# Eureka Math Grade 8 Module 2 End of Module Assessment Answer Key

## Engage NY Eureka Math 8th Grade Module 2 End of Module Assessment Answer Key

Question 1.
△ABC≅ △A’B’C’. Use the picture to answer the question below.

Describe a sequence of rigid motions that would prove a congruence between △ABC and △A’B’C’.
Let T be the Translation AWNG $$\overrightarrow{A^{\prime} A}$$ so that t(A’) = A. Let R be the rotation around A, d degrees so that R(A’B’) = AB. By hypothesis |AB| = |A’B’|. Let |∠A| = |∠A|, |∠B| = |∠B|, so the composition ʌ.R.T will map ∆A’B’C’ to ∆A’B’C’ to ∆ABC, i.e., ʌ(R(T(△A’B’C’))) = △ABC

Question 2.
Use the diagram to answer the question below.

k || l

Line k is parallel to line l. m∠EDC=41° and m∠ABC=32°. Find the m∠BCD. Explain in detail how you know you are correct. Add additional lines and points as needed for your explanation.
Let F be a point on line or so that ∠DCF is a straight angle. Then because r || l, ∠EDC ≅ ∠CFA and have equal measure. ∠ABC and ∠CFA are the remote interior angles of △BCF which means ∠BCD = ∠ABC + CFA. Therefore ∠BCD = 32 + 41 = 73°.

Question 3.
Use the diagram below to answer the questions that follow. Lines L1 and L2 are parallel, L1 || L2. Point N is the midpoint of segment GH.

a. If the measure of ∠IHM is 125°, what is the measure of ∠IHJ? ∠JHN? ∠NHM?
∠IHJ = 55°
∠JHN = 125°
∠NHM = 55°

b. What can you say about the relationship between ∠4 and ∠6? Explain using a basic rigid motion. Name another pair of angles with this same relationship.
∠1 & ∠5 are corresponding angles that are equal because L1 || L2. Let T be the Translation along vector $$\overrightarrow{G H}$$. Then T(L2) = L1 and T(∠5) = ∠1.