# Eureka Math Grade 5 Module 4 Mid Module Assessment Answer Key

## Engage NY Eureka Math 5th Grade Module 4 Mid Module Assessment Answer Key

Multiply or divide. Draw a model to explain your thinking.

a. $$\frac{1}{2}$$ × 6

Explanation: Given, $$\frac{1}{2}$$ × 6
= $$\frac{6}{2}$$
= 3.

b. $$\frac{1}{2}$$ × 7
7 ÷ 2 = 3 1/2

Explanation: c. $$\frac{3}{4}$$ × 12

Explanation:
3/4 × 12 = 9 d. $$\frac{2}{5}$$ × 30

Explanation:
2/5 × 30 = 12 e. $$\frac{1}{3}$$ of 2 feet = _8_ inches
2 × 12 inches = 24 inches

Explanation:
1 feet = 12 inches
2 feet = 24 inches
Hence 1/3 × 24 inches = 8 in. f. $$\frac{1}{6}$$ of 3 yards = _________feet”

Explanation:
1/6 ×3 yards = 1 1/2 feet g. (3 + $$\frac{1}{2}$$) × 14
(3 ×14) + ( 1/2 ×14)
42 + 7
49

Explanation:
(3 ×14) + ( 1/2 ×14)
42 + 7
49 h. 4$$\frac{2}{3}$$ × 13
60 2/3

Explanation:

( 4×13) + (2/3 ×13)
52 + (2×13)/3
52 + (26/3)
52 + 8 2/3
60 2/3 Question 2.
If the whole bar is 3 units long, what is the length of the shaded part of the bar? Write a multiplication equation for the diagram, and then solve. Answer: $$\frac{9}{4}$$ or 2.25 units

Explanation:
Given, the whole bar is 3 units long,
The bar has 4 total parts, The shaded region has 3 parts.
So, the ratio of shaded parts to total parts will be $$\frac{3}{4}$$
In order to determine length of the shaded part, just multiply the ratio of the shaded parts to total parts by the total length of the bar.
Then, $$\frac{3}{4}$$ × 3 = $$\frac{9}{4}$$ or 2.25 units.

Question 3.
Circle the expression(s) that are equal to $$\frac{3}{5}$$ × 6. Explain why the others are not equal using words, pictures, or numbers.
a. 3 × (6 ÷ 5)

b. 3 ÷ (5 × 6)

c. (3 × 6) ÷ 5

d. 3 × $$\frac{6}{5}$$

Explanation:
All the correct options  have the result of $$\frac{18}{5}$$
Option b. 3 ÷ (5 × 6) gives the output of $$\frac{3}{30}$$

Question 4.
Write the following as expressions.
a. One-third the sum of 6 and 3.
1/3 × ( 6 +3 )

Explanation:
The expression for the following question is 1/3 × ( 6 +3 ).

b. Four times the quotient of 3 and 4.
4 × (3÷4)

Explanation:
The expression for the following question is 4 × (3÷4).

c. One-fourth the difference between $$\frac{2}{3}$$ and $$\frac{1}{2}$$.
1/4 × ( 2/3 – 1/2)

Explanation:
The expression for the following question is 1/4 × ( 2/3 – 1/2).

Question 5.
Mr. Schaum used 10 buckets to collect rainfall in various locations on his property. The following line plot shows the amount of rain collected in each bucket in gallons. Write an expression that includes multiplication to show how to find the total amount of water collected in gallons. Then, solve your expression. 5/8 + (4 × 1 2/8) + (2 × 1 5/8)+ 2 1/8 + (2 × 2 3/8)
5/8 + 4 + (4 ×2)/8 + 2 + (2×5)/8 + 2 1/8 + 4 + (2×3)/8
12 + 5/8 + 8/8 + 10/8 + 1/8 + 6/8
12 + 5/8 + 8/8 + 10/8 + 1/8 + 6/8
13 + 22/8
15 6/8
15 3/4

Explanation:
As asked in the question I have solved the expression and the total amount of water collected in gallons are 15 3/4.

Question 6.
Mrs. Williams uses the following recipe for crispy rice treats. She decides to make 2/3 of the recipe.
2 cups melted butter
24 oz marshmallows
13 cups rice crispy cereal

a. How much of each ingredient will she need? Write an expression that includes multiplication. Solve by multiplying.
Butter: 2/3 × 2 cups = (2×2)/3 = 4/3 = 1 1/3 cups
Marshmallows: 2/3 × 24 oz = (2×24)/3 = 48/3 = 16 oz
Cereal: 2/3 × 13 cups = (2×13)/3 = 26/3 = 8 2/3 cups

Explanation:
I have written an expression that includes multiplication is she will need 1 1/3 cups of butter, 16 ounces of marshmallows,  and 8 2/3 cups of rice crispy cereal.

b. How many fluid ounces of butter will she use? (Use your measurement conversion chart, if you wish.)
1 cup = 8 ounces
1 1/3 × 8 = (1×8) + (1/3 ×8)
= 8 + 8/3
= 8 + 2 2/3
= 10 2/3

Explanation:
In this, by using the measurement conversion chart she will use 10 2/3 fluid ounces of butter.

c. When the crispy rice treats have cooled, Mrs. Williams cuts them into 30 equal pieces. She gives two-fifths of the treats to her son and takes the rest to school. How many treats will Mrs. Williams take to school? Use any method to solve. 