of water are used daily by each person in the United States.
1 week = 7 days.
Water used in one week is 7 x 1,668 = 11,676.
Therefore 11,676 gallons of water used by one person in a week.

Question 22.
Each set of furniture costs $2,419 How much would it cost to buy 5 sets of furniture?
Answer:
Given that,
Each set of furniture costs $2,419.
The cost for 5 sets of furniture is 5 x $2,419 = $12,095.
Therefore the cost of 5 sets of furniture is $12,095.

HOT Problems

Question 23
Mathematical PRACTICE 1 Keep Trying Complete the equation.

Answer:

Question 24.
Mathematical PRACTICE 7 Identify Structure Write a four-digit number and a one-digit number whose product is greater than 6,000 and less than 6,200.
Answer:
The four digit number is 3,001.
The one digit number is 2.
3001  x 2 = 6002.
Therefore 6002 is greater than 6000 and less than 6200.

Question 25.
? Building on the Essential Question How is multiplying by multi-digit numbers similar to multiplying by two-digit numbers?
Answer:
We use the same model for the multi digit numbers and two digit numbers.
For both numbers we multiply from the right side of a number.
Example for two digit number 2 x 12 = 24.
for multi digit numbers 2 x 123 = 246.

McGraw Hill My Math Grade 4 Chapter 4 Lesson 9 My Homework Answer Key

Multiply. Check for reasonableness.

Question 1.

Answer:
First multiply 9 with 3 then you get 27.
Second multiply 9 with 10 then you get 90.
Third multiply 9 with 300 then 2,700.
Fourth multiply 9 with 1000 then 9,000
Then add the total products that is 27+ 90 +2,700 + 9,000 = 11817.

Question 2.

Answer:
First multiply 6 with 7 then you get 42.
Second multiply 6 with 40 then you get 240.
Third multiply 6 with 500 then 3000.
Then add the total products that is 42 + 240 +3000  = 3282.

Question 3.

Answer:
First multiply 3 with 1 then you get 3.
Second multiply 3 with 20 then you get 60.
Third multiply 3 with 400 then 1200.
Fourth multiply 3 with 6000 then 18,000
Then add the total products that is 3 + 60 +1200 + 18,000 = 19263.

Question 4.

Answer:
First multiply 5 with 2 then you get 10.
Second multiply 5 with 10 then you get 50.
Third multiply 5 with 500 then 2,500.
Fourth multiply 5 with 4000 then 20,000
Then add the total products that is 10 + 50 +2,500 + 20,000 = 22560.

Question 5.
3,525 × 6 = ____
Answer:
First multiply 6 with 5 then you get 30.
Second multiply 6 with 20 then you get 120.
Third multiply 6 with 500 then 3000.
Fourth multiply 6 with 3000 then 18,000
Then add the total products that is 30 + 120 +3000 + 18,000 = 21150.

Question 6.
7 × 7,441 = ____
Answer:
First multiply 7 with 1 then you get 7.
Second multiply 7 with 40 then you get 280.
Third multiply 7 with 400 then 2,800.
Fourth multiply 7 with 7000 then 49,000
Then add the total products that is 7 + 280 +2,080 + 47,000 = 52087.

Algebra Find each product.

Question 7.
n = 8
n × $685 = ____
Answer:
Given that is
n x $685
n = 8.
Substitute n value in above equation.
8 x $685 = $5,480.
Multiplication of 8 with $685 then you get $5,480.

Question 8.
n = 3
n × 5,266 = ____
Answer:
Given that is
n x 5,266.
n = 3.
Substitute n value in above equation.
3 x 5,266 = 15,798
Multiplication of 3 with 5,266 then you get 15,798.

Problem Solving

Question 9.
Mathematical PRACTICE 2 Use Number Sense One shelf in the greenhouse holds 467 plants. How many plants can 6 shelves hold?
Answer:
Given that,
One shelf in the greenhouse holds 467 plants.
Number of shelves are 6.
The number of plants in 6 shelves is 467 x 6 = 2,802.
Therefore there are 2,802 plants in 6 shelves.

Question 10.
Samantha’s parents bought her a new bed. They paid $136 each month for 9 months. How much did the bed cost?
Answer:
Given that,
They paid $136 each month for 9 months.
So, $136 x 9 = $1,224.
Therefore Samantha’s parents paid to the bed is $1,224

Question 11.
A concert hall seats 7,689 people. There were 8 concerts in June, and a ticket was sold for every seat. How many tickets were sold in June?
Answer:
Given that,
A concert hall seats 7,689 people.
There were 8 concerts in June.
A ticket was sold for every seat.
The number of tickets in June are 7,689 x 8 = 61,512.
Therefore 61,512 tickets are sold in June.

Test Practice

Question 12.
Find the product n × 2,019 if n = 5.
A. 10,000
B. 10,055
C. 10,095
D. 10,545
Answer:
Given that,
n x 2,019
n = 5.
Substitute n = 5 in equation.
5 x 2019 = 10,095.
Option C is the correct answer.