Engage NY Eureka Math 3rd Grade Module 5 Lesson 13 Answer Key
Eureka Math Grade 3 Module 5 Lesson 13 Problem Set Answer Key
Answer:
Question 6.
Use the diagram below to complete the following statements.
a. Rope ____________ is \(\frac{1}{2}\) the length of Rope B.
b. Rope ____________ is \(\frac{1}{2}\) the length of Rope A.
c. Rope C is \(\frac{1}{4}\) the length of Rope ____________.
d. If Rope B measures 1 m long, then Rope A is ____________ m long, and Rope C is ____________ m long.
e. If Rope A measures 1 m long, Rope B is ____________ m long, and Rope C is ____________ m long.
Answer:
a. Rope C is \(\frac{1}{2}\) the length of Rope B.
b. Rope B is \(\frac{1}{2}\) the length of Rope A.
c. Rope C is \(\frac{1}{4}\) the length of Rope A.
d. If Rope B measures 1 m long, then Rope A is 2 m long, and Rope C is \(\frac{1}{2}\) long.
e. If Rope A measures 1 m long, Rope B is\(\frac{1}{2}\)Â long, and Rope C is \(\frac{1}{4}\)m long.
Question 7.
Ms. Fan drew the figure below on the board. She asked the class to name the shaded fraction. Charlie answered \(\frac{3}{4}\). Janice answered \(\frac{3}{2}\). Jenna thinks they’re both right. With whom do you agree? Explain your thinking.
Answer:
Explanation :
From figure one if the Big rectangle is considered as 1 whole then \(\frac{3}{4}\) is right .
From figure Two if the Small rectangle is considered as 1 whole then \(\frac{3}{2}\) is right .
It is based on the consideration of Rectangles as 1 whole .
Eureka Math Grade 3 Module 5 Lesson 13 Exit Ticket Answer Key
Ms. Silverstein asked the class to draw a model showing \(\frac{2}{3}\) shaded. Karol and Deb drew the models below. Whose model is correct? Explain how you know.
Answer :
Both the Models are correct
Explanation :
Karol’s Diagram is a rectangle box where \(\frac{2}{3}\) is shaded and in Deb;s diagram 3 rhombus are drawn and 2 are shaded even that represent \(\frac{2}{3}\) ..
So, both diagrams represent \(\frac{2}{3}\) fractions.
Eureka Math Grade 3 Module 5 Lesson 13 Homework Answer Key
Answer:
Question 5.
Use the pictures below to complete the following statements.
a. Towel Rack ____________ is about \(\frac{1}{2}\) the length of Towel Rack C.
b. Towel Rack ____________ is about \(\frac{1}{3}\) the length of Towel Rack C.
c. If Towel Rack C measures 6 ft long, then Towel Rack B is about ____________ ft long, and Towel Rack A is about ____________ ft long.
d. About how many copies of Towel Rack A equal the length of Towel Rack C? Draw number bonds to help you.
e. About how many copies of Towel Rack B equal the length of Towel Rack C? Draw number bonds to help you.
Answer:
a. Towel Rack B is about \(\frac{1}{2}\) the length of Towel Rack C.
b. Towel Rack A is about \(\frac{1}{3}\) the length of Towel Rack C.
c. If Towel Rack C measures 6 ft long, then Towel Rack B is about 3 ft long, and Towel Rack A is about 2 ft long.
Explanation :
Towel Rack B is about \(\frac{1}{2}\) the length of Towel Rack C.
Towel Rack C = 6 ft
Towel Rack B = 6 / 2 = 3 ft.
Towel Rack A is about \(\frac{1}{3}\) the length of Towel Rack C.
Towel A = 6/3 = 2 ft .
d. 3 copies of Towel Rack A equal the length of Towel Rack C
e. 2 copies of Towel Rack B equal the length of Towel Rack C
Question 6.
Draw 3 strings—B, C, and D—by following the directions below. String A is already drawn for you.
String B is \(\frac{1}{3}\) of String A.
String C is \(\frac{1}{2}\) of String B.
String D is \(\frac{1}{3}\) of String C.
Extension: String E is 5 times the length of String D.
Answer:
Explanation :
String B is \(\frac{1}{3}\) of String A.
String C is \(\frac{1}{2}\) of String B.
String C is \(\frac{1}{2}\) × \(\frac{1}{3}\) of String A
= String C is \(\frac{1}{6}\)Â of String A
String D is \(\frac{1}{3}\) of String C.
String D is \(\frac{1}{3}\) × \(\frac{1}{6}\) of String A
= String D is \(\frac{1}{18}\) of string A
Extension: String E is 5 times the length of String D.
String D is \(\frac{1}{18}\) of string A So,
String E is 5 \(\frac{1}{18}\) of string A
= String E is  \(\frac{5}{18}\) of string A