McGraw Hill My Math Grade 4 Chapter 11 Review Answer Key

All the solutions provided in McGraw Hill My Math Grade 4 Answer Key PDF Chapter 11 Review will give you a clear idea of the concepts.

McGraw-Hill My Math Grade 4 Chapter 11 Review Answer Key

Vocabulary Check

Draw a line from each word to its definition.
McGraw Hill My Math Grade 4 Chapter 11 Review Answer Key 1
Answer:
McGraw-Hill-My-Math-Grade-4-Chapter-11-Review-Answer-Key-1

Write an example for each measurement.

Question 6.
1 yard ________________
Answer:
The width of a door will measure around 1 yard.

Question 7.
1 quart ________________
Answer:
Milk container will measure around 1 quart.

Question 8.
1 foot ________________
Answer:
Height of a cat will measure around 1 foot.

Question 9.
1 gallon ________________
Answer:
The capacity of fish tank will measure around 1 gallon.

Question 10.
1 mile ________________
Answer:
The distance between the post office and my house is around 1 mile.

Question 11.
1 ounce ________________
Answer:
The weight of a strawberry will measure about 1 ounce.

Question 12.
1 fluid ounce ________________
Answer:
The cup of milk weighs around 1 fluid ounce.

Question 13.
1 pound ________________
Answer:
A football will weigh around 1 pound.

Question 14.
1 cup ________________
Answer:
My icecream cup measures around 1 cup.

Question 15.
1 ton ________________
Answer:
The large cargo box weighs around 1 ton.

Question 16.
1 pint ________________
Answer:
A large glass of milk will weight around 1 pint.

Question 17.
1 second ________________
Answer:
My eyes blink for a duration of 1 second.

Concept Check

Complete each conversion table.

Question 18.
McGraw Hill My Math Grade 4 Chapter 11 Review Answer Key 2
Answer:
1 yard equals 36 in.
3 yards will be equal to 3Ă—36 = 108 in.
5 yards will be equal to 5Ă—36 = 180 in.
7 yards will be equal to 7Ă—36 = 252 in.
McGraw-Hill-My-Math-Grade-4-Chapter-11-Review-Answer-Key-2

Question 19.
McGraw Hill My Math Grade 4 Chapter 11 Review Answer Key 3
Answer:
1 gal equals 16 c
2 gal will be equal to 2Ă—16 = 32 c
3 gal will be equal to 3Ă—16 = 48 c
4 gal will be equal to 4Ă—16 = 64 c
5 gal will be equal to 5Ă—16 = 80 c
McGraw-Hill-My-Math-Grade-4-Chapter-11-Review-Answer-Key-3

Question 20.
McGraw Hill My Math Grade 4 Chapter 11 Review Answer Key 4
Answer:
1 yard equals 3 feet.
2 yards will be equal to 2Ă—3=6 ft.
4 yards will be equal to 4Ă—3=12 ft.
6 yards will be equal to 6Ă—3=18 ft.
8 yards will be equal to 8Ă—3=24 ft.
McGraw-Hill-My-Math-Grade-4-Chapter-11-Review-Answer-Key-4

Question 21.
McGraw Hill My Math Grade 4 Chapter 11 Review Answer Key 5
Answer:
1 min equals 60 s.
3 min will be equal to 3Ă—60=180s.
5 min will be equal to 5Ă—60=300s.
7 min will be equal to 7Ă—60=420s.
McGraw-Hill-My-Math-Grade-4-Chapter-11-Review-Answer-Key-5

Question 22.
How many times greater is one hour than one minute?
Answer:
1 hour equals to 60 mins.
Therefore, one hour is 60 times greater than one minute.

Question 23.
How many times greater is one gallon than one quart?
Answer:
1 gallon equals 4 quarts.
Therefore, one gallon is 4 times greater than one quart.

Question 24.
How many times greater is one mile than one foot?
Answer:
1 mile equals to 5280 foot.
Therefore, one mile is 5280 times greater than one foot.

Question 25.
How many times greater is one pound than one ounce?
Answer:
1 pound equals to 16 ounces.
Therefore, one pound is 16 times greater than one ounce.

McGraw Hill My Math Grade 4 Chapter 11 Review Answer Key 6

Question 26.
How many minutes have passed between the time shown on the first clock and the time shown on the second clock?
Answer:
In the first clock, the first time is 3hrs and the second time is 6 hrs 25 mins.
3hrs 25 mins have passed between the time shown on the first clock and the time shown on the second clock.
In the second clock, the time is 5hrs and the second time is 6hrs 28mins.
1hr 28mins have passed between the time shown on the first clock and the time shown on the second clock.

Question 27.
How many seconds have passed between the time shown on the first clock and the time shown on the second clock?
Answer:
In the first clock, the first time is 3hrs and the second time is 6 hrs 25 mins.
The difference between the time will be 3hrs 25 mins.
1 hr equals to 360 secs and 1 min equals 60 secs.
So, 3 hrs will be 3Ă—360=108 secs and 25 mins will be 25Ă—60=1500 secs.
108+1500=1608 secs.
1608 secs have passed between the time shown on the first clock and the time shown on the second clock.

Problem Solving

For Exercises 28-31, use the table shown. The table represents the lengths of beads that Zoe is using to make a necklace.
McGraw Hill My Math Grade 4 Chapter 11 Review Answer Key 7

Question 28.
Represent this data in a line plot.
Answer:
McGraw-Hill My Math Grade 4 Chapter 11 Review Answer Key img_1

Question 29.
What is the difference in length between the longest bead and the shortest bead?
Answer:
Length of the longest bead is \(\frac{5}{6}\) and length of the shortest bead is \(\frac{1}{6}\).
The difference in length between the longest bead and the shortest bead will be \(\frac{5}{6}\) – \(\frac{1}{6}\) = \(\frac{4}{6}\)

Question 30.
What is the total length of the beads that are \(\frac{4}{6}\) inch long?
Answer:
There are 2 ‘x’ on \(\frac{4}{6}\) inch.
So the total length of the beads that are \(\frac{4}{6}\) inch long will be \(\frac{4}{6}\) + \(\frac{4}{6}\) = \(\frac{8}{6}\)

Test Practice

Question 31.
Which bead length has enough beads to total exactly \(\frac{1}{2}\) inch if the beads of that size are laid end to end?
(A) \(\frac{1}{6}\) inch
(B) \(\frac{2}{6}\) inch
(C) \(\frac{4}{6}\) inch
(D) \(\frac{5}{6}\) inch
Answer:
Let us assume the beads of length \(\frac{1}{6}\) inch are laid end to end.
\(\frac{1}{6}\) + \(\frac{1}{6}\) + \(\frac{1}{6}\) = \(\frac{3}{6}\)
\(\frac{3}{6}\) or \(\frac{1}{2}\)
Therefore we can \(\frac{1}{6}\) inch length has enough beads to total exactly \(\frac{1}{2}\) inch if the beads of that size are laid end to end.
Therefore, option A is correct.

Reflect

Use what you learned about customary measurements to complete the graphic organizer.
McGraw Hill My Math Grade 4 Chapter 11 Review Answer Key 8
Reflect on the ESSENTIAL QUESTION Write your answer below.
Answer:
McGraw-Hill-My-Math-Grade-4-Chapter-11-Review-Answer-Key-8
We need to convert measurements so that the customary measurement of the given object can be measured with accuracy.
For example, the capacity of a milk container cannot be measured in gallons, it can be accuartely measured in pints.

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