We included **HMH Into Math Grade 6 Answer Key PDF** **Module 12 Review **to make students experts in learning maths.

## HMH Into Math Grade 6 Module 12 Review Answer Key

**Vocabulary**

**Choose the correct term from the Vocabulary box.**

Vocabulary

parallelogram

trapezoid

composite figure

Question 1.

A _____________ is a shape that can be divided into more than one of the basic shapes.

Answer:

composite figure.

Explanation:

A composite figure is a shape that can be divided into more than one of the basic shapes.

Question 2.

A _____________ is a four-sided figure with opposite sides that are parallel.

Answer:

parallelogram

Explanation:

A parallelogram is a four-sided figure with opposite sides that are parallel.

Question 3.

A ______________ is a four-sided figure with at least one pair of parallel sides.

Answer:

trapezoid.

Explanation:

A trapezoid is a four-sided figure with at least one pair of parallel sides.

**Concepts and Skills**

Question 4.

What is the area of the parallelogram?

Answer:

Area = 24.6 inches^{2}

Explanation:

Given,

h = 3 inches, base = 8.2 inches

Area of the parallelogram = b × h

Area = 3 × 8.2

Area = 24.6 inches^{2}

Question 5.

A square stepping stone has a side length of 10\(\frac{1}{4}\) inches. What is the area of the stepping stone?

Answer:

Area = 420.25 inches^{2}

Explanation:

Given, the side of length is 10\(\frac{1}{4}\) inches = \(\frac{41}{4}\)

Area of the square = S^{2}

Area = S × S

Area = \(\frac{41}{4}\) × \(\frac{41}{4}\)

Area = \(\frac{1681}{4}\)

Area = 420.25 inches^{2}

Question 6.

Tamara’s backyard pool needs a cover for the winter. The pool is rectangular with a length of 12 feet and an area of 196.8 square feet. What is the width of the pool cover Tamara’s pool will need?

Answer:

Given, the area of a rectangular pool is 196.8 square feet.

The length of the rectangle is 12 feet.

Area of the rectangular pool = l × b

196.8 = 12 × b

b = \(\frac{196.8}{12}\)

b = 16.4 feet.

Question 7.

**Use Tools** A rectangular flag consists of two right triangles. The area of each triangle is 6.6 square feet. What are the length and area of the flag? State what strategy and tool you will use to answer the question, explain your choice, and then find the answer.

Answer:

Area of the flag = 39.6 feet^{2}

Explanation:

Given Area of each traingle is 6.6 square feet and length of the other side is 2.2 feet.

Area of a traingle is \(\frac{1}{2}\) × b × h

6.6 = \(\frac{1}{2}\) × 2.2 × h

6.6 × 2 = 2.2 × h

3 × 2 = h

h = 6 feet

Area of the flag = L × b

area = 6.6 × 6

Area of the flag = 39.6 feet^{2}

Question 8.

A tile maker makes triangular tiles for a mosaic. Two triangular tiles form a square. What is the area of one of the triangular tiles?

Answer:

Given,

Two triangular tiles form a square

For a square all sides are equal.

Therefore base = 3\(\frac{1}{2}\) = \(\frac{7}{2}\) and height is \(\frac{7}{2}\)

Area of the triangle is \(\frac{1}{2}\) × b × h

Area = \(\frac{1}{2}\) × \(\frac{7}{2}\) × \(\frac{7}{2}\)

Area = \(\frac{49}{4}\)

Area = 12.25 in^{2}

Question 9.

The top of a schoolwork table is in the shape of a trapezoid. What is the area of the tabletop?

(A) 7 ft^{2}

(B) 12 ft^{2}

(C) 14 ft^{2}

(D) 24 ft^{2}

Answer:

Given b1 = 4 feet, b2 = 3 feet and height = 2 feet

Area of a trapezoid = \(\frac{a + b}{2}\) × h

Area = \(\frac{4 + 3}{2}\) × 2

Area = \(\frac{7}{2}\) × 2

Area = 7 ft^{2}

Question 10.

A tangram is a puzzle consisting of pieces that are put together to form shapes. One such shape is shown. What is the area of the figure shape?

Answer:

The area of the figure shape is 57 cm^{2}

Explanation:

Now we need to calculate the area of the given figure.

The given figure is in a rectangle shape.

Hence the area of the rectangle is l × b

Area = 6 × 9.5

Area =57 cm^{2}

Question 11.

A small plot of land is shaped like the figure shown. What is the area of the plot of land?

(A) 43 yd^{2}

(B) 153 yd^{2}

(C) 306 yd^{2}

(D) 1,188 yd^{2}

Answer:

The area of the plot of land is 153 yd^{2}

Explanation:

Given, base1 = 12 yd , base2 = 22 yd, and height = 9 yd

Area of trapezoid = \(\frac{a + b}{2}\) × h

Area = \(\frac{12 + 22}{2}\) × 9

Area = \(\frac{34}{2}\) × 9

Area = 17 × 9

Area = 153 yd^{2}

Question 12.

An artwork consists of the triangles shown, where the shaded triangle is cut out of the larger triangle. What is the area of the remaining unshaded portion?

Answer:

The area of the remaining unshaded portion = 16.2 m^{2}

Explanation:

Given, base = 8m and height = 8.1 m for larger traingle

Area of the remaining unshaded portion = \(\frac{1}{2}\) × b × h

Area = \(\frac{1}{2}\) × 4 × 8.1

Area = 16.2 m^{2}