Engage NY Eureka Math 4th Grade Module 2 Lesson 1 Answer Key
Eureka Math Grade 4 Module 2 Lesson 1 Problem Set Answer Key
Question 1.
Convert the measurements.
a. 1 km = _______1000________ m
b. 4 km = _______4000________ m
c. 7 km = ________7000_______ m
d. ___18_______ km = 18,000 m
e. 1 m = _______100________ cm
f. 3 m = _______300________ cm
g. 80 m = ______8000_________ cm
h. ____120____ m = 12,000 cm
a. 1 km = 1000 m,
Explanation:
1 km is equal to 10^{3 }meter,
1 km = 1 X 10 X 10 X 10 = 1000 meter,
So 1 km = 1000 m.
b. 4 km = 4000 m,
Explanation:
4 km is equal to 4 X 10^{3 }meter,
4 km = 4 X 10 X 10 X 10 = 4000 meter,
So 1 km = 4000 m.
c. 7 km = 7000 m,
Explanation:
7 km is equal to 7 X 10^{3 }meter,
7 km = 7 X 10 X 10 X 10 = 7000 meter,
So 7 km = 7000 m.
d. 18 km = 18000 m,
Explanation:
18 km is equal to 18 X 10^{3 }meter,
18 km = 18 X 10 X 10 X 10 = 18000 meter,
So 18 km = 18000 m.
e. 1 m = 100cm,
Explanation:
1 m is equal to 10^{2 }centimeter,
1 m = 1 X 10 X 10 = 100 centimeter,
So 1 m = 100 cm.
f. 3 m = 300cm,
Explanation:
3 m is equal to 3 X 10^{2 }centimeter,
3 m = 3 X 10 X 10 = 100 centimeter,
So 3 m = 300 cm.
g. 80 m = 8000 cm,
Explanation:
80 m is equal toÂ 80 X 10^{2 }centimeter,
80 m = 80 X 10 X 10 = 8000 centimeter,
So 80 m = 8000 cm.
h. 120 m = 12,000 cm,
Explanation:
120 m is equal to 120 X 10^{2 }centimeter,
120 m = 120 X 10 X 10 = 12,000 centimeter,
So 120 m = 12,000 cm.
Question 2.
Convert the measurements.
a. 3 km 312 m = _____3,312__________ m
b. 13 km 27 m = ______13,027_________ m
c. 915 km 8 m = _______9,15,008________ m
d. 3 m 56 cm = ________3,56_______ cm
e. 14 m 8 cm = _________1,408______ cm
f. 120 m 46 cm = _______12,046________ cm
a. 3 km 312 m = 3,312 m,
Explanation:
As we know 1 km is equal to 10^{3 }meter,
So 3 km 312 m = 3 X 10^{3 }+ 312 = 3,312 meter,
Therefore 3 km 312 m = 3,312 m.
b. 13 km 27 m = 13,027 m,
Explanation:
As we know 1 km is equal to 10^{3 }meter,
So 13 km 27 m = 13 X 10^{3 }+ 27 = 13,027 meter,
Therefore 13 km 27 m = 13,027 m.
c. 915 km 8 m = 9,15,008 m,
Explanation:
As we know 1 km is equal to 10^{3 }meter,
So 915 km 8 m = 915 X 10^{3 }+ 8 = 9,15,008 meter,
Therefore 915 km 8 m = 9,15,007 m.
d. 3 m 56 cm = 356 cm
Explanation:
As we know 1 m is equal to 10^{2 }centimeter,
3 m 56 cm = 3 X 10^{2 }+ 56 = 300 + 56 = 3,56 centimeter,
So 3 m 56 cm = 3,56 cm.
e.Â 14 m 8 cm = 1,408 cm,
Explanation:
As we know 1 m is equal to 10^{2 }centimeter,
14 m 8 cm = 14 X 10^{2 }+ 8 = 1400 + 8 = 1,408 centimeter,
So 14 m 8 cm = 1,408 cm.
f. 120 m 46 cm = 12,046 cm,
Explanation:
As we know 1 m is equal to 10^{2 }centimeter,
120 m 46 cm = 120 X 10^{2 }+ 46 = 12000 + 46 = 12,046 centimeter,
So 120 m 46 cm = 12,046 cm.
Question 3.
Solve.
a. 4 km âˆ’ 280 m
b. 1 m 15 cm â€“ 34 cm
c. Express your answer in the smaller unit:
1 km 431 m + 13 km 169 m
d. Express your answer in the smaller unit:
231 m 31 cm âˆ’ 14 m 48 cm
e. 67 km 230 m + 11 km 879 m
f. 67 km 230 m âˆ’ 11 km 879 m
Use a tape diagram to model each problem. Solve using a simplifying strategy or an algorithm, and write your answer as a statement.
a. 4 km âˆ’ 280 m
4 km – 280 m = 3,720 m
Answer:
4 kilometers minus 280 meters is equal to 3,720 meters,
Explanation:
Given 4 km âˆ’ 280 m as
4 km = 4 X 10^{3 }m = 4,000 m,
Used a tape diagram to model 4 km – 280 m = 3,720 m
as shown above in the picture,
so 4000 m
Â Â Â 280 mÂ
Â Â 3,720 m
Statement is 4 kilometers minus 280 meters is
equal to 3,720 meters.
b. 1 m 15 cm â€“ 34 cm
1 m 15 cm â€“ 34 cm =81 cm
1 meter 15 centimeters minus 34 centimeter
is equal to 81centimeters,
Explanation:
Given 1 m 15 cm âˆ’ 34 cm as
1 m 15 cm = 1 X 10^{2 }+ 15 = 100 + 15 = 115 cm,
Used a tape diagram to model 115 cm – 34 cm = 81 cm
as shown above in the picture,
so 115 cm
Â Â Â – 34 cmÂ
Â Â Â Â 81 cm
Statement is 1 meter 15 centimeters minus
34 centimeters is equal to 81 centimeters.
c.1 km 431 m + 13 km 169 m
1 km 431 m + 13 km 169 m = 14,600 m
or 14,600,000,000 mm,
1 kilometer and 431 meters plus 13 kilometers and
169 meters is 14,600 meters or 14,600,000 millimeters,
Explanation:
Given 1 km 431 m + 13 km 169 m as
1 km 431 m = 1 X 10^{3 }+ 431 = 1000 + 431 = 1,431 m
and 13 km 169 m = 13Â X 10^{3 }+ 169 =13,169 m
Used a tape diagram to model 1431 m + 13169 m =
14,600 m as shown above in the picture,
001431 m
+13169 m
14,600 m
Now 14,600 m in the smaller unit in millimeter is as
1 meter is equal to 1000 millimeter,
So 14,600 X 1000 = 14,600,000 millimeters.
Statement : 1 kilometer and 431 meters plus 13 kilometers
169 meters gives 14,600,000 millimeters.
d.231 m 31 cm âˆ’ 14 m 48 cm
231 m 31 cm – 14m 48 cm = 21,683 cm
or 2,16,830 millimeter
231 meter and 31 centimeters minus 14 meters
48 centimeters gives 216,830 millimeters,
Explanation:
Given 231 m 31 cm – 14 m 48 cm as
231 m 31 cm = 231 X 10^{2 }+ 31 = 23100 + 31 = 23,131 cm
and 14 m 48 cm = 14 X 10^{2 }+ 48 =1,448 cm
Used a tape diagram to model 23,131 cm – 1,448 cm =
21,683 cm as shown above in the picture,
23134 cm
– 1448 cm
21,683 cm
Now 21,683 cm in the smaller unit millimeters is as
1 centimeter is equal to 10 millimeter,
So 21,683 X 10 = 216,830 millimeters.
Statement : 231 meter and 31 centimeters minus 14 meters
48 centimeters gives 216,830 millimeters.
e. 67 km 230 m + 11 km 879 m
67 km 230 m + 11 km 879 m = 79,109 m
67 kilometer and 230 meters plus 11 kilometers and
879 meters is 79,109 meters,
Explanation:
Given 67 km 230 m + 11 km 879 m as
67 km 230 m = 67 X 10^{3 }+ 230 = 67000 + 230 = 67,230 m
and 11 km 879 m = 11 X 10^{3 }+ 879 =11,879 m
Used a tape diagram to model 67230 m + 11879 m =
79,109 m as shown above in the picture,
67230 m
+11879 m
79,109 m
So Â 67 km 230 m + 11 km 879 m = 79,109 m,
Statement : 67 kilometer and 230 meters plus 11 kilometers and
879 meters is 79,109 meters.
f. 67 km 230 m âˆ’ 11 km 879 m
67 km 230 m – 11 km 879 m = 55,351 m
67 kilometer and 230 meters minus 11 kilometers and
879 meters is 55,351 meters,
Explanation:
Given 67 km 230 m – 11 km 879 m as
67 km 230 m = 67 X 10^{3 }+ 230 = 67000 + 230 = 67,230 m
and 11 km 879 m = 11 X 10^{3 }+ 879 =11,879 m
Used a tape diagram to model 67230 m – 11879 m =
55,351 m as shown above in the picture,
67230 m
11879 m
55,351 m
So Â 67 km 230 m – 11 km 879 m = 55,351 m,
Statement : 67 kilometer and 230 meters minus 11 kilometers and
879 meters is 55,351 meters.
Question 4.
The length of Carterâ€™s driveway is 12 m 38 cm. His neighborâ€™s driveway is 4 m 99 cm longer. How long is his neighborâ€™s driveway?
Answer:
Neighbor’s drive is 17 m 37 cm or 1737 cm,
Explanation:
Given The length of Carterâ€™s driveway is 12 m 38 cm and
his neighborâ€™s driveway is 4 m 99 cm longer.
So neighbor’s drive is 12 m 38 cm plus 4 m 99 cm
we knowÂ 1 m is equal to 10^{2 }centimeter,
12 m 38 cm = 12 X 10^{2 }+ 38 = 1238 cm
and 4 m 99 cm = 4 X 10^{2 }+ 99 = 499 cm,
now 1238 cm + 499 cm =
1238 cm
+499 cm
1737 cm
Therefore, Neighbor’s drive is 17 m 37 cm or 1737 cm.
Question 5.
Enya walked 2 km 309 m from school to the store. Then, she walked from the store to her home. If she walked a total of 5 km, how far was it from the store to her home?
Answer:
It is 2691 m from the store to her home,
Explanation:
Given Enya walked 2 km 309 m from school to the store.
Then, she walked from the store to her home.
If she walked a total of 5 km, it is 5 km – 2 km 309mÂ from
the store to her home, So 5 km means 5 X 10^{3 }Â – (2 X 10^{3 }+ 309) =
5000 m – 2309 m =
5000 m
2309 m
2691 m
Therefore, It is 2691 m from the store to her home.
Question 6.
Rachael has a rope 5 m 32 cm long that she cut into two pieces. One piece is 249 cm long. How many centimeters long is the other piece of rope?
Answer:
The other piece of rope 283 cm long,
Explanation:
Given Rachael has a rope 5 m 32 cm long that she cut
into two pieces and one piece is 249 cm long.
The other piece of rope is 5 m 32 cm minus 249 cm long,
So, 5 m 32 cm – 249 cm = 5 X 10^{2 }+ 32 – 249 = 532 – 249 = 283 cm,
therefore, the other piece of rope 283 cm long.
Question 7.
Jason rode his bike 529 fewer meters than Allison.
Jason rode 1 km 850 m. How many meters did Allison ride?
Allison rode 2 km 379 meters or 2379 meters,
Explanation:
Given Jason rode his bike 529 fewer meters than Allison.
Jason rode 1 km 850 m. Number of meters Allison rode is
1 km 850 m + 529 m = 1 X 10^{3 }+ 850 + 529 = 1850 + 529 =
2379 meters. Therefore Allison rode 2 km 379 meters or 2379 meters.
Eureka Math Grade 4 Module 2 Lesson 1 Exit Ticket Answer Key
Question 1.
Complete the conversion table.
Distance 

71 km  ___71,000___ m 
______30____ km  30,000 m 
81 m  ____8,100______ cm 
____4______ m  400Â cm 
Explanation:
71 km is equal to 71 XÂ 10^{3 }= 71 X 1000 = 71,000 m,
so 71 km = 71,000 m.
30 km is equal to 30 X 10^{3 }= 30 X 1000 = 30,000 m,
so 30 km = 30,000 m.
81 m is equal to 81 X 10^{2 }= 81 X 100 = 8,100 cm,
so 81 m = 8,100 cm.
4 m is equal to 4 X 10^{2 }= 4 X 100 = 400 cm,
so 4 m = 400 cm.
Question 2.
13 km 20 m = ____13020___ m
Answer:
13 km 20 m = 13,020 m
Explanation:
Given 13 km 20 m as 1 km is equal to 10^{3 }m so
13 km 20 m = 13 X 10^{3}+ 20 m = 13 X 1000 + 20 =
13000 + 20 = 13020, therefore 13 km 20 m = 13,020 m.
Question 3.
401 km 101 m â€“ 34 km 153 m = _366,948 m or 366 km 948 m__
Answer:
401 km 101 m â€“ 34 km 153 m = 366,948 m or 366 km 948 m,
Explanation:
Given 401 km 101 m – 34 km 153 m as
401 km 101 m = 401 X 10^{3 }+ 101 = 401000 + 101 = 401,101 m
and 34 km 153 m = 34 X 10^{3 }+ 153 = 34153 m
Now 401,101 – 34,153 =
401101 m
34153 m
366,948 m
So, 401 km 101 m â€“ 34 km 153 m = 366,948 m or 366 km 948 m.
Question 4.
Gabe built a toy tower that measured 1 m 78 cm. After building some more, he measured it, and it was 82 cm taller. How tall is his tower now?
Draw a tape diagram to model this problem. Use a simplifying strategy or an algorithm to solve and write your answer as a statement.
Answer:
Gabe toy tower is 260 cm or 2 m 60 cm tall,
Statement: Gabe tower is 2 meter 60 centimeter tall or 260 centimeter tall,
Explanation:
Given Gabe built a toy tower that measured 1 m 78 cm.
After building some more, he measured it, and
it was 82 cm taller. So Gabe tower is 1 m 78 cm + 82 cm =
1 X 10^{2 }+ 78 cm + 82 cm = 178 cm + 82 cmÂ =
178 cm
+ 82 cm
260 cm tall.
Drawn a tape diagram to model this problem.
Used a simplifying strategy to solve
and wrote my statement as Gabe tower is 2 meter 60 centimeter tall or
260 centimeter tall.
Eureka Math Grade 4 Module 2 Lesson 1 Homework Answer Key
Question 1.
Find the equivalent measures.
a. 5 km = ______5,000_________ m
b. 13 km = _____13,000__________ m
c. _____17__________ km = 17,000 m
d. 60 km = ______60,000_________ m
e. 7 m = ________700_______ cm
f. 19 m = _______1,900________ cm
g. ______24_________ m = 2,400 cm
h. 90 m = _____9,000______ cm
a. 5 km = 5000 m,
Explanation:
1 km is equal to 10^{3 }meter,
5 km = 5 X 10 X 10 X 10 = 5000 meter,
So 5 km = 5000 m.
b. 13 km = 13,000 km,
Explanation:
1 km is equal to 10^{3 }meter,
13 km = 13 X 10 X 10 X 10 = 13000 meter,
So 13 km = 13,000 m.
c. _______________ km = 17,000 m,
17 km = 17,000 m,
Explanation:
1 m is equal to 1 Ã· 10^{3 }km,
17,000 m = 17,000 Ã· 10 X 10 X 10 = 17000 Ã· 1000 = 17 km,
So 17 km = 17,000 m.
d. 60 km = 60,000 m,
Explanation:
1 km is equal to 10^{3 }meter,
60 km = 60 X 10 X 10 X 10 = 60,000 meter,
So 60 km = 60,000 m.
e. 7 m = 700 cm,
Explanation:
1 m is equal to 10^{2 }centimeter,
7 m = 7 X 10 X 10 = 700 centimeter,
So 7 m = 700 centimeter.
f. 19 m = 1,900 cm,
Explanation:
1 m is equal to 10^{2 }centimeter,
19 m = 19 X 10 X 10 = 1,900 centimeter,
So 19 m = 1,900 centimeter.
g. ____________ m = 2,400 cm,
Explanation:
1 cm is equal to 1 Ã· 10^{2 }m,
2,400 cm = 2,400 Ã· 10 X 10 = 2400 Ã· 100 = 24 m,
So 24 m = 2,400 cm.
h. 90 m = 9,000 cm,
Explanation:
90 m is equal to 10^{2 }centimeter,
90 m = 90 X 10 X 10 = 9,000 centimeter,
So 90 m = 9,000 centimeter.
Question 2.
Find the equivalent measures.
a. 7 km 123 m = _______7,123________ m
b. 22 km 22 m = ______22,022_________ m
c. 875 km 4 m = _______875,004________ m
d. 7 m 45 cm = _______745________ cm
e. 67 m 7 cm = ________6707_______ cm
f. 204 m 89 cm = ____204,89__________ cm
a. 7 km 123 m = 7,123 m,
Explanation:
1 km is equal to 10^{3 }meter,
7 km 123 m = 7 X 10 X 10 X 10 + 123 = 7,000 + 123 = 7,123 meter,
So, 7 km 123 m = 7,123 m.
b. 22 km 22 m = 22,022 m,
Explanation:
1 km is equal to 10^{3 }meter,
22 km 22 m = 22 X 10 X 10 X 10 + 22 = 22,000 + 22 = 22,022 meter,
So, 22 km 22 m = 22,022 m.
c. 875 km 4 m = 875,004 m,
Explanation:
1 km is equal to 10^{3 }meter,
875 km 4 m = 875 X 10 X 10 X 10 + 4 =
875,000 + 4 = 875004 meter,
So, 875 km 4 m = 875,004 m.
d. 7 m 45 cm =745 cm,
Explanation:
1 m is equal to 10^{2 }meter,
7 m 45 cm =Â 7 X 10 X 10 + 45 = 745 cm,
So, 7 m 45 cm =745 cm.
e. 67 m 7 cm = 6,707 cm,
Explanation:
1 m is equal to 10^{2 }meter,
67 m 7 cm =Â 67 X 10 X 10 + 7 = 6700 + 7 = 6,707 cm,
So, 67 m 7 cm = 6,707 cm.
f. 204 m 89 cm = 204,89 cm,
Explanation:
1 m is equal to 10^{2 }meter,
204 m 89 cm =Â 204 X 10 X 10 + 89 = 20400 + 89 = 204,89 cm,
So, 204 m 89 cm = 204,89 cm.
Question 3.
Solve.
a. 2 km 303 m â€“ 556 m
b. 2 m â€“ 54 cm
c. Express your answer in the smaller unit:
338 km 853 m + 62 km 71 m
d. Express your answer in the smaller unit:
800 m 35 cm â€“ 154 m 49 cm
e. 701 km â€“ 523 km 445 m
f. 231 km 811 m + 485 km 829 m
Use a tape diagram to model each problem. Solve using a simplifying strategy or an algorithm, and write your answer as a statement.
a. 2 km 303 m â€“ 556 m
2 km 303 m â€“ 556 m = 1,747 m,
2 kilometers 303 m minus 556 meters is equal to 1,747 meters,
Explanation:
Given 2 km 303 m âˆ’ 556 m as
2 km 303 m = 2 X 10^{3 }m + 303 m = 2,303 m,
Used a tape diagram to model 2,303 mÂ – 556 m = 1,747 m
as shown above in the picture,
2303 m
– 556 mÂ
Â 1,747 m
Statement is 2 kilometers 303 m minus 556 meters is
equal to 1,747 meters.
b. 2 m â€“ 54 cm
2 m â€“ 54 cm = 146 cm,
2 meters minus 54 cm is equal to 146 centimeters,
Explanation:
Given 2 m âˆ’ 54 cm as
2 m =Â 2 X 10^{2 }cm so 200 cm – 54 cm = 146 cm,
Used a tape diagram to model 200 cmÂ – 54 cm = 146 cm
as shown above in the picture,
200 cm
Â Â –Â 54 cmÂ
Â Â Â 146 cm
Statement is 2 meters minus 54 centimeters is
equal to 146 centimeters.
c. Express your answer in the smaller unit:
338 km 853 m + 62 km 71 m,
338 km 853 m + 62 km 71m = 400,924 m
or 400,924,000 mm,
338 kilometer and 853 meters plus 62 kilometers and
71 meters is 400,924 meters or 400,924,000 millimeters,
Explanation:
Given 338 km 853 m + 62 km 71 m as
338 km 853 m = 338 X 10^{3 }+ 853 = 338000 + 853 = 338853 m
and 62 km 71 m = 62 X 10^{3 }+ 71 =62000 + 71 m = 62071 m
Used a tape diagram to model 338853 m + 62071 m = 400,924 m
as shown above in the picture,
338853 m
+62071 m
400,924 m
Now 400,924 m in the smaller unit in millimeter is as
1 meter is equal to 1000 millimeter,
So 400,924 X 1000 = 400,924,000 millimeters.
Statement : 338 kilometer and 853 meters plus 62 kilometers and
71 meters is 400,924 meters or 400,924,000 millimeters,
d. Express your answer in the smaller unit:
800 m 35 cm â€“ 154 m 49 cm
800 m 35 cm â€“ 154 m 49 cm = 64,586 cm
or 645,860 millimeter,
800 meter and 35 centimeters minus 154 meters
49 centimeters gives 645,860 millimeters,
Explanation:
Given 800 m 35 cm – 154 m 49 cm as
800 m 35 cm = 800 X 10^{2 }+ 35 = 80000 + 35 = 80,035 cm
and 154 m 49 cm = 154 X 10^{2 }+ 49 =15,449 cm
Used a tape diagram to model 80,035 cm – 15,449 cm =
64,586 cm as shown above in the picture,
80,035 cm
– 15449 cm
64,586 cm
Now 64,586 cm in the smaller unit millimeters is as
1 centimeter is equal to 10 millimeter,
So 64,586 X 10 = 645,860 millimeters.
Statement :Â 800 meter and 35 centimeters minus 154 meters
49 centimeters gives 64,586 cm or 645,860 millimeters.
e. 701 km â€“ 523 km 445 m
701 km â€“ 523 km 445 m =
701 kilometers minus 523 kilometers 445 meters
is equal to 177,555 meters,
Explanation:
Given 701 km âˆ’ 523 km 445 m,
701 km = 701 X 10^{3 }m = 701000 m,
and 523 km 445 m = 523 X 10^{3 }m + 445 m = 523445 m
Used a tape diagram to model 701000 mÂ – 523445 m = 177,555 m
as shown above in the picture,
701000 m
523445 mÂ
Â 177,555 m
Statement is 701 kilometers minus 523 kilometers 445 meters
is equal to 177,555 meters.
f. 231 km 811 m + 485 km 829 m
231 km 811 m + 485 km 829 m = 717,640 m,
231 kilometers 811 meters plus 485 kilometers 829 meters
is equal to 717,640 meters,
Explanation:
Given 231 km 811 m + 485 km 829 m,
231 km 811 m = 231Â X 10^{3 }m =231000 m + 811 m = 231811m
and 485 km 829 m = 485 X 10^{3 }m + 829 m = 485829 m
Used a tape diagram to model 231811 m + 485829 m = 717640 m
as shown above in the picture,
231811 m
+485829 mÂ
Â 717640 m
Statement is 231 kilometers 811 meters plus
485 kilometers 829 meters is equal to 717,640 meters,
Question 4.
The length of Celiaâ€™s garden is 15 m 24 cm. The length of her friendâ€™s garden is 2 m 98 cm more than Celiaâ€™s. What is the length of her friendâ€™s garden?
Answer:
The length of Celia’s friend garden is 1822 cm or 18 m 22 cm,
Explanation:
Given the length of Celiaâ€™s garden is 15 m 24 cm,
the length of her friendâ€™s garden is 2 m 98 cm
more than Celiaâ€™s. SoÂ the length of her friendâ€™s garden
is 15 m 24 cm + 2 m 98 cm =
1 m = 10^{2 }cm, 15 m 24 cm = 15 X 10^{2 }+ 24 cm =
1500 + 24 = 1524 cm and 2 m 98 cm = 2 X 10^{2 }+ 98 cm =
200 + 98 = 298 cm, Now 1524 cm + 298 cm =
1524 cm
+298 cm
1822 cm
Therefore, the length of Celia’s friend garden is
1822 cm or 18 m 22 cm.
Question 5.
Sylvia ran 3 km 290 m in the morning. Then, she ran some more in the evening. If she ran a total of 10 km, how far did Sylvia run in the evening?
Answer:
Sylvia ran 6 km 710 m or 6710 m in the evening,
Explanation:
Sylvia ran 3 km 290 m in the morning. Then, she ran some more in the evening. If she ran a total of 10 km,
So Sylvia ran in the evening is 10 km – 3 km 290 m =
as 1 km = 10^{3 }m so 10 km = 10000 m and 3 km 290 m =
3 X 10^{3 }m + 290 m =3290 m
10000 m
3290 m
Â 6710 m
Therefore, Sylvia ran 6 km 710 m or 6710 m in the evening.
Question 6.
Jennyâ€™s sprinting distance was 356 meters shorter than Tylerâ€™s. Tyler sprinted a distance of 1 km 3 m. How many meters did Jenny sprint?
Answer:
Jenny sprint distance is 647 m,
Explanation:
Given Jennyâ€™s sprinting distance was 356 meters
shorter than Tylerâ€™s. Tyler sprinted a distance of 1 km 3 m.
So number of meters did Jenny sprint is 1 km 3 m – 356 m =
1 km = 10^{3 }m so 1 km 3 m = 1 XÂ 10^{3 }m +3 m = 1000 + 3 = 1003 m,
Now 1003 m – 356 m
1003 m
356 m
647 m
Therefore, Jenny sprint distance is 647 m.
Question 7.
The electrician had 7 m 23 cm of electrical wire. He used 551 cm for one wiring project. How many centimeters of wire does he have left?
Answer:
The electrician is left with 172 cm electrical wire,
Explanation:
Given the electrician had 7 m 23 cm of electrical wire.
He used 551 cm for one wiring project.
So number of centimeters of wire left is
7 m 23 cm – 551 cm =
as 1 m = 10^{2 }cm So 7 m 23 cm = 7 XÂ 10^{2 }+ 23 =
700 + 23 = 723 cm – 551 cm =
723 cm
551 cm
172 cm
Therefore, the electrician is left with 172 cm electrical wire.