Engage NY Eureka Math 3rd Grade Module 7 Lesson 23 Answer Key
Eureka Math Grade 3 Module 7 Lesson 23 Sprint Answer Key
A
Multiply or Divide by 5
Answer:
Question 1.
2 × 5 =
Answer:
2 × 5 = 10.
Question 2.
3 × 5 =
Answer:
3 × 5 = 15.
Question 3.
4 × 5 =
Answer:
4 × 5 = 20.
Question 4.
5 × 5 =
Answer:
5 × 5 = 25.
Question 5.
1 × 5 =
Answer:
1 × 5 = 5.
Question 6.
10 ÷ 5 =
Answer:
10 ÷ 5 = 2.
Question 7.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.
Question 8.
25 ÷ 5 =
Answer:
25 ÷ 5 = 5.
Question 9.
5 ÷ 5 =
Answer:
5 ÷ 5 = 1.
Question 10.
20 ÷ 5 =
Answer:
20 ÷ 5 = 4.
Question 11.
6 × 5 =
Answer:
6 × 5 = 30.
Question 12.
7 × 5 =
Answer:
7 × 5 = 35.
Question 13.
8 × 5 =
Answer:
8 × 5 = 40.
Question 14.
9 × 5 =
Answer:
9 × 5 = 45.
Question 15.
10 × 5 =
Answer:
10 × 5 = 50.
Question 16.
40 ÷ 5 =
Answer:
40 ÷ 5 = 8.
Question 17.
35 ÷ 5 =
Answer:
35 ÷ 5 = 7.
Question 18.
45 ÷ 5 =
Answer:
45 ÷ 5 = 9.
Question 19.
30 ÷ 5 =
Answer:
30 ÷ 5 = 6.
Question 20.
50 ÷ 5 =
Answer:
50 ÷ 5 = 10.
Question 21.
___ × 5 = 25
Answer:
5 × 5 = 25.
Question 22.
___ × 5 = 5
Answer:
1 × 5 = 5.
Question 23.
___ × 5 = 50
Answer:
10 × 5 = 50.
Question 24.
___ × 5 = 10
Answer:
2 × 5 = 10.
Question 25.
___ × 5 = 15
Answer:
3 × 5 = 15.
Question 26.
50 ÷ 5 =
Answer:
50 ÷ 5 = 10.
Question 27.
25 ÷ 5 =
Answer:
25 ÷ 5 = 5.
Question 28.
5 ÷ 5 =
Answer:
5 ÷ 5 = 1.
Question 29.
10 ÷ 5 =
Answer:
10 ÷ 5 = 2.
Question 30.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.
Question 31.
___ × 5 = 30
Answer:
6 × 5 = 30.
Question 32.
___ × 5 = 35
Answer:
7 × 5 = 35.
Question 33.
___ × 5 = 45
Answer:
9 × 5 = 45.
Question 34.
___ × 5 = 40
Answer:
8 × 5 = 40.
Question 35.
35 ÷ 5 =
Answer:
35 ÷ 5 = 7.
Question 36.
45 ÷ 5 =
Answer:
45 ÷ 5 = 9.
Question 37.
30 ÷ 5 =
Answer:
30 ÷ 5 = 6.
Question 38.
40 ÷ 5 =
Answer:
40 ÷ 5 = 8.
Question 39.
11 × 5 =
Answer:
11 × 5 = 55.
Question 40.
55 ÷ 5 =
Answer:
55 ÷ 5 = 11.
Question 41.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.
Question 42.
60 ÷ 5 =
Answer:
60 ÷ 5 = 12.
Question 43.
12 × 5 =
Answer:
12 × 5 = 60.
Question 44.
70 ÷ 5 =
Answer:
70 ÷ 5 = 14.
B
Multiply or Divide by 5
Answer:
Question 1.
1 × 5 =
Answer:
1 × 5 = 5.
Question 2.
2 × 5 =
Answer:
2 × 5 = 10.
Question 3.
3 × 5 =
Answer:
3 × 5 = 15.
Question 4.
4 × 5 =
Answer:
4 × 5 = 20.
Question 5.
5 × 5 =
Answer:
5 × 5 = 25.
Question 6.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.
Question 7.
10 ÷ 5 =
Answer:
10 ÷ 5 = 2.
Question 8.
20 ÷ 5 =
Answer:
20 ÷ 5 = 4.
Question 9.
5 ÷ 5 =
Answer:
5 ÷ 5 = 1.
Question 10.
25 ÷ 5 =
Answer:
25 ÷ 5 = 5.
Question 11.
10 × 5 =
Answer:
10 × 5 = 50.
Question 12.
6 × 5 =
Answer:
6 × 5 = 30.
Question 13.
7 × 5 =
Answer:
7 × 5 = 35.
Question 14.
8 × 5 =
Answer:
8 × 5 = 40.
Question 15.
9 × 5 =
Answer:
9 × 5 = 45.
Question 16.
35 ÷ 5 =
Answer:
35 ÷ 5 = 7.
Question 17.
30 ÷ 5 =
Answer:
30 ÷ 5 = 6.
Question 18.
40 ÷ 5 =
Answer:
40 ÷ 5 = 8.
Question 19.
50 ÷ 5 =
Answer:
50 ÷ 5 = 10.
Question 20.
45 ÷ 5 =
Answer:
45 ÷ 5 = 9.
Question 21.
___ × 5 = 5
Answer:
1 × 5 = 5.
Question 22.
___ × 5 = 25
Answer:
5 × 5 = 25.
Question 23.
___ × 5 = 10
Answer:
2 × 5 = 10.
Question 24.
___ × 5 = 50
Answer:
10 × 5 = 50.
Question 25.
___ × 5 = 15
Answer:
3 × 5 = 15.
Question 26.
10 ÷ 5 =
Answer:
10 ÷ 5 = 50.
Question 27.
5 ÷ 5 =
Answer:
Question 28.
50 ÷ 5 =
Answer:
Question 29.
25 ÷ 5 =
Answer:
Question 30.
15 ÷ 5 =
Answer:
Question 31.
___ × 5 = 15
Answer:
Question 32.
___ × 5 = 20
Answer:
Question 33.
___ × 5 = 45
Answer:
Question 34.
___ × 5 = 35
Answer:
Question 35.
40 ÷ 5 =
Answer:
Question 36.
45 ÷ 5 =
Answer:
Question 37.
30 ÷ 5 =
Answer:
Question 38.
35 ÷ 5 =
Answer:
Question 39.
11 × 5 =
Answer:
Question 40.
55 ÷ 5 =
Answer:
Question 41.
12 × 5 =
Answer:
Question 42.
60 ÷ 5 =
Answer:
Question 43.
13 × 5 =
Answer:
Question 44.
65 ÷ 5 =
Answer:
Eureka Math Grade 3 Module 7 Lesson 23 Problem Set Answer Key
Question 1.
Gale makes a miniature stop sign, a regular octagon, with a perimeter of 48 centimeters for the town he built with blocks. What is the length of each side of the stop sign?
Answer:
The length of each side of the stop sign = 6 centimeters.
Explanation:
Perimeter of Gale a miniature stop sign, a regular octagon = 48 centimeters
Number of sides of Gale a miniature stop sign, a regular octagon = 8
The length of each side of the stop sign = Perimeter of Gale a miniature stop sign, a regular octagon ÷ Number of sides of Gale a miniature stop sign, a regular octagon
= 48 centimeters ÷ 8
= 6 centimeters.
Question 2.
Travis bends wire to make rectangles. Each rectangle measures 34 inches by 12 inches. What is the total length of the wire needed for two rectangles?
Answer:
The total length of the wire needed for two rectangles = 184 inches.
Explanation:
Length of the Travis’s rectangle = 34 inches
Width of the Travis’s rectangle = 12 inches
Perimeter of the Travis’s rectangle = 2 ( Length + Width)
= 2 ( 34 inches + 12 inches )
= 2 × 46 inches
= 92 inches.
The total length of the wire needed for two rectangles = 2 × Perimeter of the Travis’s rectangle
= 2 × 92 inches
= 184 inches.
Question 3.
The perimeter of a rectangular bathroom is 32 feet. The width of the room is 8 feet. What is the length of the room?
Answer:
The length of the room = 8 feet.
Explanation:
Perimeter of a rectangular bathroom = 32 feet.
Width of a rectangular bathroom = 8 feet.
Length of a rectangular bathroom = ??
Perimeter of a rectangular bathroom = 2 ( Length + Width)
=> 32 feet = (2 × Length) + (2 × 8 feet)
=> 32 feet = (2 × Length) + 16 feet
=> 32 feet – 16 feet = (2 × Length)
=> 16 feet = (2 × Length)
=> 16 feet ÷ 2 = Length
=> 8 feet = Length
Question 4.
Raj uses 6-inch square tiles to make a rectangle, as shown below. What is the perimeter of the rectangle in inches?
Answer:
Perimeter of the rectangle in inches =96-inches.
Explanation:
Length of the side square tiles Raj uses to make a rectangle = 6-inch
Number of side of square tiles in the rectangle = 16
Perimeter of the rectangle in inches = Length of the side square tiles Raj uses to make a rectangle × Number of side of square tiles in the rectangle
= 6-inch × 16
= 96-inches.
Question 5.
Mischa makes a 4-foot by 6-foot rectangular banner. She puts ribbon around the outside edges. The ribbon costs $2 per foot. What is the total cost of the ribbon?
Answer:
Total cost of the ribbon = $20.
Explanation:
Length of the rectangular banner = 6-foot
Width of the rectangular banner = 4-foot
Perimeter of the rectangular banner = 2 ( Length + Width)
= 2 ( 6-foot + 4-foot )
= 2 × 10-foot
= 20- foot.
Cost of the ribbon per foot = $2
Total cost of the ribbon = Perimeter of the rectangular banner × Cost of the ribbon per foot
= 20- foot × $2
= $40.
Question 6.
Colton buys a roll of wire fencing that is 120 yards long. He uses it to fence in his 18-yard by 24-yard rectangular garden. Will Colton have enough wire fencing left over to fence in a 6-yard by 8-yard rectangular play space for his pet rabbit?
Answer:
Yes, Colton has wire fencing left over to fence for rectangular play space for his pet rabbit.
Explanation:
Total length of wire Colton purchased = 120 yards.
Length of the rectangular garden = 24-yard
Width of the rectangular garden = 18-yard
Perimeter of the rectangular garden = 2 ( Length + Width)
= 2 ( 24-yard + 18-yard )
= 2 × 42-yard
= 84-yard.
Wire used = Total length of wire Colton purchased – Perimeter of the rectangular garden
= 120 yards – 84 yards
= 36 yards.
Length of the rectangular play space for his pet rabbit = 8-yard
Width of the rectangular play space for his pet rabbit = 6-yard
Perimeter of the rectangular play space for his pet rabbit = 2 ( Length + Width)
= 2 ( 8-yard + 6-yard )
= 2 × 14-yard
= 28-yard.
Wire left = Wire used – Perimeter of the rectangular play space for his pet rabbit
= 36 yards – 28 yards
= 8 yards.
Eureka Math Grade 3 Module 7 Lesson 23 Exit Ticket Answer Key
Adriana traces a regular triangle to create the shape below. The perimeter of her shape is 72 centimeters. What are the side lengths of the triangle?
Answer:
The side lengths of the triangle = 9 centimeters.
Explanation:
Perimeter of Adriana’s shape = 72 centimeters
Number of sides of the triangle shape = 8
The side lengths of the triangle = Perimeter of Adriana’s shape ÷ Number of sides of the triangle shape
= 72 centimeters ÷ 8
= 9 centimeters.
Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key
Question 1.
Rosie draws a square with a perimeter of 36 inches. What are the side lengths of the square?
Answer:
The side lengths of the square = 9 inches.
Explanation:
Perimeter of the Square = 36 inches
Number of sides in the square = 4
The side lengths of the square = Perimeter of the Square ÷ Number of sides in the square
= 36 inches ÷ 4
= 9 inches.
Question 2.
Judith uses craft sticks to make two 24-inch by 12-inch rectangles. What is the total perimeter of the 2 rectangles?
Answer:
Total perimeter of the 2 rectangles = 144 inches.
Explanation:
Length of the rectangle = 24-inch
Width of the rectangle = 12-inch
Perimeter of the rectangle = 2 ( Length + Width)
= 2 ( 24-inch + 12-inch )
= 2 × 36-inch
= 72 inches.
Total perimeter of the 2 rectangles = Perimeter of the rectangle × 2
= 72 inches × 2
= 144 inches.
Question 3.
An architect draws a square and a rectangle, as shown below, to represent a house that has a garage. What is the total perimeter of the house with its attached garage?
Answer:
Perimeter of the attached garage = 250 ft.
Explanation:
Length of the side AB in the attached garage = 55 ft
Length of the side BC in the attached garage = 10 ft
Length of the side CD in the attached garage = 30 ft
Length of the side DE in the attached garage = 30 ft
Length of the side EF in the attached garage = 30 ft
Length of the side FG in the attached garage = 55 ft
Length of the side GA in the attached garage = 40 ft
Perimeter of the attached garage = Length of the side AB in the attached garage + Length of the side BC in the attached garage + Length of the side CD in the attached garage + Length of the side DE in the attached garage + Length of the side EF in the attached garage + Length of the side FG in the attached garage + Length of the side GA in the attached garage
= 55 ft + 10 ft + 30 ft + 30 ft + 30 ft + 55 ft + 40 ft
= 65 ft + 30 ft + 30 ft + 30 ft + 55 ft + 40 ft
= 95 ft + 30 ft + 30 ft + 55 ft + 40 ft
= 125 ft + 30 ft + 55 ft + 40 ft
= 155 ft + 55 ft + 40 ft
= 210 ft + 40ft
= 250 ft.
Question 4.
Manny draws 3 regular pentagons to create the shape shown below. The perimeter of 1 of the pentagons is 45 inches. What is the perimeter of Manny’s new shape?
Answer:
Perimeter of Manny’s new shape = 99 inches.
Explanation:
Perimeter of the regular pentagons Manny draws = 45 inches
Number of side in the regular pentagons Manny draws = 5
Length of the side of the regular pentagons Manny draws = Perimeter of the regular pentagons Manny draws ÷ Number of side in the regular pentagons Manny draws
= 45 inches ÷ 5
= 9 inches.
Number of side Manny’s new shape has = 11 ( Side AB + Side BC +Side CD + Side DE + Side EF +Side FG + Side GH + Side HI + Side IJ +Side JK + Side KA )
Perimeter of Manny’s new shape = Number of side Manny’s new shape has × Length of the side of the regular pentagons Manny draws
= 11 × 9 inches
= 99 inches.
Question 5.
Johnny uses 2-inch square tiles to make a square, as shown below. What is the perimeter of Johnny’s square?
Answer:
Perimeter of Johnny’s square = 24 inches.
Explanation:
Number of side in the Johnny’s square = 12
Length of side in the Johnny’s square = 2 inches
Perimeter of Johnny’s square = Number of side in the Johnny’s square × Length of side in the Johnny’s square
= 12 × 2 inches
= 24 inches.
Question 6.
Lisa tapes three 7-inch by 9-inch pieces of construction paper together to make a happy birthday sign for her mom. She uses a piece of ribbon that is 144 inches long to make a border around the outside edges of the sign. How much ribbon is leftover?
Answer:
Ribbon leftover = 76 inches.
Explanation:
Length of the Lisa’s piece of construction paper = 9-inch
Width of the Lisa’s piece of construction paper = 7-inch
Perimeter of the pieces of construction paper used to make a happy birthday sign for her mom = Side AB + Side BC + Side CD + Side DE + Side EF + Side FG + Side GH +Side HA
= 9-inch + 9-inch + 9-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 18-inch + 9-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 27-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 34-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 43-inch + 9-inch + 9-inch + 7-inch
= 52-inch + 9-inch + 7-inch
= 61-inch + 7-inch
= 68-inch.
Piece of ribbon Lisa’s has = 144 inches
Ribbon leftover = Piece of ribbon Lisa’s has – Perimeter of the pieces of construction paper used to make a happy birthday sign for her mom
= 144 inches – 68-inch.
= 76 inches.