We included HMH Into Math Grade 5 Answer Key PDF Module 5 Volume to make students experts in learning maths.

How can I Cover this stain?

• Oh no! There is a stain on the wooden floor. Draw the smallest rectangular carpet you can use to cover the stain.
• What is the length of your rectangle?
___________________
• What is the width of your rectangle?
___________________
• What is the area of the carpet you used?
___________________

the length is 9Â  foot,
the width is 6 foot,
area of the carpet is 54 square foot,

Explanation:
Drawn the smallest rectangular carpet I can use to cover the stain.
The length of my rectangle is 9 foot,
The width of my rectangle is 6 foot and
Area of the carpet is 9 foot X 6 foot = 54 square foot.

Turn and Talk

• How many 1-foot-by-1-foot pieces of carpet do you need to cover only the stain? Explain your thinking.

54 pieces,

Explanation:
I need 1-foot-by-1-foot pieces of carpet to cover only the stain as area of the carpet is 54 square foot so 54 X 1 X 1 = 54 pieces.

Complete these problems to review prior concepts and skills you will need for this module.

Perimeter

Find the perimeter.

Question 1.

Perimeter = ___ units
34 units,

Explanation:
Given to find the perimeter of the shape we seperately divide and calculate so
1 part : 1 unit width and 3 units length and
perimeter of rectangle is 2 ( length + width)
= 2(1 + 3)
= 2 X 4 = 8 units,
2 part : 1 unit width and 5 units length = 2(1 + 5)
= 2 X 6 = 12 units,
3 part : 1 unit width and 6 units length = 2(1 + 6)
= 2 X 7 = 14 units,
so total perimeter is part 1+ part 2 + part 3 =
8 units + 12 units + 14 units = 34 units, or
we will count unit blocks as width 3 units and length 14 units so perimeter is
2 X ( 3 units + 14 units) = 2 X 17 units = 34 units.

Question 2.

Perimeter = ___ units
28 units,

Explanation:
Given to find the perimeter of the shape we seperately divide and calculate so
1 part : 1 unit width and 2 units length and
perimeter of rectangle is 2 ( length + width)
= 2(1 + 2)
= 2 X 3 = 6 units,
2 part : 1 unit width and 4 units length = 2(1 + 4)
= 2 X 5 = 10 units,
3 part : 1 unit width and 6 units length = 2(1 + 5)
= 2 X 6 = 12 units,
so total perimeter is part 1+ part 2 + part 3 =
6 units + 10 units + 12 units = 28 units, or
we will count unit blocks as width 3 units and length 11 units so perimeter is
2 X ( 3 units + 11 units) = 2 X 14 units = 28 units.

Area

Count to find the area of the figure.

Question 3.

Area = ___ square units
12 square units,

Explanation:
Asking to find the area of the given figure it has length of 6 units and
width of 2 units so area = 2 units X 6 units =
12 square units or if we count we have 12 –
1 unit X 1 unit squares so the area is
12 X 1 unit X 1 unit = 12 square units.

Question 4.

Area = ___ square units
13 square units,

Explanation:
Asking to find the area of the given figure
we calculate in parts
Part 1 : length is 4 units and width 1 unit,
area = 4 units X 1 unit = 4 square units,
Part 2 : length is 6 units and width is 1 unit,
area = 6 units X 1 unit = 6 square units,
Part 3 : length i s 3 units and width is 1 unit,
area = 3 units X 1 unit = 3 square units,
therefore total area is = 4 sq units + 6 sq units + 3 sq units = 13 square units or if we count we have 13 – 1 unit X 1 unit squares so the area is 13 X 1 unit X 1 unit = 13 square units.

Use the Associative Property of Multiplication

Find the unknown number.

Question 5.
4 Ã— 80 = (4 Ã— ___ ) Ã— 10
8,

Explanation:
Given to find the unknown number in
4 Ã— 80 = (4 Ã— ___ ) Ã— 10, let the unknown number
be x so 4 X 80 = (4 X x) X 10,
320 = 4x X 10,
320 = 40x,
x = 320 Ã· 40,
x = 8.

Question 6.
3 Ã— 50 = (3 Ã— ___) Ã— 10
5,

Explanation:
Given to find the unknown number in
3 Ã— 50 = (3 Ã— ___ ) Ã— 10, let the unknown number
be x so 3 X 50 = (3 X x) X 10,
150 = 3x X 10
150 = 30x,
x = 150 Ã· 30 = 5.

Question 7.
6 Ã— 70 = (6 Ã— ___) Ã— 10
7,

Explanation:
Given to find the unknown number in
6 Ã— 70 = (6 Ã— ___ ) Ã— 10, let the unknown number
be x so 6 X 70 = (6 X x) X 10,
420 = 60x,
x = 420 Ã· 60 = 7.

Question 8.
60 Ã— 9 = 10 Ã— (___ Ã— 9)
6,

Explanation:
Given to find the unknown number in
60 Ã— 9 = 10 X (___ X 9), let the unknown number
be x so 60 X 9 = 10 X 9x,
540 = 90x,
x= 540 Ã· 90 = 6.

Question 9.
30 Ã— 7 = 10 Ã— (___ Ã— 7)
3,

Explanation:
Given to find the unknown number in
30 Ã— 7 = 10 X (___ X 7), let the unknown number
be x so 30 X 7 = 10 X (x X 7),
210 = 10 X 7x,
210 = 70x,
x = 210 Ã· 70 = 3.

Question 10.
4 Ã— 40 = (4 Ã— ___) Ã— 10