Go Math Grade 4 Answer Key Homework FL Chapter 13 Algebra: Perimeter and Area Review/Test support students to improve their subject knowledge on the perimeter and area of the different shapes & gain maths skills. The answers provided in this chapter are designed by the math experts. Go ahead and download the Go Math Grade 4 Answer key pdf, to find out the Perimeter and Area of the rectangle, square, and etc. concepts easily.
Go Math Grade 4 Answer Key Homework FL Chapter 13 Algebra: Perimeter and Area Review/Test
Go Math Solution Key of grade 4 chapter 13 will provide perfect solutions in a step-by-step manner with a clear explanation of every question. Go Math taught explicitly about Perimeter and Area of different Shapes with the help of images, indicating images with arrows, and numbers. So, make use of this pdf formatted lesson-wise Go Math Grade 4 Answer Key Homework FL Chapter 13 Algebra: Perimeter and Area Review/Test & check your solutions within no time.
Chapter: 13 – Review/TestÂ
- Review/Test – Page No. 519
- Review/Test – Page No. 520
- Review/Test – Page No. 521
- Review/Test – Page No. 522
Review/Test – Page No. 519
Choose the best term from the box.
Question 1.
The number of square units needed to cover a flat surface is the ______________.
_________
Answer: Area
The number of square units needed to cover a flat surface is the area.
Question 2.
The distance around a shape is the ____________.
_________
Answer: Perimeter
The distance around a shape is the Perimeter.
Find the area of the rectangle or combined rectangles.
Question 3.
A = _____ square feet
Answer: 112 square feet
Explanation:
Given,
length = 14 ft
Width = 8 ft
Area of the rectangle = l × w
A = 14 ft × 8 ft
A = 112 square feet
Thus the area of the rectangle for the above figure is 112 square feet.
Question 4.
A = _____ square centimeters
Answer: 65 square cm.
Explanation:
Figure 1:
S = 3 cm
Area of the square = s × s
A = 3 cm × 3 cm
A = 9 square cm
Figure 2:
b = 11 cm
h = 4 cm
Area of the rectangle = b × h
A = 11 cm × 4 cm
A = 44 square cm
Figure 3:
b = 2 cm
h = 6 cm
Area of the rectangle = b × h
A = 2 cm × 6 cm
A = 12 square cm
Area of the composite figure is 9 sq. cm + 44 sq. cm + 12 sq. cm = 65 square cm.
Find the unknown measure of the rectangle.
Question 5.
A = _____ square yards
Answer: 136 square yard
Explanation:
Figure 1:
b = 12 yd
h = 8 yd
Area of the rectangle = b × h
A = 12 yd × 8 yd
A = 96 square yard.
Figure 2:
b = 16 yd
h = 1 yd
Area of the rectangle = b × h
A = 16 yd × 1 yd
A = 16 square yard.
Figure 3:
b = 4 yd
h = 6 yd
Area of the rectangle = b × h
A = 4 yd × 6 yd
A = 24 square yard.
The area of the composite figure is 96 square yard + 16 square yard + 24 square yard = 136 square yard.
Question 6.
Perimeter = 60 meters
width = _____ m
Answer: 12 m
Explanation:
Given,
Perimeter = 60 meters
length = 18 m
width = _____ m
The perimeter of the rectangle = l + w + l + w
P = 2l + 2w
60 m = 2 × 18 m + 2w
60 m – 36 m = 2w
2w = 24
w = 24/2
w = 12 meters
Thus the width of the above rectangle is 12 meters.
Question 7.
Area = 91 square feet
height = _____ feet
Answer: 13 ft
Explanation:
Given,
Area = 91 square feet
base = 7 ft
height = _____ feet
Area of the rectangle = b × h
91 sq ft = 7 ft × h
h = 91/7
h = 13 ft
Thus the height of the above rectangle is 13 ft.
Question 8.
Area = 60 square inches
base = _____ in.
Answer: 10 inches
Explanation:
Given,
Area = 60 square inches
height = 6 in
base = _____ in.
Area of the rectangle = b × h
60 square inches = b × 6 in
b = 60/6
b = 10 inches
Thus the base of the above rectangle is 10 inches.
Question 9.
What is the perimeter of a rectangle with a length of 13 feet and a width of 9 feet?
P = _____ ft
Answer: 44 ft
Explanation:
Given,
l = 13 ft
w = 9 ft
The perimeter of the rectangle = l + w + l + w
P = 13 ft + 9 ft + 13 ft + 9 ft
P = 44 ft
Thus the perimeter of the rectangle is 44 ft.
Review/Test – Page No. 520
Fill in the bubble completely to show your answer.
Question 10.
Which pair of shapes has the same area?
Options:
a.
b. 
c. 
d. 
Answer:
Explanation:
a.
4 × 2 = 8
3 × 3 = 9
8 ≠9
b.
4 × 4 = 16
3 × 5 = 15
16 ≠15
c.
3 × 4 = 12
2 × 6 = 12
12 = 12
Thus the correct answer is option c.
Question 11.
Jamie’s mom wants to enlarge her rectangular garden by adding a new rectangular section. The garden is now 96 square yards. What will the total area of the garden be after she adds the new section?
Options:
a. 84 square yards
b. 96 square yards
c. 180 square yards
d. 192 square yards
Answer: 192 square yards
Explanation:
Given that,
Jamie’s mom wants to enlarge her rectangular garden by adding a new rectangular section. The garden is now 96 square yards.
Add 96 square yards to the rectangular garden.
96 square yards + 96 square yards = 192 square yards
Thus the correct answer is option d.
Question 12.
A rectangular yoga studio has an area of 153 square feet. The width of the studio is 9 feet. What is the length of the studio?
lenght = _____ ft
Answer: 17 ft
Explanation:
Given,
A rectangular yoga studio has an area of 153 square feet.
The width of the studio is 9 feet.
Area of the rectangle = l × w
153 square feet = l × 9 ft
l = 153/9
l = 17 ft
Therefore the length of the studio is 17 feet.
Review/Test – Page No. 521
Fill in the bubble completely to show your answer.
Question 13.
Mr. Patterson had a rectangular deck with an area of 112 square feet built in his backyard. Which could be a diagram of Mr. Patterson’s deck?
Options:
a. 
b. 
c. 
d. 
Answer: c.
Explanation:
Given,
Mr. Patterson had a rectangular deck with an area of 112 square feet built in his backyard.
Area of the rectangle = l × w
A = 28 ft × 4 ft
A = 112 square feet
Thus the correct answer is option c.
Question 14.
The town indoor pool is in a rectangular building. Marco is laying tile around the rectangular pool. How many square meters of tile will Marco need?
Options:
a. 96 square meters
b. 252 square meters
c. 572 square meters
d. 892 square meters
Answer: 252 square meters
Explanation:
The outer rectangle is
l = 26 m
w = 22 m
Area of the rectangle = l × w
A = 26 m × 22 m
A = 572 square meters
The inner rectangle is
l = 20 m
w = 16 m
Area of the rectangle = l × w
A = 20 m × 16 m
A = 320 square meters
Thus the square meters of tile will Marco need is 572 – 320 = 252 square meters.
Review/Test – Page No. 522
Question 15.
A drawing of a high school pool is shown below.
What is the area of the pool? Explain how you know.
_______ square yards
Answer:
Explanation:
Figure 1:
l = 10 yd
w = 15 yd
Area of the rectangle = l × w
A = 10 yd × 15 yd
A = 150 square yard
Figure 2:
l = 15 yd
w = 10 yd
Area of the rectangle = l × w
A = 15 yd × 10 yd
A = 150 square yard
Figure 3:
l = 10 yd
w = 5 yd
Area of the rectangle = l × w
A = 10 yd × 5 yd
A = 50 square yard
Area of the pool = 150 square yard + 150 square yard + 50 square yard = 350 square yard
Question 16.
Mr. Brown has 24 meters of fencing. He wants to build a rectangular pen for his rabbits.
A. Draw two different rectangles that Mr. Brown could build. Use only whole numbers for the lengths of the sides of each rectangle. Label the length of each side.
Type below:
_________
Answer:
Question 16.
B. Find the area in square meters of each rabbit pen you made in Part A. Show your work.
Type below:
_________
Answer: 20 square meters
Explanation:
l = 10m
w = 2m
Area of the rectangle = l × w
A = 10 m × 2 m
A = 20 square meters
Therefore the area in square meters of each rabbit pen is 20 square meters.
Question 16.
C. If you were Mr. Brown, which of the two pens above would you construct for your rabbits? Explain why.
Type below:
_________
Answer: I would construct the second figure for the two rabbit pens.
Conclusion:
Once you go through the Go Math Grade 4 Review Test Solutions of ch 13, then students can immediately discover the perimeter and area of shapes. Stay Connected with us to get the Go Math Grade 4 Answer Key Chapter 13 Algebra: Perimeter and Area along with Go Math Grade 4 Answer Key Homework Practice FL Chapter 13 Algebra: Perimeter and Area pdf.