Eureka Math Grade 6 Module 4 Lesson 14 Answer Key

Engage NY Eureka Math 6th Grade Module 4 Lesson 14 Answer Key

Eureka Math Grade 6 Module 4 Lesson 14 Example Answer Key

Example 1.
Fill in the three remaining squares so that all the squares contain equivalent expressions.
Answer:

Example 2.
Fill in a blank copy of the four boxes using the words dividend and divisor so that it is set up for any example.
Answer:

Eureka Math Grade 6 Module 4 Lesson 14 Exercise Answer Key

Exercises

Complete the missing spaces in each rectangle set.

Set A

1. 5 ÷ p
Answer:
5 divided by p, \(\frac{5}{p}\),

2. The quotient of g and h
Answer:
g ÷ h, \(\frac{g}{h}\),

3.
Answer:
23 divided by w, 23 ÷ w, \(\frac{23}{w}\)

4. \(\frac{y}{x+8}\)
Answer:
y divided by the sum of x and 8, y ÷ (x + 8),

5. 7 divided by the quantity a minus 6
Answer:
7 ÷ (a – 6), \(\frac{7}{a-6}\),

6.
Answer:
The sum of m and 11 dividend by 3, (m + 11) ÷ 3, \(\frac{m+11}{3}\)

7. (f + 2) ÷ g
Answer:
The sum of f and 2 dividend by g, \(\frac{f+2}{g}\),

8. \(\frac{c-9}{d+3}\)
Answer:
The quotient of c minus 9 and d plus 3, (c – 9) ÷ (d + 3),

Set B

1. h ÷ 11
Answer:

2. The quotient of m and n
Answer:

3.
Answer:
The quotient of j and 5, j ÷ 5, \(\frac{j}{5}\)

4. \(\frac{h}{m-4}\)
Answer:

5. f divided by the quantity g minus 11
Answer:

6.
Answer:
The sum of a and 5 dividend by 18, (a + 5) ÷ 18, \(\frac{a+5}{18}\)

7. (y – 3) ÷ x
Answer:

8. \(\frac{g+5}{h-11}\)
Answer:
The quotient of g plus 5 divided by the quantity h minus 11,

Set C

1. 6 ÷ k
Answer:

2. The quotient of j and k
Answer:

3.
Answer:
a dividend by 10, a ÷ 10, \(\frac{a}{10}\)

4. \(\frac{15}{f-2}\)
Answer:

5. 13 divided by the sum of h and 1
Answer:

6.
Answer:
The sum of c plus 18 dividend by 3, (c + 18) ÷ 3, \(\frac{c+18}{3}\)

7. (h – 2) ÷ m
Answer:

8. \(\frac{4-m}{n+11}\)
Answer:
The quantity of 4 minus m divided by the sum of n and 11,

Eureka Math Grade 6 Module 4 Lesson 14 Problem Set Answer Key

Complete the missing spaces in each rectangle set.

Answer:
The quotient of h and 16, , \(\frac{h}{16}\)
m divided by the quantity b minus 33, , m ÷ (b – 33)

Answer:

The sum of y and 13 dividend by 2, (y + 13) ÷ 2, \(\frac{y+13}{2}\)

Eureka Math Grade 6 Module 4 Lesson 14 Exit Ticket Answer Key

Question 1.
Write the division expression in words and as a fraction.
(g + 12)÷h
Answer:
g+12
The sum of g and 12 divided by h, \(\frac{g+12}{13}\)

Question 2.
Write the following division expression using the division symbol and as a fraction: f divided by the quantity h minus 3.
Answer:
f ÷ (h – 3) and \(\frac{f}{h-3}\)

Eureka Math Grade 6 Module 4 Lesson 14 Long Division Algorithm Answer Key

Long Division Algorithm

Progression of Exercises

Question 1.
3,282 ÷ 6
Answer:
547

Question 2.
2,712 ÷ 3
Answer:
904

Question 3.
15,036 ÷ 7
Answer:
2,148

Question 4.
1,788 ÷ 8
Answer:
223.5

Question 5.
5,736 ÷ 12
Answer:
478

Question 6.
35,472 ÷ 16
Answer:
2,217

Question 7.
13,384÷28
Answer:
478

Question 8.
31,317÷39
Answer:
803

Question 9.
1,113÷42
Answer:
26.5

Question 10.
4,082 ÷ 52
Answer:
78.5