## Engage NY Eureka Math 5th Grade Module 2 Mid Module Assessment Answer Key

### Eureka Math Grade 5 Module 2 Mid Module Assessment Task Answer Key

Question 1.

Fill in the chart.

Words |
Expression |
The Value of the Expression |

a. 50 times the sum of 64 and 36 | 50 x (64 + 36) | 5000 |

b. Divide the difference between 1,200 and 700 by 5 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5 /(1200 – 700) | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 100 |

c. The sum of 3 fifteens and 17 fifteens | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â (3 x 15 ) + (17 x 15) | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 300 |

d. 15 times the sum of 14 and 6 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 15 x (14 + 6) | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 300 |

e. 10 times the sum of 250 and 45 | 10 Ã— (250 + 45) | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2950 |

f. 14 times the sum of 440 and 560 | (560 + 440) Ã— 14 | Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 14000 |

Answer:

a. 5000.

Explanation:

In the above-given question,

given that,

50 times the sum of 64 and 36.

50 x (64 + 36).

50 x (100).

5000.

Answer:

b. 100.

Explanation:

In the above-given question,

given that,

Divide the difference between 1,200 and 700 by 5

1200 – 700/5.

500/5.

100.

Answer:

c. 300.

Explanation:

In the above-given question,

given that,

The sum of 3 fifteens and 17 fifteens

(3 x 15) + (17 x 15).

45 + 255

300.

Answer:

d. 300.

Explanation:

In the above-given question,

given that,

15 times the sum of 14 and 6

15 x (14 + 6).

15 x (20).

300.

Answer:

e. 2950.

Explanation:

In the above-given question,

given that,

10 times the sum of 250 and 45

10 x (250 + 45).

10 x (295).

2950.

Answer:

f.14000.

Explanation:

In the above-given question,

given that,

14 times the sum of 440 and 560

14 x (440 + 560).

14 x (1000).

14000.

Question 2.

Compare the two expressions using < , > , or = . For each, explain how you can determine the answer without calculating.

a. 100 Ã— 8 25 Ã— (4 Ã— 9)

Answer:

100 x 8Â > 25 x (4 x 9)

Explanation:

In the above-given question,

given that,

100 x 8 = 800.

25 x (4 x 9).

25 x (36).

25 x 36 = 72.

so 100 > 72.

b. 48 Ã— 12 50 twelves â€“ 3 twelves

Answer:

48 x 12 > 50 twelves – 3 twelves.

Explanation:

In the above-given question,

given that,

48 x 12 = 576.

50 x 12 = 600.

3 x 12 = 36.

600 – 36.

564.

576 > 564.

c. 24 Ã— 36 18 twenty-fours, doubled

Answer:

24 x 36Â <Â 18 twenty-fours, doubled.

Explanation:

In the above-given question,

given that,

24 x 36 = 864.

18 x 24 = 432.

432 x 432 = 186624.

864 < 186624.

Question 3.

Solve. Use words, numbers, or pictures to explain how your answers to Parts (a) and (b) are related.

a. 25 Ã— 30 = ____750_______

Answer:

25 x 30 = 750.

Explanation:

In the above-given question,

given that,

25 x 30.

750.

b. 2.5 Ã— 30 = _____2.5______ tenths Ã— 30 = _____75______

Answer:

2.5 x 30 = 75.

Explanation:

In the above-given question,

given that,

2.5 x 30.

25/10 = 2.5.

2.5/30 = 75.

Question 4.

Multiply using the standard algorithm. Show your work below each problem. Write the product in the blank.

a. 514 Ã— 33 = ____16962_______

Answer:

514 x 33 = 16962.

Explanation:

In the above-given question,

given that,

514 x 33

16962.

b. 546 Ã— 405 = __2,21,130_________

Answer:

546 x 405 = 2,21,130.

Explanation:

In the above-given question,

given that,

546 x 405.

2,21,130.

Question 5.

For a field trip, the school bought 47 sandwiches for $4.60 each and 39 bags of chips for $1.25 each. How much did the school spend in all?

Answer:

The school spending in all = $264.95.

Explanation:

In the above-given question,

given that,

For a field trip, the school bought 47 sandwiches for $4.60 each and 39 bags of chips for $1.25 each.

47 x $4.60 = 216.2.

39 x $1.25 = 48.75.

216.2 + 48.75 = 264.95.

Question 6.

Jeanne makes hair bows to sell at the craft fair. Each bow requires 1.5 yards of ribbon.

a. At the fabric store, ribbon is sold by the foot. If Jeanne wants to make 84 bows, how many feet of ribbon must she buy? Show all your work.

Answer:

The number of feet of ribbon must she buy = 126 feet.

Explanation:

In the above-given question,

given that,

Jeanne makes hair bows to sell at the craft fair.

Each bow requires 1.5 yards of ribbon.

84 x 1.5.

126.

b. If the ribbon costs 10Â¢ per foot, what is the total cost of the ribbon in dollars? Explain your reasoning, including how you decided where to place the decimal.

Answer:

The total cost of ribbon in dollars = 0.1.

Explanation:

In the above-given question,

given that,

If the ribbon costs 10 cents per foot.

1 cents = 0.01 dollar.

10 x 0.01 = 0.1$

the total cost of the ribbon = 0.1.

c. A manufacturer is making 1,000 times as many bows as Jeanne to sell in stores nationwide. Write an expression using exponents to show how many yards of ribbon the manufacturer will need. Do not calculate the total.

Answer:

The number of yards of ribbon the manufacturer will need = 1500 yards.

Explanation:

In the above-given question,

given that,

A manufacturer is making 1000 times as many bows.

1000 x 1.5.

1500 yards.