## Engage NY Eureka Math 3rd Grade Module 4 Lesson 13 Answer Key

### Eureka Math Grade 3 Module 4 Lesson 13 Problem Set Answer Key

Question 1.

Each of the following figures is made up of 2 rectangles. Find the total area of each figure.

Figure 1: Area of A + Area of B: ____18_____ sq units + _____9____ sq units = _____27____ sq units

Figure 2: Area of C + Area of D: ____18_____ sq units + ___15______ sq units = ___33______ sq units

Figure 3: Area of E + Area of F: _____9____ sq units + ____21_____ sq units = ____30_____ sq units

Figure 4: Area of G + Area of H: _____49____ sq units + ___6______ sq units = ____55_____sq units

Answer:

The total area of figure 1 = 27 sq units.

the total area of figure 2 = 33 sq units.

the total area of figure 3 = 30 sq units.

the total area of figure 4 = 55 sq units.

Explanation:

In the above-given question,

given that,

the area of rectangle A + rectangle B = figure 1.

area of rectangle A = 18 sq units.

area of rectangle B = 9 sq units.

so the area of figure 1 = 27 sq units.

the area of rectangle C + rectangle D = figure 2.

area of rectangle C = 18 sq units.

area of rectangle D = 15 sq units.

so the area of figure 2 = 33 sq units.

the area of rectangle E + rectangle F = figure 3.

area of rectangle E = 9 sq units.

area of rectangle F = 21 sq units.

so the area of figure 3 = 30 sq units.

the area of rectangle G + rectangle H = figure 4.

area of rectangle G = 49 sq units.

area of rectangle H = 6 sq units.

so the area of figure 4 = 55 sq units.

Question 2.

The figure shows a small rectangle cut out of a bigger rectangle. Find the area of the shaded figure.

Area of the shaded figure: __90____ â€“ __12____ = ___78___

Area of the shaded figure: ___78___ square centimeters

Answer:

The area of the shaded figure = 78 sq cm.

Explanation:

In the above-given question,

given that,

area of longer rectangle = 90 sq cm.

area = l x b.

area = 9 x 10.

area = 90 sq cm.

area of smaller rectangle = 12 sq cm.

area = l x b.

area = 3 x 4.

area = 12 sq cm.

area of shaded rectangle = area of longer rectangle – area of smaller rectangle.

area of shaded rectangle = 90 – 12.

area of shaded rectangle = 78 sq cm.

Question 3.

The figure shows a small rectangle cut out of a big rectangle.

a. Label the unknown measurements.

Answer:

The unknown measurements = 4 cm and 5 cm.

Explanation:

In the above-given question,

given that,

the longer rectangle = 9 x 7 = 63 cm.

9 – 4 = 3.

7 – 3 = 4.

so the unknown measurements = 4 cm and 5 cm.

b. Area of the big rectangle:

___9__ cm Ã— __7___ cm = __63___ sq cm

Answer:

The area of big rectangle = 63 sq cm.

Explanation:

In the above-given question,

given that,

area of the big rectangle = l x b.

where l = length, and b = breadth.

area = 9 x 7 = 63 sq cm.

so the area of big rectangle = 63 sq cm.

c. Area of the small rectangle:

___5__ cm Ã— __4___ cm = ___20__ sq cm

Answer:

The area of small rectangle = 20 sq cm.

Explanation:

In the above-given question,

given that,

area of the big rectangle = l x b.

where l = length, and b = breadth.

area = 5 x 4 = 20 sq cm.

so the area of big rectangle = 20 sq cm.

d. Find the area of the shaded figure.

Answer:

The area of the shaded figure = 43 sq cm.

Explanation:

In the above-given question,

given that,

the area of the longer rectangle = 63 sq cm.

area = l x b.

area = 9 x 7.

area = 63 sq cm.

area of smaller rectangle = 20 sq cm.

area = l x b.

area = 5 x 4.

area = 20 sq cm.

area of shaded rectangle = area of the longer rectangle – the area of the smaller rectangle.

area of shaded rectangle = 63 – 20.

area of shaded rectangle = 43 sq cm.

### Eureka Math Grade 3 Module 4 Lesson 13 Exit Ticket Answer Key

The following figure is made up of 2 rectangles. Find the total area of the figure.

Area of A + Area of B: _____32___ sq units + ____20_____ sq units = ___52______ sq units

Answer:

The area of rectangle A and B = 52 sq units.

Explanation:

In the above-given question,

given that,

the area of rectangle A + rectangle B = figure 1.

area of rectangle A = 32 sq units.

area of rectangle B = 20 sq units.

so the area of rectangle A and B = 52 sq units.

### Eureka Math Grade 3 Module 4 Lesson 13 Homework Answer Key

Question 1.

Each of the following figures is made up of 2 rectangles. Find the total area of each figure.

Figure 1: Area of A + Area of B: ____15_____ sq units + ____9_____ sq units = ___24______ sq units

Figure 2: Area of C + Area of D: ___3______ sq units + ____8_____ sq units = ____24_____ sq units

Figure 3: Area of E + Area of F: ___12______ sq units + ____32_____ sq units = ____44_____ sq units

Figure 4: Area of G + Area of H: _____15____ sq units + ____25_____ sq units = ___40______ sq units

Answer:

The total area of figure 1 = 24 sq units.

the total area of figure 2 = 24 sq units.

the total area of figure 3 = 44 sq units.

the total area of figure 4 = 40 sq units.

Explanation:

In the above-given question,

given that,

the area of rectangle A + rectangle B = figure 1.

area of rectangle A = 15 sq units.

area of rectangle B = 9 sq units.

so the area of figure 1 = 24 sq units.

the area of rectangle C + rectangle D = figure 2.

area of rectangle C = 3 sq units.

area of rectangle D = 8 sq units.

so the area of figure 2 = 24 sq units.

the area of rectangle E + rectangle F = figure 3.

area of rectangle E = 12 sq units.

area of rectangle F = 32 sq units.

so the area of figure 3 = 44 sq units.

the area of rectangle G + rectangle H = figure 4.

area of rectangle G = 15 sq units.

area of rectangle H = 25 sq units.

so the area of figure 4 = 40 sq units.

Question 2.

The figure shows a small rectangle cut out of a big rectangle. Find the area of the shaded figure.

Answer:

The area of the shaded figure = 45 sq cm.

Explanation:

In the above-given question,

given that,

the area of the longer rectangle = 56 sq cm.

area = l x b.

area = 7 x 8.

area = 56 sq cm.

area of smaller rectangle = 9 sq cm.

area = l x b.

area = 3 x 3.

area = 9 sq cm.

area of shaded rectangle = area of the longer rectangle – the area of the smaller rectangle.

area of shaded rectangle = 56 – 9.

area of shaded rectangle = 45 sq cm.

Question 3.

The figure shows a small rectangle cut out of a big rectangle.

a. Label the unknown measurements.

Answer:

The unknown measurements = 3 cm and 4 cm.

Explanation:

In the above-given question,

given that,

the longer rectangle = 9 x 8 = 72 cm.

9 – 6 = 3.

8 – 4 = 4.

so the unknown measurements = 3 cm and 4 cm.

b. Area of the big rectangle:

____9__ cm Ã— ___8___ cm = ___72___ sq cm

Answer:

The area of big rectangle = 72 sq cm.

Explanation:

In the above-given question,

given that,

area of the big rectangle = l x b.

where l = length, and b = breadth.

area = 9 x 8 = 72 sq cm.

so the area of big rectangle = 72 sq cm.

c. Area of the small rectangle:

___3___ cm Ã— ___4___ cm = __12____ sq cm

Answer:

The area of small rectangle = 12 sq cm.

Explanation:

In the above-given question,

given that,

area of the big rectangle = l x b.

where l = length, and b = breadth.

area = 3 x 4 = 12 sq cm.

so the area of small rectangle = 12 sq cm.

d. Find the area of the shaded figure.

Answer:

The area of the shaded figure = 43 sq cm.

Explanation:

In the above-given question,

given that,

area of longer rectangle = 72 sq cm.

area = l x b.

area = 9 x 8.

area = 72 sq cm.

area of smaller rectangle = 12 sq cm.

area = l x b.

area = 3 x 4.

area = 12 sq cm.

area of shaded rectangle = area of longer rectangle – area of smaller rectangle.

area of shaded rectangle = 72 – 12.

area of shaded rectangle = 60 sq cm.

### Eureka Math Grade 3 Module 4 Lesson 13 Template Answer Key

Area of A + Area of B: _____32___ sq units + ____20_____ sq units = ___52______ sq units

Answer:

The area of rectangle A and B = 52 sq units.

Explanation:

In the above-given question,

given that,

the area of rectangle A + rectangle B = figure 1.

area of rectangle A = 32 sq units.

area of rectangle B = 20 sq units.

so the area of rectangle A and B = 52 sq units.