## Engage NY Eureka Math 6th Grade Module 2 Lesson 4 Answer Key

### Eureka Math Grade 6 Module 2 Lesson 4 Example Answer Key

Example 1.

Molly has 1\(\frac{3}{8}\) cups of strawberries. She needs \(\frac{3}{8}\) cup of strawberries to make one batch of muffins. How many batches can Molly make?

Use a model to support your answer.

Answer:

\(\frac{11}{8} \div \frac{3}{8}\) = 11 eighths Ã· 3 eighths = \(\frac{11}{3}\) = 3\(\frac{2}{3}\)

Molly can make 3\(\frac{2}{3}\) batches of muffins.

Example 2.

Mollyâ€™s friend, Xavier, also has \(\frac{11}{8}\) cups of strawberries. He needs \(\frac{3}{4}\) cup of strawberries to make a batch of tarts. How many batches can he make? Draw a model to support your solution.

Answer:

\(\frac{11}{8} \div \frac{6}{8}\) = 11 eighths Ã· 6 eighths = \(\frac{11}{6}\) = 1\(\frac{5}{6}\)

Xavier has enough to make 1 and \(\frac{5}{6}\) batches.

Example 3.

Find the quotient: \(\frac{6}{8} \div \frac{2}{8}\). Use a model to show your answer.

Answer:

2 units = 6 eighths

1 unit = 6 eighths Ã· 2 = 3 eighths

8 units = 8 Ã— 3 eIghths = 24 eighths = 3

Example 4.

Find the quotient: \(\frac{3}{4} \div \frac{2}{3}\). Use a model to show your answer.

Answer:

We could rewrite this problem to ask \(\frac{9}{12} \div \frac{8}{12}\) = 9 twelfths Ã· 8 twelfths = \(\frac{9}{8}\) = 1\(\frac{1}{8}\).

### Eureka Math Grade 6 Module 2 Lesson 4 Exercise Answer Key

Find each quotient.

Exercise 1.

\(\frac{6}{2} \div \frac{3}{4}\)

Answer:

We could rewrite this expression and solve as \(\frac{12}{4} \div \frac{3}{4}=\frac{12}{3}\) = 4.

Exercise 2.

\(\frac{2}{3} \div \frac{2}{5}\)

Answer:

We could rewrite this expression and solve as \(\frac{10}{15} \div \frac{6}{15}=\frac{10}{6}=1 \frac{4}{6}\)

Exercise 3.

\(\frac{7}{8} \div \frac{1}{2}\)

Answer:

We could rewrite this as \(\frac{7}{8} \div \frac{4}{8}=\frac{7}{4}=1 \frac{3}{4}\)

Exercise 4.

\(\frac{3}{5} \div \frac{1}{4}\)

Answer:

This can be rewritten as \(\frac{12}{20} \div \frac{5}{20}=\frac{12}{5}=2 \frac{2}{5}\)

Exercise 5.

\(\frac{5}{4} \div \frac{1}{3}\)

Answer:

We can be written this as \(\frac{15}{12} \div \frac{4}{12}=\frac{15}{4}=3 \frac{3}{4}\)

### Eureka Math Grade 6 Module 2 Lesson 4 Problem Set Answer Key

Calculate the quotient. If needed, draw a model.

Question 1.

\(\frac{8}{9} \div \frac{4}{9}\)

Answer:

8 ninths Ã· 4 ninths = 2

Question 2.

\(\frac{9}{10} \div \frac{4}{10}\)

Answer:

9 tenths Ã· 4 tenths = 2\(\frac{1}{4}\)

Question 3.

\(\frac{3}{5} \div \frac{1}{3}\)

Answer:

\(\frac{9}{15} \div \frac{5}{15}\) = 9 fifteenths Ã· 5 fifteenths = \(\frac{9}{5}=1 \frac{4}{5}\)

Question 4.

\(\frac{3}{4} \div \frac{1}{5}\)

Answer:

\(\frac{15}{20} \div \frac{4}{20}\) = 15 twentieths Ã· 4 twentieths = \(\frac{15}{4}\)

### Eureka Math Grade 6 Module 2 Lesson 4 Exit Ticket Answer Key

Calculate each quotient. If needed, draw a model.

Question 1.

\(\frac{9}{4} \div \frac{3}{8}\)

Answer:

This can be rewritten as \(\frac{18}{8} \div \frac{3}{8}\) = 18 eighths divided by 3 eighths = \(\frac{18}{3}\) = 6.

Question 2.

\(\frac{3}{5} \div \frac{2}{3}\)

Answer:

This can be rewritten as \(\frac{9}{15} \div \frac{10}{15}\) = 9fifteenths divided by 10 fifteenths, or 9 units Ã· 10 units. So, this is equal to \(\frac{9}{10}\).

### Eureka Math Grade 6 Module 2 Lesson 4 Opening Exercise Answer Key

Write at least three equivalent fractions for each fraction below.

a. \(\frac{2}{3}\)

Answer:

Sample solution include \(\frac{4}{6}, \frac{6}{9}, \frac{8}{12}, \frac{10}{15}, \frac{12}{18}\)

b. \(\frac{10}{12}\)

Answer:

Sample solution include \(\frac{5}{6}, \frac{15}{18}, \frac{20}{24}, \frac{25}{30^{\prime}} \frac{30}{36}\)