We included **HMH Into Math Grade 5 Answer Key**** PDF** **Module 5 Volume **to make students experts in learning maths.

## HMH Into Math Grade 5 Module 5 Answer Key Volume

**How can I Cover this stain?**

- Oh no! There is a stain on the wooden floor. Draw the smallest rectangular carpet you can use to cover the stain.

- What is the length of your rectangle?

___________________ - What is the width of your rectangle?

___________________ - What is the area of the carpet you used?

___________________

Answer:

the length is 9Â foot,

the width is 6 foot,

area of the carpet is 54 square foot,

Explanation:

Drawn the smallest rectangular carpet I can use to cover the stain.

The length of my rectangle is 9 foot,

The width of my rectangle is 6 foot and

Area of the carpet is 9 foot X 6 foot = 54 square foot.

Turn and Talk

- How many 1-foot-by-1-foot pieces of carpet do you need to cover only the stain? Explain your thinking.

Answer:

54 pieces,

Explanation:

I need 1-foot-by-1-foot pieces of carpet to cover only the stain as area of the carpet is 54 square foot so 54 X 1 X 1 = 54 pieces.

Are You Ready?

**Complete these problems to review prior concepts and skills you will need for this module.**

**Perimeter**

**Find the perimeter.**

Question 1.

Perimeter = ___ units

Answer:

34 units,

Explanation:

Given to find the perimeter of the shape we seperately divide and calculate so

1 part : 1 unit width and 3 units length and

perimeter of rectangle is 2 ( length + width)

= 2(1 + 3)

= 2 X 4 = 8 units,

2 part : 1 unit width and 5 units length = 2(1 + 5)

= 2 X 6 = 12 units,

3 part : 1 unit width and 6 units length = 2(1 + 6)

= 2 X 7 = 14 units,

so total perimeter is part 1+ part 2 + part 3 =

8 units + 12 units + 14 units = 34 units, or

we will count unit blocks as width 3 units and length 14 units so perimeter is

2 X ( 3 units + 14 units) = 2 X 17 units = 34 units.

Question 2.

Perimeter = ___ units

Answer:

28 units,

Explanation:

Given to find the perimeter of the shape we seperately divide and calculate so

1 part : 1 unit width and 2 units length and

perimeter of rectangle is 2 ( length + width)

= 2(1 + 2)

= 2 X 3 = 6 units,

2 part : 1 unit width and 4 units length = 2(1 + 4)

= 2 X 5 = 10 units,

3 part : 1 unit width and 6 units length = 2(1 + 5)

= 2 X 6 = 12 units,

so total perimeter is part 1+ part 2 + part 3 =

6 units + 10 units + 12 units = 28 units, or

we will count unit blocks as width 3 units and length 11 units so perimeter is

2 X ( 3 units + 11 units) = 2 X 14 units = 28 units.

Area

**Count to find the area of the figure.**

Question 3.

Area = ___ square units

Answer:

12 square units,

Explanation:

Asking to find the area of the given figure it has length of 6 units and

width of 2 units so area = 2 units X 6 units =

12 square units or if we count we have 12 –

1 unit X 1 unit squares so the area is

12 X 1 unit X 1 unit = 12 square units.

Question 4.

Area = ___ square units

Answer:

13 square units,

Explanation:

Asking to find the area of the given figure

we calculate in parts

Part 1 : length is 4 units and width 1 unit,

area = 4 units X 1 unit = 4 square units,

Part 2 : length is 6 units and width is 1 unit,

area = 6 units X 1 unit = 6 square units,

Part 3 : length i s 3 units and width is 1 unit,

area = 3 units X 1 unit = 3 square units,

therefore total area is = 4 sq units + 6 sq units + 3 sq units = 13 square units or if we count we have 13 – 1 unit X 1 unit squares so the area is 13 X 1 unit X 1 unit = 13 square units.

**Use the Associative Property of Multiplication**

**Find the unknown number.**

Question 5.

4 Ã— 80 = (4 Ã— ___ ) Ã— 10

Answer:

8,

Explanation:

Given to find the unknown number in

4 Ã— 80 = (4 Ã— ___ ) Ã— 10, let the unknown number

be x so 4 X 80 = (4 X x) X 10,

320 = 4x X 10,

320 = 40x,

x = 320 Ã· 40,

x = 8.

Question 6.

3 Ã— 50 = (3 Ã— ___) Ã— 10

Answer:

5,

Explanation:

Given to find the unknown number in

3 Ã— 50 = (3 Ã— ___ ) Ã— 10, let the unknown number

be x so 3 X 50 = (3 X x) X 10,

150 = 3x X 10

150 = 30x,

x = 150 Ã· 30 = 5.

Question 7.

6 Ã— 70 = (6 Ã— ___) Ã— 10

Answer:

7,

Explanation:

Given to find the unknown number in

6 Ã— 70 = (6 Ã— ___ ) Ã— 10, let the unknown number

be x so 6 X 70 = (6 X x) X 10,

420 = 60x,

x = 420 Ã· 60 = 7.

Question 8.

60 Ã— 9 = 10 Ã— (___ Ã— 9)

Answer:

6,

Explanation:

Given to find the unknown number in

60 Ã— 9 = 10 X (___ X 9), let the unknown number

be x so 60 X 9 = 10 X 9x,

540 = 90x,

x= 540 Ã· 90 = 6.

Question 9.

30 Ã— 7 = 10 Ã— (___ Ã— 7)

Answer:

3,

Explanation:

Given to find the unknown number in

30 Ã— 7 = 10 X (___ X 7), let the unknown number

be x so 30 X 7 = 10 X (x X 7),

210 = 10 X 7x,

210 = 70x,

x = 210 Ã· 70 = 3.

Question 10.

4 Ã— 40 = (4 Ã— ___) Ã— 10

Answer:

4,

Explanation:

Given to find the unknown number in

4 Ã— 40 = (4 Ã— ___ ) Ã— 10, let the unknown number

be x so 4 X 40 = (4 X x) X 10,

160 = 4x X 10,

160Â = 40x,

x = 160 Ã· 40 = 4.